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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
26. 501४८ (म्भाधान करवा) £Ix—5y—4=(Ix=2y+7 |
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| 2. |
route 8 to the power 10 + 4 to the power 10 whole divided by 64 square + 4 to the power 9 into 6 |
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| 3. |
17. In the given figure, AABC is right angled at B. ACDE and BCGF areproilattheUppositeanglesare equalsquares. Prove that(ii) AG BDMathematics-IX408 |
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| 4. |
CICLUL CUVULCH0003. In the brackets given below, pair of roman numbers are shown. In how manypairs, is the difference between its numbers an even number?(VII, III) (IX, III) (IV, I) (V, II) (X, VI) (IX, VIII) (III, IX) (I, X) |
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Answer» In two pairs difference in between its no. an even number |
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| 5. |
A 7cmB8. BD is one of the diagonals of a quad. ABCD. IfALBD and CMBD, show thatar(quad. ABCD) = 2 × BD × (AL + CM) |
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| 6. |
Given,ALL BD, CMä¸BD, BD = 14 cm,CM = 7 cm, AL = 5 cm |
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| 7. |
10. A and b are the points (a, 0) and (-a, 0)respectively, A point P moves Buch that<APB = 900, The locus of P is(a) xy 2a2(c) x2-y2 = a2d)x2 + y2 = a2/2 |
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Answer» let the point be p (x,y) slope of (x,y) and (a,0) => (y-0)/(x-a) = y/(x-a)slope of (x,y) and (-a,0)=> (y-0)/(x+a) = y/(x+a) now , product of slopes should be -1 since the angle is 90° so, y/(x-a)*y/(x+a) = -1=> y²/(x²-a²) = -1=> y² = a²-x²=> x²+y² = a² option b |
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| 8. |
3. In Fig. 6.53,ABD is a triangle right angled at AandAC丄BD. Show that(i) AB=BC. BD(ii) AC2-BC: DC(iii) AD-BD. CD |
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| 9. |
5. BD is one of the diagonals of a quad.ABCD. If AL BD and CM BD,show thatar (quad. ABCD)Dx (AL+CM). |
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| 10. |
1. Write down the following rational numbers as integers(a) 4(b) 134(c)(d) -1712. Identify the rational numhe)on |
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Answer» a) -4b) -13c) 4d)-17e) -12 thank...bro |
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| 11. |
A solid is in the shape of a cone standing on a hemisphere with both their radi beingI cm and the height of the cone is equal to its radius. Find the volume of the solidandin terms of T |
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| 12. |
UXXXIXIX,XXIV,Complete the following.a) V,, VII,b)_, XXII,c)-, XXXIV, XXXV,d) IX, Xe) 1,-, XIII,, IV. |
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Answer» a)VI,VII,X,XI,XIIb)XXI,XXIII,XXV,XXVI,XXVIIc)XXXIII,XXXVI,XXXVII,XXXVIII.d)XI,XII,XIVe)II,III,V,VI,VII. |
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| 13. |
CP(b) Factorise :-492-962-16c2 +24bc(c) In the given diagram 'O' is the centre of the circle and AB (CD.AB-24 cm and distance betweenthe chords AB and CD is 17 cm.If the radius of the circle is 13 cm, find the length of the chord CD? |
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| 14. |
16÷4+4×5 |
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Answer» =4+4 x5=4+20=24 is the answer 24 is the right answer ap is question ko BODMAS rule se lagao ge = 4+4 x 5 = 4+20= 24 this is the correct answer 24 is the right answer 4+4*54+2024is right answer 24 is the correct answer 24 is the right answer 24 is the right answer 24 is the correct answer.... 24 is the right answer. plz like my answer 24 is the right answer by bodmas=4+4×5 = 4+20 = 24 24 is the correct answer 24 is the correct answer of the given question 4+4*524is correct answer 24 is the answer of the following 16÷4+4×54+4×54+20=24 4+4×54+2024 is the answer 16÷4+4×5=4+20=24 is the correct answer 24 is the right answer 24 is the correct answer |
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| 15. |
. In parallelogram ABCD, the angles A and Care obtuse. Points X and Yare taken on the dingonal BD Buch that the angles ZXAD and AYCB areright nngles, prove that XA = YC.Triangles Congruence of Triangles407 |
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| 16. |
how is the net of the following solid shape related to its property?A.cuboid B.triangularC.cube |
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Answer» ggggggghggggghhhhgggggggggggghhhhhhhhhhhhhhhhgggg hey what is this ? this type answer this aap given |
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| 17. |
(2y + 2 x + y) (43)de 5 , 13 4 17 beFind the value of x + y Ansio)Q3. 217 9-3 |
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| 18. |
Rz ol ŕ¤ŕ¤ż 3+2+5 |
