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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Ifof an estate is worth of R53400Then the value of whole estate is |
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Answer» Let whole value be x Then(3/7) x = 53400x = 53400*7/3x = 17800*7x = 124600 Value of whole estate = Rs 1,24,600 |
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| 2. |
if 4/5 of an estate be worth Rs.1680,find the value of half of the estate. |
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| 3. |
8. If of an estate be worth * 1,68,000. Find the valueof half of the estate- |
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Answer» 4/5 estate=168000 rs1estate=4*168000/5=134400 rsSo half estate=134400/2= rs67200 |
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| 4. |
24. In a quiz, positive marks are given for correct answers and negative marks are given for incorrect answers. If Jack's scores in fivesuccessive rounds were 25, 5, 10, 15 and 10, what was his total at the end ? |
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| 5. |
nd the original price of a washing machine which was brought forinclusive of 8% GST.13,500 |
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Answer» Find the percentage of the price including GST : Percentage = 100 + 8 = 108% Price including GST = Rs 13500 (Given) Find the original price: 108% = Rs 13500 1% = 13500 ÷108 = Rs 125 100% = 125 x 100 = Rs 12,500 Answer: The original price is Rs 12500 |
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| 6. |
EXERCISE 2.2ow would you rewrite Euclid's fifth postulate so that it would be easier to understand2. Does Euclid's fifth postulate imply the existence of parallel lines? Explain. |
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| 7. |
find the value of(3.51 285(23.15) |
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| 8. |
x[4+6]5x=2x+5 |
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| 9. |
If $ Z_{1}=-1, Z_{2}=i $ then find $ \operatorname{Arg}\left(\frac{Z_{1}}{Z_{2}}\right) $ |
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| 10. |
A cylinder having height and diameter 14 cm, is filled with water up tothe brim. Four equal solid spheres are placed into it. The diameter ofeach sphere is equal to the radius of the base of the cylinder. Whatfraction of water overflows? |
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Answer» Volume of cylinder= pi*r*r*h = 22/7*7*7*14= 22*7*14 = 2156 cm^3 Volume of one sphere= 4/3*pi*r*r*r= 4/3*22/7*7/2*7/2*7/2= 1/3*11*7*7 Volume of 4 spheres= 2156/3 cm^3 Thus, fraction of water overflow is 1/3 of volume of cylinder |
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| 11. |
Exel1.Ravish ordered a pizza and paid285 inclusive of taxes dR35. Find the tax%. |
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| 12. |
5xy2. Expand(1) 2a(3x + 5y)(4) (-6)(5x-Ty2)(7) (6r3y - 1)(-2x2) |
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Answer» Post only one question at a time. expansion expansion cube root of 729 what is this Garden what is terrace garden science question rational indices |
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| 13. |
.Write equation of x-axis |
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Answer» We know a general equation of a straight line is,y=mx+cWhere c is the intercept of the line on y-axis and m is the gradient of the line. Since intercept of x-axis on y-axis is zero, so c=0. Gradient of x-axis is also zero because it makes an angle zero with itself. So m=tan(theta)=0. Putting these values in the general equation we get,y=0*x+0y=0. Thus we get the equation for x-axis as y=0. can we write (5,0) yes |
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| 14. |
find TSA of The vessel in the form of a hemisphere surmounted by a hollow cylinder diameter is equal to 14 cm height equal to 13 cm |
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| 15. |
Write True (T) or False (F )against each of the following statements:16:24:: 20:30 (b) 21:6:35: 10 (e) 12:18:28:12 |
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| 16. |
If the roots of a quadratic equation be 2 and -3,then write the equation. |
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Answer» Roots of equation are 2 and - 3 We know,Sum of roots = - b/a2 - 3 = - b/a-1 = - b/ab = a Product of roots = c/a2*-3 = c/a-6a = c Equation isax^2 + bx + c = 0ax^2 + ax - 6a = 0x^2 + x - 6 = 0 |
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| 17. |
०. नीy = ARGg€ (1= 1o ,, |
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Answer» (3*-6)(7-2)-22-7+3*(8-3)-18*9-22-7+3(5)=-162-22-7+15=-176 |
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| 18. |
d 1j:â = B 4814 ST ARGT %A A Pt L=== |
