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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 601. |
5×2+0×5+8×0+9+8 |
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Answer» =10+0+0+17=10+17=27 0 5×2+0×5+8×0+9+8= 10+0×5+8×0+9+8= 10\xa0+8×0+9 + 8= 10 + 9 + 8= 19 + 8= 27 |
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| 602. |
1. Find the sum of the sequence 7,77,777,7777,......to n terms. Please give a detailed explanation |
| Answer» 7, 77, 777, 7777 ….to n terms. Sn=7+77+777+7777+……+to n terms introducing 9 = (7/9) [9+99+999+……+ to n terms] = (7/9) [(10-1) + (100-1) + (1000-1) +……...+ to n term] = (7/9) [10+100+1000+……... n terms – (1+1+1+1+…… n terms) = (7/9) [10+100+1000+………n terms –n] \xa0Here a=10, r=10 \xa0= (7/9) [10(10n-1)/ (9) - n] | |
| 603. |
Write the relation R = [(x,x3):x is a prime number less than 10] in a roster form |
| Answer» QUESTIONWrite the relation R = {(x,\xa0x3):\xa0x\xa0is a prime number less than 10} in roster form.SOLUTIONR = {(x,\xa0x3):\xa0x\xa0is a prime number less than 10}The prime numbers less than 10 are 2, 3, 5, and 7.∴R = {(2, 8), (3, 27), (5, 125), (7, 343)} | |
| 604. |
Derivatives?? |
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Answer» hnn ? question pehle tumhara visible hua....but type krke pehle mene rkha tha...gya nii toh meri glti thodi hai?? ???ohho....prr btya kisne mene aaneko ...toh socho mene pehle se yha ques dlne ki tyri ni ki hogi?!? |
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| 605. |
4-1 = ?? ? |
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Answer» seconds ka frk hai bss dono timing me??lol ??? |
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| 606. |
Tan(225°) cos(405) +tan(765°) cot(675°) =0Prove that |
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| 607. |
Find trigonoometric ratios cosec(-1200) |
| Answer» Ans:- (-√3/2) | |
| 608. |
find the general solution of the equation : sin x + sin 3 x + sin 7 x |
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Answer» Oh okk thank u... But i want to know the answer... General solution are deleted topic from this chapter |
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| 609. |
Find the value of cos\u2061(-960°) |
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| 610. |
If y=3[x]+2 = 2[x+4] . Find the value of [x+y] a) 26 b) 20 c) 14 d) None |
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Answer» A Hii Aadya ji 26 The answer is 26 [most probably]First find x3[x]+2 = 2[x+4] [given]3x +\xa02 = 2x + 83x - 2x = 8 - 2therefore x = 6Now, y=3[x]+2 or y =\xa02[x+4]\xa0Putting the value of x ,we get y = 20\xa0now x+y = 20 + 6= 26\xa0\xa0 |
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| 611. |
For any set A and B show that P(A intersection B) = P(A) Intersection P(B) |
| Answer» We have to show that P(A ∩ B) = P(A) ∩ P(B)LHS:Let x ∈ P(A ∩ B)=> x ∈ (A ∩ B)=> x ∈ A and x ∈ B .............1RHS:x ∈ P(A) ∩ P(B)=> x ∈ A and x ∈ B ............2From equation 1 and 2, we getP(A ∩ B) = P(A) ∩ P(B)Hence proved. | |
| 612. |
Integration?? |
| Answer» Hii Aadya ji | |
| 613. |
1-1 = ? ? |
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| 614. |
1+1 = ? ? |
| Answer» idk | |
| 615. |
4+4-7 |
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Answer» Shi kha.... Bhai mzak kr rhe ho kya ? 1 1 Are u serious?!???sry to say this....but agr apko ye nii aata...to 11th ki maths kya ghnta solve krr paoge... |
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| 616. |
X+ygreater than 0,x+3ygreater than 60 |
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Answer» What\'s the question askingHere what to findPlzz mention Ssss |
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| 617. |
Greatest integer function of [0.9 bar] |
| Answer» Hi | |
| 618. |
Which of the following are sets? Justify your answer. |
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Answer» Hi jyoti What are the set Where are the sets |
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| 619. |
tan a + tan b/ sin a+sin b=cot(a-b) prove that |
| Answer» You can saw from google | |
| 620. |
Challenge !!!!If |x| |
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Answer» 1 1/2 1 /2 1 |
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| 621. |
If X =(1,2,3,4...10),A=(1,2,5)and B=(6,7)then prove that - A intersection B\'=A |
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Answer» A=(1,2,5)B=(6,7)X is the universal set for A and B (X=(1,2,3...10)B\'=(1,2,3,4,5,6,7,8,9,10)From LHS side(1,2,3) intersection (1,2,3,4,5,6,7,8,9,10)(1,2,5)(which is equal to A) Hence it is proved A=(1,2,5)B=(6,7)X is the universal set for A and B { X =(1,2,3,4...10)}B\'={1,2,3,4,5,8,9,10} from LHS side{1,2,5} intersection{1,2,3,4,5,8,9,10}{1,2,5} (which is equal to A)Hence it is proved |
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| 622. |
Find the equation of the locus of a point which is at a distance 5 from A(4,-3). |
| Answer» it is a circle whose centre is (4,-3) and radius 5 | |
| 623. |
Find the domain of f(x) = √(log1/4 + log1/3 + log1x/2) |
| Answer» Log/1/2 | |
| 624. |
Greatest integer function ?? |
| Answer» Good morning | |
| 625. |
2+2+2+ |
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Answer» 5+1? ye konse ch me se hai bhai... |
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| 626. |
Can anyone answer my ques ?????? |
