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aa8​Eachinteriorangleofaregularpolygonwithnsides=180−(360n)⇒180−(360n)=135⇒360n=45⇒n=8 ans.

Put X=0-3y=6y=-2(0,-2)Put y=02(x)=6X=3(3,0)Put X=612-3y=6-3y=-6y=2(6,2)Put y=22x-6=62x=12X=6(6,2)

y=-1, x=3/2y=0, x=3y=1, x=9/2

x + 2y = 6 x = 6-2y solutions are : (4,1),(2,2),(0,3),(-2,4)

Given:- Total cost of cultivating the rectangular field at Rs.15 per metre square is RS. 18330.=>Area of the rectangular field=18330/15=1222 sq metres.

It's breadth is 26 m.=>Length=Area/breadth=1222/26=47 m

It's Perimeter=2(47+26) m=146 m

Cost of fencing the field =perimeter×20=Rs.(146×20)=Rs.2920

Volume of the well=πr^2 h=22/7*3/2*3/2*280

so cost of sinking a tube well=>22/7*3/2*3/2*280*15

=>Rs.29700

now the cost of cementing its inner curved surface

area=2πrh*10=>2*22/7*3/2*280*10

=>Rs.26400

In the process of their struggle withcolonialismpeople began discovering their unity.Anti-colonial movementgave a strong issue to the people with which they could identify and could come on a common platform. ... Hence, thegrowth of nationalism in the colonies is linked to an anti-colonial movement.

According to your question in India,the growth of modern nationalism is linked to the anti-colonial movt. because:

1.People began discovering their unity in the process of their struggle against colonialism.

2.The sense of being oppressed under colonialism provided a shared bond that tied many different group together.But each class and group felt the effects of colonialism differently,their experiences were varied,and their notion of freedom was not always the same.

3.The congress under Mahatma Gandhi tried to foge these groups together within one movt.But the unity didn't emerge without conflict.

Let the speeds of the cars be x km/hr and y km/hrCase 1:When the cars are going in the same directionRelative speed = x - yDistance = 100 kmTime = 100 / (x - y) = 5 hrsx - y = 100 / 5=20x – y = 20 ------------- (1)Case 2:When the cars are going in the opposite directionRelative speed = x + yTime =100 / (x + y) = 1 hrsx + y = 100 ------------- (2)Solving the equations (1) and (2),x = 60y = 40Hence the speeds of the cars are 60 km/hr and 40 km/hr.

But the ans is 17

Let speed of faster car = x Km/ hSpeed ofslowercar = y km /hRelative speed when both cartravelsinsame direction= x - yIf the cars travel in thesame directionat different speeds, they meet in 5 hoursSpeed = distance/ timeTotal distance = 100 kmSpeed x – y = 100/5X – y = 20Add y both side we getX = 20 + y …(1)Relative speed when both cartravelsin opposite direction = x + yIf they travel towards each other, they meet in 1 hour.Speed = distance/ timeTotal distance = 100 kmSpeed x + y = 100/1Plug the value of x form equation first we get20 + y + y = 1002y = 80Y = 40Plug the value of y in equation first we getX = 20 + 40X = 60

Hence speeds are 40 Km /h and 60 Km /h

Consider the two cars starting from the pointsandwhich are 100 km apart to beand, respectively.

Consider the speed of carandto bexkm/hr andykm/hr, respectively.We are to find the speed of the cars.When the two cars move in the same directions, they meet at a point in 5 hours. Let this point be.Therefore,The distance travelled by car X = AQ = 5xkmThe distance travelled by car Y = BQ = 5ykmClearly, AQ - BQ = AB

Therefore, (i)

When the two cars move towards each other, they meet at a point betweenandin 1 hour. Let this point beP.

Therefore,The distance travelled by car X = AP =xkmDistance travelled by Y car Y = BP =ykmClearly,

Therefore, (i)We add the equations (i) and (ii),By substituting the value ofxin equation (ii), we haveTherefore, the speeds of the car X and car Y are 60 km/hr and 40 km/hr.

let the speed=x ,ditance =yfor the sum of direction x-y=100/5=20 eq 1.for opposite directions x+y=100/1=100 eq2 .add 1and 2 x+y=100x-y=202x=80 x=40put in 1 x-y=100y=100-40y=60 km/hr

thanks

Thanks

Option (D) is correct.

Line AB || Line CD On transversal EF Angle AGH =Angle GHD.....(1)(alternate angle theorem)AGH =2 LGH ...(2) (Angle bisector)GHD=2 MHG....(3)(Angle bisector)From 1, 2, and 3: LGH = MHGTherefore line GL || line HM.... (Alternate angle test).

A. 4a +2 = 26. => 4a = 24 , so a = 24/4 = 6

B. 2a-7 = 13 => 2a = 13+7 , => a = 20/2 = 10

Difference between 3 hrs 12 minutes and 1 hr 40 minutes

3 hrs 12 min = 3 + 12/60= 3 + 1/5 = 16/5

1 hr 40 min = 1 + 40/60= 1 + 2/3 = 5/3

Then, 16/5 - 5/3 =( 48 - 25)15= 23/15 hrs= (23/15) *60 min= 23*4 = 92 min

Therefore 3 hr 12 min more than 1 hr 40 min by 92 min or 1 hr 32 min

In such kind of questions, take the LCM of 12,15 i.e. 60. Assume 60 ltrs is the capacity of cistern.Now, the rate of filling for pipe P- 60/12 = 5 ltrs per min.the rate of filling for pipe Q- 60/15 = 4 ltrs per min

So at the end of 3 mins, the cistern will have - 15 ltrs (From pipe P-5X3) +12 ltrs (From pipe Q-4X3) =27 ltrs

At the end of 3 mins, cistern will have remaining capacity of33 ltrs (60 ltrs- 27 ltrs)

As only pipe Q will fill the cistern = 33/4 = 8.25 mins =8 mins 15 seconds.

In such kind of questions, take the LCM of 12,15 i.e. 60. Assume 60 ltrs is the capacity of cistern.Now, the rate of filling for pipe P- 60/12 = 5 ltrs per min.the rate of filling for pipe Q- 60/15 = 4 ltrs per min

So at the end of 3 mins, the cistern will have - 15 ltrs (From pipe P-5X3) +12 ltrs (From pipe Q-4X3) =27 ltrs

At the end of 3 mins, cistern will have remaining capacity of33 ltrs (60 ltrs- 27 ltrs)

As only pipe Q will fill the cistern = 33/4 = 8.25 mins =8 mins 15 seconds.

Your correct answer isa--. A.Mb--. P.Mc--. P.Md--. P.M

Let n terms of AP add upto 990

Sum of n terms of APSn = n/2(2a + (n - 1)d)

Given a = 2, d = 7-2 = 5

Then,990 = n/2(2*2 + (n - 1)5)990 = n/2(4 + 5n - 5)990*2 = n(5n - 1)5n^2 - n - 1980 = 05n^2 - 100n + 99n - 1980 = 05n(n - 20) + 99(n - 20) = 0(5n +99)(n - 20) = 0n = - 99/5, 20

Therefore sum of 20 terms of given AP is 990

a)8+(-17)=-9b)2+(-12)=-10d)(-13)+25=12e)(-3)+(-9)=-12

I have one doubt

C & D CONFUSE😕❓ you know answer of question

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