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Intregationof 4e^3x+14/3e^3x+x+ ce^3x= e^3x/3+c

let the number = xthan the number be 8x and 3xaccording to the question , if the sum of numbers = 1438x + 3x = 143= 11x = 143x = 143/11x= 13 one number = 8x = 8*13 = 104other number = 3x = 3*13=39

ans 2 is wrong posted

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Other answers are

2) cone -- 3-dimensional 3) cylinder - 3-dimensional4) triangle -2-dimensional.

Sn = (n/2)(2a+(n-1)d)90 = (n/2)(4+(n-1)8)180 = n(8n-4)180 = 8n^2-4n8n^2-4n-180 = 0n=5

an = a + d (n -1 )Sn = n * [ a + a + d (n-1) ] / 2 = n * mean of 1st term and nth term90 = n * [ 4 + 8 n - 8 ] /2 => 180 = 8 n² - 4 n => 2 n² - n - 45 = 0n = 5 => an = 2 + 4 * 8 = 34

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This is correct answers

Given,ABB×999=ABC123To find,value of A,B and CLet A be 8,B be 7C be 6.Calculation,When we multiply=>877×999=876123.

right answer is 18 plz like

The right answer is c

d) is the correct answer

option a is the right answer

option c is correct answer.

define all the things then write as X and B are not equal to each other so r||n.

thank you atal let god bless you thanks

500:50100:1010:1correct answer

₹5 to 50 paise1₹= 100 paise5₹=500 paise500 paiseto 50 paise500/5010:1

is the correct answer is

1)a) ₹5 : 50paisa500paisa : 50 paisa10 :1b) 15 kg : 210 gm 15000 gm : 210500 : 72)6 student need 3 computer1 student need 3/6 computer24 students need 3×24/6 = 12 computer

1)a 500paisa:50paisa =10:1b)15000gm:210gm =500:7c)900cm:27cm=100:3d)720hour:36hour=20:1

a) 10:1b) 500:7 c) 100:3d) 20:1is the correct answer of given

the required option is c 92degree

BAE = AED (एकांतर कोण)AED = 35°

∆CED मेंCDE + CED + EDC = 180°53° + CED + 35° = 180°CED = 180 - 88CED = 92° Ans.

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2 3+ 6 8+ 9 5---------- 1 8 6

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A bar is also used when we use logarithm to the base10,

where¯2.75means−2 + .75, the integral part being characteristic and fractional or decimal part is mantissa.

and¯3.78is−3+.78

Hence¯2.75 +¯3.78

=−2+0.75−3+0.78

=−5+1.53

=−4+0.53

=¯4.53

Let distance between home and school be x

We know,Distance = speed*time

Then,As per given conditionx/12 + x/8 = 5(2x + 3x) = 5*245x = 5*24x = 24

Therefore, distance between home and school = 24 km

i) 8×7 = 56ii) 11×6 = 66

Volume of cube= a^3= 1728= a= 12now volume of pyramid= a^2(h/3)= 144*12/3= 144*4= 432cm^3

24×999=23976 is the answer

999 * 102 =(1000-1)*(100+2)=100000+2000-100-2= 101898

A steamer going downstream in a river covers the distance between two towns in 20 hour coming back upstream it covers this distance in 25 hours the speed of water is 4 km/h. find the distance between the two town.:Let s = speed of the boat in still waterthen(s-4) = speed upstreamand(s+4) = speed downstream;Distance both ways is equal. Make a distance equation; Distance = Time * speedUp distance = down distance25(s-4)= 20(s+4):25s - 100 = 20s + 8025s - 20s = +100 + 805s = 180s = 180/5s = 36 mph:Find the distance:Dist = time * speeddownstream: d = 20(36+4) = 800 mandUpstream: d = 25(36-4) = 800 m

A steamer going downstream in a river covers the distance between two towns in 20 hour coming back upstream it covers this distance in 25 hours the speed of water is 4 km/h. find the distance between the two town.:Let s = speed of the boat in still waterthen(s-4) = speed upstreamand(s+4) = speed downstream;Distance both ways is equal. Make a distance equation; Distance = Time * speedUp distance = down distance25(s-4)= 20(s+4):25s - 100 = 20s + 8025s - 20s = +100 + 805s = 180s = 180/5s = 36 mph:Find the distance:Dist = time * speeddownstream: d = 20(36+4) = 800 mandUpstream: d = 25(36-4) = 800 m

Verices= 3 edges= 6= 3*6= 18please like the solution 👍 ✔️

∆ABC is an equilateral triangle.AB = BC = CA = 9 cmO is the circumcentre of ∆ABC.∴ OD is the perpendicular bisector of the side BC. (O is the point of intersection of the perpendicular bisectors of the sides of the triangle)In ∆OBD and ∆OCD,OB = OC (Radius of the circle)BD = DC (D is the mid point of BC)OD = OD (Common)∴ ∆OBD ≅ ∆OCD (SSS congruence criterion)⇒ ∠BOD = ∠COD (CPCT)∠BOC = 2 ∠BAC = 2 × 60° = 120° ( The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle)

In ∆BOD,Sin ∠BOD

Thus, the radius of the circle is 3√3

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another method plzzzz

/_ C = 60° as all sides are equal/_ABD=120° Linear pair /_E =120° opposite angles are equal/_ A= 60° 360°- (120°+120°) =360°-240°=120° =120÷2=60°

try drawing the picture and multiplying the h by the b

Equation4 / (x - 3) = 5 / (2x + 3)Cross multiply4 (2x + 3) = 5(x - 3)8x + 12 = 5x - 158x - 5x = - 15 - 123x = - 27x = - 27 / 3x = - 9

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cos45/(sec30+cosec30)

=1/√2/(2/√3+2)=(1/√2)/2(1/√3+1)=√2*√3/(1+√3)

=√6/(1+√3)

999 995/995 × 999 = 999 × 995 = 994005