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Answer» Maan lo ki 3 + 2√5 parimaye hai to 3 + 2√5 = k , √5 = (k - 3)/2 To bum jante hai ki √5 aparimaye hai aur (k-3)/2 parimaye hai . Jo humari kalpana ke hisab se galat hai so, √5 aparimaye. |
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| 19. |
(vii) 2x+y=17Ix+2y=11 |
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| 20. |
(16-4)(5-3)âŹ16-4(5-3) |
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Answer» (16 - 4)(5 - 3) = 12*2 = 24. 14 - 4(5-3) = 14 - 4*2 = 14 - 8 = 6 |
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| 21. |
52. The total surface area of a solid cylinderis 231 cm2. If the curved surface area of2this solid cylinder is 3 of its total surfacearea, find its radius and height. |
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| 22. |
6. Find the area of the given figure, if BCa, BDb, DE-C |
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| 23. |
In the given figure, if AC BD, then prove that AB CDB- |
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| 24. |
1 work out the following BubstractionProbleme. Dand check your oner.1 1000-356 |
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Answer» 644 is the correct answer 644 will nbe the correct answer 644 is the correct answer 1000-356644check✔644+356 =1000 Hence answer verified 1000-356=644 is the answer |
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| 25. |
Sec HonL 5 marks each)a) In a quadrilatera AB c Dand carelateral ABCD, Do and cLD and ic respectiveand co arebisectorsrove that.. LcoDt difterent |
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Answer» Angle COD= 1800- 1/2angle C-1/2 angle D=1800-1/2(angle C+D)----------(1) Angle (A+B+C+D)=3600 AngleC+D= 3600 - AngleA- angle B--------------(2) Substituting (2) in (1) Angle COD= 1800-1/2(3600- angle A- Angle B) Angle COD= 1800-1800+1/2 Angle A + 1/2 Angle B= 1/2(Angle A+ Angle B) |
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| 26. |
7. ABCD is a parallelogram. Find x, y and z.250+Fig. Q.7Dand |
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Answer» y = 69° X = 55°Z = 111°This is the correct answer for this question Thank you |
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| 27. |
Solve the following pair of linear equations.3x+4y-10 and 2x-2y 217. |
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| 28. |
Solve the following equations.3x-y=7; x + 4y = 11 |
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Answer» 3x - y = 7......(1)x + 4y = 11......(2) Multiply eq(1) by 4 and add eq(2)12x - 4y = 28x + 4y = 11 13x = 39x = 36/13 = 3 Put value of x = 3 in eq(1) 3*3 - y = 79-7 = yy = 2 Value of x = 3, y = 2 |
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| 29. |
D211.In the given figure ifline segments POand RS intersect at point T, such thatPRT = 40°, ZRPT = 95º andZTSQ = 75°, find 2 SQT.SOS |
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| 30. |
Fig.o.3gIn Fig. 6.42, if lines PQ and RS intersect at point T, such that L PRT = 40°,L RPT = 95。and TSQ = 75°, find SQT. |
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Answer» Where is the figure? Ok |
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| 31. |
drawn out into a wire of diaellllIA solid cube of metal each of whose sides measures 2.2 cm is melted to form a cylindricalwire of radius 1 mm. Find the length of the wire so obtained.ho dud out to sink a well which is 20 m deep and has |
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Answer» Length of the edgebe 2.2 cm=aVolume of the cube=a³=(2.2)³=10.648cm³ Volume of the wire=πr²hRadius = 1 mm = 0.1 cm volume of cube = volume of wire height=volume/πr²=10.648×7/22×0.1×0.1=338.8cm |
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| 32. |
6px-2qy+3rz;6qy-rz-11px;10rz-2px-3qy |
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Answer» 6px-2qy+3rz, 6qy-rz-11px, 10rz-2px-3qy=6px-11px-2px+6qy-2qy-3qy+3rz-rz+10rz= 6px-13px+6qy-5qr+3rz+9rz=-7px+qr+11rz=qr+11rz-7px |
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| 33. |
52. Observe the following solid shape52Which one of the following is the topview of the given solid? |
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Answer» from top view we can see only 4 squares so (4) is the answer. sure?? |
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| 34. |
19. In the Fig., solid consists of a cylindrical sectionof length 6.5 cm and surmounted by a cone at oneend, a hemisphere at the other end. Given thatcommon radius is 3.5 cm and total height of solidis 12.8 cm, find the volume of solid.6.5 cm -3.5 cm 112.8 cm |
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Answer» data 36 cm and divide by 3.5 cm is equal to 12.8.18 she is equal to answer will come |
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| 35. |
7, what should be added toto get 18 ? |
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| 36. |
What should be added to 7 to get 18? |
