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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
ve Lul WSUU VUL 110 110 47le 2. Find the greatest number that will divide 967 and 1463 to leaveader 7 in each case.01A1A |
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Answer» 967÷138=71463÷209=7 |
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| 2. |
using long division method ,perform the division (p^3+p^2-132p) ÷ (p^2 -11p) |
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| 3. |
Long-DivisionMethod,35.00 00 |
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Answer» thank you |
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| 4. |
By long division methodx⁴+3x²+7 by x+1 |
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| 5. |
S.1. By using commou multiple method, find the LCM of:() 2, 5 and 10(ul) 15, 20 and 30(iv) 10, 15, 20 and 45(v) 36, 48, 54 and 60. |
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Answer» lcm is ist question 2 5 10 |
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| 6. |
Evaluate the square root of 22.09 by long division method. |
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| 7. |
find the square root of 4356 using long division method |
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Answer» the answer will be 987 the right and correct answer is 987 |
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| 8. |
6. Show that the angles of an equilateral triangie are 60° each. |
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| 9. |
evaluate the square root of 22.09 by long division method |
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Answer» PLEASE HIT THE LIKE BUTTON |
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| 10. |
Proove that √2 is irrational number by long division method. |
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| 11. |
1) a + b2)-la +b)3) b4)a |
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| 12. |
LA and ( are acute anglesthen ST LA (Bch thato ssu |
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| 13. |
Construct an equilateral triangle each of whose sides measure 6.2 cm. Measure each one of its angle |
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| 14. |
Find the length of the radius of the incircle of an equilateral triangle whose sides are 8 cmin length.] |
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| 15. |
Sin CA+B) = LACos (A-B) = 1342Lind the value ofA LA and B |
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Answer» 7936×35 277,760 is the correct answer 277,760 is the answer of the question plz mark me best the correct answer is 277.760 277,760 is the right answer. |
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| 16. |
If cosec ∅ = 2x and cot∅ = 2/x, find the value of 2(x^2-1/x^2) |
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| 17. |
लघु उत्तरीय प्रश्न10. सिद्ध कीजिए : 2tan-=cOScos-la-ba+b |
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Answer» thanks for raising the doubt with us hope it helps! |
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| 18. |
15 multiple of 8 |
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Answer» 15 multiples of 8 are8,16,24,32,40,48,56,64,72,80,88,96,104,112,120 |
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| 19. |
Show that2l a a1b b(b-c)(e-a)la-b)1 c c2 |
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| 20. |
In AABC, LA + <B = 65° and <B + <C = 140°, find the value of LB and |
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Answer» Triangle ABC so A+B+C = 180 A + B = 65 B + C = 140 A + B + B + C = 65 + 140 = 205 180 + B = 205 B = 25 A = 65 - 25 = 40 C = 140 - 25 = 115 thanks |
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| 21. |
757 5. TR AABCH ZC=3 /B=2(LA+ /B)तो त्रिभज के तीनों कोण ज्ञात कीजिए। |
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| 22. |
[sin (-) tan (90° +) sin (180° +)sec (270° + )]/[sin ( 360°-) cos (270° )cosec (180°-) cot (360°-] |
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| 23. |
15. From the figure below LACD+ICBF+BAF is(a) >180° but <270°(b) 270°(c) >270° but <360°(d) 360 |
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| 24. |
Simplify\frac{\cos (360+A) \cdot \sec (-A) \tan (180-A)}{\sec (360+A) \cdot \sin (180+A) \cdot \cot (90-A)} |
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| 25. |
\operatorname { cot } x \operatorname { cot } 2 x - \operatorname { cot } 2 x \operatorname { cot } 3 x - \operatorname { cot } 3 x \operatorname { cot } x = 1 |
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| 26. |
x \text { cot } 2 x - \operatorname { cot } 2 x \operatorname { cot } 3 x - \operatorname { cot } 3 x \operatorname { cot } x = 1 |
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| 27. |
x \operatorname { cot } 2 x - \operatorname { cot } 2 x \operatorname { cot } 3 x - \operatorname { cot } 3 x \operatorname { cot } x = 1 |
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| 28. |
Findthe areaofequilateraltriangie whose sides are 6cm |
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Answer» Area of an equilateral triangle is √3×a×a/4 . Here,a=6. So area=√3 ×36/4 =9√3 cm square. |
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| 29. |
22.cot x cot 2x-cot 2x cot 3x-cot 3x cot x = 1 |
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Answer» L.H.S=cot x. cot 2x - cot 2x. cot3x - cot x. cot3x =cot x. cot 2x - cot3x(cot 2x +cot x) =cotx .cot 2x - cot (x+2x) .(cot 2x+ cot x) [we can writecot3x as cot(x+2x)] =cotx.cot2x- {(cot x. cot 2x -1)/(cot x + cot 2x)}.(cot x + cot 2x) [since cot(a+b)=(cot a. cot b -1)/(cot b+cot a)] =cot x. cot 2x -cot x. cot 2x +1 =1 =R.H.S |
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| 30. |
22,cot x cot 2x-cot 2x cot 3x-cot 3x cot x = 1 |
