81279 + Interview Questions in Mathematics QA in Mathematics

1.	( - 1 ) ^ { 6 } \times ( - 1 ) ^ { 3 } \times ( - 1 ) ^ { 2 }
Answer» -1 power 6 will be 1-1 power 3 will be -1-1 power 2 will be 1so their product will be -1

Discussion

2.	leadradical Sans aund regaieindicesA61)2195
Answer»

Discussion

3.	2 \frac { 1 } { 2 } \times 1 \frac { 1 } { 2 } \times 5 \frac { 1 } { 2 }
Answer»

Discussion

4.	8/9 \div 6/12
Answer» 8/(3×3)+6/(3×4)=(8×4+6×3)/(3×3×4)=50/36=25/18

Discussion

5.	100 99X: : X : x2फंलन हा... चुागाएंलिए सिद्ध कीजिंए कि (1) >100/'(0)..
Answer»

Discussion

6.	10% more than 90 is(i) 110 (i) 98 (i) 99 (iv) 1001
Answer» 99 because 90 ka 10% 9 hai so 90+9=99 10% of 90=9. 90+9=99

6.

10% more than 90 is(i) 110 (i) 98 (i) 99 (iv) 1001

Answer»

99 because 90 ka 10% 9 hai so 90+9=99

10% of 90=9. 90+9=99

Discussion

7.	lim a sinx-x Sin ax→a2axxa
Answer»

Discussion

8.	Prove that (x- 1) is a factor of both x^99-1 and x^100 -1.
Answer» (x-1)= 0 therefore x = 1 =x^99-1=1^91-1=1-1=0 and =x^100-1=1^100-1=1-1=0 So, it is proved that (x-1) is a factor of these two .

8.

Prove that (x- 1) is a factor of both x^99-1 and x^100 -1.

Answer»

(x-1)= 0 therefore x = 1

=x^99-1=1^91-1=1-1=0

and

=x^100-1=1^100-1=1-1=0

So, it is proved that (x-1) is a factor of these two .

Discussion

9.	\frac{(15)^{-3} \times(-12)^{4}}{5^{-6} \times(36)^{2}}
Answer» (5×5×5×5×5×5×(-12)×(-12)×(-12)×(-12))/(36×36×15×15×15) = (5×5×5×12×12)/(3×3×3×3×3) = 18000/243 If you find this answer helpful then like it.

9.

\frac{(15)^{-3} \times(-12)^{4}}{5^{-6} \times(36)^{2}}

Answer»

(5×5×5×5×5×5×(-12)×(-12)×(-12)×(-12))/(36×36×15×15×15) = (5×5×5×12×12)/(3×3×3×3×3) = 18000/243

If you find this answer helpful then like it.

Discussion

10.	The simplified form of the national expression \left(\frac{x^{2}}{x^{2}-y^{2}}-1\right)\left(\frac{x-y}{y}+2\right) is:\begin{array}{ll}{\text { (A) } \frac{x}{(x+y)}} & {\text { (B) } \frac{y}{(x+y)}}\end{array} \quad(C) \frac{y}{(x-y)} (D) $\frac{x}{(x-y)}$
Answer»

Discussion

11.	\frac{(15)^{-3} \times(-12)^{4}}{5^{-3} \times(36)^{2}}
Answer» answer will be 74.07

Discussion

12.	Solve the followingx - b / x + b = a + b / a - b
Answer» thanks

Discussion

13.	5. Solve b-c,xea-b
Answer» (x-b-c)/a+(x-a-b)/c+(x-c-a)/b=3bc(x-b-c)+ab(x-a-b)+ac(x-c-a)=3abcbcx-b²c-bc² +abx- a²b -ab² +acx -a²c -ac²=3 abcabx+bcx +cax=3 abc+ a²b +ab²+ b²c+ bc²+ a²c+ ac²X(ab+bc+ac)= abc+ a²b +ab²+ abc+ b²c +bc²+ abc +a²c +ac²X(ab+bc+ac)=ab(c+a+b)+bc(a+b+c)+ac(b+a+c)X(ab+bc+ac) =(a+b+c) (ab +bc+ ac)X =(a+b+c) (ab+bc+ac)/(ab+bc+ac)X=a+b+c

Discussion

14.	(d) 2.0228o. if angle is divided between a and B in such way thattanaxtan then sin (a - b) = ?sport in perce'ऋण पर ब्याज का ।प्रतिशत अधिक है?
Answer»

