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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Check whether-2 and 2 are the zeroes of the polynomial x^4- 16 |
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| 2. |
(2x+1)(3x+2)=6(x-1)(x-2) check whether this equation is qudratic or not |
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Answer» (2x+1)(3x+2)=2x(3x+2)+1(3x+2)= 6x^2+4x+3x+2=6x^2+7x+2; (x-1)(x-2)=x(x-2)-1(x-2)=x^2-2x-x+2; 6( x^2-2x+2)=6x^2-12x+12; not quardratic |
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| 3. |
Check whether 2 is a root of the equation2 x^{2}-7 x+6=0 |
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Answer» putting x= 22(2)^2 - 7(2) + 6= 2(4) - 14 + 6= 8+6-14= 14 - 14= 0 Hence, 2 is a root of the equation. |
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| 4. |
Check whether the following equation is quadrx(e,+ 1)+8=(x + 2) (x-2) |
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| 5. |
Check whether the numbers 2, 4, 8 are in continued proportion or |
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Answer» 2/4=4/84*4=2*8 (cross multiply16=16 (continued proportion) |
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| 6. |
DatePageA man rosses a dlagonelěpe eo |
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| 7. |
AlB is a line segment and P is its mid-point. D andE are points on the same side of AB such that(see Fig. 7.22), Show that(i) Δ DAPs Δ EBP(u) AD BE |
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| 8. |
In a binomial distribution the mean is 12 andthe standard deviation is 3. Then thedistribution is163 I |
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Answer» Option (1) is correct |
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| 9. |
Find the mean of the Binomial distribution B (4, 1/3) |
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| 10. |
s, Suppose X has a binomial distribution B 6,.Show that X 3 is the mostlikely outcome.(Hint : P(X3) is the maximumamong all P(x), x, : 0.1 ,2,3,4,5,6) |
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| 11. |
5. Let OA, OB, ОС be three rays such that OC lies between oaов. Suppose the bisectors of ZAOC anto each other. Prove that B,O,A are collinearandd ZCOB are perpendicular |
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| 12. |
Multiply the binomial(0) (2x + 5) and (4x 3)u ad(2,51+ 0.5m) |
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Answer» (2x+5) × (4x-3)8x^2-6x+20x-158x^2+14x-15 c.s Rai junior high school |
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| 13. |
For a Binomial distribution mean is 5 and the number of trials is 50. Find the variance. |
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| 14. |
8.Bring out the fallacy, if any in the statement "the mean of a Binomial distribution is 5 and standarddeviation is 3. |
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| 15. |
In the given figure, a circle touches all the four sides of a quadrilateral ABCD whose sides are All smBC(b)7 cm and CD4 cm. Find AD.14 |
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| 16. |
D 26 cmC24. Find the area of the quadrilateral ABCD inwhich BCD is an equilateral triangle, eachof whose sides is 26cm, AD 24 cm andBAD 90°. Also, find the perimeter of thequadrilateral. (Given, V3 1.73.) |
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| 17. |
. In the given figure, a circle touches all thefour sides of a quadrilateral ABCD whose threesides are AB-6 cm, BC 7 cm and CD 4 cm.Find AD |
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| 18. |
16. In the given figure, ABCD is a cyclic Dquadrilateral whose sides AB and DOare produced to meet in E.Prove that AEBC ~ ΔEDA. |
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| 19. |
9. In the given figure, a circle touches all thefour sides of a quadrilateral ABCD whose threesides are AB = 6 cm, BC = 7 cm and CD = 4 cm.Find AD. |
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| 20. |
ll Lil, alld they intersect each other at right anglesFind the area of the quadrilateral field ABCD whose sides AB - 40 m, BC -28 m,CD 15 m, AD -9 m and ZA 90 |
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Answer» PLEASE LIKE IT, IF YOU FIND THE ANSWER HELPFUL. |
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| 21. |
θcot θ27. Prove that fan-I + sec θ.cosecθ+I-co18 1-tan θwhereis an acute angle. |
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Answer» GIVEN:- tanθ/(1 - cotθ) + cotθ/(1 - tanθ) => tanθ/(1 - 1/tanθ) + (1/tanθ)/(1 - tanθ) => tan²θ/(tanθ - 1) - 1/tanθ(tanθ - 1) => 1/(tanθ - 1) { tan²θ - 1/tanθ } => 1/(tanθ - 1) { (tan³θ - 1)/tanθ) => {(tanθ - 1)(tan²θ + 1 + tanθ)}/{(tanθ - 1)(tanθ)} => tanθ + cotθ + 1 => sinθ/cosθ + cosθ/sinθ + 1 => (sin²θ + cos²θ)/sinθ . cosθ + 1 => 1/sinθ . cosθ + 1 => cosecθ . secθ + 1 |
