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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Self Assessme1. A rectangular piece of metal with sides 24 cmand 18 cm costs1080. How much will a squarepiece of the same metal of side 16 cm cost if thecost of metal is proportional to its area(a) 840(c) 720(b)(d)640900 |
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Answer» Area of Reactangular piece= length * breadth= 24 * 18= 432 cm^2 Area of Square piece= side*side= 16*16= 256 cm^2 Now, 432 cm^2 cost = 10801 cm^2 cost = 1080/432 = 2.5 Then,256 cm^2 cost = 232*2.5= Rs 640 (b) is correct option |
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| 2. |
80 m 15 cm + 12 m 37 cm |
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Answer» 92 m 52 cm (it is the answer) 80+12=92m 15+37= 52cm |
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| 3. |
Fins in the blanks220+C-117- 720 (i) (-5) +48).(1) 53) +2 = - +(-3) |
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| 4. |
the length of two adjacent sides of a parallelogram are respectively 51 cm. and 37 cm. one of its diagonal is 20 cm. find the area of parallelogram . |
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| 5. |
(A):54. FFके रके यु2,5,9, 19, 37,(A) 73 (B)75 (0)76 (D) 78The following question consists of a pair of numbersthat have a certain relationship to each other, followedby four other pairs of numbers given as alternatives.Select the pair in which the numbers are similarlyrelated as in the given pair.11 : 1210(A)8:448B16:216007:1029(D)9:729प्रकार |
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Answer» 8:448 8 × 8 × (8 - 1) = 64 × 7 = 448 11 × 11 × (11 - 1) = 1210 |
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| 6. |
(a)isdoubled(b) becomes3times(c)becomes8times(d)honeUllese.16. The height of a cone is 24 cm and the diameter of its base is 14 cm., then its curved surfacearea is(a) 550cm 2(b) 704 cm2(c) 705 cm2(d) none of these |
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| 7. |
6.9 822(AW)सभी खण्ड कीजिए :%) चित्र में, 70. 1. 80 है।-सिद्ध:कीजिए :AB? + CD? = BD? + AC? |
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| 8. |
06. A coin is tossed 200 times and is found that a tai) comes up for 120 times. Find the probabilityof getting a tail. |
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Answer» probability of getting a tail would be= 120/200= 60/100= 30/50= 3/5thanks |
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| 9. |
ABCD isa rhombus. If AC 6 cm and BD 9 cm, find4.ar (ABCD)5. |
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| 10. |
Queston7. Find HCF of the numbers given below:k, 2k, 3k, 4k and 5k, where k is any positive integer |
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Answer» 2k = 2×k 3k = 3×k 4k = 2² × k 5k = 5 × k HCF (Highest common factor) = k |
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| 11. |
A room is 9 m long, 8 m broad and 6.5 m high. It has o2 m × 1.5 m and three windows each of dimensions 1.5 m x 1 m.washing the walls at Rs 3.80 per square metre.ne door of dimensionsFind the cost of white |
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| 12. |
whether or not the following are composite numbers39, 47, 57, 69, 83, 93, 103other the given numbers are even or not: |
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Answer» 39,57,69,93,......this is the right answer 39,57,69,93 is the answer 39,57,69,93 is the answer |
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| 13. |
4 w/â .(5 - ) o|) e |
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| 14. |
“सऋद्ध ऊऊ..ऊ _ToE BT W .. |
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| 15. |
(d) A farmer wants to fertilize his fieldGameswhose dimensions are 70 ft by 20 ft.He has bought five bags of fertilizer,75 meach of which can cover 200 sq.ft. Are they sufficient to fertilize his field? If not, how much more fertilizer he has tobuy? (Hint: First find the area of the field and then compare it with the given area.) |
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Answer» area of rectangle =l+b so, |
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| 16. |
(অDTT W TJ | এতমূUT\T)In which the following rational number can be expressedas a terminating decimal?তলৰ পৰিমেয় সংখ্যাবােৰৰ কোনটোৰ দশমিক বিস্তৃতি পৰিসমাপ্তি থাকিব?77(a).০০(b) 3(c) 2(d) .125. |
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Answer» b. 13/125 it should be the ans terminating decimal (b) =13/125 b. 13/125 it should be the ans |
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| 17. |
Toe0 %Fabea whole number |
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Answer» Yes,Thewhole numbersare thenumbers 0, 1, 2, 3, 4, and so on (the naturalnumbersand zero). Negativenumbersare not considered "whole numbers." All naturalnumbersarewhole numbers, but not allwhole numbersare naturalnumberssince zero is awhole numberbut not a naturalnumber. 0 is a whole number.? = true yes 0 is a whole number 😀 yes 0 is a whole number 0 is a whole number=yes (true) |
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| 18. |
(Converse of Theorem 8) If the two diagonals of a parallelogram areequal, prove that the parallelogram is a rectangle. |
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| 19. |
ORIftwo intersecting chords of a circle make equal angles with the diameter passing throughtheir point of intersection, prove that the chords are equal.ABCD is a rhombus. Show that the diągonal AC bisects ZA as well as zC and diagonal BDbisects zB as well as LD. |
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| 20. |
.AABDABAC(SAS-criteria).Hence, BD ACREM 9 (Converse of Theorem 8) If the two diagonals of a parallelogram areequal, prove that the parallelogram is a rectangle. |
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| 21. |
Verify Rolle's theorem for thefunction,f(x) = x2 + 2x-8 in |
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Answer» pls post it clearly once again sorry it was clear my mistake thankyou |
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| 22. |
TN %(ovitf (3% (3ÂŤ (3 L] â |
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| 23. |
