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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If 15 workers can build a wall in 48 hours, how many workers will be requiredto do the same work in 30 hours ?2. |
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Answer» total work need to be done=48×15=720 menhoursnow to complete in 30 hrs men required=720/30=24 |
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| 2. |
Subtract (3 -trom the sum ofand |
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Answer» 2 2 |
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| 3. |
Evaluate s and y trom the iare given |
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| 4. |
anging at some distance trom a Zomall Luiiding The aralè ot elevationDards Ihe Vuitding.ind -the distance he Dallked towUt |
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| 5. |
1. The number of enrolments in a school has increasedtrom 1800 to 2016. The percentage increase in theenrolments is |
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Answer» 1800 + 1800x/100 = 2016 18x = 216 x = 12% |
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| 6. |
B.If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 timesthe least, then the numbers are(a) 5, 10, 15, 20 (b) 4, 10, 16, 22 (c) 3,7, 11, 15 (d) none of these |
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| 7. |
8. If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 timesthe least, then the numbers are699 5, 10, 15, 20 (b) 4, 10, 16, 22 (c) 3,7, 11, 15 (d) none of these |
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| 8. |
Find the values ofthe follov-1Sin" | 2」 |
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| 9. |
issubtractedfromtimesnumber,theresutIs20lessuiailhieet7. If 16twoa8.tive even numbers is half the smaller number. Find the numbers.Four-ninth of the greater of the two consecuthan the three-tenth of the smaller |
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| 10. |
22Find the area ofthe ellipse1 |
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| 11. |
2+3+7*8(900)+7 |
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Answer» 50412 will be the answer for thiswe applied bodmas rule here |
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| 12. |
A tap can fill an empty tank in12 hours and another tap carnempty half the tank in 10 hoursIt both the taps are opened simultaneously, how long would ittake for the empty tank to befilled to half its capacity? 1(1J 30 hours (2)20 hours(3) 15 hours (4) 12 hours |
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Answer» Answer: 3)15 hoursExplanation:if emptying pipe empty half the tank in 10 hours then emptying pipe fill the tank in 10*2=20 hoursTotal capacity=60A fills in 12 hours thus efficiency=5B empty in 20 hours thus efficiency =-3(A-B) efficiency=5-3=2 units/hr= (1/2 of TC)/2 units=30/2=15 hrs |
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| 13. |
2. In the adjoining figure, AOB is a straightline. Find the value of x. Hence, find LAOCand ZBOD55° |
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| 14. |
if 15 workers can builder wall in 48 hours how many workers will be required to do the same work in 30 hours? |
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Answer» 15 workers => 48 hrs x=> 30 hrs 15×48=x×30 15*48/30= x x=24workers Answer : 24 |
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| 15. |
2. In the adjoining figure, AOB is a straightline. Find the value of x. Hence, find ZAOCand ZBOD. |
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Answer» (3x-7)+55+(x+20)=1804x+68=180X = 28 Angle AOC = 3*28-7=77Angle BOD = 28+20=48 |
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| 16. |
2. In the adjoining figure, AOB is a straightline. Find the value of x. Hence, find ZAOCand ZBOD55° |
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| 17. |
2. In the adjoining figure, AOB is a straightline. Find the value of x. Hence, find ZAOCand ZBOD55°(3x-7A+20) |
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| 18. |
Lhp the alining figure AOB is a straight lineFind the value of x0it the |
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| 19. |
12m,10. A park is in the shape of a quadrilateral ABCD has AB = 9m, BCCD= 5m, AD m 8 m andC = 90°. Find the area of the park. |
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| 20. |
1. A park, in the shape of a quadrilateral ABCD, has LC-90 AB-9 m, BC- 12mCD-5m and AD 8m. How much area does it occupy? |
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| 21. |
C-2s) - Съ00) t Coo) 30 |
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Answer» six hundred and fifty five one thousand two hundred and five (-25)+(300)+900+30-25+12301205 the answer is correct.plz accept my best answer -25-(-300)+400+30-25+300+400+30-25+730705 is the best answer 705 is the right answer 705 is the best answer. |