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| 37. |
7. What should be added to 7 to get 18? |
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| 38. |
et of radius 4 em, a circle of radius 3 cm is removed. Find the area, of the remaining sheet. (Take π=3.14) |
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Answer» Area of the circle with radius 4 cm = πr² = π(4)² = 16 π cm² Area of the circle with radius 3 cm which is removed = π(3)² = 9π cm² Remaining area = 16π - 9π = 7π = 7 x 3.14 = 21.98 cm² |
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| 39. |
39. Some hemispherical shells are made by melting a solid cylindrical metal rod of radius8 em and height 57 cm. If the outer and inner radius of the hemispherical shell is 3 cmand 2 em respectively, what could be the number of shells made?(1) 100(4) 133 |
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Answer» 114. |
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| 40. |
p-3-If x =hptq-Jp-q , then prove that q?-2px +q=0. |
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Answer» X= √p + q + √p - q / √p + q - √p - q rationalizing x = 2p + √p² - q² / 2q = p + √p² - q² / q ⇒ xq - p = √p² - q² squaring both sides ⇒ q²x² + p² - 2qxp = p² - q² ⇒ q²x² -2pqx +q² = 0 ⇒ q( qx²-2px + q ) = 0 therefore ans = 0 |
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| 41. |
19. The graph of the wo equations3x4y-7-0and6x + 8y-14 0 are(1) One and unique (2) Paraliel(3) Intersect(4) of these |
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Answer» option 1because a1/a2=b1/b2=c1/c2 |
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| 42. |
4. In Fig. 3.42, if lines PQ and RS intersect at point T, such that 4PRT0and < TSQ750, find 2 SQT. |
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Answer» Given: ∠PRT= 40°, ∠RPT=95°, ∠TSQ=75° In△PRT,∠PTR+∠PRT+∠RPT=180°[sum of interior angles of a triangle is180°].⇒∠PTR+40∘+95∘=180∘⇒∠PTR+135∘=180∘⇒∠PTR=180∘−135∘⇒∠PTR=45∘⇒∠QTR=∠PTR=45∘(vertically opposite angles) In△TSQ,∠QTS+∠TSQ+∠SQT=180∘[sum of interior angles of a triangle is180∘].45∘+75∘+∠SQT=180∘⇒120∘+∠SQT=180∘⇒∠SQT=180∘−120∘⇒∠SQT=60∘Hence, ∠SQT=60∘ hit like if you find it useful |
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| 43. |
6. By what number should0 be divided to get18 |
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Answer» ATQ -55/18 ÷ (X) = -22/9 => X = (-55/18)/(-22/9) = 5/4. |
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| 44. |
11. What should be added to 7 to get 18? |
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| 45. |
11. What should be added to 7to get 18? |
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Answer» 18- 38/5 will give you answer 52/5 is the correct answer of the given question 58 or 5 is the answer 52/5 is the right answer |
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| 46. |
Find the equation of a line passing through(-1, 3) and(6) parallel to x-axis (ii) parallel to y-axis.(ii) is neither parallel to x-axis nor to y-axis. |
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Answer» U've may b posted another solution bcz it is not the correct answer |
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| 47. |
The Coordinates (2,0) (-3,0) (4,0) are lies ona) Y-axis b) X-axis c) On both axis d) |
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Answer» The given coordinate (2,0) , (-3,0) (4,0)have x - axis only the y - coordinate is always 0. So, given coordinate are only in positive and negitive x - axis therefore , option (b) x - axis is correct |
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| 48. |
7.The point(-6,0) lies on..axisa).y-axis b) x-axis c)both axes d)none of these. |
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Answer» option B is the answer |
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| 49. |
25. A metallic cylinder has radius 3 em and height 5 cm. To reduce itsweight, a conical hole is drilled in the cylinder. The conical hole has aradius of cm and its depth is % cm. Calculate the ratio of the volumeof metal left in the cylinder to the volume of metal taken out in conicalshape. |
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| 50. |
LF+FEED2 (ABBC+AC)T17. ABCD is a parallelogram in whelogram in which bisectors of ZA and ZC meet the diagonalBD at P and Q respectirvely Prove that PCOA is a parallelogram.IS. ABCD is a parallelogram and EF BD. R is mid point of EF. Prove thatE C |
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Answer» Since diagonal of a square bisects the vertex and BD is the diagonal of square ABCD CBD=CBD=45° Given :EF || BD ⇒ ∠CEF = ∠CBD = 45° and ∠CEF = ∠CDB = 45° (corresponding angles) ⇒ ∠CEF = ∠CFE ⇒ CE = CF (sides opposite of equal angles are equal) .......(1) Now BC = CD (Sides of square) ........(2) Subtracting (1) from (2) we get ⇒ BC – CE = CD – CF ⇒ BE = DF |
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