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Answer» L.H.S=cot x. cot 2x - cot 2x. cot3x - cot x. cot3x =cot x. cot 2x - cot3x(cot 2x +cot x) =cotx .cot 2x - cot (x+2x) .(cot 2x+ cot x) [we can writecot3x as cot(x+2x)] =cotx.cot2x- {(cot x. cot 2x -1)/(cot x + cot 2x)}.(cot x + cot 2x) [since cot(a+b)=(cot a. cot b -1)/(cot b+cot a)] =cot x. cot 2x -cot x. cot 2x +1 =1 =R.H.S |
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| 31. |
64. The length of a rectangle is thrice as long as the side of a squareside of the square is 4 cm more than the width of the rectangle.Tbeing equal, find their dimensions. |
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| 32. |
72, cot x cot 2r-cot 2r cot 3x-cot 3x cot x =1 |
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Answer» don't confuse these type of question read carefully. Use identity or formula l.and convey your logic |
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| 33. |
\int\left(\frac{\cot ^{2} 2 x-1}{2 \cot 2 x}-\cos 8 x \cdot \cot 4 x\right) d x |
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Answer» These are the options |
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| 34. |
\int \frac { d x } { \operatorname { cot } \frac { x } { 2 } \cdot \operatorname { cot } \frac { x } { 3 } \cdot \operatorname { cot } \frac { x } { 6 } } |
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Answer» Note : ∫ tan ( mx ) dx = ( 1/m )· ln | sec mx | = ( - 1/m )· ln | cos mx | ... ... (1)......................................... We have, I = ∫ { -1 / [ cot ( x/2 )· cot ( x/3 )· cot ( x/6 ) ] dx I = ∫ [ - tan(x/2)· tan(x/3)· tan(x/6) ] dx .................... (2)......................................... We have ... tan(x/2 - x/3) = tan(x/6) ⇒ [ tan(x/2) - tan(x/3) ] / [ 1 + tan(x/2)·tan(x/3) ] = tan(x/6) ⇒ tan(x/2) - tan(x/3) = tan(x/6) + tan(x/2)·tan(x/3)·tan(x/6) ⇒ - tan(x/2)·tan(x/3)·tan(x/6) = tan(x/6) + tan(x/3) - tan(x/2) .... (3).........................................From (1), (2) and (3), I = ∫ [ tan(x/6) + tan(x/3) - tan(x/2) ] dx = 6. ln | sec(x/6) | + 3. ln | sec (x/3) | - 2. ln | sec(x/2) | + C ..... Ans. = 2. ln | cos( x/2 ) | - 3. ln | cos( x/3 ) | - 6. ln | cos( x/6) | + C ... Ans. |
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| 35. |
1. Find the least number of four digits which is divisible by 4, 6, 80. Ans.- 1080 |
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Answer» 1080 will be the number which is divisible by 4,6,8 and 10 and not leaving any remainder |
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| 36. |
\int e ^ { x } ( 1 - \cot x + \cot ^ { 2 } x ) d x |
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| 37. |
1.Find the values of k for which the points are collinear (-2, 3), (3,-1),CBSE 20111 |
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| 38. |
1. Draw a line segment AB of length 7 cm. Using ruler and co, 3CBSE 20111=find a point P on AB such that |
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| 39. |
decrease 1080 by 40% |
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Answer» 40% of 1080=40 x 1080 =432 Decrease =1080-432=648 |
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| 40. |
(b) T2% of it is1080. |
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Answer» Ans :- Given12% =1080 Then1%=1080/12=90 Whole quantity =100% So whole quantity =90x100 =₹9000 |
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| 41. |
12 \% \text { of it is } \geqslant 1080 |
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| 42. |
. How many cuboids of sides 6cm, 5cm and 8 cm should be joined to makea perfect cube? |
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Answer» thanks |
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| 43. |
12% of it is ₹1080 |
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| 44. |
The list price of an article is 450 and it is sold for 360.Find: (0) the discount,(ii) the discount percent. |
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Answer» hit like if you find it useful |
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| 45. |
The diagram shows a square divided into strips of equal width. Three strips are black and two are grWhat fraction of the perimeter of the square is grey?(a) 2/3c) 2/5 |
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| 46. |
Seema has a roll of ribbon of length of 30 m. If she cuts strips of length8 per meter how many strips can she get from the roll.How much of the roll will be left |
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Answer» 3strips and ,6meter left 3strips and 6 meter left Total length of ribbon = 30 by m Length of each strip = 8 m Then,Number of strips = 30/8= 3 strips. Length of Roll left= 30 - 8*3= 30 - 24 = 6 m |
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| 47. |
18. A Cycle is brought for Rs.900 and sold for Rs.1080. Find the gain perce.ఒక సైకిలును రూ. 900ను కొని, రూ.1080 లకు అమ్మగా అతడు పొందే లాభసటము |
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Answer» Given:Cp=900 RsSp=1080 RsGain=Sp-Cp=1080-900=180Gain%=(Gain×100)/CP=180×100 -------------. 900=20% |
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| 48. |
(a) Nine hundred ninety nine crore ninehundred ninety nine thousand ninehundred ninety eight. |
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Answer» 9090 90000000 900 99000 998 The number is 9999999998. right |
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| 49. |
11 cost or 1 7 diesel is36.6. 36strips, each containing 12 tablets cost R 1512. How many tablets can1176?Mathematics Bo148 |
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| 50. |
rience,thelocusof(1,R)is2e+3y1=.EXEXAMPLE 58) The lines x + y = la l and ax-y-l intersect eachother in the first quadrant. Then the set of all possible values of a isthe interval.thIAIEFF 20111 |
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Answer» see this. No option (a) is correct given I solved for x part only.. this is the correct. |
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