Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Solve the following simultaneous equations:1/x+1/y= 12;3/x-2/y=1

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let 1/x = a and 1/y = bso Equation will be,a + b = 12 ......(1)3a - 2b = 1 ......(2)Eliminating b by 2×(1) + (2)2a + 2b = 243a - 2b = 1

5a = 25a = 5so, b = 12 - a = 12-5 = 7so x = 1/5 and y = 1/7

2.

2. Which term of the AP 21, 18, 15is zero?

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3.

ezuotivunOlead rati3 0

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4.

4. Write the remainder, if twice of (5b +a) is subtracted from 3(a +5b)(1) 5(a +5b) (2) 5(5b-a) (3) 5b +a (4) O

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5.

(1) 3a + 5b = 26: a + 5b = 22

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Explanation : 3a + 5b = 26 a + 5b = 22 3a + 5b - a - 5b = 26 - 22 2a = 4 a = 2 6 + 5b = 26 5b = 20 b = 4

Solution : a = 2 , b = 4

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6.

15ing rati(5) Calculate the area of the triangle shown.semD

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tan45=x/4-x1=x/4-x4-x=x2x=4x=2area=1/2(b)(h) =1/2(4)(x) =1/2(4*2) =1/2*8 =4 sq cm

7.

Find the cost of carpeting a room 13 m by 9 m with a carpet ofwidth 75 cm at the rate of Rs. 105 per metre.

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8.

04-SHOW THAT (X2) IS A FACTOR OF F(X) = 2X-3X 17X+30

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9.

26. If \vec{a} |=2, \vec{b} \}=7 \text { and }(\vec{a} \times \vec{b})=(3 \hat{i}+2 \hat{j}+6 \hat{k}), find the angle betweena and b.

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10.

4 + 4.44 + 44.4 + 4.04 + 444 का मान होगा-(a) 472.88(b) 495.22(c) 500.88(d) 477.2

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4 + 4.44 + 44.4 + 4.04 + 444

= 448 + 8.48 + 44.4

= 448 + 52.88

= 500.88

(C) is correct option

11.

6.A library has to accommodate two different types of books on a shelf. The books are 6and 4 cm thick and weight 1 kg and 1 kg each, respectively. The shelf is 96 cm long anatmost can support a weight of 21 kg. How should the shelf be filled with the books oftypes in order to include the greatest number of books? Make jt as an LPP and solve itgraphically.

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12.

(3a+5b) (3a-5b)

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6 a -10b I think that it is if it is not I am sorry

(3a+5b)(3a_5b(3a+3a)(5b_5b)6a_b

13.

( x v ) ( 5 x + 2 y ) ( 5 x - 2 y ) = 25 x ^ { 2 } + 4 y ^ { 2 }

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14.

3a+5b=26,a+5b=22

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nice

15.

3a + 5b = 26: a + 5b = 22

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3a + 5b = 26......(1)a + 5b = 22........(2)

Subtract eq(2) from eq(1), we get

2a = 4a = 4/2 = 2

Put value of a = 2 in eq(1)3*2 + 5b = 265b = 26 - 65b = 20b = 20/5 = 4

Value of a = 2, b = 4

16.

3a+5b = 26: a + 5b = 22

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17.

-8*x/3 %2B x %2B 7=-5*n/2 %2B 17/6

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x + 7 -8x/3 = 17/6 - 5x/2

7 - 17/6 = 8x/3 - 5x/2 - x

(42-17)/6 = (16x - 15x)/6 - x

25/6 = x/6 - x

25/6 = (x - 6x)/6

25/6 = -5x/6

x = -5

18.

3a + 5b = 26; a + 5b = 22

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3a+5b-a-5b=26-22=42a=4a=26+5b=26 5b=26-6=20b=4

19.

(1) 3a + 5b = 26; a + 5b = 22

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Explanation : 3a + 5b = 26 a + 5b = 22 3a + 5b - a - 5b = 26 - 22 2a = 4 a = 2 6 + 5b = 26 5b = 20 b = 4

Solution : a = 2 , b = 4

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20.

