This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
u lu get after 5years.4Priyanka deposited 650She withdrew 1250 thamount will she get after two years?0 in a bank for one year. The bank pays interest at the rate of 9% per annum.mount for 2 years.Whatillafter the end of the year and deposited the remaining amount for 2 years. What |
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Answer» Answer: Step-by-step explanation: P=6500,r=9%per annum Amount of 1 year = rs (6500×9×1)/100 =rs(65-9)=585 Amount after 1 year = rs (6500+585)=rs 7085 Priyanka withdrew rs 1250 after 1 year Balance amount = rs (7085-1250) =rs 5835 Now, Interest for next two years balance amount = rs (585×9×2)/100=rs 1050.30 Hence,The amount after 3 years Rs (5835+1050.30)= rs 6885.30. |
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| 2. |
3. Javed deposited 12000 rupees at 9 p.c.p.a. in a bank for some years, and withdrew hisinterest every year. At the end of the period, he had received altogether 17,400 rupees.For how many years had he deposited his money ? |
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Answer» At the end of the period Javed got 17400. This means he got 12000 which he had deposited and 5400 extra as interest. Now t he had deposited the money at simple Interest. So his Interest came to be 5400. According to your question, every year he gets 9 % of the principle as Interest. 9 % means he is getting 1080 Rs every year. So if he is getting 1080 Rs every year, Then in how many years will he get 5400 Rs ? Let's just divide 5400 by 1080 . 5400÷1080 = 5 years |
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| 3. |
Javed deposited 12000 rupees at 9 p.cp.a. in a bank for some years, and witinterest every year. At the end of the period, he had received altogether 17,400 rupeesFor how many years had he deposited his money?drew his |
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Answer» So at the end of the period Javed got 17400. This means he got 12000 which he had deposited and 5400 extra as interest. Now I assume that he had deposited the money at simple Interst. So his Interest came to be 5400. According to your question, every year he gets 9 % of the principle as Interest. 9 % means he is getting 1080 Rs every year. So if he is getting 1080 Rs every year, Then in how many years will he get 5400 Rs ? Let's just divide 5400 by 1080 . 5400÷1080 = 5 years .. please like the solution 👍 ✔️ |
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| 4. |
AdditionGhe♡ 4, 8, |
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Answer» 19/12 is the roght answer 3/7+5/6=53/42 is the correct answer |
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| 5. |
A man borrows, 10.000-at 5% per anniumcompound interest. He repays 35% of thesum borrowed at the end of the first year and2% of the-sum borrowed at the end ofthe second year. How much must he pay atthe end of the third year in order to clear thedebt ? |
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| 6. |
④ If 8 women earn 2880 in 6 days, what vvm r5. 4 soldiers can dig a trench in 5 days. In how many days can 10 soldiers do this iobaSpespe:t n hours and A kash taks |
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| 7. |
In the number 6,43,590 the digits 3 and 9 were interchanged by mistake. find the difference of the original number formed by mistake. |
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Answer» The difference between 649530 and 643590 is 5940 difference of 643590 and 649530= 5940 5940 is your right answer. |
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| 8. |
In the number 6,43,590 the digits 3 and 9 were interchanged by mistake. find the difference of the original number formed by mistake. please give answer in words. |
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| 9. |
Find the zwrcesof theRyno mia.x2+t-2, and vehitre 어elanon beteen-the cofficents and十heスeroes of.thelolynoma |
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Answer» Here the given equation is x²+(1/6x)-2=0multiplying the above equation by 6 we get6x²+x-12=0or,6x²+9x-8x-12=0or,3x(2x+3)-4(2x+3)=0or,(3x-4)(2x+3)=0Hence the zeros of the polynomial arex=4/3 andx=-3/2 Now for a quadratic polynomialax²+bx+c=0the relation between coefficient a b and c and their roots m and n arem+n=-b/amn=c/a For the given equationm=4/3 n=-3/2and a=1,b=1/6 and c=-2now m+n=-1/6and -b/a=-1/6therefore,m+n=-b/aalso m x n=-2and c/a=-2Hence m x n=c/a Hence the relation between the coefficients of polynomial and its roots (or zeros) are verified. |
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| 10. |
Example 6. Find the equation of the st. linethrough the origin making angle of 60° with thest. line x+ 3y +33-0. (H.P.B. 2005 S) |
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| 11. |
X+1)4x3+6x2+8( |
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| 12. |
ion 6x2 + x-2 = 0. |
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Answer» 6x^2 + x - 2 = 06x^2 + 4x - 3x - 2 = 02x(3x + 2) - 1(3x + 2) = 0(2x - 1)(3x + 2) = 0x = 1/2, - 2/3 |
