Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

7. The following table gives the number of different fruits kept in a hamperType of fruit Mangoes Apples Oranges CoconutsPomegranatesNumber263021Represent the above data by a pie chart.Hint. Total number of fruits 90.

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2.

P(B)Ex, (3) A eand is drawn from o well shufled pask of S2 playing eards. Find the(i) a face cant6card is drawn from a well shuftled pack of 52 pprobability of each event. The card drawn is (i) a red catrt

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i) number of red cards = 26. Probability of a red card = 26/52 = 1/2ii) numbe of face cards = 12Probability of a face card = 12/52= 3/13Please hit the like button if this helped you

3.

5* = x²-1. The given equation will have :

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there is no solution for the above equation because always 5^x will be greater than x^2-1.

4.

реореж96рео (- 1410%)

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cosec(-thita) = -cosecthita (thita = acute angle)

Cosec(-1410) = -cosec1410

= -cosec(360*3+330)

= -cosec(330)

= -[-cosec(270+60)]

= +[sec60]

= +2

5.

given equation.3-3x-7x+ 2 2x-3Solve:

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6.

The sum of two numbers is 2490. If65% of one number is equal to 8.5%of the other. Then the numbers are:a) 1411, 1079 b) 1410, 1079c) 1411, 1078 d) 1410,.1078

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Suppose numbers are x and y x + y = 2490 6.5% of x = 8.5% of y 6.5x = 8.5y 13x = 17y x = 17y/13 17y/13 + y = 2490 30y/13 = 2490 y = 83×13 = 1079 x = 2490 - 1079 = 1411

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7.

Ex. 14. cosec(-1410)

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8.

\operatorname { cosec } ( - 1410 ^ { \circ } )

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9.

Find the value of trigonometric function cosec(-1410°)

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10.

दि पहले / प्राकृत संख्याओं का योग § 1+ पहले # प्राकृत संख्याओं के वर्गों का योग 5, तथा पहले ॥प्राकृतसंख्याओंहों का योग 55 हो, तो सिद्ध कीजिए कि-- मै953 =84(1+8S,) (NCERT)

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11.

1o If s, S and S, are the sum of firstnatural numbers, their squares and theircubes respectively then show that9S22-s, (1+8S,).

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12.

Joseph kept 26 eards in a cap, bearing one English alphabet on each card. Ongcard is drawn at random. What is the probability that the card drawn is a vowedcard ?

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No. of event= 5 ( no. of vowel)Total event=26P(E)=5/26

13.

) Total surface area of a solid hemisphere is 675π sq. cm Find the curved surface area of ttie solidhemisphere

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14.

ULTEUTUthe value of b for which (2x + 3) is a factor of 2x+ 9x2-x-b.ia

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15.

-an SsDAcles ttie, tha vetticalamgle

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Y u had written x 2 times

because it is isosceles triangle..so 2 angles will be same

16.

Eu.mple is ; Solve the following paa esequitions by ted cǐ4 thrm o a p

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17.

'i1.Ifthettieratio of A.M. and G.M. of two positive numbers a and b is m : n, then prove that:hunbels.prov ethat:a:b-(m+vm.nz)(m-

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AM of number a and b = (a + b)/2 GM of number a and b = √ab

Here, AM : GM = m : n (a + b)/2 : √ab = m : n (a + b)/2√ab = m/n Applying componendo and dividendo rule,(a + b + 2√ab)/(a + b - 2√ab) = (m + n)/(m - n)(√a² + √b² + 2√ab)/(√a² + √b² -2√ab) = (m + n)/(m - n) (√a + √b)²/(√a - √b)² = (m + n)/(m - n) take square root both sides,( √a + √b )/(√a - √b) = √(m + n)/√(m - n) again applying componendo and dividendo,( √a + √b + √a - √b)/(√a + √b - √a + √b) = {√(m + n) + √(m - n)}/{√(m + n) - √(m - n) }2√a/2√b = {√(m + n) + √(m - n)}/{√(m + n) - √(m - n) }√a/√b = {√(m + n) + √(m - n)}/{√(m + n) - √(m - n) }taking square both sides, a/b =[{√(m + n) + √(m - n)}/{√(m + n) - √(m - n) }]²a/b = {m + n + m - n - 2√(m² - n²)}/{m + n + m - n -2√(m² - n²)}a/b = {2m + 2√(m² - n²)}/{2m - 2√(m² - n²)}a/b = {m + √(m² - n²)}/{m - √(m² - n²)}

hence, a : b = m + √(m² - n²) : m - √(m² - n²)

18.

