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if 4 is root of given equation then put value of x in the equation.4^2-9*4+k=0=>36-16=k=>k=20

Let it is added n times

(4/9)*n=8n=8*9/4

n=2*9=18

Option a is correct

4p<18-64p<12p<12/4p<3

Since the area of square is 1296 cm^2so its side will be √1296=36 cmSince the area of circles is max2xdiameter will be equal to a sideSo 2(2r)=36So r=36/4 = 9cmthe circumference = 2πr=18π cm≈56.57 cm

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Cube root of - 1728

Prime Factors of - 1728= - (2*2*2*2*2*2*3*3*3)

cuberoot(-1728)= {- (2)^6 × (3)^3}^1/3= - (2)^2×(3)= - 4*3= - 12

(4) is correct option

(2/√5+√3) + (1/√3+√2) - (2/√5-√2)=2(√5-√3)/2 + (√3-√2) - 2(√5+√2)/3= √5 - √3 + √3 - √2 -2√5/3 -2√2/3=(√5 + √2)/3

sqaure root of 4 is 4 = 2²so √4 = 2

2 is the square root of 4

square root of 4 is 22×2=4

square root of 4 is √4=2

P-2is the correct answer of this questions

Suppose you have a fair coin: this means it has a50%chance of landing heads up and a50%chance of landing tails up. Suppose you flip it three times and these flips are independent. What is the probability that it lands heads up, then tails up, then heads up? So the answer is 1/8, or 12.5%.

how does first line occures

Diagonal of a square = √2a

So

√2(6+2√5) = √2a

a = 6+2√5

= 2(3+√5) cm

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there are total 90 two digit numbers among them 6 are perfect squares so probability is 6/90 = 1/15

Tnzz

Side of square paper

=√784cm=28cm

Radius of each circular plate

=14×28cm=7cm

Circuference of each circular plate

=2×22/7×7

=44cm

Total number of outcomes =36For sum to be 9(6,3)(3,6)(4,5)(5,4)=4 outcomesHence probability will be4/36=1/9

Probability of throwing a sum of 9= excepted outcomes/total outcomes=4/36=1/9

hence for atleast head =1-3/4=1/4

sir i want in solution

Probability = possible outcomes / total outcomes

All outcomes are (H, T), (T, H), (H, H), (T, T)

1) Probability of at least one head = 3/4

2) Probability of no head = 1/4

On throwing a die, a number which appears on the die, which is the factor of 4 is 4.Required probability=1/6

Total number of possibilities is 36now to get same number only 6 possibilities(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)hence.probability will be 6/36=1/6Total of 10(4,6),(6,4),(5,5)Probability is 3/36=1/12

answer 7/2 hoga and solution uper wala hi sahi hai

use sinA/a=sinB/b=sinC/cuse these both side and get the proof ready.

Answer isx=3.

Explanation:

log6216=x∴log663=x∴3log66=x∴3⋅log6log6=x∴x=3. (answer

putting x value in eq. to be solved(2y+6)^3 -8y^2 -36 (2y+6)y -216=8y^3 -8y^2=8y^2 (y-1)

Circumference of circle = pi × d

= 3.14 × 10 cm

= 31.4 cm

Total no of possibilities = 4

For two (random) coin tosses you have four possible combinations:

1. 1 toss and 1 head2. 1 head and 1 Toss 3. Both toss4. Both head

No of possibility that we get, one head = 3

So probability of getting one head = 3/4

Total no of possibilities = 4

For two (random) coin tosses you have four possible combinations:

1. 1 toss and 1 head2. 1 head and 1 Toss 3. Both toss4. Both head

No of possibility that we get, one head = 3

So probability of getting one head = 3/4

total outcomes=4(hh)(tt)(ht)(th)required outcomes=2(ht)(th)probability=2/4=1/2

6p+1/3+1=7p-3/26p+1/4=7p-3/22(6p+1)=4(7p-3)12p+2=28p-12-28p+12p= -12-2-16p= -1416p=14p=14/16p=7/8p=0.875