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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find out the area of the designed region in given Fig. whichis common between the two quadrants of having circles ofradius 8 cm each6. |
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| 2. |
10. A pleure is 7 cm wide. How much should it be trimmed to fit in a frame 7cm wide |
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| 3. |
10. A picture is 7 cm wide. How much should it be trimmed to fit in a frame 7cm wide?10 |
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| 4. |
10. A picture iscm wide. How much should it be trimmed to fit in a frame 7cm wide10 |
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Answer» Actual width of the picture = 735cm=385cm Required width of the picture = 7310cm=7310cm ∴ Extra width = (385−7310)cm = (76−7310)cm ∵LCMof5and10is10 = 310cm Hence, the width of the picture should be trimmed by 310 cm. Actual width of the picture = 735cm=385cm Required width of the picture = 7310cm=7310cm ∴ Extra width = (385−7310)cm = (76−7310)cm ∵LCMof5and10is10 = 310cm Hence, the width of the picture should be trimmed by 310 cm |
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| 5. |
\left. \begin{array} { l } { | \frac { x ^ { 2 } + 6 } { 5 x } | \geq 1 } \\ { ( - \infty , - 3 ) } \\ { ( b ) ( - \infty , - 3 ) \cup ( 3 , \infty ) } \\ { ( c ) R } \\ { ( - \infty , - 3 ] \cup [ - 2,0 ) \cup ( 0,2 ] \cup [ 3 , \infty ) } \end{array} \right. |
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| 6. |
2. How many 5-cup servings are there ina cup of peanut butter? |
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Answer» To find this divide them7/8÷1/214/8=7/4 |
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| 7. |
227025%"A' purchased some oranges at a total cost of Rs. 1200/-. He sold rd part ofthese oranges at a loss of 20%. If 'A' had a profit of 10% then at what profitremaining oranges were sold ?A. 16%B. 15%c. 22%D. 25%12 |
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Answer» cp of 3 ora=40, cp of 5 ora=60, sp of 3 ora=50cp of 15 ora=200, cp of 15 ora=180cp of 30 ora=380sp of 3 ora=50sp of 30 ora=500 cp sp380 500 profit=(120/380)*100 11=31 -----%19 1/3 of 1200= 40020% loss sp= 400×80/100= 32010 get overall 10% profit sp = 1200×110/100=1320₹remining orange = 1200-400= 800₹to be sold ₹ 800 oranges in 1320-320= 1000₹profit= 1000-800= 200%profit = 200×100/800= 25% |
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| 8. |
Arnab brought a car of 80,500 and sold it to his friend of 7 90,000Find his total gain or loss.: |
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Answer» gain = 90000-80500/80500 = 9500/80500 = 0.11% |
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| 9. |
10. Two television were bought for20,000 each. The shopkeeper made a loss ofprofit of 5% on the other. Find his total gain or loss percent in the whole transaction |
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Answer» 20000*105/100=2100020000*95/100=19000 21000+19000=40000no loss and no gain this is not right answer |
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| 10. |
7222The diameter of a circle is 14 cm. What will be its circumference?**G) 192 cm |
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Answer» Diameter of circle = 14 cm Then,Radius of circle r = 14/2 = 7 cm Circumference of circle= 2*pi*r= 2*22/7*7= 44 cm |
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| 11. |
A cone, a hemisphere and a cylinder haveequal bases. If the heights of the cone andthe cylinder are equal to its commonradius, then the ratio between theirvolumes is:3) 1:2:3 |
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| 12. |
A solid is in the shape of a cone standing on a hemisphere with both their radii beingequal to 1 cm and the height of the cone is equal to its radius. Find the volume of thesolidin terms of Tt. |
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| 13. |
The cost of a pen drive is 455. How much the cost of 35 such pen drives? |
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Answer» Cost of 35 such pen drives will be 35×455 = 15925 Rs |
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| 14. |
lagstall.The angles of elevation of an artificial earth satellite, as measured from twotionis 4000 km, find the height of the satellite.s are on the same side of it are 30° and 60° If the distancearth sta-e between the earth stations |
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| 15. |
27. A man on the top of a vertical observation tower observes a car moving at a uniform speed comingdirectly towards it. If it takes 12 minutes for the angle of depression to change from 30° to 45e, how4long will the car take to reach the observation tower from this point? |
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| 16. |
A man on the top of a vertical observation tower observes a car moving at a uniform speedcoming directly towards it. If it takes 12 minutes for the angle of depression to change from30° to 45%, how long will the car take to reach the observation tower from this point?27,4 |
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| 17. |