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| 13. |
the decimal form of 1/2 |
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Answer» The decimal form of 1/2 isequal to 0.5 how did u know the answer |
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| 14. |
Change to decimal form:2/5 |
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Answer» 0.4 2/5 in decimal form = 0.4 |
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| 15. |
23 + 2/100 + 5/1000 in decimal form is written as |
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| 16. |
29The periodicity of the decimal form of is31 3 |
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Answer» 2/9 = 0.222222222222222.....Therefore periodicity is 1 |
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| 17. |
What should be divided by í to getWhat should be divided b |
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Answer» Let x should be divided by 6/11 to get 3/5 Then,x ÷ (6/11) = 3/5x = 3/5 * 11/6x = 11/5*2x = 11/10 Therefore,11/10 should be divided by 6/11 to get 3/5 |
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| 18. |
d. x3+ 6x2+ 11x + 6 by x +3 |
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| 19. |
a rational number in it's decimal expansion is 327.7081. what can you say about the prime factors of q, when this number is expressed in the form of p/q? give reasons. |
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Answer» If the factors of denominator of the given rational number is of form 2ⁿ 5^m ,where n and m are non negative integers, then the decimal expansion of the rational number is terminating otherwise non terminating recurring.We know that a rational number has either terminating or non terminating repeating decimal expansion. SOLUTION:Here, 327.7081 has terminating decimal expansion so it represents a rational number.327.7081= 3277081/10000= p/qThus q=10⁴ , whose factors are 2⁴ × 5⁴. |
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| 20. |
Find the remainder when x-2x2+1 is divided by x-1 |
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Answer» Use remainder theorem, So, when p(x) = x⁴ + x³ - 2x² + 1 is divided by x - 1 the remainder will be p(1). So, p(1) = 1 + 1 - 2 + 1 = 1 So, remainder is 1 Hit like if find useful |
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| 21. |
EXERCISE 2.3Find the remainder when x+3x +3 + 1 is divided b(ii) x(ii) x(iv) |
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| 22. |
sTp + spe - 5 |
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Answer» √5 - 3√5 + √125 -2√5 + √ 5³ -2√5 + 5√5 3√5 |
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| 23. |
2. Find six rational number between 3 and 4. |
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| 24. |
Find Six Rational number between 5/7 and 6/11 |
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Answer» multiplying with 11 to 5/7 and 7 to 6/11to make the denominator commanso 5/7*(11/11)= 55/77and (6/11)*(7/7)= 42/77so six rational number will be56/77, 57/77,58/77,59/77,60/77 ,61/77 Thank you |
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| 25. |
Find the six rational number between 3 and 4 |
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Answer» where is the answer ? |
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| 26. |
End six rational number between 5 and 1 |
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| 27. |
(1) Write the numberin decimal form. |
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Answer» we can divide the numbersnumerator ÷ denominator = 5 ÷ 3 =1.6666 =1.67your answer is 1.67 Given number, 5/3=1.6666..., =1.67. |
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| 28. |
47. What will the sum in decimal form of 1o 10 100 |
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| 29. |
135.Write inin decimal form |
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Answer» It has a Non Terminating Repeating Decimal Expansion.your answer is 19.2857142 or 19.29 approximately |
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| 30. |
1) Write 120 in decimal form.200 |
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Answer» 127/200= 0.635thanks |
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| 31. |
Write the following in decimal form 1upon 2 |
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Answer» Decimal form of ½= 0.5 |
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| 32. |
127200) Write the rational number decimal form.2 |
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Answer» In the decimal form127/100= 1.27 |
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| 33. |
I. Write the following in decimal form and say what kind of decimal1/11 |
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| 34. |
Using the remainder theorem, find the remainder, when p(x) is divided by gty)where3. p(x)--6x2+9x+3, g(x)-x-1. |
