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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2151. |
which term of the progression 20,19¼,18½,17¾......is the first negative term? |
| Answer» Given, a = 20 and d =\xa0{tex}-\\frac 34{/tex}Let the nth term be first negative term{tex}a + (n - 1)d {/tex}< 0{tex}\\therefore{/tex}\xa0{tex}20 + ( n - 1 ){/tex} ( - {tex}\\frac 34{/tex}\xa0) < 0\xa020- {tex}\\frac 34{/tex}n + {tex}\\frac 34{/tex}\xa0< 0- {tex}\\frac 34{/tex}n + {tex}\\frac {83}4{/tex}\xa0< 0{tex}\\frac {83}4{/tex}\xa0< {tex}\\frac 34{/tex}n3n > 83n >\xa0{tex}\\frac { 83 } { 3 } = 27 \\frac { 2 } { 3 }{/tex}Hence 28th term is first negative. | |
| 2152. |
1$ = what |
| Answer» Rs 64.4228 | |
| 2153. |
Hello ☺☺ .... |
| Answer» | |
| 2154. |
what is value tan 30 |
| Answer» 1 upon root3 | |
| 2155. |
How to drive the formula for the curved surface area and total surface area of fristm |
| Answer» It\'s not in our syllabus | |
| 2156. |
Cone volume formula |
| Answer» {tex}V = \\pi r ^ { 2 } \\frac { h } { 3 }{/tex} | |
| 2157. |
12.2 |
| Answer» | |
| 2158. |
How I get basic firmula |
| Answer» Check formulae in revision notes :\xa0https://mycbseguide.com/cbse-revision-notes.html | |
| 2159. |
Kx (x-2)+6=0 |
| Answer» We have, kx(x - 2) + 6 = 0{tex}\\Rightarrow k x^{2}-2 k x+6=0{/tex}........(1)We know that quadratic equation {tex}ax^2+bx+c=0{/tex},a≠0, has equal roots if its discriminant D is 0.D = 0\xa0{tex}\\Rightarrow{/tex}{tex}b^2-4ac=0{/tex}{tex}\\Rightarrow{/tex}4k2 - 4(k)6 = 0 [from given quad. equ.(1); a=k≠0, b= -2k, c= 6]{tex}\\Rightarrow{/tex}4k2 - 24k = 0\xa0{tex}\\Rightarrow{/tex}4k(k - 6) = 0 {tex}\\Rightarrow{/tex}k - 6 = 0 [ since, k≠0]{tex}\\Rightarrow{/tex}k = 6\xa0Hence the value of K is 6. | |
| 2160. |
3x-4/7+7/3x-4=5/2 |
| Answer» 3x-4/7 +7/3x-4=5/2Taking LCM ,we get(3x-4)(3x-4)+49/7(3x-4)= 5/29x2+16-24x+49/21x-28=5/29x2\xa0-24x+65/21x-28=5/2By cross multiplication , we get18x2-48x+130= 105x-14018x2\xa0-48x-105x+130+140=018x2\xa0-153x +270 =018x2\xa0-108x -45x+270 =018x(x-6) -45(x-6) =0(x-6)(18x-45)=0x=6 or x =45/18=5/2\xa0 | |
| 2161. |
1+1 ? |
| Answer» 2 | |
| 2162. |
Linear equation in two variable ?? |
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Answer» Graph is also important Cross-multiplication , factorisation method, and solve for x and y Solve all word problems |
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| 2163. |
If SinA+Sin^3A= Cos^2A. PROVE Cos^6A-4Cos^4A+8Cos^2A=4 |
| Answer» | |
| 2164. |
Sir my request 10th class exam date sheet 2018 |
| Answer» Check datesheet here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 2165. |
How to find the relationship between areas and sides of similar triangle |
| Answer» The ratio of areas of two similar triangles is equal to the square of ratio of its corresponding sides. | |
| 2166. |
Jard |
| Answer» | |
| 2167. |
Area enclosed by the circle and common tangent |
| Answer» | |
| 2168. |
The perpendicular from the centre of a circle to a chord bisects chord |
| Answer» | |
| 2169. |
How to do qus of perabola |
| Answer» | |
| 2170. |
Percent mean |
| Answer» | |
| 2171. |
how much ncert came in board exm |
| Answer» | |
| 2172. |
If the n-2, 4n-1 and 5n+2 are in AP, find thevale of n ? |
| Answer» N=1 | |
| 2173. |
6+6 |
| Answer» 12 | |
| 2174. |
Equtation |
| Answer» | |
| 2175. |
How to download cbse latest sample paper |
| Answer» Check sample papers here :\xa0https://mycbseguide.com/cbse-sample-papers.html | |
| 2176. |
Find the value of √6plus√6plus√6plus.... |
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Answer» No Aise kaise nhi hoga .?? ?√6 kidar gya madam |
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| 2177. |
how can i score best marks in it? |
| Answer» | |
| 2178. |
Find the ratio of radius at which area and perimeter of circle are equal |