Discussion

15.	Solve the following\frac{x-b}{x+b}=\frac{a+b}{a-b}
Answer»

Discussion

16.	(b) Solve the triangle ABC with a-2, b=213, c= 4.
Answer» We know that SinA/a=SinB/b=SInc/cso heresina/2=sinb/2root 3=sinc/4sina/sinb=1/root 3

Discussion

17.	\left. \begin{array} { l } { 26 \times ( - 48 ) + ( - 48 ) \times ( - 36 ) } \\ { ( - 57 ) \times ( - 19 ) + 57 } \end{array} \right.
Answer»

Discussion

18.	36 \div ( 10 %2B 2 ) %2B 5 \times 6 - 4 \times 8
Answer» 36÷(10+2)+5×6-4×8=36÷12+30-32=3+30-32=1

Discussion

19.	36 \times 1
Answer» 36×1=36 is the simple mulitiplication 36*1 equal to 36 it is right

19.

36 \times 1

Answer»

36×1=36 is the simple mulitiplication

36*1 equal to 36 it is right

Discussion

20.	Observations of some data are $ \frac{x}{5}, x, \frac{x}{4}, \frac{x}{2} $ and $ \frac{x}{3} $ where $ x>0 $ . If the median of thedata is $ 8 . $ Find the value of $ x $ .
Answer» Data is x/5, x/4, x/3, x/2,xMedian =x/38=x/3 x=24

20.

Observations of some data are $ \frac{x}{5}, x, \frac{x}{4}, \frac{x}{2} $ and $ \frac{x}{3} $ where $ x>0 $ . If the median of thedata is $ 8 . $ Find the value of $ x $ .

Answer»

Data is x/5, x/4, x/3, x/2,xMedian =x/38=x/3

x=24

Discussion

21.	( - 36 ) \times ( - 1 ) + ( - 24 ) \div 6
Answer»

Discussion

22.	Show that f:R tends to R is givenby f(x)=-sinx, x€R is neither one-one nor onto
Answer»

Discussion

23.	f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+\ldots+\frac{x^{2}}{2}+x+1
Answer»

Discussion

24.	dy/dx,y=sinx/x
Answer» hit like if you find it useful

Discussion

25.	,,ĺŻ¸ęˇ¸,peiPOR IS
Answer» As, OPQ forms another triangle in PQR,..as per the rule for formation of triangles,length of a side of a triangle < sum of the other two sides, In triangle OPQ, OQ<PQ+OPOP<PQ+OQhence, PQ<OP+OQ

25.

,,ĺŻ¸ęˇ¸,peiPOR IS

Answer»

As, OPQ forms another triangle in PQR,..as per the rule for formation of triangles,length of a side of a triangle < sum of the other two sides,

In triangle OPQ,

OQ<PQ+OPOP<PQ+OQhence, PQ<OP+OQ

Discussion

26.	A87 +38. X= 7 - 134 xy=1 969, CARME CT, *xyty - 12161, xÂ²-xyty? - 11
Answer» root7+root3/root7-root3 x root7 - root 3/root7-root3=(root7+root3)(root7-root3)/(root 7- root3)^2=(root49-root 21+root21+root 9)/7-3=(root 49+root 9)/4=(7+3)/4=10/4

Discussion

27.	Solve: +ax _ by = a2-b2
Answer» x/a + y/b = 2ay + xb = 2ab----------( 1 ) ax - by = a² - b²---------( 2 ) from-----( 1 ) &-------( 2 )multiply ( 1 ) by "a" ( 2 ) by "b" abx + a²y = 2a²babx - b²y = ba² - b³-------------------------------------------------y(a² + b²) = 2a²b - ba² + b³ y(a² + b²) = a²b + b³ y(a² + b²) = b(a² + b²) y = b [ put in -----( 1 )] we get, ay + xb = 2ab a(b) + xb = 2ab xb = 2ab - ab x = ab/b x = a I HOPE IT WOULD HELP YOUPLEASE HIT THE LIKE BUTTON

27.

