This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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25. Which of the following equations could not used to solve the problem?DANIAFind two numbers whose sum is 24 if the second number is three times the first0x + 3(24 - x) = 2(24 - x) = 3:x + 3xx3(24- |
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Answer» x+3x=24 is right answer x+3x = 24 is correct answer |
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| 2. |
(vi) x = 5. o (x+4a X+ 4b—4daं % 4‘,) अब भान दिजाय कार्नि |
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| 3. |
x/y=a+2/a-2 হলে দেখাও যে x²-y²/x²+y²=4a/a²+4 |
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Answer» please second step describe I am not understand second step |
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| 4. |
Find the area bounded by y log,xy0 andx-2 |
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| 5. |
Find the area bounded by integral lim 0 to 2 pi (six.dx) |
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| 6. |
Find the area bounded by curvesy=x^{2} and x=y^{2} |
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| 7. |
Find the area bounded by the curves x y2 and x 3-2y? |
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| 8. |
Find the area bounded by curves {(x,y) : y 2x2 and ylxl). |
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| 9. |
30. If seco +tanep. then find the value of cosect. |
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Answer» Secθ+tanθ=p ----------------------(1)∵, sec²θ-tan²θ=1or, (secθ+tanθ)(secθ-tanθ)=1or, secθ-tanθ=1/p ----------------(2)Adding (1) and (2) we get,2secθ=p+1/por, secθ=(p²+1)/2p∴, cosθ=1/secθ=2p/(p²+1)∴, sinθ=√(1-cos²θ)=√[1-{2p/(p²+1)}²]=√[1-4p²/(p²+1)²]=√[{(p²+1)²-4p²}/(p²+1)²]=√[(p⁴+2p²+1-4p²)/(p²+1)²]=√(p⁴-2p²+1)/(p²+1)=√(p²-1)²/(p²+1)=(p²-1)/(p²+1)∴, cosecθ=1/sinθ=1/[(p²-1)/(p²+1)]=(p²+1)/(p²-1) Ans. |
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| 10. |
o) A boy walks 6 km in 1 hour 30minutes |
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Answer» Distance travelled=6kmtime taken=1 hour 30 minutes=1.5 hr∴Speed=6 km/1.5 hr=4 km/hr |
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| 11. |
B L0=C+x9 g~ Z'xg ; o |
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| 12. |
द 1 L0 20 31 7 56 70 E/ |
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Answer» that's question answer is=43 |
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| 13. |
०09 809 L0 UIS + O SO 509 UIS 4है |
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| 14. |
af Seco. Sind =0then find the value of 0. |
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Answer» 0° is the correct answer of the given question sec x-sinx=1/cosx-sinx1=sinxcosx |
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| 15. |
4. Is the area of the largest circle that can be drawninside a rectangle of length a cm and breadth b cm(a> b) is b2 cm"? Why? |
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Answer» solution:-we know that Area of circle = πr²andin a rectangle length is great than it's breadth [ a> b] andwe can only draw a circle inside a rectangle with circle's diameter equal to breadth. => d = breadth of rectangle = b => 2r = b => r = b/2 Andthe Area of circle with radius (b/2) is = πr² = π×(b/2)² => b²π/ 4 sq. unit. |
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| 16. |
104 If x= a seco and y = a tane, then the value of |
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| 17. |
Find the area bounded by the curves y4ax and y X4a |
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| 18. |
2. Find the area bounded by curves (x - I)V+ y 1 and1. |
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| 19. |
Express the following number in standard form(a)8780.93 |
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Answer» 8780.93 = 878093*10^-2 |
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| 20. |
Express each of the following rational numbers as a decimal.Express each of the following as a decimal, as far as 3 decimal places.Express each rational number as a fraction in simplest form:(1) 0.84 (11) 0.015 (iii) 52.54 (iv) -129.6(v) 0.0008 |
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| 21. |
The perimeter of a rectangular piece of paper is 56 cm,If the length is three times its width, what is its width? |
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| 22. |
The length of a rectangle exceeds the width by 14 cm. The perimeter of the rectangle is 160 cm. Find the length andwidth of the rectangle. |
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Answer» let. length be l and breadth be Bso according to question B+14=lnow perimeter=2(l+b/)160=2(b+14+b)80=2b+1426=66b=33cmhence l=33+14=47cm |
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| 23. |
, towards cast and then fromExAMPLE 6 Supal walks km rom a place towards east and then1 Am towards west Where will he be now from P |
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| 24. |
Find the sum aF the tuoo middle most33:3 |
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Answer» 17/3 |
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| 25. |
Seco tcoseco - $not caseSeco X.coseco |
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| 26. |
0.) ) secO+tan+1 _ ८०5४९0) धान कान (व, secO—tan+1~ 1-हांए9 |