27. A man on the top of a vertical observation tower observes a car moving at a uniform speed 4coming directly towardst.If it takes 12 minutes for the angle of depression to change from30 to 450, how long will the car take to reach the observation tower from this point? |
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| 18. |
8. 40 dozenoranges were purchased at18 perdozen. Half of them were sold at 2 perorange. By that time, 20 oranges went rot.The remaining oranges were sold at 1.25each. Calculate the profit or loss per cent. |
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Answer» Total cost of oranges CP = 18*40 = 720 Selling price of 20 dozen oranges SP1 = 2*12*20 = 480 Selling of remaining orangesSP2 = (20*12 - 20)*1.25 = 220*1.25 = 275 Profit % ={ [(SP1 + SP2) - CP] /CP}*100 = [(755 - 720)/720]*100 = 350/72 = 4.86% |
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| 19. |
8 e ure, SP = x+8 = 317. Meenakshi sells a pen for 54 and losesand (ii) the loss per cent.54 and losesof her outlay.of her outlay. Find (i) the cost price of the pen,Adenler |
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| 20. |
The cost price of goods is 20%below the marked price. He soldhalf the stock at the marked price.One quarter at a discount of 10%on the marked price and rest at adiscount of 30% on the markedprice. His total gain is: |
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Answer» Suppose cost price of watch =xThen, profit percentage =x%Selling price=x(100+x)/100 Given that selling price is Rs.96. Therefore,x(100+x)/100=96 100x+x²=9600 x²+100x−9600=0 (x+160)(x−60)=0 x=60(taking +ve value) i.e., cost price = Rs.60profit percentage = 60% If he sells it at twice the percentage profit, i.e., at 120%,new selling price=60×(100+120)/100 =60×220/100 = 6 × 22 = 132 Like my answer if you find it useful! |
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| 21. |
A necklace has 3 strings of pearls. Each string has I00 pearls. The pearls come in packetseach containing 120 pearls. How many packets of pearls would be required to make13 722 such necklaces? |
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Answer» Each necklace has 300 pearls. Total pearls = 13722*300 = 4116600 No of packets = 4116600/120 = 34305 packets mera answer 28500 hai ye nahin hsi |
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| 22. |
A necklace has 3each containing13 722 such necklacs strings of pearls, Each string has 100 pearls. The pearls come in packetsming 20 pearls. How many packets of pearls would be required to makepe |
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| 23. |
1. If one pencil costs5.50, what is the cost of 17 such pencils? |
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Answer» 93.5 is the answer because One costs 5. 50so 17 will cost= 17*5*50= 93.5 rupees cost of 1 pencil=5.50cost of 17 such pencil=17 × 5.50=93.50 rupees is the answer.plz like thanks |
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| 24. |
(xi) One-fourth of x is multiplied by twice the slfl2. On15 and one pencil costs 7 3. What is the total cost of x pens and y pencit using numbers, literale pen costs |
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Answer» One pen costs 15. So x pens cost 15x.One pencil costs 3.So y pencils cost 3y.So total cost = 15x+3y |
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| 25. |
One pencil costs2 and one fountain pen costs? 15. If Shila pays? 100 to purchasepencils and fountain pen, write a linear equation and draw a graph with this data.What value is depicted by Shila in the question ? |
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| 26. |
10. The cost of a pen is = 16 and that of a pencil is 743. Which costs more and by how much? |
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Answer» It's 12 and 9 over 20 |
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| 27. |
4. The cost of a pen ist6 and that of a pencil is 4 Which costs more and by how mud |
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| 28. |
b sinx—tanxEvaluatelimit x = 0 R h |
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Answer» Like my answer if you find it useful |
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| 29. |
16. The cost of a pen is163and that of a pencil is43. Which costs more and by how much?54 |
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| 30. |
Q1.Whatis prime numbersQ2.Find the HCF of 18,24,32.Q3.Find the common factors of 15,25,30.SeQ4.Find the prime factorization of 980.Q5.Write the define of polygon.Q6.Write seven consecutive composite nunumber between them.te the cum hy rounding off the |
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Answer» 1.The numbers which is only divisible by itself and 1. 2. H.C.F of 18,24,32 is 2. 3) common factor of 15,25 and 30 is 1 and 5 4) prime factorisation of 980 is 2×2×5×7×7. 5) a plane figure with at least three straight sides and angles, and typically five or more. |
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| 31. |
ress each number as a product of its prime factors:140(ii) 156(ii) 3825(iv) 5005I the LCM and HCF of the following pairs of integers and verifyst of the two numhers |
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Answer» 3825 = 3 x 3 x 5 x 5 x 17 |
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| 32. |
| था कक A Lok oS stz |