Solve: +ax _ by = a2-b2

Answer»

x/a + y/b = 2ay + xb = 2ab----------( 1 )

ax - by = a² - b²---------( 2 )

from-----( 1 ) &-------( 2 )multiply ( 1 ) by "a" ( 2 ) by "b"

abx + a²y = 2a²babx - b²y = ba² - b³-------------------------------------------------y(a² + b²) = 2a²b - ba² + b³

y(a² + b²) = a²b + b³

y(a² + b²) = b(a² + b²)

y = b [ put in -----( 1 )]

we get,

ay + xb = 2ab

a(b) + xb = 2ab

xb = 2ab - ab

x = ab/b

x = a

I HOPE IT WOULD HELP YOUPLEASE HIT THE LIKE BUTTON

Discussion

28.	-bbx - ay- a bSolve: ax + by a
Answer» ax=a-b-byx=a-b-by/a← bx-ay=a+bsubstitutingb(a-b-by/a)-ay=a+bab-b²-b²y/a-ay=a+bab-b²-b²y-a²y/a=a+bab-b²-(b²+a²)y=a²+ab-(b²+a²)y=a²+ab-ab+b²(b²+a²)y=-(a²+b²)y=-(a²+b²)/a²+b²y=-1← substituting value of yx=a-b-b(-1)/ax=a-b+b/ax=a/ax=1

28.

-bbx - ay- a bSolve: ax + by a

Answer»

ax=a-b-byx=a-b-by/a←

bx-ay=a+bsubstitutingb(a-b-by/a)-ay=a+bab-b²-b²y/a-ay=a+bab-b²-b²y-a²y/a=a+bab-b²-(b²+a²)y=a²+ab-(b²+a²)y=a²+ab-ab+b²(b²+a²)y=-(a²+b²)y=-(a²+b²)/a²+b²y=-1←

substituting value of yx=a-b-b(-1)/ax=a-b+b/ax=a/ax=1

Discussion

29.	Solve: ax + by = a-band bx-ay = a + b
Answer»

Discussion

30.	A tree is broken at a height of 4 m from the ground. Its top touches the ground at a distance of3 m from the base of the tree. Find the original height of the tree.7.
Answer»

Discussion

31.	सिद्ध कीजिए\sin ^{-1} \frac{3}{5}-\sin ^{-1} \frac{8}{17}=\cos ^{-1} \frac{84}{85}
Answer»

Discussion

32.	125 ^ { 3 } =
Answer» 125 =555

Discussion

33.	125(3overline)
Answer» 125.3333333.........

Discussion

34.	24 x 36 =
Answer» 24×36=864 is the correct answer

Discussion

35.	3. The angle of elevation of the top of a building from the foot of the tower is 30° and the angle ofelevation of the top of the tower from the foot of the building is 60°0. If the tower is 60 m high,find the height of the building.
Answer»

Discussion

36.	\operatorname { sin } ^ { - 1 } \frac { 3 } { 5 } + \operatorname { cos } ^ { - 1 } \frac { 15 } { 17 } + \operatorname { sin } ^ { - 1 } \frac { 36 } { 85 } = \frac { \pi } { 2 }
Answer» sin^-1(3/5) + sin^-1(36/85) = π/2- cos^-1(15/17) => sin^-1(3/5√1-(36/85)² + 36/85√1-(3/5)²) = π/2 - cos^-1(15/17) => sin^-1(3/577/85 + 36/854/5) = sin^-1(15/17)=> sin^-1(375/425) = sin^-1(15/17)=> sin^-1(15/17) = sin^-1(15/17) => L.H.S = R.H.S

36.

\operatorname { sin } ^ { - 1 } \frac { 3 } { 5 } + \operatorname { cos } ^ { - 1 } \frac { 15 } { 17 } + \operatorname { sin } ^ { - 1 } \frac { 36 } { 85 } = \frac { \pi } { 2 }

Answer»

sin^-1(3/5) + sin^-1(36/85) = π/2- cos^-1(15/17)

=> sin^-1(3/5*√1-(36/85)² + 36/85*√1-(3/5)²) = π/2 - cos^-1(15/17)

=> sin^-1(3/5*77/85 + 36/85*4/5) = sin^-1(15/17)=> sin^-1(375/425) = sin^-1(15/17)=> sin^-1(15/17) = sin^-1(15/17) => L.H.S = R.H.S

Discussion

37.	\frac x ^ 3 - x - 24 x ^ 3 %2B x ^ 2 - 36
Answer» As it's a 0/0 formwe diffrentiated it as after diffrentiation it is not a 0/0 then we put the limits

Discussion

38.	36 x5+424 x 5+4
Answer» ((36×5+4)/5)×(5/(24×5+4))=(36×5+4)/(24×5+4)=184×124= 22816

