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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
RIMSHA kahan ho yrr plzz come sryy baba |
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| 2. |
Probility |
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| 3. |
What is volume of a cylindrical container having a cone shaped |
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| 4. |
RIMSHA I\'m waiting where r u |
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| 5. |
Hii adiit ab toh message kar do |
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| 6. |
RIMSHA r u online |
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| 7. |
show that any positive integer is of the form 4q +1 or 4q + 3, where q is some integer. |
| Answer» By Euclid\'s division algorithm,a = bq + r = 4q + rTake b = 4.Since, 0 {tex}\\leqslant{/tex}\xa0r < 4, r = 0,1, 2, 3{tex} a=4q,4q+1,4q+2 ,4q+3{/tex}Clearly, a =4q=2(2q) and\xa04q+2=2×(2q+1)So 4q and 4q+2 are evenTherefore 4q + 1, 4q + 3 are odd, as they are proceeding numbers of even numbers 4q and 4q+2.{tex}\\therefore{/tex}\xa0Any positive odd integer is of form 4q+1 or 4q+3 .Where q is a positive integer. | |
| 8. |
Hey dear RIMSHA come here plzz |
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| 9. |
What is polinomial |
| Answer» Expression in form of a1+a2x+a3(x)2.... | |
| 10. |
2x2 _7x +3=0 method of completing square |
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| 11. |
3-6+3_6/6 |
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| 12. |
Wlcmm frndzzz |
| Answer» No function | |
| 13. |
Hii sahil kya Kar rahe ho |
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| 14. |
Find the values ofall the trigonometric |
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| 15. |
Yaha kisko maths pasand h?? |
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| 16. |
Hii sahil kaha ho |
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| 17. |
If the edge of a cube is increased by 50 percent.what is the increase in his volume |
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| 18. |
What is the ratio of [x-3] and [ 3x-7] |
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| 19. |
(x-5)(x-6)=25/576;x=? |
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| 20. |
Find the value of k for which root are real and equal .K2x2 - 2(2k - 1)x + 1 |
| Answer» {tex}k^2x^2-2(2k-1)x+1{/tex}on comparing with standard quadratic equation, we get a = k2, b = 2(2k-1) and c = 1\xa0For real and equal roots. D = 0\xa0=> b2-4ac = 0\xa0{tex}[2(2k-1)]^2-4\\times k^2\\times 1= 0\\\\=> 4(4k^2+1-4k)-4k^2=0\\\\=> k^2+1-4k-k^2=0\\\\=> 1 = 4 k \\\\=> k = {1\\over 4}{/tex} | |
| 21. |
Find area of quadrant of a circle whose circumference is 44 Cm.??? |
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Answer» 38.5cm^2 It is wrong ans.mil gya 77/2 h. Maybe 154/7 cm^2 |
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| 22. |
Hey supriya from where r u |
| Answer» From UP ..Pankaj | |
| 23. |
Aditi ek br message karo mujhe mai apko irritate nhi karunga bs kuch baat karni h |
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| 24. |
Sahil answer me please |
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| 25. |
Aditi jaldi ise number pe 8826277849 message karo |
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| 26. |
Can you tell me the time table of class 10th ?? |
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| 27. |
