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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7301. |
If sinA=1/2(x+1/x) then prove that sin3A +1/2(x^3+1/x^3)=0 |
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| 7302. |
Am.8 and gm 5 obtain quadratic eqn |
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| 7303. |
Tan theta + tan2theta+√3tan theta tan2theta =√3 |
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| 7304. |
sin20°sin40°sin60°sin80°=3÷16 |
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| 7305. |
Find sum1+4+10+20+35......n terms |
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Answer» Nth term of this series = an = n(n+1)(n+2)/6 = (1/6) *(cube(n)+ 3*sqr(n)+ 2n). Now sum of all n terms = sum of cubes of first n natural numbers + 3* ( sum of Squares of first n natural numbers + 2 ( sum of first n natural numbers).. Use standard identities of sum of first n natural numbers, sum of squares of first n natural numbers, sum of cubes of first n natural numbers.. you can find answer but you have to know n terms formula is n ( n +1)÷2 See the ques. Is wronge it is not a A.P. and not an G.P. |
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| 7306. |
How is conditional implication logically equivalent to contrapositive -with practical example |
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| 7307. |
sinA+sinB |
| Answer» 2sinA+B/2cosA-B/2 | |
| 7308. |
Prove the bionomial theorem with any positive integer |
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| 7309. |
If A=[_1,1) |
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| 7310. |
To prove (Cos8ACos5A-Cos12ACos9A/Sin8ACos5A+Cos12ASin9A=Tan4A) |
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| 7311. |
Prove that 3^1/2×3^1/4×3^1/8.....=3 |
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| 7312. |
find the number of squres that can be formed on chess board |
| Answer» Hi lady bahubali remember I am your katappa | |
| 7313. |
How we can learn trigonometry formula like tan x, sin-x, with the trick all school to collage. |
| Answer» Yaad krke!!!!!? | |
| 7314. |
how we will find that theeta lies in which quadrant? |
| Answer» Imagine a revolving line in XY plane from origin. The Angle between this line and POSITIVE X AXIS and is measured as POSITIVE\xa0when this line\xa0is revolved in ANTICLOCKWISE DIRECTION keeping its one end fixed at origin.\xa0When revolving line is along POSITIVE X AXIS, angle is zero degree. If line is revolved through 45 degree in anticlockwise direction with respect to positive x axis, line will be in first quadrant, hence angle will be in first quadrant. If line is revolved through 150 degree in anticlockwise direction, angle is in second quadrant. For negative angles line has to be revolved in CLOCKWISE direction. Negative angles are also measured with respect to POSITIVE X AXIS. | |
| 7315. |
FInd square root of complex no -15-8i |
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| 7316. |
Comic sections |
| Answer» Pehle likhna sikh lo its better for you | |
| 7317. |
What is a derivative of a trigonometric function |
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| 7318. |
X/x-2-4/x*x-2x |
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| 7319. |
Limit X tends to state route to bracket X upon x minus 2 minus 4 x square |
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| 7320. |
What is the formula of Tn in A.P. |
| Answer» A+(n-1)d | |
| 7321. |
What is conic sections |
| Answer» A chapter of a maths book | |
| 7322. |
Sin√x derivate this question from first principle |
| Answer» Anjali dear derivative bahut bada hai | |
| 7323. |
n(n+1)(n+5) is multiple of 3 |
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Answer» To verify : n(n+1)(n+5) is divisible by 3 or notLet us use Principle of InductionLet f(n) = n(n+1)(n+5) = n3+6n2+5nLet us verify for n= 1: f(1) = 12 = 3*4 ; Hence f(n) is divisible by 3 for n = 1Let us assume that f(n) is divisible by 3 for any natural number n = aThat is f(a) = a3+6a2+5a = 3 (m) ;Let us Prove that f(a+1) is also divisible by 3 if f(a) is divisible by 3f(a+1) = (a+1)3+6(a+1)2+5(a+1) = a3+9a2+20a+12 = (a3+6a2+5a)+3a2+15a+12 = 3m+3a2+15a+12= 3(m+a2+5a+4); Hence f(a+1) is also divisible by 3.Hence it is TRUE that n(n+1)(n+5) is divisible by 3 Hi you are manjeet and I am manjit |
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| 7324. |
88×9 |
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Answer» 792 792 |
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| 7325. |
Limits at infinity X2/1+X2 by l hospital rule |
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| 7326. |
Sum of the cube of n terms of natural number |
| Answer» (n (n+1)/2)^2 | |
| 7327. |
Last year question papers for state level |
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| 7328. |
√2-√1+cosx/sinxsinx |
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| 7329. |
How do you find mean deviation from given mean |
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Answer» First Find mean (average) of all observations. Then find MOD value of difference between mean and each observation. Then find mean of all MOD values of differences. This is mean deviation. It\'s formula is sum of observations /no of observations |
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| 7330. |
If tanA= sinA - cosA/sinA +cosA, then show that sinA + cosA =√2cosA |
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| 7331. |
If y = √x/a +√a/xThen prove that2xy * dy/dx = x/a - a/x |
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| 7332. |
Lim x->0. (x cosecx-cotx) |
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Answer» Sorry answer is 1 Lim at x=0. x. 1/sinx -cosx/sinxLim at x=0. 1-cosx/sinxLim at x=02sin^2x/2/sinx. 2Lim at x=0 (sinx/2)^2/sinx/2*2=2*2*1=4Answer is 4 |
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| 7333. |
sinA-sinB |
| Answer» 2sin(a-b/2)cos(a+b/2) | |
| 7334. |
SinA=1/2. Find sin3A |
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| 7335. |
Cosx/x=? |
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Answer» Not 1 , we have to solve by using appropraite properties or formulae 1 |
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| 7336. |
Example 6 chapter 5 |
| Answer» U see it on the viba app on Google ,this app is very useful in mathematics problems | |
| 7337. |
Genral Solution SIN2X-SIN4X+SIN6X |
| Answer» Sin2x+sin6x-sin4x2sin4xcos2x-sin4xsin4x(2cos2x-1)sin4x=0 or 2cos2x-1=0x=nπ\\4 or x=nπ+-π\\6. | |
| 7338. |
Solve:lim x->infinite, (x^2+x+1)^1/2 -(x^2+1)^1/2 |
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| 7339. |
2sinx |
| Answer» 2cos x | |
| 7340. |
Differentiate xcosx from 1st principle. |
| Answer» -xsinx+cosx | |
| 7341. |
Sin2x+ cos2x |
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| 7342. |
If a set has n elements then how many subsets there are in its powerset? |
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Answer» Your answer is wrong . 2^n |
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| 7343. |
Sin5x-2sinx+sin3x÷Cos5x-cosx=tanx |
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| 7344. |
Proof of MI by binomial theorme |
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| 7345. |
Find the value of a and b so that the points (a, b, 3) (2,0,-1) and (2,0,-1) are collinear |
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| 7346. |
What is partial differential method |
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| 7347. |
Value of cos18 |
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| 7348. |
Weitage of ech chapter in final exam |
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| 7349. |
cos sq.2x-cos sq.6x=sin4x.sin8x.How it solved?? |
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| 7350. |
I need to download math unsolved question papers. How i will download it? |
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