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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
x²(a²+b²)+2(ac+bd)x+(c²+d²)=0, prove that ad-bc=0 |
| Answer» | |
| 2. |
The distance between Alisha house and hurry house is |
| Answer» The distance between Alisha house and hurry house is | |
| 3. |
The surface area of a solid metallic sphere is 616cm^ .it |
| Answer» The distance between Alisha house and hurry house is | |
| 4. |
A circle touches all 4side of equal ABCD prove that AB+CD-8C+DA |
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| 5. |
वन अपॉन माइनस वन |
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Answer» No idea -1 |
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| 6. |
3d shapes historical monument of sikkim ppt |
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| 7. |
Find the 11th term from the last term (towards the first term) of the AP:10,7,4,............,-62 |
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Answer» -32 The 11th term is -32 The 11th term is -32 |
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| 8. |
8x²–22x–21=0 |
| Answer» 8x^2-28×-6×-21=04×(2×-7)-3 (2×-7)=0(4×-3)=0, (2×-7)=0×=3/4,×=7/2 it\'s answer | |
| 9. |
How can you find the centre of circle ifarc is given |
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Answer» Construction Select any three points in arc and join to form two line segments in V form.... Then draw bisector of both line segments where the bisector will meet, the centre is there.. The solution of the question is given in NCERT book of class 9 maths in constriction chapter... |
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| 10. |
Find the value of m so that the quadratic equation "mx(5x - 6) = 0" has two equal roots. |
| Answer» 5mx^2 - 6mx = 0 Here, D = 0D = b^2 - 4acD= (6m) ^2 - 4 × 5m × 00 = 36m^2 m^2 = 36m = 6 | |
| 11. |
(Sec theta - cos theta)(cosec theta -sin theta)(tan theta+cot theta)=1 |
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| 12. |
A bird is flying at height |
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Answer» Question is wrong ? ? Then what happen ?? |
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| 13. |
Check whether the following are quadratic equations:(i)(x+1)^2=2(x-3) |
| Answer» (x+1)^2 =2(x-3)...x^2 +1 + 2×x×1 = 2x - 6x^2 +2x-2x+1+6 =0x^2+0x+7=0so ,it is a quadratic equation as a=1,b=0 nd c=7 | |
| 14. |
A circle is inscribed in the quadrilateral ABCD. Given AB=6cm, BC=7cm and CD=4cm. Find AD |
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| 15. |
A big circle has radius 6 cm the concentrically circle radius is |
| Answer» Less than 6cm | |
| 16. |
198906÷2 |
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Answer» This question answers is 99453 99453 99453? 99463 will be the answer. 99453 |
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| 17. |
Chapter 10 exercise 10.1 |
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| 18. |
Then the time taken to go downstream will be expressed as |
| Answer» Distance÷ (speed of boat in Stillwater+speed of current) | |
| 19. |
22×2 |
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Answer» 44 44 44 |
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| 20. |
What is total surface area of cylinder |
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Answer» TSA = 2πr(h+r)CSA = 2πrh 2πr(h+r), curves surface area of 2πrh Total surface area of cyl 2πr(h+r),curved surface area 2πrh U know curved surface area? |
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| 21. |
Find the mean of ist 30 natural number |
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Answer» mean = 1 + 2 + 3.... 29 + 30 a = 1d = 1n = 30 Sum = n/2 (2a + (n-1) d)Sum = 30/2 (2 + (30-1)×1)Mean = 15 × 31 Mean = 465.. 15.5 |
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| 22. |
Write first four term of ap when a=6,d=-4 |
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Answer» 6, 2, -2, -6 6,10,14,18 |
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| 23. |
Who is ramanujar |
| Answer» What is natural no. | |
| 24. |
Find the nth term of the AP: 7,13,19,25,.......... |
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Answer» 151 a=7d=13-7=6an=? an= a+(n-1) dan=7+(n-1) 6an=7+6n-6 = 6n-1Therefore the answer is 6n-1 nth term is 19th term is 115 Not possible Fg |
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| 25. |
A metallic cube of edge 1cm is melted into a wire of diameter 4mm,, then find the length of the wire |
| Answer» Volume of cube = volume of wirea^3=πr^2h10^3=(22/7)×4^2×h1000=(22/7)×16h(1000×7)/(22×16)=h29.88mm =h | |
| 26. |
Consider the following frequency distribution:Class0-940-4910-1920-2930-39ty118Frequency131015 |
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| 27. |
What is the meaning of term An in the arithmetic progression Chapter |
| Answer» An = nth term of an A.P. | |
| 28. |
kx^2+1-2(k-1)x+x^2=0 |
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| 29. |
Odd no. |
| Answer» Numbers that are not divisible by 2 are called odd number. | |
| 30. |
Define real no. |
| Answer» Real numbers are those who can be represented on number line. | |
| 31. |
In an a.p the sum of its first n terms is 3n2+n find its 22nd term |
| Answer» 130 | |
| 32. |
Proof of alternate segment theorem |
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| 33. |
Find mode of the following frequency distribution. Marks obtained:10-25.25-40 |
| Answer» | |
| 34. |
Mind maps of ch 9 |
| Answer» AB =7cmin the ratio 2:3 | |
| 35. |
What was arothematic progression formula |
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Answer» An=a+(n-1)×dSn=n/2 {2a+(n-1)×d}Sn=n/2(a+l) Sn=n/2{2a+(n-1)d} |
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| 36. |
Tank contwo tankers contain 620 litres and 840 litres of diesel respectively |
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| 37. |
Elpis |
| Answer» | |
| 38. |
4√3x²+5x-2√3=0 |
| Answer» 4√3x*2+8x-3x-2√3=04x(√3x+2)-√3(√3+2)=0(4x-√3)(√3x+2)=04x=√3;√3x+2x=(√3/4);x=(2/√3) | |
| 39. |
Find the mean.Class F 0-2 1 2-4 2 4-6 1 6-8 8-10 56 10-12 12-14 3 2 |
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| 40. |
√42+√42+√42... Till infinity? |
| Answer» | |
| 41. |
A metric progression |
| Answer» Arithmetic progression | |
| 42. |
Exercise 5.4 solution |
| Answer» Search from Google bro | |
| 43. |
In the given figure, BO and CO are bisector of /B and /C respectively . If /A = 50 , then /BOC=? |
| Answer» BOC=115 | |
| 44. |
Budding |
| Answer» A small part of body of parent organism grow out as a bud which became new organism.example hydra | |
| 45. |
4x2-2(a2+b2)x+a2b2=0 |
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| 46. |
Find the roots of equations x²-3x-10=0 |
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Answer» -2 and 5 x² - 3x - 10 = 0=> x² - (5 - 2)x - 10 = 0=> x² - 5x + 2x - 10 = 0=> x(x - 5) + 2(x - 5) = 0=> (x - 5)(x + 2) = 0x - 5 = 0 or x + 2 = 0=> x = 5 or => x = - 2Roots are 5, - 2 |
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| 47. |
Ex 4.2 Q1 |
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Answer» Factorisation x=-5,2 |
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| 48. |
Show that x = -3 is the solution of the equation x2+6x +9 = 0. |
| Answer» x2 + 6x + 9 = 0.Put x = -3 in the equation{tex}\\Rightarrow{/tex}{tex}(-3)^2\xa0+ 6(-3) + 9{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}9 - 18 + 9 =0{/tex}Hence, it is a solution of the given equation. | |
| 49. |
what is culminative frequency? |
| Answer» 2? | |
| 50. |
Show that any positive odd integer is of the form 6q +1 0r 6q +3 or 6q +5.where q is some integer |
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