Discussion

39.	(D)000(a)/078यदि a= 2, b= 4,c= 1 तो 2-3bc+4ac का मान ज्ञात करो?1.0(त
Answer» substitute values in given equation answer is 0 a=2, b=4, c=1a^2-3bc+4ac2^2-3×4×1+4×2×14-12+8-8+80 a=2,b=4,c=1a^2-3bc+4ac2^2-3×4×1+4×2×14-12+8-8+80 a=2, b= 4, c= 1a^2 -3bc+4ac= (2)^2-3(4)(1)+4(1)(2)= 4-12+8= 12 -12= 0 a=2, b=4 ,c=1=a^2-3bc + 4ac=2^2-3×4×1+4×2×1=4-12+8=-8+8=0is the correct answer Ans=(2×2)-(3×4×1)+(4×2×1)=4-12+8=12-12Answer =0

39.

(D)000(a)/078यदि a= 2, b= 4,c= 1 तो 2-3bc+4ac का मान ज्ञात करो?1.0(त

Answer»

substitute values in given equation answer is 0

a=2, b=4, c=1a^2-3bc+4ac2^2-3×4×1+4×2×14-12+8-8+80

a=2,b=4,c=1a^2-3bc+4ac2^2-3×4×1+4×2×14-12+8-8+80

a=2, b= 4, c= 1a^2 -3bc+4ac= (2)^2-3(4)(1)+4(1)(2)= 4-12+8= 12 -12= 0

a=2, b=4 ,c=1=a^2-3bc + 4ac=2^2-3×4×1+4×2×1=4-12+8=-8+8=0is the correct answer

Ans=(2×2)-(3×4×1)+(4×2×1)=4-12+8=12-12Answer =0

Discussion

40.	cos2 e[2001]3. Prove that: 1-= sin e.1+ sin e
Answer» sin€ iss lye hum bol rhe h 1- cos^2A/1+sinA=1- (1-sin^2A)/(1+sinA){a^2-b^2=(a+b)(a-b)}=1- (1+sinA)(1-sinA)/(1+sinA)= 1-(1-sinA)= 1-1+sinA=sinA

40.

cos2 e[2001]3. Prove that: 1-= sin e.1+ sin e

Answer»

sin€ iss lye hum bol rhe h

1- cos^2A/1+sinA=1- (1-sin^2A)/(1+sinA){a^2-b^2=(a+b)(a-b)}=1- (1+sinA)(1-sinA)/(1+sinA)= 1-(1-sinA)= 1-1+sinA=sinA

Discussion

41.	71077-289माननन3750Mondayमोहन ने3/150 रू ८ प्रतिशत वाकिर___की दर से पर 3वर्ष के लिए:(RdHd 44 कि U-1चुमा पो078-28818Tuesday
Answer» A=,p(1+r/100)ⁿA=3750(1+6/100)^3A=3750×53/50×53/50×53/50A=4428.81 answer A= 3750×53/50×53/50×53/50A= 4428.82

41.

71077-289माननन3750Mondayमोहन ने3/150 रू ८ प्रतिशत वाकिर___की दर से पर 3वर्ष के लिए:(RdHd 44 कि U-1चुमा पो078-28818Tuesday

Answer»

A=,p(1+r/100)ⁿA=3750(1+6/100)^3A=3750×53/50×53/50×53/50A=4428.81 answer

A= 3750×53/50×53/50×53/50A= 4428.82

Discussion

42.	e of sinsinIS :
Answer» sin^-1(sin3pie/4)=3pie/4

Discussion

43.	5x- 5x 1Group C (3 marks)llowing (69 86)つ·J7至79: -64. 801)3
Answer» please specify your question.

Discussion

44.	In a certain year the population of our country was about 98crore . if it increase by 2% , what will be its population after one year
Answer» population = 98,00,00,000 98,00,00,000 + 2*98,00,00,000/100 = 98,00,00,000 + 1,96,00,000 = 99,96,00,000 thanks but its wrong answer sorry its right answer

44.