(i) 482 +8s

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4s(s+2) that is a answer

4s^2+8s4s(s+2) is the factor

it is the right answer of x

4s(s+2) is the correct answer

4s² + 8s= 4s(s+2)is the factor of the given equation.

4s(s+2) is the best answer

4s(s+2)that is a correct answers

4s(s+2) is the best answer

4s(s+2) is the correct answer

4s (s+2) is the correct answer.

4s(s+2)is is the best answer

4s(s+2).....right answers.....

4S ( S + 2 ) is answer

4s(s+2) is the correct answer

answer hoga 4s(s+2) it's the answer

4s(s+2) is the correct answer

4s(s+2) 4s=0 s+2=0 s=0/4. s= -2 s=p

19.

4. Locate V8 on the number line.

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20.

14. Locate V8 on the number line.

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21.

8s. Find the Painil, it the compounannuall atinterest cothe

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thanks

22.

How to know that any given equation of ellipse is of vertical or horizontal ellipse?

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Ans :- Wheneverthelarger number (a2) is underneaththex, then it isa horizontal ellipse. (You can remember this becausethex-axis isthe horizontal axis.) 2)Tell ifthisellipseishorizontal orverticalandfindits center point,a, and b. Now we need to decide if thisellipseisvertical or horizontal.

23.

-9x2 x=-2

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-9×2x=-22x=-2/-9x=0.222/2x=0.11

24.

(9x2-4) Bx + 2)

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9x^2 - 4 = (3x+2)(3x - 2)So, (9x^2 - 4)/(3x+2)= [(3x+2)(3x-2)] / (3x +2)= 3x - 2

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25.

factorisation of 9x2-64

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9x^2-64(3x)^2-(8)^2(3x+8)(3x-8)thanks

26.

1. 9x2-16y

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9x^2-16y^2= (3x)^2-(4y)^2

Formulaa^2-b^2= (a+b)(a-b)Herea= 3xb= 4ySo(3x+4y)(3x-4y)Please like the solution 👍 ✔️👍

why 9x^2 becomes 3x^2

27.

Find the difference in the place value of both 8s in number 819802.

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800000 - 800

= 799,200

wrong answer

28.

cos(e^x %2B log(x, 10))

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29.

factories 3x2 -3x

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=3x2-3xFactorise, take 3x common=3x(x-1)

30.

(४) का मान होगा न Rx=(3+ 18) हो तो (४ * 1

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31.

what is factories

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Ans :- A factory or manufacturing plant is an industrial site, usually consisting of buildings and machinery, or more commonly a complex having several buildings, where workers manufacture goods or operate machines processing one product into another.

32.

Factorise :Y. Rx - 16

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8(x+2y) is the answer

8 × x +8×2×y =8(x+2y)

33.

थे रारहरगमटे| र्प्ग्ब उप ०्ण्न्ट बनाओ (्ण| == x\rx-cot(Z गा न

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LHS = cos(3π/2 + x).cos(2π+x)[cot(3π/2 -x) + cot(2π+ x) ]

we know, cos(3π/2 + x) = sinx cos(2π+x) = cosx cot(3π/2 -x) = tanx cot(2π+x) = cotx, use this here,

= sinx.cosx[tanx + cotx ]= sinx.cosx [sinx/cosx + cosx/sinx]= sinx.cosx[(sin²x + cos²x]/sinx.cosx = (sin²x + cos²x ) = 1 = RHS

34.

10. Fnd the roots of the equationrx-3 3 0,3)

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x-1/x-2+x-3+x-4 =3 1/3x-1/3x-9 = 10/3x-1/3(x-3) =10/3x-1/x-3 = 10x-1= 10(x-3)x-1 = 10x-3010x-x = 30-19x= 29x = 29/9

35.

