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((16b^5)+(8b^7)+(32b^3))÷4b^2=(4b^3)+(2b^5)+8b

=(sinA+cosecA)²+(cosA+secA)²

=sin²A+cosec²A+2sinAcosecA+cos²A+sec²A+2cosAsecA

=sin²A+cos²A+cosec²A+sec²A+2sinA×1/sinA+2cosA×1/cosA

=1+cosec²A+sec²A+2+2

=5+(1+cot²A)+(1+tan²A)

=7+tan²A+cot²A

Identities used:1+tan²A=sec²A

1+cot²A=cosec²A

sin²A+cos²A=1

cosecA=1/sinA

secA=1/cosA

4)-1 and 5)B this is the answer of your questions

Answer:A)0Explanation:First of all cos 172 = -cos 8So now we have= cos 52 + cos 68 - cos 8

Applying Identity,cos A − cos B = −2 sin ½ (A + B) sin ½ (A − B)

Now, cos 52 - cos8, here let's A = 52, B=8cos 52 - cos 8 = -2sin[60/2]sin[44/2]cos52 -cos8 = - sin 22socos 52 + cos 68 + cos172= cos52 + cos68 - cos8= cos52 - cos8 + cos68= - sin22 + cos68but by the complementary relationshipsin 22 = cos68 , (since 22+68 = 90)so finally= -cos 68 + cos 68= 0

newdelhi is right ans D

1.6=y/1.5y=1.6×1.5y= 2.4 is the answer

thank you

2x + 3y =-4.........(1)x - 5y = 11..........(2)(2)×2;2x - 10y = 22......(3)(1)-(3);13y =-26;y=-2then x =1

(radius) I guess......

2x+y =6 .............(i)

Find points on x-axis and y-axis by putting y=0 and x=0

The points are A(3,0) and B(0,6) .Join AB

2x -y +2 = 0 ........................(ii)

here points will be P(-1,0) and Q(0,2) Join PQ

Find the point of intersection of (i) and (ii) by adding

4x =4 or x =1 and y =4.................(iii)

Area of the region below (i) line taking limits from 1 to 3

integrate[6-2x]

6x -x^2 and take limits from 1 to 3

[18 - 9]- [6-1] = 9 -5 =4 square units...................Ans

Area below (ii) line

integral [2x+2] taking limits from -1 to+1

[x^2 +2x] take limits from -1 to+1

[1+2] - [1-2] = 3 +1 = 4 square units.........................Ans

Total area = 4+4 = 8 square units

Thrust is but another name of Force.hence 50N

Average rate of change = 340-68/(10-2)= 272/8 = 34 calories/ ounce

suppose the total no. of worker are x then 40% of X = 0.4x are women and 60% are men = 0.6x

now 40% of women gave vote in favor = 0.4(0.4x) = 0.16x nad 60% of men gave vote = 0.6*(0.6x) = 0.36x

so total votes in favor are = 0.16+0.36 = 0.52x

in % =(0.52x/x)*(100) = 52%

hii

19683

the answer comes out be 59,048

the correct answer is 2186

a large wave that cause destruction when it reaches land and can cause due to earthquake in the surface of the sea.

a large wave that cause destruction

a large wave that cause destruction when it reaches land and can cause due to earth quake in the surface of the sea

the large wave that cause destruction

6y=15y=15/6 =5/2=2.5

(a) 1+2+3+....+20=20*21/2=210(b) 7+14+21+....+140=7(1+2+3..+20)=7*20*21/2=1470(c)-1+6+13+...132suppose total number of terms are nso 132=-1+(n-1)*7133=(n-1)*7n-1=19n=20so sum=(20/2)(-1+132)=10*131=1310

= 3please like the solution 👍 ✔️

√(3+√(27+√(73+8))√(3+√27+9√(3+6= 3

6y = (29)^2 - (23)^26y = 29x29 - 23x236y = 841 - 5296y = 312Y = 52

how explain me

which part you don't understand

next step 3apon 5

next step 3 upon 5

dekho 243 ko 3 power 5 lekh sakte ho ok. ha aur 32 ko 2 power so ab jo bhar -4/5 ander aa jaega power me to 5 cancel ho jaega..

thank you for solving my qouires

6y=15y=15/6 =5/2=2.5

x2 +x=132x2+x-132=0x=11,-12

x² + 5x + 6x² + 2x + 3x + 6x(x+2) + 3 (x + 2)(x+2) (x+3)

x should be greater than -5

please like the solution 👍 ✔️👍

Ty

5×[7+(-6)]=5×7+5×(-6)5×[7-6]=35+5×(-6)5×1=35-305=5