| Answer» area of a circle; pie r2perimeter of a circle: 2 pie requating both formula:pie r2\xa0\xa0= 2 pie r\xa0r =2\xa0 | |
| 2179. |
Explain the theory of cards briefly |
| Answer» | |
| 2180. |
Sin teehta= |
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Answer» P/H Perpendicular/Hypotenuse. Perpendicular of right angled triangle divided by its hypotenius. P/h |
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| 2181. |
S and T are points on sides PR and QR of ∆PQR such that angle P=angle RTS. Show that∆RPQ~∆RTS |
| Answer» In triangle RPQ and RTS.angle P= angle T (given )Angle R = Angle R (common)By AA, triangle RPQ ~ RTS.. | |
| 2182. |
Give me algebraic identities |
| Answer» | |
| 2183. |
Is there any derivation for section formula? |
| Answer» | |
| 2184. |
Tan x°=5/12 and tan y°=3/4 AB=48m find the length of CD |
| Answer» | |
| 2185. |
If one zero of polynomial is 1/2 and other is £ for 2x^2 +3x+£ |
| Answer» | |
| 2186. |
COS 45°/SEC 30°+COSEC 30° |
| Answer» 4 root 2 + root 3 by 2 root 2 | |
| 2187. |
Check whether 2^n can end with the digit 6 for any n ? |
| Answer» | |
| 2188. |
Check whether 2^n can end with the digit 6 |
| Answer» | |
| 2189. |
If cot( |
| Answer» | |
| 2190. |
Any news about date sheet 2018 |
| Answer» Check datesheet here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 2191. |
(Sin70° + Cos40°)/(Cos70°+Sin40°) what is the value ? |
| Answer» | |
| 2192. |
What is the prime numbers |
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Answer» Those numbers which r divisible by 1& itself known as prime numbers. The number which are divisible by 1 and itself |
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| 2193. |
What is the formula of hollow cylinder |
| Answer» K | |
| 2194. |
howwe proof √5 |
| Answer» | |
| 2195. |
If tan theta is 15/8 then evaluate (2+2 sin theta)(1- sin theta)/(1+ cos theta) (2-2 cos theta) |
| Answer» | |
| 2196. |
Board paper sum |
| Answer» You can check last year papers here :\xa0https://mycbseguide.com/cbse-question-papers.html | |
| 2197. |
If x=2/3 and x=-3are roots of the quadratic equation ax+7x+b=0 find the values of a and b |
| Answer» {tex}\\because{/tex}\xa0x =\xa0{tex}\\frac{2}{3}{/tex}\xa0is a root of {tex}ax^2 + 7x + b = 0{/tex}{tex}\\therefore{/tex}\xa0a({tex}\\frac{2}{3}{/tex})2 + 7{tex}\\times{/tex}{tex}\\frac{2}{3}{/tex}\xa0+ b = 0{tex}\\Rightarrow{/tex}{tex}\\frac{4a + 42 + 9b}{9}{/tex}\xa0= 0\xa0{tex}\\Rightarrow{/tex}\xa0{tex}4a + 9b + 42 = 0{/tex} ...(i)Also x = 3 is a root{tex}\\therefore{/tex}\xa0{tex}a(3)^2 + 7\\times3 + b = 0{/tex}{tex}\\Rightarrow{/tex}{tex}9a + b + 21 = 0{/tex}{tex}\\Rightarrow{/tex}{tex}9(9a + b + 21) = 9\\times0{/tex}{tex}\\Rightarrow{/tex}{tex}81a + 9b + 189 = 0 {/tex}...(ii)(ii) and (i), we get{tex}\\Rightarrow{/tex}\xa077a = -147\xa0{tex}\\Rightarrow{/tex}\xa0a =\xa0{tex}\\frac{-147}{77}{/tex}\xa0=\xa0{tex}\\frac{-21}{11}{/tex}When a =\xa0{tex}\\frac{-21}{11}{/tex}, eq.(i) becomes-4{tex}\\times{/tex}{tex}\\frac{21}{11}{/tex}\xa0+ 9b + 42 = 0{tex}\\Rightarrow{/tex}{tex}\\frac { - 84 + 99 b + 462 } { 11 }{/tex}\xa0= 0{tex}\\Rightarrow{/tex}99b + 378 = 0 b =\xa0{tex}\\frac{-378}{99}{/tex}\xa0=\xa0{tex}\\frac{-42}{11}{/tex}{tex}\\therefore{/tex}\xa0a =\xa0{tex}\\frac{-21}{11}{/tex}, b =\xa0{tex}\\frac{-42}{11}{/tex}. | |
| 2198. |
Express HCF of 72 and 124 as a linear combination of 72 and 124 |
| Answer» | |
| 2199. |
How many types of trigonometry |
| Answer» | |
| 2200. |
X2-7x+9 |
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Answer» It has been formulated in order to protect the consumers in market place which has been sign by the government of india in 1896 It is an consumer protection act taken by the government in 1896. It is known as copra What is Gg???? Gg |
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