0.2...600 72- आ 32

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1. cos(A+B) = cosA cosB - sinA sinB.2. cos(A - B) =cosA cosB + sinA sinB.3. sin(A+B) = sinA cosB +cosA sinB.4. sin(A - B) = sinA cosB - cosA sinB.

lets say A+B = C and A-B = DAdd equations of number (1) and (2) , i.e. (1) + (2) ->cos C + cos D = 2 cos [(C+D)/2 ] cos [ (C-D)/2 ]and Subtract equation of number (4) from (3), i.e. (3) - (4) ->sin C - sin D = 2 cos [(C+D) /2 ] sin[(C- D) /2]

so cos 7x + cos 5x = 2 cos(12x/2) cos ( 2x/2)and sin 7x - sin 5x = 2 cos(12x/2) sin ( 2x/2 )

(cos 7x + cos 5x)/sin 7x - sin 5x = cos(x)/sin(x)= cot(x).

36.

d)Factorise the expression and divide 12xy (9x2-16y2) ÷4xy (3x+4y)

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12xy(3x-4y)(3x+4y)------------------------------4xy(3x+4y)

=3(3x-4y)

37.

Solve 9x-5(2x-3) = 1-2x and verify the result.

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38.

9x2+24xy+16y2

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9x²+24xy+16y²

= (3x)²+2*(3x)*(4y) +(4y)²= (3x+4y)²

39.

2.The eccenticity of the ellipse 9x2 +16y2 = 144

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40.

11.Show that (4/3-3/4y)2+2xy= 16/9x2 +9/16y2

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thanks

41.

14. If 3x + 4y = 16 and xy = 4; find the value of9x2 16y2mher T

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Given (3x + 4y) = 16 andxy = 4

(3x + 4y)^2 = 9x^2 + 16y^2 + 24xy

16*16 = 9x^2 + 16y^2 + 24*4

9x^2 + 16y^2 = 256 - 96= 160

42.

Two numbers are in the ratio 5:6.8subtracteted from each of the numbers, the 12,mes 4:5. Find the numbers.[NCERT Exemplar

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Let the two no be x and ytherefore x / y = 5 / 66 * x = 5 * y6 * x - 5 * y = 0 * 5 30 * x - 25 * y = 0..................(i)also (x - 8)/(y - 8) = 4 / 55 * x - 40 = 4 * y - 325 * x - 4 * y - 8 = 0 *630 * x - 24 * y - 48 = 0 .....................(ii)subtracting (i) from (ii)y - 48 = 0y = 48putting y = 48 in x/y = 5/6x/48 = 5/6x = 5 * 48 / 6x = 5 * 8x = 40therefore the two numbers are 40 and 48

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I don't get it pls explain deeply

43.

10. In Fig. 4.103, III m and nil p. If Z1 = 60°, thenprove that 22 = 2 21.(CCE 16]

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angle 1 and angle 3 are equal because they are corresponding.And angle 3 and 2 are Co-interior so angle 3 + angle 2=180* . so angle 2 = 120* .Half of 120* is 60*(angle 1)

44.

factories x³_3x²_9x_5

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45.

factories 6xy-4y+6-9x

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6xy - 4y + 6 - 9x= 6xy - 4y - 9x + 6= 2y(3x - 2) - 3(3x - 2)= (2y - 3)(3x - 2)

46.

factories 4psqare - 9qsquare

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4p²-9q²(2p)²-(3q)²

a²-b²=(a-b)(a+b)

(2p)²-(3q)²=(2p+3q)(2p-3q)

47.

17. Solve for x.(9x 18)°

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The given figure is regular pentagon.

So, all angles must be equal.

We know sum of all angles in pentagon is 540°.

5 × ( 9x - 18°) = 540°

9x - 18° = 540°/5

9x - 18° = 108°

9x = 108° + 18°

9x = 126°

x = 126°/9

x = 14°

So, each angle is 9x - 18° = 9 ×14 - 18

= 108°

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48.

solve :9x+x-3x

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7x is the best answer

7x is the correct answer

(9+1-3) x = (10-3)x = 7x is the proper answer

7x is the proper answer

9x+x-3x = 10x- 3x= 7x

49.

). Solve the following -(ii) 45x2+9x

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hit like if you find it useful

thanks

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50.

19. The polynomials 9x + 3x2 - 13 and 2x? -5x + a are divided by (x - 2). The remainder ineach case is the same. Find the value of a.

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