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Answer» Ok |
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| 35. |
The remainder obtained on dividing x3 +3x2-5x + 4by (x-1) is(a) 1(c) 2(b) 1(d) 3 |
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Answer» Answer : d) 3. Explanation : |
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| 36. |
14. Using remainder theorem, find the remainder whenp (x)4x3- 12x2+ 14x -3 is divided by q (x)2x-1. |
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| 37. |
using the remainder theorem, find the remainder, when pta) is divided bwhere3.p(x) =x3-6x2 + 9x + 3, g(x) =x-1. |
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| 38. |
On dividing x3-3x2+x+2 by a polynomial g(x), the quotient and the remainderwill be x-2 and -2x+4 respectively .find g(x). |
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| 39. |
factorize x3-3x2+3x+7 |
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Answer» thnc |
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| 40. |
Find the HCF by long divisia) 434, 775b) 264 |
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| 41. |
2. Find six rational number between 3 and 4.3. Find the remainder when x3+3x2+3x+1 is divided by xQR |
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| 42. |
and S arpoints 0nu c2.5 cmThen find whether Rs IDF |
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Answer» In a triangleΔDEF,R and S are two points on the sides DE and EF respectively. ER=5cm, RD=2.5cm, FS=3.5 andSD=1.5cm.∴, ER/RD=5/2.5=2/1 and FS/SD=3.5/1.5=7/3∵, ER/RD≠FS/SD∴, RS is not parallel to DF. |
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| 43. |
નીચે આપેલ શ્રેણી પૂર્ણ કરો.3, 7, 23, 95...(A) 62(C) 479(B) 128 -(D) 575 |
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Answer» 3 * 2 +1 = 77 * 3 +2 =2323 *4 +3 =9595 *5+4 = 479see the number you multiply it goes up by one, as does the number you add:)option (c) is the correct answer Plz like my answer and accepted as best 3 7 23 95 3 × 2 + 1=77 × 3 + 2 = 2323 × 4 + 3 = 9595× 5 + 4= 479 so 479 is the answer here 2 3 4 5 1 2 3 4 are in increasing order 3*2+17*3+223*4+395*5+5=479 3*2+17*3+223*4+395*5+5=479 479 is the answer of the following 1) 3x2+1=7; 7×2+2=21+2=23, 23×4+3=92+3=95, 96x5+4=479 option C (479) is the best answer of the following question 3(2) +1=7(2) +2=23(3) +3=95(5) +4=479 479 is the correct answer of the given question the following question answer is 479 that is right answer:479 479 is the correct answer according to sequence. 479 is the. correct answer of this question. The best answer is 479 479 is the right answer 479 is the right answer of this question. 3×2+1=77×3+2=2323×4+3=95so,95×5+4=479. ans. 33×2+1=77×3+2=2323×4+3=9595×5+4=479option (c) 479 is the correct answer. 479 is the best answer |
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| 44. |
L. The place value of 2 in 6294el s0n 20emal 2o 200 |
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Answer» Answer: (d) 2000Explanation:Place value can be defined as the value represented by a digit in a number on the basis of its position in the number.therefore the place value of 2 in 62941 = 2*1000 = 2000 |
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| 45. |
Find the common difference of the Arithmetic Progression (A.P.)13-а3-2a, , , (a #0)аЗа,, За |
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| 46. |
19. If the sum of n terms of a G.P. is 255, nth term is 128and common ratio is 2, then first term will be(a) 1(c) 7(b) 3(d) of these |
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| 47. |
Find the common difference of the Arithmetic Progression (A.P.)1 3-a 3 2aа, За , За(a*0), |
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Answer» Common difference=(3-a/3a-1/a)=3-a/3a-3/3a=3-a-3/3a=-a/3a=-1/3 |
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| 48. |
cm35. IF 9" term of an arithmetic progression is -- and common difference is -. Find the 20 |
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Answer» nth term of an AP isan = a + (n - 1)d Where,a = first termd = common difference Given, d = 5/4a9 = - 6 Now,-6 = a + 8da = - 6 - 8*5/4 = - 6 - 10a = - 16 Therefore,25th terma25 = - 16 + 24*5/4 = - 16 + 6*5 = - 16 + 30 = 14 |
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| 49. |
Find the common difference of the Arithmetic Progression (A.P.)1 3 a3-2aа, За , За , (а关0) |
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Answer» Common difference 3-a/3a-1/a=3-a/3a-3/3a=3-a-3/3a=-a/3a=-1/3 |
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| 50. |
Check whether g(x)(x-3) is a factor of p(x)(x^3 + 7x^2 +3x-6) |
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Answer» if we put x=3 in p(x) and if answer will 0 then we can say that x-3 is a factor. p(x) = x*x*x + 7x*x - 3x - 6 p(3) = 3*3*3 + 7*3*3 - 3*3 - 6 = 27 + 42 - 9 - 6 = 54 not equal to 0 so x-3 is not a factor of p(x) so g(x) is not a factor of p(x) |
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