Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

25. Which of the following equations could not used to solve the problem?DANIAFind two numbers whose sum is 24 if the second number is three times the first0x + 3(24 - x) = 2(24 - x) = 3:x + 3xx3(24-

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x+3x=24 is right answer

x+3x = 24 is correct answer

2.

(vi) x = 5. o (x+4a X+ 4b—4daं % 4‘,) अब भान दिजाय कार्नि

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3.

x/y=a+2/a-2 হলে দেখাও যে x²-y²/x²+y²=4a/a²+4

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please second step describe

I am not understand second step

4.

Find the area bounded by y log,xy0 andx-2

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5.

Find the area bounded by integral lim 0 to 2 pi (six.dx)

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6.

Find the area bounded by curvesy=x^{2} and x=y^{2}

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7.

Find the area bounded by the curves x y2 and x 3-2y?

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8.

Find the area bounded by curves {(x,y) : y 2x2 and ylxl).

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9.

30. If seco +tanep. then find the value of cosect.

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Secθ+tanθ=p ----------------------(1)∵, sec²θ-tan²θ=1or, (secθ+tanθ)(secθ-tanθ)=1or, secθ-tanθ=1/p ----------------(2)Adding (1) and (2) we get,2secθ=p+1/por, secθ=(p²+1)/2p∴, cosθ=1/secθ=2p/(p²+1)∴, sinθ=√(1-cos²θ)=√[1-{2p/(p²+1)}²]=√[1-4p²/(p²+1)²]=√[{(p²+1)²-4p²}/(p²+1)²]=√[(p⁴+2p²+1-4p²)/(p²+1)²]=√(p⁴-2p²+1)/(p²+1)=√(p²-1)²/(p²+1)=(p²-1)/(p²+1)∴, cosecθ=1/sinθ=1/[(p²-1)/(p²+1)]=(p²+1)/(p²-1) Ans.

10.

o) A boy walks 6 km in 1 hour 30minutes

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Distance travelled=6kmtime taken=1 hour 30 minutes=1.5 hr∴Speed=6 km/1.5 hr=4 km/hr

11.

B L0=C+x9 g~ Z'xg ; o

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12.

द 1 L0 20 31 7 56 70 E/

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that's question answer is=43

13.

०09 809 L0 UIS + O SO 509 UIS 4है

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14.

af Seco. Sind =0then find the value of 0.

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0° is the correct answer of the given question

sec x-sinx=1/cosx-sinx1=sinxcosx

15.

4. Is the area of the largest circle that can be drawninside a rectangle of length a cm and breadth b cm(a> b) is b2 cm"? Why?

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solution:-we know that Area of circle = πr²andin a rectangle length is great than it's breadth [ a> b] andwe can only draw a circle inside a rectangle with circle's diameter equal to breadth.

=> d = breadth of rectangle = b

=> 2r = b => r = b/2 Andthe Area of circle with radius (b/2) is

= πr² = π×(b/2)²

=> b²π/ 4 sq. unit.

16.

104 If x= a seco and y = a tane, then the value of

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17.

Find the area bounded by the curves y4ax and y X4a

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18.

2. Find the area bounded by curves (x - I)V+ y 1 and1.

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19.

Express the following number in standard form(a)8780.93

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8780.93

= 878093*10^-2

20.

Express each of the following rational numbers as a decimal.Express each of the following as a decimal, as far as 3 decimal places.Express each rational number as a fraction in simplest form:(1) 0.84 (11) 0.015 (iii) 52.54 (iv) -129.6(v) 0.0008

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21.

The perimeter of a rectangular piece of paper is 56 cm,If the length is three times its width, what is its width?

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22.

The length of a rectangle exceeds the width by 14 cm. The perimeter of the rectangle is 160 cm. Find the length andwidth of the rectangle.

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let. length be l and breadth be Bso according to question B+14=lnow perimeter=2(l+b/)160=2(b+14+b)80=2b+1426=66b=33cmhence l=33+14=47cm

23.

, towards cast and then fromExAMPLE 6 Supal walks km rom a place towards east and then1 Am towards west Where will he be now from P

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24.

Find the sum aF the tuoo middle most33:3

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17/3

25.

Seco tcoseco - $not caseSeco X.coseco

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26.

0.) ) secO+tan+1 _ ८०5४९0) धान कान (व, secO—tan+1~ 1-हांए9

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As 1=sec^2-tan^2LHS sec+tan - (sec^2 - tan^ 2)/tan -sec + 1

take common sec + tan (1-sec + tan)/tan-sec+1

sec + tan

1/cos + sin/cos

1+sin/cos

multiply numerator and denominator by 1-sin

we get

1-sin^2/cos-cos sin

take cos common from denominator and 1-sin^2 is cos^2

cos^2/cos(1-sin)

cos/1-sin = RHS

27.

