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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Nache j Sade naal tenu Dil v deyange ?? |
| Answer» ????? | |
| 2. |
Result kdo a? |
| Answer» | |
| 3. |
Sin23.cos67 + cos23.sin67 |
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Answer» Its ans is 1 2 |
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| 4. |
How much is the value of 1+1=? |
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Answer» Yarr yeh toh IIT level ka hai or ham toh 10th mai hai Very difficult cant solve??? |
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| 5. |
If the mean=6.4 then find the value of pX|2|4|6|8|10|12|F|3|p|5|3|2|1| |
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| 6. |
Anybody can answer the difference between centre and center? |
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Answer» The meaning is same Difference? American and British spelling |
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| 7. |
Hiii frd??? |
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Answer» Hii ????? |
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| 8. |
a2b+d2 |
| Answer» | |
| 9. |
R u all busy with studies |
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Answer» In jannat only In which state is jannat Only 6 more days are left 4 exam I am from jannat... About maths paper Noo Which stae r u from mollika Yes No |
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| 10. |
Solve for x: 1/2x-3 + 1/x-5=10/3 |
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| 11. |
Hlo guys? |
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Answer» F9 nd u ?? How r u all Hi reet Hii Wtsapp guys Hey Hello |
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| 12. |
Hlw tu |
| Answer» Hlw tu ? | |
| 13. |
If height=base=x then what is hypotensue |
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Answer» Wrong By Pythagoreas theorem, it\'s root 2 xHere is outside the root |
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| 14. |
Hiii i m back frnds .....???? |
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Answer» Hmm Hii smart boy n girls Hi Hi Hiii?? |
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| 15. |
The first term of an APis -7 and common difference 5,find its 18tern and general term |
| Answer» A18 = A + 17d\' A18= 78 | |
| 16. |
Hyyy frnd can we all make an fb grup |
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Answer» Send ur id Yup |
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| 17. |
√sec |
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| 18. |
If cos + sin =root 2 cos then show that cos - sin = roost 2 sin |
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| 19. |
(a-b)^3 |
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| 20. |
Prove that : Cos A -sin A +1 ---------------------------- =.cosec A+cot A Cos A +sin A -1 |
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| 21. |
Who is my friend , I help you my good friend. |
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Answer» I am ur girl friend Anurag Yes muja tumari help chahia Anurag but jashan ko plz chup karao Energy , i am old Me yar plz ananya dur ra ???? ?????? Abhi tmhari help ki jrurat Riddhi ko h BHAI TU HAI KON??? I MEAN NEW HAI YA OLD Mee?? |
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| 22. |
Anjali |
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Answer» Kyunki ab mein famous hun isliye see to up anjali is no more. ??? #single ? |
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| 23. |
I have a one in the units rod. I am greater than 63 and less than 80. What number am i |
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| 24. |
How to logout |
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Answer» If u want to logout then delete this app By log out |
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| 25. |
IF Sn denote the sum of the first n terms of an AP and S2n =3Sn ,then S3n :Sn is equal to what no.? |
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| 26. |
Yaar koi amit ko bulavo |
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Answer» Hii ..kha se ho Wah Itna confidence sa ki tum hi hoga No amit singh No Hii..Nancy..u mean Amit Kumar Hii See above |
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| 27. |
In a quadrilateral, angle A+angle D=90\'. Prove that Ac2+BD2=AD2+BC2 |
| Answer» Given: In quadrilateral ABCD,{tex}\\angle A + \\angle D = 90 ^ { \\circ }{/tex}AC and BD are joinedTo prove: AC2 + BD2 = AD2 + BC2Construction: Produce AB and DC to meet at P.Proof: In\xa0{tex}\\triangle{/tex}APD,{tex}\\angle A + \\angle D = 90 ^ { \\circ }{/tex}(given){tex}\\therefore \\angle P = 90 ^ { \\circ }{/tex}\xa0{tex}\\left( \\because \\angle A + \\angle P + \\angle D = 180 ^ { \\circ } \\right){/tex}Now in right\xa0{tex}\\triangle A C P , \\angle A P D = 90 ^ { \\circ }{/tex}AC2 = PA2 + PC2 ....(i)(Pythagoras Theorem)and in\xa0{tex}\\triangle{/tex}BPDBD2 = PB2 + PD2Adding (i) and (ii)AC2 + BD2 = PA2 + PC2 + PB2 + PD2= (PA2 + PD2) + (PC2 + PB2)= AD2 + BD2({tex}\\therefore{/tex}\xa0In right\xa0{tex}\\triangle{/tex}APD, PA2 + PD2 = AD2 and similarly PC2 + PB2 = BD2) | |