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Answer» hit like if you find it useful |
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| 19. |
1(13) Anju's mother is 3 1/2 times as old as AnjuAfter 2 years, Anju's mother will be 3times as old as she will be then. Find theirpresent ages |
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| 20. |
पे - v%[कि .7 & बाग पु ARG T - &E’mvm' VI हल T [Py 4- - ~| Q |
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Answer» sum of angles of quadrilateral is 360°let x be 4th anglethen 60°+70°+120°+x=360°250°+x=360°x=110° |
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| 21. |
बे g ARG QX NT(कि 4,000 रु. पर 3 वर्ष में 10 प्रतिशत की दर से । |
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Answer» SI = P*R*T/100 Given P = 4000, R = 10%, T = 3 Then, Interest = 4000*10*3/100 = 400*3 = Rs 1200 |
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| 22. |
B)26years(D) 50 years)so years(A) 24 f30(B) 26 ri(C)(D)50 |
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Answer» Let father's age = x years. Rohan's age = x-26 grandfather's age = x+20 equation: x+x-26+x+20 =84=>3x =84+6=>3x =90=>x =30 years. Ans: Father's age = 30 years. Option(C) is correct |
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| 23. |
§ _/‘ZS JQI _/\9 fg ) 8 01 ge गए Ayrdurt ‘02z—/\ 8 ‘ _/\g A z 8 A ¢ J.q .S |
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| 24. |
f4°F b+ g 02 + |
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Answer» The minimum value ofatan²θ +b cot²θ is 2√(ab) Here, a = 9 and b = 4 So, 2√(ab) = 2√(9×4) = 12 Arithmetic mean is always greater than or equal to geometric mean. AM ≥ GM or (a+b)/2≥ √(ab) Minimum value of a+b = 2√(ab) Arithmetic mean =9 tan^2θ + 4 cot^2θ Geometric mean =√(9tan^2θ × 4 cot^2θ) tan^2θ = 1/cot^2θ So, Geometric mean =√(9 × 4) = 6 Minimum value = 2× GM = 12 Wrong answer |
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| 25. |
Ohm's law states(a) EL = L-(c) Be =dIdt(b)ER-RI(d)F=ma |
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Answer» E=RIvoltage applied is directly proportional to current |
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| 26. |
A particle is projected vertically up, attains heighth at 2 s and 6 S. The maximum height attained byparticle is(1) 120 m(3) 75 mVA(2) 80 m(4) 60 m12 |
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| 27. |
wice its breadth. What are the length arg tuheThe base of an isosceles tiangleis cm. The perimetd of the tfiof the tfangle is 45 Cm4-Cm15 |
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Answer» given b=4/3 cmp=4 2/15=62/15cmp=sum of all sideslet equal sides be xthen 2x+b=62/152x+4/3=62/152x=62/15 - 4/32x=(62-20)/152x=42/15x=21/15x=7/5cmequal sides are 7/5 cm thanks |
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| 28. |
Evaluate ri |
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Answer» 1^ 39= 1thanksplease like the solution 👍 ✔️ |
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| 29. |
|11].--.,- 4| ! =वक समीकरण 3-3} + 30 =0र।8. जाँच करें कि निम्नलिखित बिन्दुओं में कौन रैखिक समीकरण(i) A (-6,0)(ii) B (0, 10) (iii) C (3,-5)(V) E (-9.5) (vi) F (-3,5) (111) G(-9, -5)||५|| |
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Answer» 1,2,7 is the answer. option 4 not appear clear |
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| 30. |
tuhe Car is toundUy the car to reach the foot of the tower from this point.16. The angles of elevation of the top of a tower from two points at a distance of 4 m and9 m from the base of the tower and in the same straight line with it are complementaryProve that the height of the tower is 6 m |
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| 31. |
ri) 2x2 + x-4-0 |
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Answer» Please like the solution 👍 ✔️👍 |
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| 32. |
Mr. Gupta opened a recurring deposit accountin a bank. He deposited2,500 per month fortwo years. At the time of maturity he got67,500. Find:(i) the total interest earned by Mr. Gupta(ii) the rate of interest per annum. |
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Answer» this is wrong bro answer is correct if you need any clarifications kindly refer this |
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| 33. |
EXAMPLE 36 In two concentric circles, prove that all chords of the outer circle which touchthe inner are of equal length. |
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| 34. |
Find the union and intersection of the following pair of sets:A= {2, 3, 5, 6,7}, B={14, 5, 7, 8} |
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| 35. |