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Answer» Bt what was the question Apna question to bolo bro..... Ok if anybody else can answer |
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| 627. |
If A &B are any two sets, find the number of elements in the set A intersection ( A U B) |
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Answer» Answer is A. ...Kyonki (A U B) mein A aur B dono ke saare elements honge... So jab iska A se intersection hoga tab A aaraam se common aa jaayega? A |
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| 628. |
If |x| |
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| 629. |
Find the value of n!/(n-r)! Where r =4 |
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| 630. |
Logarithm?? |
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| 631. |
Find the sum of 17 th term of an AP,5,9,13,17....... |
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| 632. |
Sin2 6x - sin2 4x = sin 2x sin10x |
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Answer» Hi LHS = sin²(6x) - sin²(4x)Use the formula,(a² - b²) = (a - b)(a + b)= (sin6x -sin4x)(sin6x +sin4x)Now,Use the formula,sinC + sinD = 2sin(C+D)/2.cos(C-D)/2sinC - sinD = 2cos(C+D)/2.sin(C-D)/2={2cos(6x+4x)/2.sin(6x-4x)/2}{2sin(6x+4x)/2.cos(6x-4x)/2}={2cos5x.sinx}{2sin5x.cosx}={2sin5x.cos5x}{2sinx.cosx}Use the formula,sin2A = 2sinA.cosA= sin2(5x).sin2(x)= sin10x.sin2x =RHS |
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| 633. |
F(x)=2x√1-x^2 |
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| 634. |
Whosoever support but the thing how cheap the people are becoming of India!! |
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Answer» These are nkt people , these are demons and they do not have any right to live in India. I dont know why these hell people are freea Yup.. some Indian People fail to understand that it\'s cricket, it\'s a game. Some day you score,some day you don\'t ..!.....and people shouldn\'t criticise any player for not playing well in a tough situation:( |
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| 635. |
If secX =13\\5x lies in the founts quadrant . Find the value of other five trigonometric function |
| Answer» Answer:1) sec X = 13/5\xa0x lies in 4th quadrant.\xa0cos X = 1/ secx2)\xa0So,\xa0cos\xa0x\xa0=\xa05/13\xa0sin X = √ 1- cos²x3)\xa0sin\xa0X\xa0=\xa0-12/13\xa0⚆As sin functions-ve in 4th quadrant.\xa0cosec X = 1/sin X4)\xa0cosec\xa0X\xa0=\xa0-13/12⚆As\xa0cosec\xa0functions-ve\xa0in\xa04th\xa0quadrant.\xa0tan X = √ sec² x-15)tan\xa0X\xa0=\xa0-12/5\xa0⚆As tan functions-ve in 4th quadrant.\xa0Cot x = 1/ tan X6)Cot\xa0x\xa0=\xa0-5/12 | |
| 636. |
Who is फालतु here. |
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Answer» Oh nice of you?\u200d♀️ Vishal Pandey |
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| 637. |
Prove that cot(A+15°) -tan (A-15°) =4cos2A\\ 1+2sin2A |
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| 638. |
Solve the equation cos theta + sin30 = 2cos20 |
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| 639. |
If log1216 = a, then the value of log627 in terms of \'a\' is...??? |
| Answer» X^n + y^n/x^n-1 + y^n-1 =root xy | |
| 640. |
The sum of values of x satisfying the following equation is : log4(x+1) + log4(x+4) = 1... |
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| 641. |
Solve for x :- 1+6log(x+2) 4 = log4(x+2) |
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Answer» F U C K **** |
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| 642. |
Challenge!!!Solve for x:$$\\dfrac{d}{d cosx} (sinx)$$ |
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Answer» Answer is cot x Let u =sinx and v= cosx.....d(sinx)/d (cosx)......d(u/v)= (v du + u dv )/ v².....[ cosx × d(sin x) - sinx × d(cosx)] / (cosx)²Since, d(sin x) = cos x and d(cos x) = -sin xTherefore, [(cosx)² + (Sinx)²]/ (cosx)²= 1/ (cos x)²=(secx)² Mera toh kuch or hii answer arha hai...?sec²x.... Not x but solve it |
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| 643. |
Immediately |
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| 644. |
A set which has exactly 10 elements and it through a defining property |
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| 645. |
1*6583/700 |
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| 646. |
If log72 = m, then log4928 is equal to..?? |
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Answer» It\'s Okay!!! ... Gud Mrng!! ? Kisi ne nhi answer btaya ? |
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| 647. |
8÷2(2+2) = ? a) 16 b) 1 c) None |
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Answer» 1 1 according to bodmas 8 ÷ 2(2 + 2) =\xa08 ÷ 2(4) =\xa08÷ 8 = 1 |
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| 648. |
(x + root 1-x^2)⁴ can anyone solve this by using binomial theorem |
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| 649. |
Find logx of 5root 0.96 |
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| 650. |
M maths ki questions solve ni kr pata . Samaj ni atta aur pta bhi nhi chalta.Kase kru?? |
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Answer» I think apko Maths ki basic knowledge nahii hai....If I\'m right....then why did u take maths subject in 11th... agar itni hi difficulty ho rhi hai smjhne mein toh koi or subject le lete na!?! aage ka ho jayega socho mat ki nahi hooga karke dekho hoga just start karo ek taraf se Mt kr fir |
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