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Find the cost price:

1 quintal = Rs 700

100 quintal = 700 x 100 = Rs70,000

Find the selling price of 50 quintal:

1 quintal = Rs 1000

50 quintal = 50 x 1000 = Rs 50,000

Find the remaining amount of quintal:

Remaining amount = 100 - 50 = 50 quintal

Find the selling price of the remaining quintal:

1 quintal = Rs 800

50 quintal = 800 x 50 = Rs 40,000

Find the total selling price:

Total = 50,000 + 40,000 = Rs 90,000

Find the gain:

Gain = Selling Price - Cost Price

Gain = 90,000 - 70,000 = Rs 20,000

Gain percentage = gain / cost price x 100

Gain percentage = 20,000/70,000 x 100 = 28.57%

The gain is Rs 20,000 and it is 28.57%

thanks for this answer

(2187)³/⁷=(3⁷)³/⁷=3³=27

the ratio of the length of a vertical pole and it's shadow on the ground is 7:2 . find the length of the pole if the length of the shadow is 2.4.

thanks

Let AO=HCD=OB=60mA'B=AB=(60+H)m

In triangke AOD,tan30'=AO/OD=H/OD

H=OD/√3OD=√3 H

Now, in triangle A'OD,tan60'=OA'/OD=(OB+BA')/OD√3=(60+60+H)/√3 H =(120+H)/√3 H=>120+H=3H 2H=120 H=60m

Thus, height of the cloud above the lake = AB+A'B =(60+60) = 120m

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3 is the answer of this question

3is right answer ka answer hai

Given series 2187, 729, 243, 81, 27, 9,..... is geometric series with common ratio r= 729/2187 = 1/3and first term a = 2187

Its nth term = ar^[n-1]

Then 7th term = 2187 * (1/3)^[7-1]= 2187 * 1/(3)^6= 2187/729 = 3

Number in the place of ? will be 3.

3 is the right answer

3 is the answer for the question.

Thecube rootof2187is 12.980246132767

2187/3=729729/3=243243/3=8181/3=2727/3=99/3=33/3=1

3×3×3×3×3×3×3=2187Hence3^7=2187

2187/3=729/3=243/3=81/3= 27/3=9/3=3; 3^7=2187

2187/3=729/3=243=81/3=27/3=9/3=3;3^7=2187

Let the share of Bobby be x the share of Saina be 2x the share of Veenu be 5x.

:. percentage of money that Sania gets={2x/(x+2x+5x)}×100={2x/8x}×100=0.25×100=25%

option (b) is correct.

suppose shares of bobby sania and veenu is x 2x and 5xpercentage of sania=2x/8x*100=25%

Lets say we can do selection in way such that we need to select any 4 people out of 10 and out of these 4 we need to get max number of pairsthus no of ways of doing it =10C4×4C2= 1260

49 is 7^2hence7^2*z^-3/(7^-3*10*z^-5)=7^5*z^2/10

thanks

4.Tine of ascent = Time of descentThus, time of ascent, t = 20/2 = 10 secLet the acceleration due to gravity on the planet is g'.then, by using v = u + at0 = 20 - (g' X 10) (as u = 20 m/s and t = 10s and direction of g' is opposite to that of u)g' = 2 m/s^2Thus, weight of the body = mg' = 0.5kg X 2 m/s^2 = 1 kgm/s^2 = 1N

Let radius of the hall = rAs per question= Volume of cylindrical Hall + Volume of dome = πr²*r+ (4/3) πr³/2 = πr³ + 2πr³/3 =5πr³/3then we have 5πr³/3=48510 r³=9264.72 ⇒ r=21.0028 Area of floor= πr²=π*441.118=1385.81 Floor area is 1385 m²

Let centre of circle be O.<BAC = 120°

consider ∆ABO and ∆ACO1) OA =OA --- common side2) OB = ON --- radii of same circle3) AB = AC --- tangents from same pointtherefore ∆ABO congruent to ∆ACOtherefore <ABO = <ACO = 60°

as tan 60° = √3therefore in ∆ABOBO/AB = 6/AB = √3AB = 6 / √3AC = 6 / √3

23yrs

Given :A circle C (0,r) and a tangentlat point A.

To prove :OA⊥l

Construction :Take a point B, other than A, on the tangentl. Join OB. Suppose OB meets the circle in C.

Proof:We know that, among all line segment joining the point O to a point onl, the perpendicular is shortest tol.

OA = OC (Radius of the same circle)

Now, OB = OC + BC.

∴ OB > OC

⇒ OB > OA

⇒ OA < OB

B is an arbitrary point on the tangentl. Thus, OA is shorter than any other line segment joining O to any point onl.

Here, OA ⊥l

13)

Let the speed of stream be uLet speed of boat in still water be v

Time taken to cover 2 km distance upstream =2/v - u = 25/60 = 5/125v - 5u = 24........ (1)

Time take to cover 2 km distance downstream =2/v + u = 20/60 = 1/3v + u = 6............. (2)

Multiply eq(2) by 55v + 5u = 30....... (3)

Add eq(1) and eq(3)10v = 54v = 5.4 km/hr

Put value of v in eq(2)v + u = 6u = 6 - 5.4u = .6 km/hr

Therefore, speed of stream = .6 km/hr

question is not clear enough..

Renuka=12so Sanjay=12+3=15Mother=40i) Renuka/Sanjay=12/15=4/5ii) Sanjay/mother=15/40=3/8

Given : x = a and y = b is solution of x - y = 2 and x + y = 4.

We have

x - y = 2 ....(1)x + y = 4 ....(2)

Eliminating y by (1) and (2)

2x = 6

x = 3

y = 4 - 3 = 1

So, x = a = 3 and y = b = 1

Let son's age is xafter 8 years, x+8/25+8=4/9x+8/33=4/99(x+8)=132x+8=132/9x+8=14.66x=6.66

let sons age be x so mother's age will be x+25

after 8 yrs sons age = x+8mother's age = x+25+8 = x+33

as per given condition x+8/x+33 = 4/9by cross multiply 4(x+33)=9(x+8)4x+132 = 9x+72subtracting 4x on both sides ( always try to take variables first this makes calculation easy)4x+132-4x = 9x+72-4x132=5x+725x+72=132 ( i am just interchanging the places)subtracting 72 on both sides5x+72-72=132-725x=60dividing by 5 on both sides5x/5 = 60/5x=12sons age 12mothers age 12+25 =37

thank u very mych

thank u very much

thnx

given, AC(AB+BC)=16DC=4EF =7now, we know tangent drwan from point are equal. then, EF=ED. ........(I)

DC=BC. ......(ii) AB=AF. .......(iii) so, Perimeter of triangle =ED+DC+BC+AB+AF+FE=(ED+DC)+(BC+AB)+(AF+FE)=2DC+AC+2EF=2*4+16+2*7=8+16+14=28

28 is the correct answer of the given question

1(-10)-2(5-12)+3(2+8)=-10-2(7)+3(10)=-10-14+30=30-24=6

0.8 is bigger than 0.7 as comparing digit after decimal 8 is bigger than 7.