I Splce and the simple eventll the first st die is tossed once.is the probability that tuhe number that comes up is 9?Whs is the probability thot the number comes up is less than 97o coins are tossed together, what are the ch |
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| 36. |
5) Which number comes between 30 and 32 ?31 |
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Answer» 31 comes between 30 and 32. |
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| 37. |
When a number is multiplied by the smallest prime number, the product comesout to be (-*7). Find the number. |
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| 38. |
alta0.The outer length and breadth of a photo frame is 80 cm , 50 cm. If the width ofthe frame is 3 cm all around the photo. What is the area of the picture that will bevisible? |
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Answer» Outer length = 80 cmOuter breadth = 50 cmThickness = 3 cmInner length = 80 - 3 = 77 cmInner breadth = 50 - 3 = 47 cm Area = L * B= 77 * 47= 3619 cm² 3619cm is the answer |
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| 39. |
I f the volume of a right circular cone ofheight 9 cm is 48 π cm, find the diameter of itsbase |
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| 40. |
formed.i) A cubical block of side 10 cm is surmounted by ahere.is the largest diameter that the hemisphere can have? Findthe cost of painting the total surface area of the solid so formed, at[CBSE 2015)lindor orith a hemisphere on onethe rate o5per 100 sq cm. Use π3.14/ |
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| 41. |
72). SimplifyF-1X-412×:/デ[52 × 7-453 × 7 |
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Answer» (5^[-1-2]×7^[2+4])^7/2*(5^[-2-3]×7^[3+5])^-5/2= (5)^[-21/2]x(7)^21 * (5)^[25/2]x(7)^-20= (5)^[4/2]*(7)^[21-20]= (5)^2 * (7)^1= 25*7= 175 ans |
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| 42. |
4-53. The domain of the function f(x)=-2is |
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Answer» how to solve For domainx^2-9 should not be 0 x^2= 9x= +-3R-(+-3)is domain domain of f(x) is R-(+3,-3) |
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| 43. |
¢ Cf—) & 5}3.\ 3,7"‘53& न) कृषि > ¥4\ |
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| 44. |
A die is tossed once.a) What is the probability that the number that comes up is 9?b) What is the probability that the number comes up isless than 9? |
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Answer» A die has 1,2,3,4,5,6. so i) the probability is zero. |
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| 45. |
Describe the problems faced by the Weimar Republic. |
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| 46. |
7. Find the different national numbers between the rational numbers |
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| 47. |
Find ten national numbers between and |
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| 48. |
nstaid isee F1g. 13.10).5. A vessel is in the form of an inverted cone. Itsheight is 8 cm and the radius of its top, which isopen, is 5 cm. It is filled with water up to the brimWhen lead shots, each of which is a sphere of radius0.5 cm are dropped into the vessel, one-fourth ofthe water flows out. Find the number of lead shotsdropped in the vessel.diffeExadayFig. 13.16lindor ofheight 220 cm and base diameter 24 cm |
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| 49. |
17.Prove that sum of the squares of the diagonals of a parallelogram is equal to sum of thesquares of its sides. |
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Answer» In parallelogram ABCD, AB = CD, BC = ADDraw perpendiculars from C and D on AB as shown.In right angled ΔAEC, AC2= AE2+ CE2[By Pythagoras theorem]⇒ AC2= (AB + BE)2+ CE2⇒ AC2= AB2+ BE2+ 2 AB × BE + CE2 → (1)From the figure CD = EF (Since CDFE is a rectangle)But CD= AB⇒ AB = CD = EFAlso CE = DF (Distance between two parallel lines)ΔAFD ≅ ΔBEC (RHS congruence rule)⇒ AF = BEConsider right angled ΔDFBBD2= BF2+ DF2[By Pythagoras theorem] = (EF – BE)2+ CE2[Since DF = CE] = (AB – BE)2+ CE2 [Since EF = AB]⇒ BD2= AB2+ BE2– 2 AB × BE + CE2 → (2)Add (1) and (2), we getAC2+ BD2= (AB2+ BE2+ 2 AB × BE + CE2) + (AB2+ BE2– 2 AB × BE + CE2) = 2AB2+ 2BE2+ 2CE2 AC2+ BD2= 2AB2+ 2(BE2+ CE2) → (3)From right angled ΔBEC, BC2= BE2+ CE2[By Pythagoras theorem]Hence equation (3) becomes, AC2+ BD2= 2AB2+ 2BC2 = AB2+ AB2+ BC2+ BC2 = AB2+ CD2+ BC2+ AD2∴ AC2+ BD2= AB2+ BC2+ CD2+ AD2Thus the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides |
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| 50. |
√2-1+√3-√2+√4-√3+.....+√n-√n-1 show the method |
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Answer» the answer will be √n-1 because other will be cancelled out |
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