L0in

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Suppose you have a ∆ABCAll the exterior angles will be equal to(180-A)°(180-B)°(180-C)°respectively (Angles on the same line) so if you sum it up it will be equal to 540 - (A+ B + C )And by angle sum property A+B+C = 180°Therefore Sum = 540 - 180 = 360

28.

2. Draw a square of side 6 cm. Draw the largestpossible circle inside it. Find the diameter ofthis circle.

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29.

(vi) If Seco stand o ther what is the valueok seco-tanter

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30.

Find the area bounded by the curve y = f (x) and x-axis between x = 0 and x = 12wheref(x) = min. (tan x, cot x, 1/3).

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31.

a^{4}+2 a^{2} b^{2}+b^{4}

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32.

if l=145, n=51, cf=11, f= 18 and h=5 then find the median of the data.

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33.

If \frac{a}{b}=\frac{2}{3} , then find the values of the following expressions.(i) $ \frac{4 a+3 b}{3 b} $(iii) $ \frac{a^{3}+b}{b^{3}} $(ii) $ \frac{5 a^{2}+2 b^{2}}{5 a^{2}-2 b^{2}} $(iv) $ \frac{7 b-4 a}{7 b+4 a} $

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34.

a ^ { 4 } + 2 a ^ { 2 } b ^ { 2 } + b ^ { 4 }

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a^4+2a^2b^2+b^4=(a^2)^2+2(a^2b^2)+(b^2)^2=(a^2+b^2)^2

35.

b^4 %2B a^4 - 2*a^2*b^2

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36.

\left. \begin{array} { l } { \text { Which of the following is the factor of } 4 a ^ { 2 } + b ^ { 2 } - 4 a b + 2 b - 4 a + 1 } \\ { ( A ) ( a - b ) } \\ { ( C ) ( a - b + 2 ) } \\ { \text { Facionize } a ^ { 3 } + ( b - a ) ^ { 3 } - b ^ { 3 } } \end{array} \right.

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37.

From a square metal sheet of side 28 cm, a circular sheet is cut off. Find the radius of thelargest possible circular sheet that can be cut. Also find the area of the remaining sheet.

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38.

7. From a squaremetal sheet of side 28 cm, a circular sheet is cut off. Find the radius of thelargest possible circular sheet that can be cut. Also find the area of the remaining sheet.

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39.

The side of a square metal sheet is 7 m. A circu-lar sheet of maximum radius is cut out of it andremoved. Find the area of the circular sheet (in ft^2)

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Diameter of largest circle that can be cut is 7cm. (see picture)So radius = 7/2 = 3.5m

Area of circular part is πr^2=22/7*3.5*3.5=22*0.5*3.5=38.5m^2

40.

o (o) ou + w (8) O(u + u)-(v) OL-(a) o

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hit like if you find it useful

41.

\left. \begin{array} { l } { x ^ { 2 } - 2 x - 8 } \\ { \text { V) } 4 u ^ { 2 } + 8 u } \end{array} \right.

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i) x² -2x -8x² +2x -4x -8x(x+2) -4(x +2)(x+2)( x-4)

ii)4u² +8 u4u (u+2)

(iv) not answer this

42.

Py 9.32In Fig.9.33, ABC and BDE are two equilatoradtriangles such that D is the mid-point of BC HAEintersects BC at F, show that0) aa(BDE)ar(ABC)(ii)ar(BDE)"-ar (BAE)(iüi) ar (ABC) 2 ar (BEC"(iv) ar (BFE) mar (AFI)(v) ar(BFE) 2 ar (FED)Fig. 9.33(vi) ar (FED)ar(AFC)HEC and AD. Show that BE.JACand DE IAB,elint Join

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43.

Srikar says that the order of the polynomial (x^2-5) (x^3+1) is 6. Do you agree with him ?

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44.

1 Findthe355

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2/5 + 6/7 + 3/5= (14 + 30 + 21)/35= (65)/35= 13/7

2/5+6/7+3/514+30+21/3565/3513/7

45.

Fend the value of 11183 = 12023 .

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46.

18.25. Fend & if ya lot*1455

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4/-5=×/-45×=-45×4/-5×=3636 is the answer

47.

The capacity of a closed cylindrical vessel of height 1 m is 15.4 litres. How manys)square metres of metal sheet would be needed to make it?

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48.

(III) capac-ty of a closed cylindrical vessel of height 1 m is 15.4 litres. How manyetres of metal sheet would be needed to make it?paciuare m

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49.

Tet. 24x750XC का घालाक के कप मेंमक्ता कीजिए।

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2power8*5power4 is answer

8²×5⁴×5² is the answer of your question

50.

79·77韌何TET =き1950,TA-25%.

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