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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
\int \operatorname { cos } x \cdot \operatorname { cos } 2 x \cdot \operatorname { cos } 3 x \cdot d x |
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| 2. |
Find the volume of wood required to make a tarTheclosed box of external dimensions 80 cm75 cm and 60 cm, the thickness of walls of the 10.box being 2 cm throughout |
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Answer» 1 |
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| 3. |
( x + \frac { 1 } { x } ) = 5 \cdot ( x ^ { 3 } + \frac { 1 } { 2 x ^ { 3 } } ) = ? |
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| 4. |
D) of theseIf P, Q. R are collinear points such that P(7, 7),0(3,4) and PR = 10, then R is-A) (1,1) B) (1.-1) C) (-1,1) D) (-1,-1) |
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| 5. |
(g) 7 x 20-5 x 10-45+p |
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Answer» 7×20 - 5×10 - 45 + p = 140 - 50 - 45 + p = 90 - 45 + p = 45 + p If you find this answer helpful then like it. |
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| 6. |
7 \cdot x = \frac { 4 } { 5 } ( x + 10 ) |
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Answer» 5x=4(x+10)=4x+40so x=40 |
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| 7. |
y = x \cdot ( x - 1 ) ( x - 2 ) \text { then } \frac { d y } { d x } |
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| 8. |
\tan ^ { - 1 } \frac { 1 } { \sqrt { x ^ { 2 } - 1 } } \cdot | x | > 1 |
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| 9. |
Five line on plants |
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Answer» Plantsinclude familiar types such as trees, herbs, bushes, grasses, vines, ferns, mosses, and green algae. ... The evaporation of water from pores in the leaves pulls water through theplant. This is called transpiration. Aplantneeds sunlight, carbon dioxide, minerals and water to make food by photosynthesis. |
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| 10. |
A Cricket player scored 180 runs in the first match and 257 runs in the scondmatch. Find the number of runs he should score in the third match so that theaverage of runs in the three matches be 230. |
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| 11. |
A Cricket player scored 180 runs in the first match and 257 runs in the secondmatch. Find the number of runs he should score in the third match so that theaverage of runs in the three matches be 230. |
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Answer» _______________Match | Runs _______________first | 180_______________Second | 257_______________Third | x _______________ Average Runs = 230 ( Given ) *********************************** Average= (Total Runs )/( No. of matches ) ************************************* ( 180 + 257 + x )/3 = 230 => 437 + x = 3 × 230 => x = 690 - 437 x = 253 Therefore. , The number runs Scored by the player in third match = x = 253 |
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| 12. |
Po lic cycle To Wпсi Kuju polorA Cricket player scored 180 runs in the first match and 257 runs in the secondmatch. Find the number of runs he should score in the third match so that theaverage of runs in the three matches be 230. |
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Answer» the correct answer is no but 4 253 is the right answer Total run in all 3 matches = 230*3 = 690Total run in the 2 matches = 180+257=437So the run made by the cricketer in the third match is= 690-437=253Hope this answer help you. Solution : _______________Match | Runs_______________first | 180_______________Second | 257_______________Third | x_______________ Average Runs = 230 ( Given ) *********************************** Average= (Total Runs )/( No. of matches ) ************************************* ( 180 + 257 + x )/3 = 230 => 437 + x = 3 × 230 => x = 690 - 437 x = 253 Therefore. , The number runs Scored by the player in third match = x = 253 correct answer is 253 runs |
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| 13. |
started her dance practice at 5: 40 p.m andstopped it at 7 10 p.m. How long did she practice? |
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Answer» She practiced for 1:30 hours |
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| 14. |
EXERCISE 10.4roles of radii 5 cm and 3 cm intersect at two points and the distance betwerntres is 4 cm. Find the length of the common chord.l chords of a circle intersect within the circle, prove that the segmentling seements of the other chord. |
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| 15. |
Ragini started her dance practice at 5: 40 p.m. andstopped it at 7 10 p.m. How long did she practice? |
