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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2751. |
Find the multiplicative inverse of 4-√-9 |
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Answer» 4/root(16+9)-3i/root(16+9)=4/25-3i/25=(4-3i)/25 Firstly u take reciprocal of this value then rationalise the answers is in the form of a+ib Do reciprocol and rationalise it |
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| 2752. |
Find the sum to n terms of the A.P. whose k^th term is 5k+1 |
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| 2753. |
Covert the complex number 3(cos5 /\\ /3 - i sin /\\ / 6) into polar form |
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| 2754. |
Show that the points A( 4,6,-5), B(0,2,3) and C(-4,-4,-1) form the vertices of an isoscles triangle |
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Answer» From this method the answer is wrong Just calculate the distance between ab BC and CA uses distance formula then you will get the measurement of two of the sides equal hence prove that it is an isosceles triangle |
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| 2755. |
divide 10 hours for Conic sections, 3 D geometry and sequence and series? |
| Answer» 5 hrs for sequence , 3 and half hrs for conic sections and 1 and half hrs for 3d | |
| 2756. |
Tan√x ,diffrentiate by 1st principle |
| Answer» First apply first principle method and after apply sandwich theorem | |
| 2757. |
d/dx √cosx |
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| 2758. |
Vehn diagram of B\' |
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| 2759. |
9/3 |
| Answer» 3 | |
| 2760. |
Find a g p for which the sum of first two term is -4 |
| Answer» Question is incomplete.. | |
| 2761. |
Integration of dx/ 3x+5 is 1. Not defined 2. 3 ln(3x+5) + c 3. ln(3x+5)/3 + c4. None of these |
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| 2762. |
Vein digram |
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| 2763. |
1 ki power -1 = |
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Answer» 1 1/1 |
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| 2764. |
Solve the quadratic equation 2x^2 - (3+7i)x -3(3-9i)=0 |
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| 2765. |
Chapter 13 qution 3 |
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| 2766. |
Find the length of the medians of the triangle with vertices A(0,0,6),B(0,4,0)and(6,0,0) |
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| 2767. |
Check whether the P(A) and P(B) are consistently definedP(A)=0.5,P(B)=0.7,P(A intersection B)=0.6 |
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Answer» P(A union B) = 0.7 No because P(A) is less than P(B) |
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| 2768. |
Formula of circumstances |
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| 2769. |
Find thedomain of function of y where y: 10/ log 1-x + root over x-2 |
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| 2770. |
lim. [x-1], where [ . ] is greatest integer. functionx-> 1 |
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| 2771. |
-x square becomes +x? |
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Answer» (-X)^2=(-X)*(-X)=X^2As product of -ve number with -ve number is +veHence square of -ve no. is +vesquare of imaginary numbers is negative only as i^2=-1 Due to mode |
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| 2772. |
-This is a non subjective question-Where can I find solutions for CBSE sample papers? |
| Answer» I think google | |
| 2773. |
How many 4 letter word can formed using the letter of the word of ineffective |
| Answer» There are 11 letters in the word INEFFECTIVE i.e E E E, F F, I I, C, T, N, V=6c1(i) There is only one set of three same letters i.e E E E.These 4 letter can be arranged in ways=4!/3!1!Hence the total number of words consisting of 3 same and one different letters = 6c1×4!6×4=24.(ii) There are three sets of two some letters i.e E E, F F, I I . Out of these three sets two can be selected in ways.Now, 4 letters in each group can be arranged in ways.=3c2Hence the total number of words consisting two same letters of one kind and 2 same letters of other kind =3c2×4!/2!2!=3×6=18(iii) Out of 3 sets of two same letters one set can be chosen in ways.Now, from the remaining 6 distinct letters, 2 letters can be chosen in ways. So there are group of 4 letters each=3c1×6c2Now, letters of each group can be arranged among themselves in ways. = 4!/2!Hence, the total number of words consisting two same letters and 2 different = (3c1×6c2)×4!/2!=3×15×6=270(iv) There are 7 distinct letters E, F.So the total number of 4 letters words in which all letters are different = 7c4×4!=840 | |
| 2774. |
How many three digit numbers are divisible by 7? |
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Answer» Digit divided by 7=105,112,119..........,994 it is in A.P USING An=a+(n-1)d,105+(n-1)7=994 105+7n-7=9947n=994-98 , 7n=896 , n=896/7=128So,n=128 Smallest three digit no. divisible by 7 = 105Largest three digit no. divisible by 7=994Therefore AP: 105,112,119,....,994.Using nth term formula, an=a+(n-1)dWe get n = 128.Ans. 128 three digit numbers are divisible by 7 |