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Answer» As 1=sec^2-tan^2LHS sec+tan - (sec^2 - tan^ 2)/tan -sec + 1 take common sec + tan (1-sec + tan)/tan-sec+1 sec + tan 1/cos + sin/cos 1+sin/cos multiply numerator and denominator by 1-sin we get 1-sin^2/cos-cos sin take cos common from denominator and 1-sin^2 is cos^2 cos^2/cos(1-sin) cos/1-sin = RHS |
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| 27. |
L0in |
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Answer» Suppose you have a ∆ABCAll the exterior angles will be equal to(180-A)°(180-B)°(180-C)°respectively (Angles on the same line) so if you sum it up it will be equal to 540 - (A+ B + C )And by angle sum property A+B+C = 180°Therefore Sum = 540 - 180 = 360 |
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| 28. |
2. Draw a square of side 6 cm. Draw the largestpossible circle inside it. Find the diameter ofthis circle. |
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| 29. |
(vi) If Seco stand o ther what is the valueok seco-tanter |
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| 30. |
Find the area bounded by the curve y = f (x) and x-axis between x = 0 and x = 12wheref(x) = min. (tan x, cot x, 1/3). |
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| 31. |
a^{4}+2 a^{2} b^{2}+b^{4} |
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| 32. |
if l=145, n=51, cf=11, f= 18 and h=5 then find the median of the data. |
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| 33. |
If \frac{a}{b}=\frac{2}{3} , then find the values of the following expressions.(i) $ \frac{4 a+3 b}{3 b} $(iii) $ \frac{a^{3}+b}{b^{3}} $(ii) $ \frac{5 a^{2}+2 b^{2}}{5 a^{2}-2 b^{2}} $(iv) $ \frac{7 b-4 a}{7 b+4 a} $ |
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| 34. |
a ^ { 4 } + 2 a ^ { 2 } b ^ { 2 } + b ^ { 4 } |
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Answer» a^4+2a^2b^2+b^4=(a^2)^2+2(a^2b^2)+(b^2)^2=(a^2+b^2)^2 |
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| 35. |
b^4 %2B a^4 - 2*a^2*b^2 |
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| 36. |
\left. \begin{array} { l } { \text { Which of the following is the factor of } 4 a ^ { 2 } + b ^ { 2 } - 4 a b + 2 b - 4 a + 1 } \\ { ( A ) ( a - b ) } \\ { ( C ) ( a - b + 2 ) } \\ { \text { Facionize } a ^ { 3 } + ( b - a ) ^ { 3 } - b ^ { 3 } } \end{array} \right. |
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| 37. |
From a square metal sheet of side 28 cm, a circular sheet is cut off. Find the radius of thelargest possible circular sheet that can be cut. Also find the area of the remaining sheet. |
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| 38. |
7. From a squaremetal sheet of side 28 cm, a circular sheet is cut off. Find the radius of thelargest possible circular sheet that can be cut. Also find the area of the remaining sheet. |
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| 39. |
The side of a square metal sheet is 7 m. A circu-lar sheet of maximum radius is cut out of it andremoved. Find the area of the circular sheet (in ft^2) |
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Answer» Diameter of largest circle that can be cut is 7cm. (see picture)So radius = 7/2 = 3.5m Area of circular part is πr^2=22/7*3.5*3.5=22*0.5*3.5=38.5m^2 |
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| 40. |
o (o) ou + w (8) O(u + u)-(v) OL-(a) o |
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Answer» hit like if you find it useful |
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| 41. |
\left. \begin{array} { l } { x ^ { 2 } - 2 x - 8 } \\ { \text { V) } 4 u ^ { 2 } + 8 u } \end{array} \right. |
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Answer» i) x² -2x -8x² +2x -4x -8x(x+2) -4(x +2)(x+2)( x-4) ii)4u² +8 u4u (u+2) (iv) not answer this |
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| 42. |
Py 9.32In Fig.9.33, ABC and BDE are two equilatoradtriangles such that D is the mid-point of BC HAEintersects BC at F, show that0) aa(BDE)ar(ABC)(ii)ar(BDE)"-ar (BAE)(iüi) ar (ABC) 2 ar (BEC"(iv) ar (BFE) mar (AFI)(v) ar(BFE) 2 ar (FED)Fig. 9.33(vi) ar (FED)ar(AFC)HEC and AD. Show that BE.JACand DE IAB,elint Join |
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| 43. |
Srikar says that the order of the polynomial (x^2-5) (x^3+1) is 6. Do you agree with him ? |
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| 44. |
1 Findthe355 |
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Answer» 2/5 + 6/7 + 3/5= (14 + 30 + 21)/35= (65)/35= 13/7 2/5+6/7+3/514+30+21/3565/3513/7 |
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| 45. |
Fend the value of 11183 = 12023 . |
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| 46. |
18.25. Fend & if ya lot*1455 |
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Answer» 4/-5=×/-45×=-45×4/-5×=3636 is the answer |
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| 47. |
The capacity of a closed cylindrical vessel of height 1 m is 15.4 litres. How manys)square metres of metal sheet would be needed to make it? |
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| 48. |
(III) capac-ty of a closed cylindrical vessel of height 1 m is 15.4 litres. How manyetres of metal sheet would be needed to make it?paciuare m |
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| 49. |
Tet. 24x750XC का घालाक के कप मेंमक्ता कीजिए। |
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Answer» 2power8*5power4 is answer 8²×5⁴×5² is the answer of your question |
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| 50. |
79·77韌何TET =き1950,TA-25%. |
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