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Answer» Started at 5 : 40 p.m. and stopped at 7 : 10 p.m. Total duration = 7 : 10 - 5 : 40 = 1 hr 30 min If you find this answer helpful then like it. |
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| 16. |
Find the length and surface area of a wooden plank of width 3m, thickness 75 cm andvolume 33.75m3 |
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| 17. |
Il 8 loss and no profit. Find theu HoDilycle for which Raju purchased it.9. A Cricket player scored 180 runs in the first match and 257 runs in the sccondmotch. Find the number of runs he should score in the third match so that theaveroge of runs in the three matches be 230.10. Sudhir's prsent |
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Answer» Let the runs in third match be X.Then, (180+257+X)/3 = 230=> 437+X = 690=> X = 690-437=> X = 253. Please hit the like button if this helped you out. |
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| 18. |
cket player scored 180 runs in the first match and 257 runs in the secondthird match so that thematch. Find the number of runs he should score in theaverage of runs in the three matches be 230 |
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Answer» Total run in all 3 matches = 230*3 = 690Total run in the 2 matches = 180+257=437So the run made by the cricketer in the third match is= 690-437=153 Like my answer if you find it useful! |
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| 19. |
लि ही The oda uaf O S0 o % a orede )i one~ ki ufg “fw Nt e uz&. i Ureke . g e ण लू ७ कल5९1७५ |
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Answer» Angle of sector = (Area of sector / Area of circle) * 360= 360/9= 40 degrees. PLEASE HIT THE LIKE BUTTON thx |
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| 20. |
बिंदु (15, 8) की दूरी मूलबिंदु से ज्ञात कीजिए।व न. e Nt s, |
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| 21. |
1. The smallest whole number is |
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Answer» smallest whole number is 0 Zero is the smallest whole number. Thewhole number seriesis 0,1,2,3,4... |
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| 22. |
Which is the smallest whole number? |
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Answer» 0 zero is a smallest whole numbers |
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| 23. |
3.Which is the smallest whole number? |
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Answer» 0 zero is a smallest whole numbers |
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| 24. |
1. The smallest whole number is(a) 1(b) 0(c) 2 |
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Answer» (b) 0the smallest whole number is 0 the answer of the question is0 |
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| 25. |
Find the smallest whole number by which 252 shouldbe divided. So as to get a perfect square. Also find thesquare root of the square number so obtained. |
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Answer» 1 |
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| 26. |
sqrt(3)*x^2 %2B 11*x %2B 6*sqrt(3)=0 |
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Answer» √3x²+11x+6√3=√3x²+9x+2x+6√3 =√3x(x+3√3)+2(x+3√3) =(√3x+2)(x+3√3)X=-3√3and X=-2/√3 [-3*sqrt(3),-2*sqrt(3)/3] |
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| 27. |
thesame.). A gulab jamun, contains sugar syrup up to about 30% of its volume.Calculate the total amount of syrup which would be found in 45 gulabjamns, each of shaped like a cylinder with two hemispherical ends withdiameter 2.8 cm and length 5 cm. |
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| 28. |
1) Tho cireles intersect coch otherat points C and D. Their comment AB touches the circles atpoint A and B. Prove that |
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| 29. |
Find the smallest whole number that must be added to the number 267 to obtain a perfect cube. |
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Answer» 267+76=343 which is the cube root of 7. so 76 must be added |
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| 30. |
(-8)/21 %2B (-6)/11 %2B 3/7 %2B 5/22 |
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| 31. |
three angles of a quadrilateral are in the ratio 4:5:3. the difference of the least and the greatest of three angles is 45 degree. find all the four angles of a quadrilateral . |
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| 32. |
Of the three angles of a triangle, one is twice the smallest and another is three times thesmallest. Find the angles. |
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| 33. |
The angles of a triangle are arranged in ascending orderof magaitude, If the difference between two.consecutiveangles is 10e, find all the three angles. |