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| 2775. |
Prove that sinx + cos x=1 |
| Answer» sin x + cos x is equal to 1 so on squaring both sides science sin x sin square x is equal to 1 - cos x cos square sin square x is equal to 1 - 2 cos x + cos square x so on both on lhs and RHS one gets cancelled then 2 cos x - 2 cos square x is equal to zero let us consider f of x is equal to 2 cos x - 2 cos square x so on common to cos x bracket 1 - cos x is equal to zero cos x is equal to zero cos x is equal to -1 integrating with potential solutions x is equal to zero x is equal to 5 by 2 x is equal to 3 pi by 2 and x is equal to 25 but only x is equal to zero x is equal to 25 by 2 and X is 2 Pi it is in the period of coordinates zero to buy a real so cos x + sin x is equal to 1 | |
| 2776. |
Solution of 201 and 2017 year paper |
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| 2777. |
If sinx=-4/5 and x lies in third quadrant then find the value of cosx/2 |
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| 2778. |
how many hours are sufficient for revising sequences and series? |
| Answer» If you were perfect in solving questions before then one or one and half hour if not then two or two and half hour | |
| 2779. |
Find the n if n-1p3:np4=1:9 |
| Answer» To use parmotation formula and compare n-1p3 to np4 and 1to9 | |
| 2780. |
i+√i |
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| 2781. |
How many question from each chapter mark wise |
| Answer» Ch1(6 marks)...Ch2(8 marks)...Ch3(15 marks)...ch4(6 marks)...Ch5(5 marks)...Ch6(6 marks)...Ch7(6 marks)...Ch8(6 marks)...Ch9(8 marks)...Ch10(6 marks)...Ch11(6 marks)...Ch12(2 marks)...Ch13(6 marks)...Ch14(3 marks)...Ch15(6 marks)...Ch16(5 marks)... | |
| 2782. |
Find the square root of z = -2-2√(3i) ? |
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Answer» See 474 page no of ncert book class 11example 12 buddy =-O |
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| 2783. |
+8653685-%%949434994* /%64967 -94964%+984%7949- -% 94 7. 9467646764=4 |
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| 2784. |
1sin2 |
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| 2785. |
Prove 7^2n+2^3n-3 3^n-1 is divisible by 5 by binomial expression |
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| 2786. |
HCF of 196&38220 |
| Answer» hcf means highest common factors which terms occurs common in given terms like 54 and 27 the HCFof them r 54 =2×27 =2×3×3×3 and in 27 = 3×3×3 there u can see 3 is coming three times and is common between both the terms therefore thier hcf is 3×3×3 =27 in ur case the answer is 196 =2×2×7×7 and 38220 = 2×2×3×5×7×7×13 their gcf is 2 ×2×7×7 =196 becoz these numbers r common in both and after multiply their answer is 196 | |
| 2787. |
If tan b=sina-cosa/sina+cosaPT sina+cosa=√2 cosb |
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| 2788. |
In how many way we can arrange the letters of word commerce |
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Answer» 8!/2!2!2!=5040 saif is right here becoz we have 8 alphabet here and three alphabet r repeating these r m,e,c there we divided 8!/2!2!2! 8!/2!.2! 8!/2!2!2! = 5040 |
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| 2789. |
Which are the calculus chapter ?? |
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Answer» In standard of class or +1 or +2 limits with derivatives are calcus Integration and limit Integration and differentiation are collective called calculus. |
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| 2790. |
What is the use of trigonometry in our daily life? |
| Answer» There are various applications of trigonometry in our daily life dealing with the construction processes,etc. | |
| 2791. |
(x+1)^1/2+|x-1|=0 find x |
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| 2792. |
cos(180°÷7°)+cos(540°÷7°)+cos(900°÷7°)=1/2 |
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| 2793. |
Using binomial theorem, evaluate Cube root of 127 up to 4 places of decimal |
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| 2794. |
Sum of first p,q,r terms of AP are a,b,c Prove that. A/p (q-r)+b/q (r-p)+c/r (p-q) |
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| 2795. |
Cosx/1+sinx=tan(π/4-x/2) |
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| 2796. |
First principle f(x) =sun x |
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| 2797. |
Write the 5 first 5 terms of the sequences a1= a2= 2 , an=an-1 -1 , 2 |
| Answer» The question is not correctan=an-1-1,n>2 | |
| 2798. |
If sinx=cosx, write the value of 2tan^2x+cos^2x |
| Answer» 3-sin^2x | |
| 2799. |
Prove that n(n+1)(2n+1) is divisible by 6 |
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| 2800. |
Lim theta tends to 0 ,1-cos theta/ 1-cos3 theta |
| Answer» Let theta=xSo, lim x->0 1-cosx/1-cos3x=lim x->0 2sin^2(x/2) / 2sin^2(3x/2)=[lim x->0 sin(x/2) / sin(3x/2)] [limx->0 sin(x/2) / sin(3x/2)]= [lim x->0 sin(x/2)/(x/2) × lim x->0 (x/2) / sin3x/2)] [ lim x->0 sin(x/2)/(x/2) × lim x->0 (x/2)/sin(3x/2)] = [1× lim 3x/2->0 (3x/2)/sin(3x/2)× lim x->0 (x/2)/(3x/2)] [ 1 × lim 3x/2->0 (3x/2)/sin(3x/2) × lim x->0 (x/2)/(3x/2)]= (1× lim x->0 x/3x)(1×lim x->0 x/3x)= (1/3)(1/3)=1/9, is the required answer. | |