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Algebra is one of the broad parts of mathematics, together with number theory, geometry and analysis. In its most general form, algebra is the study of mathematical symbols and the rules for manipulating these symbols; it is a unifying thread of almost all of mathematics

vector algebra. : analgebrafor which the elements involved may representvectorsand the assumptions and rules are based on the behavior ofvectors.

given is algebraic expression as well as polynomial.

Linear pair means sum of angles=180°

3x+2x+10=180

5x+10=180

5x=180-10

5x=170

x=170/5

x=34

The integrating factor is e^(integral(1 dx)) = e^x.

Multiply both sides by e^x:e^x dy/dx + e^x y = e^(2x)==> (d/dx)(e^x * y) = e^(2x), by the product rule for derivatives.

Integrate both sides: e^x * y = e^(2x)/2 + C==> y = e^(x)/2 + Ce^(-x).

Find C via y(0) = 1:1 = 1/2 + C ==> C = 1/2.

So, the final answer is y = (e^x + e^(-x))/2.

I hope this helps!

tysm

28/11 is the radius of the circle which is of length 7 Pi cm and the sector bounds an area of 28 cm2

Zeroes are 3 and 4

this is not correct

integrating 5x^4-5{x^(5)/5} = - x^5

part 1

part 2

thanks

Algebra is one of the broad parts of mathematics, together with number theory, geometry and analysis. In its most general form, algebra is the study of mathematical symbols and the rules for manipulating these symbols; it is a unifying thread of almost all of mathematics.

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holy

2sin 45. cos 45. tan 45

= 2sin 45. cos 45. sin 45/cos 45

= 2sin^2 45

= 2(1/sqrt(2))^2 [sin 45 = 1/sqrt (2)]

= 2*1/2

= 1

Equilateral triangle have equal sidesPerimeter of equilateral triangle = 3*side18 = 3*sideSide = 18/3 = 6 cm

Area of triangle = 1/2*base*altitude = 1/2*6*4 = 12 cm^2

Monika went to the market with Rs. 3000

She bought a frock,a toy and a bag with Rs.578.75,Rs.309 and Rs.1862

Therefore,By the problem,Her total money left over=Rs.{3000-(578.75+309+1862.85)=Rs.(3000-2750.60)=Rs.249.40

Rs.249.40 money is left with Monika

sin³30+cos²45sin30=1/2cos45=1/√(2)sin³30+cos²45=(1/2)³+(1/√(2))²=1/8+1/2=5/8

a1=17a2=14d=14-17d=-3

a5=a+4da5=17+4×-3a5=17-12a5=5

A . =2 πr h +2 πr^ 2 .968=2*22/7*7(h+r)968/44=h+r22=h+rH=22-7=15cm

AB = ADAB = ACSO, AC = ADIn triangle ABC,BCA = ABC ........1In triangle ADC,ACD = CDA .......2From 1 and 2 we get,BCA + ACD = ABC + CDAor, BCD = ABC + CDA ......3Now,BCA + ABC + CDA = 180°[sum of all angles]or, BCA + BCA = 180°[From 3]or, 2BCA = 180°or, BCA = 90°Therefore BCD is a right angled triangle....Proved.

perimeter of rectangle=2(l+b)=42b=8.5so l=21-8.5=12.5so area of rectangle=lb=12.5*8.5=106.25which is equal to area of a circleso area of a circle=106.25m*m

Please specify the question that needs to be answered and post complete question

please give me answer

Let us assume sum as 100Amount =sum+simple interestIf amount becomes 400(as 4 times the sum) Then simple interest is 300By using formula pnr/100 (100*x*10)/100=300 _X=30 yrs_

let the principle be P and rate be R S.I = A - P

ATQ

3000-P = PR*2/100 .....(1) => 3000-P = PR/50 => PR = 50(3000-P)

and also 3250-P = 3PR/100...... (2)

so, 3250-P = 3*[50(3000-P)]/100=> 325000-100P = 450000-150P=> 50P = 125000 => P = 125000/50 = 2500.so, R = 50*(500)/2500 = 10%

cosecx cotx= 1/sinx×cosx/sinx= cosx/sin^2x= cosx/1-cos^2x5)cosx (1-sinx)/(1+sinx)(1-sinx)cosx(1-sinx)/1-sin^2x= cosx (1-sinx)/cos^2x= 1-sinx/cosx

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x+y=20, x-y=5;/2y=10, y =5, x=15,

Let the length of the rectangular garden be '4x'.

Then, breadth = 3x

• Now, we know that area of a rectangle = Length × breadth

• So, area of the rectangular garden = 4x × 3x= 12x²

• But, given area of the garden = 1200 m²

=> 12x² = 1200

=> x² = 1200/12

=> x² = 100

=> x = √100

=> x = √10 × 10

=> x = 10

• Hence, the length of the rectangular garden = 4x = 4 × 10 = 40 m

• And, the breadth of the rectangular garden= 3x= 3 × 10= 30 m

• Now, perimeter of the rectangular garden

= 2 (length + breadth)

= 2 (40 + 30)

= 2 × 70

= 140 m

• Now, cost of fencing 1 m = 7.50 Rs.

So, cost of fencing 140 m

= 140 × 7.5

= 1050 Rs.

thanks