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| 22. |
swer any one OA man takes a loan of 5000 at 6% simple interest and after 1 year hetakes another loan of same amount at 7% simple interest. After how manyyears of taking the first loan the interest of both the loans will be equal? |
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| 23. |
amount to in 2 years 8 monuns al 900At what rate per cent per annum will 3600 amount to 4734 in 34 inyears?years |
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| 24. |
parately fill a cistern in 15 hours and 20 hours respectively. There is a third30 hours. In how mucc al the three pipes are simultaneously opened, then the cistern is filled9. Two pipes A and B can sepipe at the bottom to empty it. Ifpipes are simpipe alone can empty the cistern? |
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Answer» In such kind of questions, take the LCM of 12,15 i.e. 60. Assume 60 ltrs is the capacity of cistern.Now, the rate of filling for pipe P- 60/12 = 5 ltrs per min.the rate of filling for pipe Q- 60/15 = 4 ltrs per min So at the end of 3 mins, the cistern will have - 15 ltrs (From pipe P-5X3) +12 ltrs (From pipe Q-4X3) =27 ltrs At the end of 3 mins, cistern will have remaining capacity of33 ltrs (60 ltrs- 27 ltrs) As only pipe Q will fill the cistern = 33/4 = 8.25 mins =8 mins 15 seconds. plz clear ur imagge la jdjdjdbejeijxjjxkieje |
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| 25. |
Find tbes ofthe shdedo in Fig 12.19.PO-34 on PR-7 m and O is the centre of th |
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Answer» Given : PQ= 24 cm ,PR = 7 cm We know that any angle made by the diameter QR in the semicircle is 90°. ∠RPQ = 90° In right angled ∆RPQ RQ² = PQ² + PR² [By pythagoras theorem] RQ² = 24² + 7² RQ² = 576 + 49 RQ² = 625 RQ = √625cm RQ= 25 cm radius of the circle (OQ)= 25 / 2 cm Area of right ∆ RPQ= ½ × Base × height Area of right ∆ RPQ= ½ × RP × PQ Area of right ∆ RPQ = ½ × 7 × 24 = 7 × 12 = 84 cm² Area of right ∆ RPQ = 84 cm² Area of semicircle= πr²/2 = (22/7) × (25/2)² / 2 = (22 × 25 × 25)/ (7× 2 × 2 × 2) = 11 × 625 /28 = 6875/28 cm² Area of semicircle = 6875/28 cm² Area of the shaded region = Area of semicircle - Area of right ∆ RPQ = (6875/28 - 84 )cm² = (6875 - 2532)/ 28 Area of the shaded region = 4523 / 28= 161.54 cm² Hence, the area of the shaded region = 161.54 cm² Like my answer if you find it useful! |
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| 26. |
(a) 15 is bigger than : |
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Answer» 15 is bigger than the number 1,2,3,4,5,6,7,8,9,10,11,12,13 15 is bigger than the numbers from -infinite to 14 on the number line. 15 is bigger than some numbers like 14'13'12'11'10'9'8'7'6'5'4'3'2'1 15 is bigger then - infinite to 14 15 is biggest than 14 15 is bigger than 1,2,3,4,5,6,7,8,9,10,12,13,14 1,2,3,4,5,6,7,8,9,10,11,12,13,14 |
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| 27. |
- Two inlet pipes A and B can fill anempty cistern in 22 and 33 h,respectively. They are switched ONtogether but pipe B had to be closed7 h before the cistern was full. Howmany hours in all did it take the twopipes to fill the cistern? |
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Answer» (9h+7h)=16h was taken by the two pipes to fill the cistern |
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| 28. |
bstituting m=-3 in 4m2, 24m + 36 qivesă |
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Answer» If you like the solution, Please give it a 👍 |
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| 29. |
In the following figure, O is the centre of asemi-circular arc and AOB is a straight lineFind the area of the shaded region. |
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| 30. |
The diagonal of a quadriand the perpendiculars dropped on it from theremaining opposite vertices are 8 m and 13 m. Findthe area of the field4.lateral shaped field is 24mx/13 m/ 1 24min |
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| 31. |
Fig 11-44)3 cm24m14 |
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Answer» thanks bro Thanks for solving |
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| 32. |
Findthe area.24m25m17m515m12m12m19m |
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Answer» Something is missing in the figure area of trectangle+area of two triangles+area of right triangle whose base is 7 +area of bigger triangle=62+30+30+84+101.5 something is missing. |
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| 33. |
32. The measures of sides of triangular garden is 40m, 32m and24m. Find area of garden |
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Answer» Like if you find it useful |
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| 34. |
12. If an amount takes 4 years with therate of 12-% to be 3750, then theamount will be |
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Answer» 4*25*3750/100*21875 |
