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2

2 is the right✔ answer

this question not match

very bad

let ( x1 , y1 ) = A( 2 , 0 ) ,( x2 , y2 ) = B ( 0 , 2/9 ) ;

mid point of joining of A and B = ( x1+ x2 /2 , y1 + y2 /2 )( 1 , p/ 3 )= ( 0 + 2 /2 , 0 + 2/9 / 2 )= ( 1 , 1/9 )p/3 = 1/9

[∵ If ( a , b ) = ( c , d ) then a = c and b = d ]

p = 1/3 --- ( 1 )

according to the problem given ,

put ( -1 , 3p ) in the equation 5x + 3y + 2 =05 ( -1 ) + 3× ( 3p ) + 2 = 0-5 + 3× 3 ( 1/3 ) + 2 =0 [ from ( 1 ) ]-5 + 3 + 2 =00 = 0 [ true ]Therefore ,5x + 3y + 2 =0 line passes through thepoint ( -1 , 3p ) .

Circumference = 2πr=> 2 × (22/7) × r = 6.6=> r = (6.6 × 7)/2 × 22 r = 1.05 cm

wrong

169 should no come

and instead of 381 it is 9

Given:-h=3mr=1.75m

the volume of cone =1/3pi×r×r×h=1/3×22/7×1.75×1.75×3=385/40×1000/1000=9.62kl

Let theta = x

Then,(sinx + 1 + cosx)(sinx - 1 + cosx).secx.cosecx

= (sinx + cosx + 1)(sinx + cosx - 1).secx.cosecx

= [(sinx + cosx)^2 - 1].secx.cosecx

= (sin^2 x + cos^2 x + 2sinx.cosx - 1).secx.cosecx

= (1 - 1 + 2sinx.cosx).secx.cosecx

= 2sinx.cosx.1/cosx.1/sinx

= 2

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m and n are zeroesm+n=5/amn=c/agivenm+n=10=mn5/a=10a=1/2c/1/2=10c=5

Given : f(x) = kx² + 4x + 4 and α and β are zero of f(x)

so, α + β = -4/k and αβ = 4/k

(α +β)² = α² + β² + 2αβ

(-4/k)² = 24 + 2 × (4/k)

16/k² = 24 + 8/k

2/k² = 3 + 1/k

2/k² = (3k + 1)/k

2/k = ( 3k + 1)

2 = 3k² + k

3k² + k - 2 = 0

3k² + 3k - 2k - 2 = 0

3k ( k + 1) -2 ( k + 1) = 0

(3k - 2) ( k + 1) = 0

so, k = 2/9 and -1

Given, sinθ-cosθ = 0

sinθ = cosθsinθ/cosθ = 1tanθ = 1

But, tan45 = 1

So,tanθ=tan45θ = 45°

sin45 = 1/√2, cos45 = 1/√2

Therefore, sin⁴θ+cos⁴θ = (1/√2)⁴+(1/√2)⁴= 1/4+1/4 = 2/4 = 1/2 = 0.5

Given : ax² - 6x - 6

Product of zeros

-6/a = 4

a = -6/4 = -3/2

Radius of cylindrical tank = 154cm = 1.54mheight of water =3mif height is 4.5 m then let the volume be vvolume of cylinder v = 22/7 *r *r*(H-h) =22/7*1.54*1.54*(4.5-3) =22/7*2.3716*1.5 =22*0.3388*1.5=11.1804 m^3please like the solution 👍 ✔️

Volume of cuboid = LBH = 57×4×3 = 684cm²

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Y cordianate= 10/4x cordianate= 10/5

(a/b)^[ x-1] = (b/a)^[x-3]

(a/b)^[ x-1] = (a/b)^[-(x-3)]

x - 1 = - x + 32x = 4x = 4/2x = 2

Value of x = 2

For polynomial ax^2 - 6x - 6 product of zeroes is 0

Then,Product of zeroes = - 6/a

Hence,-6/a = 4a = - 6/4 = - 3/2

a=a, b=-6, c=-6Product of roots=4c/a=4-6/a=4a=-3/2

Let the larger angle be= asmall angles be = b, c

1. a= b+ca+b+c=180°acc to eq 1

2(c+b) = 180°c+b = 90°

c+b = athereforeone angle is 90° i.e a.Hence proved.

You give a wrong question

Hii o know that these question

Hii app konsse class may hoo

sinx^4 + cosx^4=1; ( sinx^2 + cosx^2)( sinx^2+cosx^2)= (1)(1)=1

1answer is the best

For equation (ax^2 - 6x - 6)Product of zeros is 4

We know for equation ax^2 + bx + c = 0Product of zeroes = c/a

Then,-6/a = 4a = - 6/4 = - 3/2

the volume of the iron used to make tank is 44/21 m

The hemispherical bowl can hold milk is equal to the volume of the hemispherical bowl.

Given diameter of the hemispherical bowl = 10.5cm

radius of the hemispherical bowl (r) = 10.5/2 = 5.25 cm

volume = (2/3)*Π*(5.25)3

= (2*3.14*5.25*5.25*5.25)/3 (Π = 3.14)

= 2*3.14*5.25*5.25*1.75

= 302.91 cm3

= 303 cm3

Now 1000 cm3= 1 litre

So 303 cm3= 303/1000 = 0.303litre

thanks bhai

Thanks for the answer

Let p and -p are two zeroes of the quadratic polynomialFormula : sum of the zeroes = -b/ap-p=-b/a0=-b/aHence,b=0Answer: b=0

a×b=x²cos²A-y²sin²Aa×b=x²cos²A-y²(1-cos²A)ab-y²=cos²A(x²+y²)(ab-y²)/cos²A=(x²+y²)

a²+b² is the correct answer of the given question

eight person can sit in a car how many cars will be needed for vansh 168 person person