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| 22. |
D 28 cm24. Find the area of the quadrilateral ABCD inwhich BCD is an equilateral triangle, eachof whose sides is 26 cm, AD=24cm and<BAD=90". Also, find the perimeter of thequadrilateral. (Given, V3 = 1.73.) |
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| 23. |
HFof840yapplyingtheFundamentalrind the LCM and8. Find the sum of the first 19 terms of the AP, whose nth term is given by t, 7-41.9 Let Pix, ) be any phint on the line ining the noints Ala nd RIO h Show thaitTheorem of Arithmetic. |
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Answer» Like my answer if you find it useful! |
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| 24. |
Tr Find the sum of the first 25 terms of an А.Р. whosenth term is given by a,-2-3n.ICBSE 20041 |
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| 25. |
(i) Find the sum of the first 25 terms of an A.P. whose nth term is given by t= 7 - 3n |
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| 26. |
If 'A is the area of right triangle and 'a' is one of the sides containing right angle. Prove thatfan2Aathe length of the altitude on the hypotenuse is |
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Answer» LetAbe the area of the right triangle andbbe one of the sides containing the right angle. Letxbe the length of the other leg us observe the following figure. Area of a triangle isA=1/2*b*XThus is X=2A/bApply Pythagoras theoremHypotenuse=√b^2+x^2=√b^2+(2A/b)^2=1/b√b^4+4A^2Area of triangle A=1/2*hypotenuse*hhenceH=2Ab/√b^4+4A^2 |
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| 27. |
B e L e e e e L P e S किन्नर=fi%i‘#JfiEM g Z 2 = ‘T T o ! = a’b b = Ll Jzu.g?_%flm‘ i}% For 2R and b:3 : |
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Answer» Multiply (2/3)a^2b * (6/5)a^3b^2=(4/5)a^[2+3]b^[1+2]= (4/5)a^5b^3= (4/5)(2)^5(3)^3= (4/5)*32*27= 3456/5= 691.2 thanks |
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| 28. |
£l b B e nal e SRS Lo I is ) डा 095 () 99 (%)= ee T e e T T 021 हरे कह Wil 2 UPD T [k (€ (0“न तन |
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Answer» વિસ્તાર = થીટા /360* π * ત્રિજ્યા ^ 2= 120/360*22/7*21*211/3*22/7*21= 22*21cm^2462cm^2Answer 30 more than one_half of its complement |
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| 29. |
inofaitsnyomoneadjacentangleangleis 4 timesdetermine |
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Answer» Let the first angle be x and the second angle be y.Then x = 4y/55x = 4y 5x - 4y = 0 ......(1)Also x + y = 180° .......(2)Multiply eq (2) by 5Then 5x + 5y = 900° ......(3)(3) - (1) we get9y = 900°y = 100°Put this value in eq (2)x + 100° = 180°x = 180° - 100°x = 80°Therefore, the angles are 80°, 100°, 80°, 100° because in a parallelogram opposite angles are equal. |
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| 30. |
The height of a circular cylinder is 20em and the radii of its base is 7cm. Find thevplume of the cylinder |
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Answer» Given radius r = 7 cm, height h = 20 cm Volume of cylinder= pi*r*r*h= 22/7*7*7*20= 22*140= 3080 cm^3 What is the formula of volume of cylinder |
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| 31. |
angle of a parallelogram is 409 more than its adjacent angle. Find the angles of theparallelogram |
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| 32. |
If one angle of a parallelogram is 36 degrees less than twice its adjacent angle, then find the angles of parallelogram. |
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| 33. |
Totution ul the cow.Take t 3.14et of diameter 2.8 m is spoted in the centre with a 20 em striped bordert Find the area of tstriped portion of the carpet to the nearest cm2 |
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Answer» Area of stripped portion = ( Area of carpet - Area of inner portion) Diameter of carpet = 2.8m = 280cm So radius of carpet= 140cm Area of carpet= 22/7(140*140) = 61600 cm sq Radius of inner portion = 140-20=120cm Area of inner portion= 22/7 (120*120) = 45216 cm sq. Area of stripped portion = 61600-45216= 16384 cm sq. |
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| 34. |
If an angle of a parallelogram isof its adjacent angle, then find the measure of all the anglesof the parallelogram. |
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| 35. |
て59000 at 81, p.athe interest comporundid anruallyRavi investe d 灭Soooo at 81.po. 千or 3mCalculatea) The ambunt tanding to her Creditat tttl end +he econd Year |