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Answer» In the Lok Sabha, the lower House of the Indian Parliament, both Presiding Officers—the Speaker and the Deputy Speaker- are elected from among its members by a simple majority of members present and voting in the House. As such, no specific qualifications are prescribed for being elected the Speaker. The Constitution only requires that Speaker should be a member of the House. But an understanding of the Constitution and the laws of the country and the rules of procedure and conventions of Parliament is considered a major asset for the holder of the office of the Speaker. The election of the Speaker of the Lok Sabha is an important event in the life of the House. |
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| 33. |
A shopkeeper buys 50 pencils at Rs. 100 and sells them at 45 pencils for Rs. 90.Find his loss / gain percent. |
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| 34. |
(हट 2४ 0 पुर: Lok el /5 |
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Answer» 2x²+x-528=0=>2x²-32x+33x-528=0=>2x(x-16)+33(x-16)=0=>(2x+33)(x-16)=0=>x=16 or x=-16.5 |
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| 35. |
3. 16 pencils, 4 pencils in 1 packet.Total number of pencils-Number of pencils in each packetNumber of packets requiredDivision fact: |
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Answer» total number of pencils16number of pencils in each packet =4hence packet required will be 16/4=4 |
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| 36. |
7185 87 3412(A) 135(B) 85(C) 195(D) 95 |
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Answer» the answer is 12*6. + 9*7= 135 |
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| 37. |
d-53ct 2= db by Method completing farmulasome 3002 - 53cta= co by m |
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| 38. |
a Express cach number as a product of its prime factorsprime factors: H38250 240r) 5005 |
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Answer» for 140 |
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| 39. |
DULIWAPO6. Find all the prime factors of 1729 and arrange them in ascending order. Now statererelation, if any, between two consecutive prime factors.The |
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Answer» 7 13 and 19 are the prime factors of 1729 |
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| 40. |
relation,e factors of 1729 and arrange them in ascending order. Now stateIf any, between two consecutive prime factors |
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| 41. |
*॥ 23 से 30 तक प्रथक प्रश्न के 4 अक है।23. Find the square root of 2correct to two places of decimal.का वर्गमूल दशमलव के दो स्थानों तक शुद्ध ज्ञात कीजिए। |
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| 42. |
23. Show the numbers 7, (-2), (-8) and 4 on a number line.24. Raman ordered the integers from least to greatest as -5,-7.-18,-12, -35. Correct theorder ofthe integers. |
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Answer» -35 , -18 , -12 , -7 , -5 If you find this answer helpful then like it. |
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| 43. |
25(iii)If sec0--, then find the value of tan θ.Solve the following questions (Any three) : |
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| 44. |
72% of student out of 25 are good in mathematics.find number of student? |
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Answer» thanks |
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| 45. |
prime factors of 5005 |
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Answer» Prime divisor of 5005 = 5, 7, 35, 11, 385, 13 thks yyr |
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| 46. |
Prime factors of 50 are |
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Answer» 50 = 2×5×5 are the prime factors Prime factor of 50=2×5×5× 2,5,5 - these three.... 50and Multiples 50is a composite number.50= 1 x50, 2 x 25, or 5 x 10.Factors of 50: 1, 2, 5, 10, 25,50.Prime factorization:50= 2 x 5 x 5, which can also be written 2 x 5².Jan 30, 2014 1,2,5,10,25,50 are the best answer 2 is the correct answer 2 and 5 is the correct answer 50 = 2×5×5 is the prime factors 50=2*5*5 is the prime factor |
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| 47. |
Write the prime factors of 84. |
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| 48. |
8.By selling 200 books, a man gains the selling price of 400 books. Find his gain percent00/ INhat will be the cain percent if sold for double |
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Answer» Selling books 200 SP of one book = x SP of 200books = 200x profit = 400x CP = 400-200 = 200x His gain in percent = 400x/200x x 100 = 200% |
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| 49. |
if there is a gain of 5 p. in a rupee find the gain percent |
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Answer» it will be 5 percentage of gain as1.05-1.00/1.00*100= 5 percentage |
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| 50. |
Please tell al Compound intust fernulo |
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Answer» pls tell how to find ci ,principal ,rate formulas compound interest= amount - principle all other values will be given in numerical. |
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