how that the diagonal Acbisects ZA as well as 4C and diagonal BD bisectsINCERTm IKvs 20141Q. LASCD is a rhombus. Show that the diagonal ACQ. 1.AScD is a rhombus.Z8 as wwell as ED |
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| 24. |
x ^ { 3 } p ^ { 2 } - 8 y ^ { 3 } p ^ { 2 } - 4 x ^ { 3 } q ^ { 2 } + 32 y ^ { 3 } q ^ { 2 } |
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| 25. |
.W7. Find ten rational numbers between |
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| 26. |
find toe w rational number between -2and 5 |
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| 27. |
..welive4. Find ten rational numbers between |
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Answer» the rational number between |
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| 28. |
149 A man bought apples at 10 for t 75 and sold them at t 75 per dozen. Flund his loss per cent. |
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Answer» cost of 10 apples=75cost of 1 apple=7.5SP of 12 apples= 75SP of 1 apple=6.25loss = CP-SP=7.5-6.25=0.75loss percent=(loss/CP)*100=(0.75/7.5)*100=10% |
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| 29. |
28/ Anju bought 8 apples. She found 3 of them rotten. What fraction ofapples was good? |
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Answer» Number of good apples = 8-3 = 5. Total apples = 8. Fraction of good apples = 5/8 Please hit the like button if this helped you |
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| 30. |
8.the lineJoining A(B) MidpointdividesyÇ), B (x2Jh)in 1: 1 ratio.A) CentriodC) Points of intersection D) Origin. |
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Answer» Midpoint divides the line in 1:1 ratio. |
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| 31. |
he common ratio of G.P2 4 8 |
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Answer» comman ratio will ve-1/8/1/4=-1/2 thanks thank you junior |
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| 32. |
9. In a G.P. the ratio of the sum of first 3 terms is to that of first 6 terms is 125 : 152. Find thecommon ratio. |
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Answer» Thanks |
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| 33. |
InaG.P.theratioof the sum of first 3 terms is to that of first 6 terms is 125 152. Find thecommon ratio. |
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| 34. |
In a GP tn-(-l)" 2017. Find the common ratio |
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Answer» t(n) = (-1)ⁿ 2017 t(1) = - 2017 t(2) = 2017 So, common ratio is t(2)/t(1) = -1 thanks for solving |
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| 35. |
ontassociălive |
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| 36. |
. In a school, of students are girls. If the number of boys in the school is 200. Find the totalnumber of students in the school. |
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Answer» If total student=xgirls=3/5 xSo,boys = 2/5x=200X=200*5/2=500Total students=500 |
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| 37. |
The sum of the first 3 terms and the sum ofthe first 6 terms of a Geometric series are inthe ratio 125: 152. Find the common ratio ofthe series. |
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| 38. |
the finst termthe10. The ratio of the sum of first three terms is to that of first 6 terms of a G.P. is 125:152. Findcommon ratio.n1respectively. Find the sum of n terms of the |
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Answer» thanks answer is right |
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| 39. |
7. Ifcot6= ——7, evaluate : (1) (s Bl 9) \v (ll) cot’ 08 (1 + cos 8)(1 — cos9) |
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Answer» cot^2theta= 49/64 = (7/8)^2 |
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| 40. |
HOT ont (Simplify):1. 3+ 7.2 + 3.75. |
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Answer» This question Answer is 13.95 |
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| 41. |
7 यदि ८006 - L, तो gy (L*sin O)1-sin8); 8 | (1+ cos 8)(1—cos 0)2B 1 B A |
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| 42. |
फिट(1+ cos 8) (1 - cos 8) |
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Answer» √( 1-cos theeta)^2/√1-cos^2 theeta= √((1-cos theeta/sin theeta)^2= 1-cos theeta/ sin theta cosectheta - cot thetathanksplease like the solution 👍 ✔️👍 |
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| 43. |
8. Let R, and R2 are the remainders when the polynomial+2x2- 5ax - 7 and +ax2 - 12x +6 are divided bý x + 1 and x - 2 respectively, find the value of a if R,R2 |
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| 44. |
(3) Smt Desai sold shares of face value100 when the market value was 50 andreceived 4988.20. She paid brokerage 0.2% and GST on brokerage 18%, then howmany shares did she sell? |
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| 45. |
Smt. Desai sold shares of face value Rs. 100 when the market value was Rs.50 and received 4988.20. She paid brokerage 0.2% and GST on brokerage18%, then how many shares did she sell ? |
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| 46. |
5. Let A 1, 2, 3, 4, 6). Let R be therelation on A defined by[(a, b): a, bEA, b is exactly divisible by a).(i) Write R in roster form(ii) Find the domain of R(ii) Find the range of R. |
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Answer» ५५७७७७४६७३५७६३५७३४७७३६७४७८४ |
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| 47. |
Let F: R²R and g: RPR betwo functions defined by f(x) = 24th,g(x) = 2 Verify (gof): fog! |
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| 48. |
Let R be the relation in the set {l, 2,3,4) given by R= {(12), (2,2), (1,1), (4,4).(1.3), (3,3), (3, 2).] Then(a) R is reflexive and symmetric but not transitive(b) R is reflexive and transitive but not symmetric(c) R is symmetric and transitive but not reflexive(d) R is an equivalence relation1. |
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| 49. |
(dâa)+ = b) + (b-d)eznopeg g1 |
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| 50. |
7. Let A1,2,3,4,63 and Let R be a relation on Adefined byR = {(a,b)| a divides b}Find (i) R, (ii) dom R, (ii) rngR, (iv) RI,v) domRi, (vi) rm-1 |
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