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Total amount = 8500(1+8/100)²

= 8500*108*108/100*100

= 9,914.4

Compound interest = 9914.4 - 8500

= 1414.4 rupees

36725 X, 487= 17885075

36725×487 =17885075.

cost of one scooter=rs36725cost of 487 scooter=rs36725*487=RS 17885075

A point is an exact position or location on a plane surface. It is important to understand that a point is not a thing, but a place. We indicate the position of a point by placing a dot with a pencil.

. is full-stop which we use to put at end of the sentence. It is used to complete a sentence. This we cannot use in interrogative statements . In interrogative statements we use "?" .

Given,Principal amount P = 400, Rate of Interest = R, Time period = 1.5 years, SI = 478 - 400 = 78

SI = P*R*T/10078 = 400*R*1.5/100R = 78/4*1.5R = 78/6 = 13%

Therefore, Rate of Interest = 13%

bhai question to pehele thik se padho

SI = (P×R×T)/100SI = Amount - Principal = 478 - 400 = 7878 =(400×R ×3/2)/10078 =6RR=13%

2,4,6,8,10 are multiplesn=5a=2d=2Sn=n/2(2a+(n-1)d)S5=5/2(2*2+(4)*2)S5=5/2(4+8)S5=5/2*12=5*6=30

27 is the correct answer

a) is the right answer

option a is correctyou can check the other options

2.05= 205/100= 41/20 = 2 ×1/20 so option a is correct

a is. right. answer

a. is the correct answer h

13. Changing 2.05 in fraction, we get205/100

Simplifying 205/100, we get41/20

Now, changing 41/20 into mixed farction, we get2 and 1/20

Therefore, answer (a) is correctHope this helps you....💛

Given,3 bulbs are selected at random classified as defective (D),non-defective (N)

The sample space S is

S={DDD,DDN,DND,DNN,NDD,NDN,NND,NNN}

Given, P = 8000, A = 16000, T = 5 yearsLet Rate of Interest = R

Then,For compound interestA = P(1 + R/100)^516000/8000 = (1 + R/100)^5(1 + R/100)^5 = 2.......(1)

Let for T = 20 years, Amount = A1

A1 = P(1 + R/100)^20A1 = 8000[(1 + R/100)^5]^4A1 = 8000(2)^4A1 = 8000*16A1 = 128000

Therefore, After 20 years amount will become Rs 128000

6400square root =√64*100=8*10=80

thanks

5^(2x+1)÷5^2=5^3so 5^(2x+1-2)=5^32x-1=3so 2x=4so x=2

|-12|=12 |-10|=1025-12+10=23

if he sell 18 machines. Then he will get a commission of 12000

5(2x-5)÷(2x-5)=5

Where is the solution I can ! see

1. invisible -visible2 problems-solution3 legal-illegal4.inclining-declining

A DC stands for DIRECT CURRENT. DIRECT CURRENT and VOLTAGE has constant amplitude at all time, hence there is no variations in its amplitude and has zero frequency. While the AC stands for Alternating current, which means the voltage and current varies with time. It has different Amplitude at different time. Due to variation it has some constant frequency, which is normally 50 or 60 Hz.

please post complete image of the question

Let the side length of an equilateral triangle ∆PQR is a and PT be the altitude of ∆PQR as shown in figure.Now, PQ = QR = PR = a We know, in case of equilateral triangle, altitude divide the base in two equal parts. e.g., QT = TR = QR/2 = a/2 Given, QS = QR/3 = a/3 ∴ ST = QT - QS = a/2 - a/3 = a/6 Also PT = √(PQ² - QT²) = √(a² -a²/4) = √3a/2

Now, use Pythagoras theorem for ∆PST PS² = ST² + PT² ⇒PS² = (a/6)² + (√3a/2)² = a²/36 + 3a²/4 = (a² + 27a²)/36 = 28a²/36 = 7a²/9 ⇒9PS² = 7PQ² Hence proved

The fraction is 5/12

Let the speed of the stream is u km/h

Then,

30/(15+u) + 30/(15-u) = 4.5

30*30/(225-u*u) = 4.5

225 - u*u = 200

u = 5 km/h

given : ABCD is a trapezium . such that AB || DC.E is the mid-point of BC.TPT:area(∆ABE)+area(∆DEC)=1/2*area(trapeziumABCD)proof:area(∆ABE) = 1/2*area(∆ABC) ..........(1) [since the median divides the triangle into equal parts]similarly area(∆DEC) = 1/2*area(∆BDC)...........(2)area(∆BDC)=area(∆ADC) [triangles formed between same pair of parallel lines and with the same base are equal in areas]thereforearea(∆DEC)=1/2*area(∆ADC)......(3)adding eq(1) and eq(3):area(∆ABE)+area(∆DEC)=1/2*[area(∆ABC)+area(∆ADC)]=1/2*area(trapeziumABCD)

give figure of this question.

The Imperial Bank of India is the Presidency Bank of India.

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sum triples so I = 2P 2P = P×15×T/100 T = (2×100)/15 = 13.33 years = 13 years 4 months