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| 34. |
(679+267) â(679-267) _ 5679% 267 |
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Answer» PLEASE LIKE THE SOLUTION |
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| 35. |
15.43fthe letters of the word LATE' be permuted and the words so formed be arrangedN asin a dictionary, find the rank of the word LATE. |
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| 36. |
The angles of a triangle are arrangedin ascending order of their magnitude.the difference between twoconsecutive angles is 10°, find thethree angles. |
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| 37. |
4+4Ă18-6-8123 x 6 146 x |
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Answer» (4 + 4*18 - 6 - 6)/(123*6 - 146*5)= (4 + 72 - 12)/(738 - 730)= 64/8= 8 144-4÷738-730=130÷8=16 |
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| 38. |
उदाहरण 146: गुणनखण्ड प्रमेय का उपोग करते हुए बहुपद 3 +x® —Tx* x4 6 1_ गुणनखण्ड कीजिए । |
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| 39. |
iiuilavlllgtlesamebaĹĄe,findtheratiooftheir heights if their volumes areequal.A conical tent is 3 m deep and its circular top has radius 1.75 m, find the capacity of the tank inkiloletres.nes bave their heights in the ratio 1 3 and the radii of their bases in the ratio 3:1, find |
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Answer» Given:-h=3mr=1.75m the volume of cone =1/3pi×r×r×h=1/3×22/7×1.75×1.75×3=385/40×1000/1000=9.62kl |
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| 40. |
{halide. पड 19% 2xp + 267 - &g — 2+ A+ |
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Answer» Please like the solution 👍 ✔️👍 |
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| 41. |
1. What is the value of (cos^267° sin^223°)? |
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Answer» cos²67° - sin²23°cos²(90° - 23°) - sin²(23°)sin²(23°) - sin²(23°)0 |
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| 42. |
12340 subtracted from a number gives 95 267. What is the number? |
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| 43. |
If one zero of P(x)of k.4x2 (8 k2 -40 k) x- 9 is negative of the other find the |
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Answer» let the zeros be alpha and -alphasum of zeros = -b/a 0 = (8k^2 - 40k)/48k(k-5)=0k=5 |
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| 44. |
The volume of a reservoirs is 108m³ water poured into it at the rate of 60 litres per minute. How many hours will be taken to fill the reservoirs? |
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Answer» Rate of flow of water = 60 litres/minute Volume of the tank = 108 m3 1 m3 = 1000 litres 108 m3= 108000 litres Time taken to fill the complete tank= 108000/60 = 1800 minutes = 1800/60 hours = 30 hours The tank will be filled completely in30 hours. |
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| 45. |
omial -8x + k is 40, find the valuefthe sum of squares of zeroes of the polynomiala-8 +kis 40, 6of k |
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Answer» 64-2k= 40k= 12 |
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| 46. |
Water is pouring into a cubiodal reservoir at the rate of 60 litres perminute. Ifthe volume of reservoir is 108 m, find the number of hours itwill take to fill the reservoir. |
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| 47. |
Water is pouring into a cubiodal reservoir at the rate of 60 litres perminute. Ifthe volume of reservoir is 108 m3, find the number of hoursitwill take to fill the reservoir.8. |
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Answer» Rate of flow of water = 60 litres/minute Volume of the tank = 108 m3 1 m3 = 1000 litres 108 m3= 108000 litres Time taken to fill the complete tank= 108000/60 = 1800 minutes = 1800/60 hours = 30 hours The tank will be filled completely in30 hours. |
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| 48. |
n two allbys A and 8, tle ratio Znc andin uInthe new ally |
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Answer» Zinc : Tin A 5x : 2x = 7x B 3y : 4y = 7y => A = 7x = 7 kg. x = 1 kg ∴∴Zinc in Alloy A => 5 kg Tin in Alloy A => 2 kg. => B => 7y = 21 kg. y = 3 kg. Zinc in alloy B =>3×3==9kg Tin in alloy B =>3×4=12kg ∴∴after mix-up the ratio of zinc and tin in new alloy |
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| 49. |
sally two questionShow that tan73° + cot 61°tan 17 + cot 29°= tan 730 cot 610 |
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| 50. |
Ritu borrowed some money at 12% per annum. She had topaydid she borrow Rs.180 as interest after 3 years. What sum did she borrow? |
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