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| 36. |
an A.P. is 21. Ifecond number is reduced by 1 while the third is increased by 1, the three consecbers which are consecutivetermsofl/ The sumterms of a G.P. results. Find these numbers. |
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| 37. |
Also, find the interest paid by him.26. Find whether or not the first polynomial is a factor of the second polynomiat3x +2, 3x4 +5x3 x213x 10 |
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| 38. |
14) The Cooking Club made some pies to sell atada basketball game to raise money for thenew math books. The cafeteria contributedfour pies to the sale. Each pie was then cutinto five pieces and sold. There were a totalof 60 pieces to sell. How many pies did theclub make? |
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Answer» Let the club make n pies Cafeteria contributed 4 pies then total number of pies = n + 4 Each pie cut into 5 pieces, then total number of pie pieces = (n + 4)*5 Given total number of pie pieces to sell = 60 Thus, (n + 4)*5 = 60n + 4 = 60/5 n + 4 = 12n = 12 - 4 = 8 Therefore total number of pies club make is 8 |
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| 39. |
oth5 meach one hepiesDede per |
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Answer» Let the piece of cloth is x metre and it costs Rs.y/metre. Then by the given conditions -∴, xy=200 -------------(1) and(x+5)(y-2)=200or, xy+5y-2x-10=200or, 200+5y-2x-10=200or, 5y-2x-10=0or, 5y=2x+10or, y=(2x+10)/5Putting in (1),x(2x+10)/5=200or, x(2x+10)=200×5or, 2x²+10x=1000or, x²+5x-500=0or, x²+25x-20x-500=0or, x(x+25)-20(x+25)=0or, (x+25)(x-20)=0either, x+25=0or, x=-25or, x-20=0or, x=20Since the length of the cloth can not be negative,∴, x=20 metrePutting in (1),20y=200or, y=10∴, the cloth is 20 m long and the original rate is Rs. 10/metre |
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| 40. |
fan angle of a parallelogram is two-third of its adjacent angle, then find all the angles ofthe parallelogram. |
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| 41. |
(ii) If an angle of a Parallelogram is two-third of its adjacent angle,find the angles of the parallelogram. |
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| 42. |
15.यदि x2 + 17x+ 72 = 0 तो x का मान क्या होगा ?(A)-9 या 8 (B)-8 या 9 (C)-8 या 9 (D)8 या 9) (B)(C) ) (A) ) (D) |
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Answer» I want to know the answer option c is the right answer option c is the right answer |
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| 43. |
.A circular rug of diameter 1.4 m is spotted in the center with 20 cm striped border Find thethe striped portion of the rug to the nearest em. |
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Answer» but the answer is 7543cm square |
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| 44. |
A circular carpet of diameter 2.8 m is spotted in the centre with a 20 cm striped border. Find the area of thestriped portion of the carpet to the ncarest cm2 |
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Answer» PLEASE LIKE IT, IF YOU FIND THE ANSWER HELPFUL. |
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| 45. |
If an angle of a parallelogram is two-third of its adjacent angle, then find all the angles ofthe parallelogram. |
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| 46. |
(7/8)^3*(7/8)^(-6)=(7/8)^(2*x - 1) |
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Answer» x=-1 is the right answer zhjsdbdodvddBhddbhidibdodbd X= -1 is the correct answer of the given question |
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| 47. |
ldA "NO=dNd í˝aHpa ledO TINd991 |
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Answer» Thanks |
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| 48. |
15. A hollow cylinder has solid hemisphereinward at one end and on the other end itis closed with a flat circular plate. The heightof water is 10 cm when flat circularsurface is downward. Find the level of water,when it is inverted upside down, commondiameter is 7 cm and height of the cylinder is0 cm. |
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Answer» thnx |
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| 49. |
Find the. sumttems of the sertest/ |
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Answer» If you like the solution, Please give it a 👍 |
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| 50. |
is 7, now ieyis arethere dnd what is tieir sun?Find the-sum of first 2 terms of an APin which d -7 and 22nd em is 149, |
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Answer» hello |
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