In a certain year the population of our country was about 98crore . if it increase by 2% , what will be its population after one year

Answer»

population = 98,00,00,000

98,00,00,000 + 2*98,00,00,000/100

= 98,00,00,000 + 1,96,00,000

= 99,96,00,000

thanks but its wrong answer

sorry its right answer

Discussion

45.	02. cose + sido -p andSeco + coseco =q, Prove thatqCp21)=2p?4. Od
Answer» q(p^2-1) = 2p =>LHS = q(p^2-1) =>sec +cosec [(sin + cos)^2-1 => (sec+cosec) [sin^2+cos^2+2sin.cos -1] = >(1/cos +1/sin) [1+2sin.cos-1] {{identity: sin^2+cos^2=1}} taking LCM of 1/sin + 1/cos=> (sin+cos/sin.cos)[2sin.cos] = >sin + cos /sin.cos* 2sin.cos => 2(sin + cos) = >2(p) {{sin + cos = p :(given in question)}} Therefore 2p i.e. = RHS

45.

02. cose + sido -p andSeco + coseco =q, Prove thatqCp21)=2p?4. Od

Answer»

q(p^2-1) = 2p

=>LHS = q(p^2-1)

=>sec +cosec [(sin + cos)^2-1

=> (sec+cosec) [sin^2+cos^2+2sin.cos -1]

= >(1/cos +1/sin) [1+2sin.cos-1]

taking LCM of 1/sin + 1/cos=> (sin+cos/sin.cos)[2sin.cos]

= >sin + cos /sin.cos* 2sin.cos

=> 2(sin + cos)

= >2(p) {{sin + cos = p

:(given in question)}}

Therefore 2p i.e. = RHS

Discussion

46.	3-5 x10x 1255-7 x65
Answer»

Discussion

47.	Add: 125+/3 and - 5 5 -3
Answer» √(125+√3+(-5√5-√3)5√5+√3-5√5-√3=0

Discussion

48.	1 3Show that sin+sin sin 8517
Answer» Let sin^-1 (3/5) = Q sinQ =3/5 cosQ = 4/5 sin^-1 (8/17) = BsinB = 8/17cos B = 15/17 now ,Q + B = T (let )take both side sin sin (Q + B) = sinT SinQ .cosB +cosQ.sinB =sinTput value ,3/5 x 15/17 + 4/5 x 8/17 = sinT (45 + 32) /85 = sinT sinT = 77/85 T = sin^-1(77/85) Like my answer if you find it useful!

48.

1 3Show that sin+sin sin 8517

Answer»

Let sin^-1 (3/5) = Q sinQ =3/5 cosQ = 4/5

sin^-1 (8/17) = BsinB = 8/17cos B = 15/17

now ,Q + B = T (let )take both side sin sin (Q + B) = sinT SinQ .cosB +cosQ.sinB =sinTput value ,3/5 x 15/17 + 4/5 x 8/17 = sinT (45 + 32) /85 = sinT sinT = 77/85

T = sin^-1(77/85)

Like my answer if you find it useful!

Discussion

49.	Find the values of the following trigonometric ratios:(1) sin(ii)sin 17 π) tan-3
Answer» i) 0.0912, ii) 0.802, thnx

49.

Find the values of the following trigonometric ratios:(1) sin(ii)sin 17 π) tan-3

Answer»

i) 0.0912, ii) 0.802,

thnx

Discussion

50.	Prove that:sin . + sin51 778517
Answer»

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

( - 1 ) ^ { 6 } \times ( - 1 ) ^ { 3 } \times ( - 1 ) ^ { 2 }

leadradical Sans aund regaieindicesA61)2195

2 \frac { 1 } { 2 } \times 1 \frac { 1 } { 2 } \times 5 \frac { 1 } { 2 }

8/9 \div 6/12

100 99X: : X : x2फंलन हा... चुागाएंलिए सिद्ध कीजिंए कि (1) &gt;100/'(0)..

10% more than 90 is(i) 110 (i) 98 (i) 99 (iv) 1001

lim a sinx-x Sin ax→a2axxa

Prove that (x- 1) is a factor of both x^99-1 and x^100 -1.

\frac{(15)^{-3} \times(-12)^{4}}{5^{-6} \times(36)^{2}}

The simplified form of the national expression \left(\frac{x^{2}}{x^{2}-y^{2}}-1\right)\left(\frac{x-y}{y}+2\right) is:\begin{array}{ll}{\text { (A) } \frac{x}{(x+y)}} &amp; {\text { (B) } \frac{y}{(x+y)}}\end{array} \quad(C) \frac{y}{(x-y)} (D) $\frac{x}{(x-y)}$

\frac{(15)^{-3} \times(-12)^{4}}{5^{-3} \times(36)^{2}}

Solve the followingx - b / x + b = a + b / a - b

5. Solve b-c,xea-b

(d) 2.0228o. if angle is divided between a and B in such way thattanaxtan then sin (a - b) = ?sport in perce'ऋण पर ब्याज का ।प्रतिशत अधिक है?