| 28. |
What is the meaning of SPST |
| Answer» State Public Services Tribunal | |
| 29. |
Find the sum of first 25th term of an A.P whose nth term is given Tn=7n-3 |
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| 30. |
Ethe Saare vehle Ee aa Koi Padh v lo |
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Answer» Hlo Hlo* Jlo |
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| 31. |
Ki chalda |
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Answer» Oh acha Chat chalda |
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| 32. |
Find the eleven term from the last term of the ap 23. 19 ..-65 |
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Answer» -25 -25 |
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| 33. |
How we will fund the 11th term of So whose first term is 12, 15, 16 |
| Answer» Use the formula :Tn=a+(n-1)dWhere, n=no. of terms,a=first term,d=common difference | |
| 34. |
The two opposite verticesof square are(-1,2) and(3,2) find coordinate of other two vertices |
| Answer» Let ABCD be a square and B (x, y) be the unknown vertex.AB = BC{tex} \\Rightarrow {/tex} AB2 = BC2\xa0{tex} \\Rightarrow {/tex}\xa0(x + 1)2 + (y - 2)2 = (x - 3)2 + (y - 2)2{tex} \\Rightarrow {/tex} x2 + 1 + 2x + y2 + 4 - 4x = x2 - 6x + 9 + y2 + 4 - 4x{tex} \\Rightarrow {/tex}\xa02x + 1 = - 6x + 9{tex} \\Rightarrow {/tex}\xa08x = 8{tex} \\Rightarrow {/tex}\xa0x = 1 ........ (i)In {tex}\\triangle{/tex}ABC, AB2 + BC2 = AC2{tex} \\Rightarrow {/tex}\xa0(x + 1)2 + (y - 2)2 + (x - 3)2 + (y - 2)2 = (3 + 1)2 + (2 - 2)2{tex} \\Rightarrow {/tex}x2 + 1 + 2x + y2 - 4x + 4 + x2 + 9 - 6x + y2 + 4 - 2y = 16 + 0{tex} \\Rightarrow {/tex}\xa02x2 + 2y2 + 2x - 4y - 6x - 4y + 1 + 4 + 9 + 4 = 16{tex} \\Rightarrow {/tex}\xa02x2 + 2y2 - 4x - 8y + 2 = 0{tex} \\Rightarrow {/tex}\xa0x2 + y2 - 2x - 4y + 1 = 0 ..... (ii)Putting the value of x in eq. (ii),1 + y2 - 2 - 4y + 1 = 0\xa0{tex} \\Rightarrow {/tex}\xa0y2 - 4y = 0\xa0{tex} \\Rightarrow {/tex}\xa0y(y - 4) = 0{tex} \\Rightarrow {/tex}\xa0y = 0 or 4Hence the other vertices are (1, 0) and (1, 4). | |
| 35. |
What is honourable card |
| Answer» The five highest cards in each suit (A- K - Q - J - 10) are called the honours or honour cards. | |
| 36. |
Guys math paper preparetion ke easy tips aur formule btao plz help me |
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Answer» Kos cheez ka practice Are u on? Apna name btaoo Btao Only pratice Koi ho plz btao Maii batau |
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| 37. |
Sin60cos30 |
| Answer» 3/4 | |
| 38. |
solve for x1\\(x-1)(x-2) + 1\\(x-2)(x-3) =2\\3 |
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| 39. |
Solve. ax^2+(4a^2-3b)x -12ab = 0 |
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| 40. |
if a has probality4/3 and b has probality8/5 what that c has neither chances |
| Answer» Dono probability ko sum karke 1 se subtact kar do... Answer aa jayega.. | |
| 41. |
What value of tan thita ? |
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Answer» Pappu ho itna bhi nahi pata Opposite of theta/adjacent of theta |
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| 42. |
Divide 39 in two parts such that their product is 324. How to solve |
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Answer» Let first number be xLet the second number be 39-xAccording to the question,(x) (39-x) =32439x-x²=324-x²+39x-324=0-(x²-39x+324)x²-39x+324=0Now splitting the middle termx²-27x+12x+324=0x(x-27)+12(x-27)x=27 or x=-12....I hope this helps you ? I2+27=39 and 12×27=324 No its right question I think its wrong question |
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| 43. |
How to solve trigonometry sum |
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Answer» By using ur own hand ??? By pen By inteligente mind?? by identities |
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| 44. |
How to solve math paper quickly |
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Answer» By fast speed nd intelligent mind...?? Start with 4 marks questions |
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| 45. |
2×999999 |
| Answer» 1999998 | |
| 46. |
Sample papers free me nhi ayega |
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Answer» It is available in net Do u want sample paper Matlab |
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| 47. |
find the sum of first 30 multiples of 11 |
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Answer» 11, 22,33 --------S30 =15{2(11)+29(11)} =15(22+319) =15(341) =5115 jaldi bata do koi fully solved chahiye 5115 |
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| 48. |
Prove that the angle made by the intercept of the circle at its centre is 90 . (100% coming quest.) |
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| 49. |
What will be number of real zeroes of polynomial x square +1? |
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Answer» 2 X=-1 2 |
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| 50. |
If D is HCF of 40 and 65 find the value of integers x and y which satisfy d= 40x+65y. |
| Answer» Very easy one use Euclid division algorithm and point every steps as an equation and then solve it | |