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Given

a and b are zeros of 4x² + 3x + 7

So,

a + b = - 3/4

ab = 7/4

So,

value of 1/a + 1/b

(a+b)/ab

-3/4--------7/4

-3/7

tq

the answer to this question is option a Nigeria

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LHS : cot A + tan B/ cot B + tan A= (cotA + 1/cotB) / (cotB + 1/cotA)

= (cotAcotB + 1) / cotB / (cotAcotB + 1) / cotA

= cotA / cotB

= cotA. tanB

= RHS

Hence proved

LHS:(1 + tan^2 A) + (1 + cot^2 A)= sec^2 A + cosec^2 A= 1/cos^2 A + 1/sin^2 A= (sin^2 A + cos^2 A) /cos^2 A. sin^2 A= 1/(1 - sin^2 A). sin^2 A= 1/(sin^2 A - sin^4 A)= RHS

Hence proved

Let theta = A

Given,cos A + cos^2 A = 1cos A = 1 - cos^2 Asin^2 A = cos A

Then,sin^2 A + sin^4 A= sin^2 A(1 + sin^2 A)= cos A + cos^2 A= 1

Hence proved

Replace A by X in the equation.

(-4)×(-5)×(-8)×(-10) = 20×80 = 1600

In one hourbus will cover 250*60 meter=15000 meter

while car will cover 4500meterso bus is faster

sin^2(1-sin^2)sin^2*cos^2

2cos pi/13 cos 9pi/13+ cos 3pi/13 +cos 5pi/13

=cos 10 pi/13 +cos 8 pi/13 +cos 3pi/13 +cos 5pi/13

=cos 10 pi/13 +cos 3pi/13 +cos 8pi/13 +cos 5pi/13

=2 cos pi/2 .cos 7 pi/26 +2 cos pi/2 .cos 3 pi /26

=2 (0)cos 7 pi /26 + 2(0) cos 3pi/26

=0 =R.H.S.

Let the speed of the goods train be x km/hrThen, speed of express train = (x+20) km/hrGoods train leaves a station at 6pm and express train leaves the station at 8pmalso express train reaches its destination 36min before goods train.

We known that,Time taken = distance covered /speedTotal distance = 1040 kmTime taken by goods train to cover 1040 km = 1040/x

Time taken by express train to cover 1040 km = 1040/(x+20)As per given condition we have,1040/x = 1040/(x+20) + 2(36/60)

1040/x-1040/(x+20) = 2(3/5)

(1040x+20800-1040x)/(x²+20x) = 13/5

13x² + 260x = 104000

x² + 20x - 8000=0

x² + 100x - 80x - 8000=0

x(x+100) - 80(x+100)=0

(x-80)(x + 100)=0

x = 80 (or) x = -100Here x>0Therefore x = 80

Hence, speed of goods train = 80 km/hrspeed of express train = 100 km/hr

Let the speed of the goods train be 'x' km/hrThen, speed of express train=(x+20) km/hrGoods train leaves a station at 6pm and express train leaves the station at 8pmalso express train reaches its destination 36min before goods train.We known that,Time taken = distance covered /speedTotal distance=1040kmTime taken by goods train to cover1040 km=1040/x

Time taken by express train to cover 1040 km=1040/(x+20)As per given condition we have,1040/x=1040/(x+20)+2(36/60)

1040/x-1040/(x+20)=2(3/5)

(1040x+20800-1040x)/(x²+20x)=13/5

13x²+260x=104000

x²+20x-8000=0

x²+100x-80x-8000=0

x(x+100)-80(x+100)=0

(x-80)(x+100)=0

x=80 (or) x=-100Here x>0Therefore x=80

Hence speed of goods train=80 km/hrand speed of express train=100 km/hr

Ans :- 2a + 3 + 6 = 0 2a = -9 a = -9/2

2a+3+6=02a+9=02a=-9a=-9/2

Roster form of R = { (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (1,7) , (1,8) , (1,9) , (2,2) , (2,4) , (2,6) , (2,8) , (3,3) , (3,6) , (3,9) , (4,4) , (4,8) , (5,5) , (6,6) , (7,7) , (8,8) , (9,9) }

Domain of R = { 1 , 2 , 3 , 4 , 5 ,6 , 7 , 8 , 9 }

Range of R = { 2, 3, 4, 5, 6, 7, 8, 9 }

Step-by-step explanation:

Given: Set A = { 2, 3, 4, 5, 6, 7, 8, 9 }

Relation R = { ( x, y ) : y belongs to A and x divides y}

To find: Arrow Diagram, Roster form , Domain and Range of R.

Let x belong to natural no.

then, Roster form of R

R = { (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (1,7) , (1,8) , (1,9) , (2,2) , (2,4) , (2,6) , (2,8) ,

(3,3) , (3,6) , (3,9) , (4,4) , (4,8) , (5,5) , (6,6) , (7,7) , (8,8) , (9,9) }

Domain of R:

Let say Set B is domain of R, then B = { 1 , 2 , 3 , 4 , 5 ,6 , 7 , 8 , 9 }

or B = { x : x ∈ N and x ≤ 9}

Range of R:

Let say set C defines Range of R, then C = { 2 , 3 , 4 ,5 , 6 , 7 , 8 , 9 }

Range of R = Set A

range of r= set ais a answer

g(x) = |2x+5| its domain is R Now for f(x) given domain is [-5,7]So for domain of f(g(x)) take the intersection of R and [-5,7] .so we get the that is [-5,7]. so option D) is correct

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The elements on the diagonal of askew-symmetric matrixare zero, and therefore also its trace. If is a real skew-symmetric matrixand is a real eigenvalue, then , i.e. the nonzero eigenvalues of askew-symmetric matrixare purely imaginary.

thanks

sorry mijshe nahi aataha ha

transitive is the correct answer for this

I know you don't know

& altitudes

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Single question per time please .