-8*x/3 %2B x %2B 7=-5*x/2 %2B 17/6

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21.

15 %2B 17

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So(+15)-(-17)= 15+17= 32thanks

+15-(-17)=15+17=32 is the answer

32 is th best answer

15 + 17 (- *- =+)=32

Know, =(+15)-(-17)=(+15)+17=32

given ,15-(-17)=15+17=32

22.

(Q.9 Find the value of A and B7 A-B 726

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49 was the right answer

So A= 3B= 4as 73-47= 26

The value of A is 3 and B is 4

A=3B=4THEN 73-74=26

73- 4726 is the best answer

a=3b=4

26 is the right answer

49 is right answer of this question

73-47=26so A=3 and B=4

59 is correct answer

23.

Bhavani tosses a2 coin and a5 coin simultaneously. what is the probability that shegets at least one tail?

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probability (getting a tail)=1/4

24.

3.)Carlos is arranging books on shelves. He has 24will have the same numbers of novels and autobiographies. Hbooks on shelves, what are the possible numbers of shelves Carlos will use?novels and 16 autobiographies. Each shelff Carlos must place all of theWhat is the greatest number of shelves?ow many of each book in this many shelves?

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Here, each shelf should have the same number of novel and autobiography. So, it should be the common divisors of 24 and 16. but the greatest would be the GCD of the numbersthe GCD is 8The greatest number of shelves is 8.

So he can have, 3 novels and 2 autobiographies in each shelf.

25.

6. Using prime factorisation, find the HCF and LCM of(İ) 24, 36, 40(ii) 30,72,432(iii) 21, 28, 36, 45

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26.

2. By re-arranging the given numbers, evaluate :(i) 2 x 487 x 50(ii) 25 x 444 x 4

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27.

6.Usingprime factorisation find(i) 24, 36, 40the HCF and LCM of01) 30, 72, 432) 21, 28, 36, 45HCF of two numbers is 23 and their Ld is 1449 Hone of

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28.

HCF of 8 and 36

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Find the prime factors for each number as:

8=2×2×236=2×2×3×3

Now identify the common factors and determine the HCF:

8=2×2×236=2×2×3×3

Therefore:HCF=2×2=4

29.

6. Using prime factorisation, find the HCF and LCM of(i) 24, 36, 40(ii) 30,72,432(iii) 21, 28, 36, 45

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30.

let d be the HCF of 24 and 36.Find two numbers a and b such that d=24 a + 36 b

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31.

Find LCM and HCF of a) 14 , 28 , 36

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32.

The LCM of 36 and 45 is 180. Find their HCF

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lcm *hcf = product of the numbers

180*hcf = 36*45

hcf = 1620/180

Hcf = 9

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33.

3, Given,prove that\frac{3 a-5 b}{3 a+5 b}=\frac{3 c-5 d}{3 c+5 a}

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thanks frn where are you from

34.

\left( \frac { 1 } { 2 } a ^ { 2 } + \frac { 3 } { 5 } b ^ { 3 } \right) ^ { 2 } - \left( \frac { 1 } { 2 } a ^ { 2 } - \frac { 3 } { 5 } b ^ { 3 } \right) ^ { 2 }

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35.

( 5 a + 3 b ) ^ { 3 } - ( 5 a - 3 b ) ^ { 3 }

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(a+b)^3 =a^3 +b^3 +3ab (a+b)(a-b)^3 =a^3 -b^3 -3ab (a-b)(5a+3b)^3 =125 a^3 +27 b^3 +15ab (5a+3b)=125 a^3 +27 b^3 +75a^2 b+45a b^2........ (1)(5a-3b)^3 =125 a^3 -27 b^3 -15ab (5a-3b)=125 a^3 -27 b^3-75a^2 b+45ab^2......... (2)subtracting 2 from 1(5a+3b)^3 -(5a-3b)^3=54b^3+150a^2 b

36.

e) Ramesh says, "I hope I get one more coin. Then mycoin collection will have 1000 coins". How manycoins does Ramesh have?