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| 35. |
si dength of Guld jommun 25 cm| Radies of Gulab jangan linenright of their fou kind of gudal anthem| 30.1. I qutab jammenon1300 x 4sx LTPhiyoCoo |
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Answer» height of cylinderrical portion of gulab jamun=5-1.4-1.4=2.2cm 30%of gulab jamun300/100*4.5*[πr2h+4/3πr3 |
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| 36. |
4. What are the dimensions of the cuboidformed by 6 cubes, each with the dimensions2 cm x 2 cm x 2 cm, placed side by side?Draw a figure to show the cuboid |
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| 37. |
12. On paying 5/13 th part of his debt, a man finds that he has a further debtof 400. What was his debt ? |
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Answer» let the debt be xso we make equation x - 5x/13 = 4008x/13 = 400x = (400×13)/8 = 50×13x = ₹650so debt is ₹650 |
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| 38. |
A rectangular field is 40 mand 30 m broad, A pit 10 m long 2.5 m broad and 7 m deep has been dug outin thcentre of the field. The earth taken out of it is evenly spread over the remaining part of the field. Findthe rise in the level of the field. |
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| 39. |
blhich Playphnuncl ts bigger: Ohe.measuringd2om n dength and somin |
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Answer» area of playground 1=lb=120*50=6000m² area of playground 2=lb=130*40=5200m² area of playground 1> area of playground 2 so playground 1 is bigger |
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| 40. |
26.lona AB and CD ,、the a |
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Answer» I do not understand your writing a=20°(vertically opposite angle)c+20=90° then c=70°b=c+d=90+70=160° |
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| 41. |
हे न दवाहे). ठ< कु. ... 2. »7 = 6mLonayoluvme. 06 ८-00 गान १५ ४ 0 2-८० ८-21 है.1 ) |
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| 42. |
27.The perimeter of a semi-circular region is 144 cmWhat is its area? |
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Answer» wrong answer |
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| 43. |
0x-7x+2 (n) |
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Answer» x^2-7x+2= 0a= 1 b= -7 c= 2D= b^2-4ac= (-7)^2-8= 41 |
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| 44. |
Find the mean of first 5 whole numbers |
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Answer» First 5 whole numbers are 0,1,2,3,4sum of the observations ,∑xi = 0+1+2+3+4 = 10no of observations ,∑fi= 5mean =∑xi /∑fi = 10/5 = 2 so the mean is 2 first 5 whole numbers are 0,1,2,3,4 In 0,1,2,3,4 the median is 2 because first, we take pairs that means .first number it is 0 and last number it is 4 .So,0 and 4 are pairs if we look like that the pairs are;0 and 41 and 3 and last number is= 2So,the mean of first five whole number is =2 |
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| 45. |
The cost of painting the surface of a spheis Rs 1526 at the rate of 6 per m^2.Fthe radius of sphere. (pi=3.14) |
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| 46. |
Prove that volume of largest cone, which can be inscribed in a sphe8is | 7 th part of volume of sphere. |
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| 47. |
ORA semi-circular sheet of paper of diameter 28 cm¡ is bent into an open conical cup. Find the depth and capacityof the cup.Section-D - |
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Answer» Like if you find it useful |
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| 48. |
24. The angle of elevation of the top Qof a vertical tower PQ from a point Xon the ground is 60°. At a point Y, 40 m vertically above X, the angle ofelevation is 45°. Find the height of tower PQ. ITake 3-1.73.]CBSE 2083C] |
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| 49. |
3A rope that is in length is cut into 2pieces of equal length. How lonapiece? Solve with a drawing.is each |
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Answer» 3/4/2=3/8 is the length of each piece. |
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| 50. |
14. A semi circular sheet of metal of diameter 28 cmis bent into an open conical cup. Find the depth andIT-II (2011)]capacity of the cup. |
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Answer» Given: Diameter = 28 cm Radius, r = 14 cm Circumference of semi circle = πr= (22/7) x 14 = 44 cm This becomes circumference of base of cone2πR = 44R = 44 x (7/44)R = 7 cm The radius of semi circular sheet = slant height of conical cupThat is l = 7 cm We know that r2+ h2= l2142+ h2= 72196 – 49 = h2h2= 147 Therefore, h = 7√3 cm That is depth of the conical cup is 7√3 cm Capacity of cup = (1/3)πr2h = (1/3) x (22/7) x 72x 7√3 = 622.37 cu cm |
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