Solve the following\frac{x-b}{x+b}=\frac{a+b}{a-b}

(b) Solve the triangle ABC with a-2, b=213, c= 4.

\left. \begin{array} { l } { 26 \times ( - 48 ) + ( - 48 ) \times ( - 36 ) } \\ { ( - 57 ) \times ( - 19 ) + 57 } \end{array} \right.

36 \div ( 10 %2B 2 ) %2B 5 \times 6 - 4 \times 8

36 \times 1

Observations of some data are $ \frac{x}{5}, x, \frac{x}{4}, \frac{x}{2} $ and $ \frac{x}{3} $ where $ x&gt;0 $ . If the median of thedata is $ 8 . $ Find the value of $ x $ .

( - 36 ) \times ( - 1 ) + ( - 24 ) \div 6

Show that f:R tends to R is givenby f(x)=-sinx, x€R is neither one-one nor onto

f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+\ldots+\frac{x^{2}}{2}+x+1

dy/dx,y=sinx/x

,,ĺŻ¸ęˇ¸,peiPOR IS

A87 +38. X= 7 - 134 xy=1 969, CARME CT, *xyty - 12161, xÂ²-xyty? - 11

Solve: +ax _ by = a2-b2

-bbx - ay- a bSolve: ax + by a

Solve: ax + by = a-band bx-ay = a + b

A tree is broken at a height of 4 m from the ground. Its top touches the ground at a distance of3 m from the base of the tree. Find the original height of the tree.7.

सिद्ध कीजिए\sin ^{-1} \frac{3}{5}-\sin ^{-1} \frac{8}{17}=\cos ^{-1} \frac{84}{85}

125 ^ { 3 } =

125*(3*overline)

24 x 36 =

3. The angle of elevation of the top of a building from the foot of the tower is 30° and the angle ofelevation of the top of the tower from the foot of the building is 60°0. If the tower is 60 m high,find the height of the building.

\operatorname { sin } ^ { - 1 } \frac { 3 } { 5 } + \operatorname { cos } ^ { - 1 } \frac { 15 } { 17 } + \operatorname { sin } ^ { - 1 } \frac { 36 } { 85 } = \frac { \pi } { 2 }

\frac x ^ 3 - x - 24 x ^ 3 %2B x ^ 2 - 36

36 x5+424 x 5+4

(D)000(a)/078यदि a= 2, b= 4,c= 1 तो 2-3bc+4ac का मान ज्ञात करो?1.0(त

cos2 e[2001]3. Prove that: 1-= sin e.1+ sin e

71077-289माननन3750Mondayमोहन ने3/150 रू ८ प्रतिशत वाकिर___की दर से पर 3वर्ष के लिए:(RdHd 44 कि U-1चुमा पो078-28818Tuesday

e of sinsinIS :

5x- 5x 1Group C (3 marks)llowing (69 86)つ·J7至79: -64. 801)3

In a certain year the population of our country was about 98crore . if it increase by 2% , what will be its population after one year

02. cose + sido -p andSeco + coseco =q, Prove thatqCp21)=2p?4. Od

3-5 x10x 1255-7 x65

Add: 125+/3 and - 5 5 -3

1 3Show that sin+sin sin 8517

Find the values of the following trigonometric ratios:(1) sin(ii)sin 17 π) tan-3

Prove that:sin . + sin51 778517

100 99X: : X : x2फंलन हा... चुागाएंलिए सिद्ध कीजिंए कि (1) >100/'(0)..

The simplified form of the national expression \left(\frac{x^{2}}{x^{2}-y^{2}}-1\right)\left(\frac{x-y}{y}+2\right) is:\begin{array}{ll}{\text { (A) } \frac{x}{(x+y)}} & {\text { (B) } \frac{y}{(x+y)}}\end{array} \quad(C) \frac{y}{(x-y)} (D) $\frac{x}{(x-y)}$

Observations of some data are $ \frac{x}{5}, x, \frac{x}{4}, \frac{x}{2} $ and $ \frac{x}{3} $ where $ x>0 $ . If the median of thedata is $ 8 . $ Find the value of $ x $ .

125(3overline)