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999 coins because he need 1 more coin then he will have 1000 coins

37.

:. If two coins are tossed together, what are the chances of getting 'tail, tail"

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When two coins are tossed the probabilities are HH,HT,TH,TT

So, the chance is 1/4

38.

116 avcoins are tossed. Find the probability of the events:2. Two(i) at least one tail turns up(ii) no head turns up.(iii) at the most one tail turns up.

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Sample space,S= {HH,HT,TH,TT}n(S)=4

Event A: at least one tail turns up.A={HT,TH,TT}n(A)=3P(A)=n(A)/n(S) =3/4Event B:

Event B: no heads turn upB={TT}n(B)=1P(B)=n(B)/n(S) =1/4Event C: at the most one tail turns up.C={HH,HT,TH}n(C)=3P(C)= n(C)/n(P) = 3/4I hope it's help you and sorry for half answer

39.

toExerciseI. Answer Orally:1) Mahesh had 30. If he spends 15, what amount rwith him? 152) Amith had 15 marbles. Pavan gave him 5 marblesis the total number of marbles Amith has?Rehaman had 50. He went to a market andpur vegetables for28. What is the amount left with hIf 3 students are absent in a class of 26 studentmany students are present in the class?

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1)the amount left with Mahesh=30-15=Rs152)marbles with amith=15+5=203)the amount left with rehaman=50-28=rs22

40.

Puri. Dilferentiate the following functionsw.rd.x\begin{array}{l}{\sqrt{x+\frac{1}{x}}} \\ {\frac{1}{\sqrt{x}+7}-\frac{1}{\sqrt{7-3 x}}}\end{array}.

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41.

13. Find the real value of a for which 3-2ai' +(1-a)i +5 is real.

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42.

\left. \begin{array} { l } { 7 + 3 \sqrt { 5 } = 7 - 3 \sqrt { 5 } = a + \sqrt { 5 b } } \\ { 3 + \sqrt { 5 } = 3 - \sqrt { 5 } } \end{array} \right.

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43.

-3/5 %2B 3/4 %2B 7/3

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( 7/3 + 3/4) + (-3/5)

(28+ 9)/12 - 3/5

37/12 - 3/5

(185 - 36)/60

149/60

44.

“ thate 5% o) el. Seco X (osec s

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45.

10.83 litre of petrol costs then und meof the11. Ramesh eams 240.000 per month. He spends 2 of the income on food,remaining on LIC premium and then of the remaining on other expenses. Findhow much money is left with him

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Given:Per month earning = Rs.40,000

3/8 = foodSo 3/8 x 40,000 = Rs 15,000

Remaining = 40,000 - 15,000 = Rs 25,000

1/5 = LIC Premium So 1/5 x 25,000 = Rs 5,000

Remaining = 25,000 - 5,000 = Rs 20,000

1/2 on remaining expenses1/2 x 20,000 = Rs10,000

Total amount remaining with him is Rs 20,000 - 10,000 = Rs 10,000

46.

' 30.4 1 рдиProve that :L e = cosec 6 + sec 8 - cosec 0.sec 6.secO+1 cosecH+1

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47.

1) The L.C.M. of 18 and 12 is 36. Find their HCF.

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6 is the correct answer

48.

Consider f:R. →[4,00] given by f(x)= x2 +4. Show that f is invertible of given with theinvers f- of f given by f(y)= Vy-4, where R is the set of all non-negative real nos.

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49.

A cube is made by arranging 64 cubes having side of I cm, find total surfacearea of cube so formed.

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It will make a new cube whose new side is 64

Total surface area = 6a2

= 6 *64*64

= 24576 cm²

this question answer is 96 sq. cm

50.

Rehan works in soap factory. He is playing with arranging cubic soan<ing cubes. If he has to arrange 216 soap then how many soapsPur in first line of cube.

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Just take out the square of 216

just take out the cube root of 216.. so 6 soaps will occur in first line of cube..