The circumference of a 9 M high wooden cone is 44 M find the surface area of the cone |
| Answer» Let radius of the base be r m; h = 9 mCircumference of the base = 2{tex}\\pi{/tex}r = 44m{tex}\\Rightarrow 2 \\times \\frac { 22 } { 7 } \\times r = 44{/tex}r = 7 mVolume of the cone =\xa0{tex}\\frac { 1 } { 3 } \\pi r ^ { 2 } h = \\frac { 1 } { 3 } \\times \\frac { 22 } { 7 } \\times ( 7 ) ^ { 2 } \\times 9 \\mathrm { m }^3{/tex}{tex}= \\frac { 1 } { 3 } \\times 22 \\times 7 \\times 9 \\mathrm { m } ^ { 3 }{/tex}= 22\xa0{tex}\\times{/tex}\xa021 m3= 462 m3 | |
| 28. |
Find the coordinates of the point a y axis which is nearest to the point (2,5) |
| Answer» The point on y-axis that is nearest to the point(2,5) is (0,5). | |
| 29. |
Gud ni8 gyyss swtt dream |
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| 30. |
7-/3 |
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| 31. |
One zero of polynomial 3x³ +16x²+15x-18 is 2/3find other zeroes of polynomial |
| Answer» The given polynomial p(x)=3x3+16x2+15x-18Since\xa0{tex}\\frac { 2 } { 3 }{/tex} is a zero of p(x), so\xa0{tex}\\left( x - \\frac { 2 } { 3 } \\right){/tex} is a factor of p(x).{tex}\\Rightarrow{/tex}\xa0(3x - 2) is also factor of p(x)On dividing p(x) by (3x - 2) , we getSo f(x)=(3x-2)(x2+6x+9)= (x2\xa0+ 3x + 3x + 9)(3x - 2)=[x(x+3)+3(x+3)](3x-2)= (x + 3)(x + 3)(3x - 2){tex}\\therefore{/tex}\xa0x = -3 or x = -3 or x =\xa0{tex}\\frac { 2 } { 3 }{/tex}Thus, the other two zeros are -3, -3. | |
| 32. |
How many marks of unit 6 is there |
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| 33. |
Anjli Pragya RIMSHA come where r u |
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| 34. |
Show that exactly 1of the number n, n+2 or n+4 is divisible by 3 |
| Answer» Let n =3kthen n + 2 = 3k + 2and n + 4 = 3k + 4Case 1: When n=3k ,n is divisible by 3 ............(1)n + 2 = 3k + 2or, n + 2 is not divisible by 3n + 4 = 3k + 4= 3(k + 1) + 1or, n + 4 is not divisible by 3Case 2:When n=3k+1, n is not divisible by 3\xa0n + 2 = (3k + 1) + 2=3k + 3 = 3(k + 1){tex} \\Rightarrow{/tex}\xa0n+ 2 is clearly divisible by 3..........................(2)n + 4 = (3k + 1) + 4= 3k + 5= 3(k + 1) + 2{tex}\\Rightarrow{/tex}\xa0n + 4 is not divisible by 3Case 3:When n=3k+2,n is not divisible by 3\xa0n + 2 = (3k + 2) + 2= 3k + 4(n + 2) is not divisible by 3x + 4 = 3k + 6 = 3(k + 2){tex}\\Rightarrow{/tex}\xa0n + 4 is divisible by 3........................(3)Hence, from (1),(2) and (3) it is clear that\xa0exactly one of the numbers n, n + 2, n + 4, is divisible by 3. | |
| 35. |
Aditi hme bhul gyi kya ??? |
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| 36. |
Hey RIMSHA aapko meri wjh she problem ho rhi h Sryyy ab aap jao |
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| 37. |
A right circular cone of radius 3 cm and CSA is47.1 find volume |
| Answer» Given, Radius of the cone, r = 3cmCurved surface area of the cone = 47.1 cm2\xa0{tex}\\pi r l = 47.1{/tex}{tex}\\therefore \\quad l = \\frac { 47.1 } { 3 \\times 3.14 } = 5 \\mathrm { cm }{/tex}{tex}h = \\sqrt { 5 ^ { 2 } - 3 ^ { 2 } } = 4 \\mathrm { cm }{/tex}Slant\xa0height of the cone = 5cmHeight of the cone = 4cmVolume of cone\xa0{tex}= \\frac { 1 } { 3 } \\pi r ^ { 2 } h{/tex}{tex}= \\frac { 1 } { 3 } \\times 3.14 \\times 3 \\times 3 \\times 4{/tex}{tex}= 37.68 \\mathrm { cm } ^ { 3 }{/tex}Volume of the cone = 37.68cm3 | |
| 38. |
The sum of n terms of an AP is 3n2+5. Find the AP hence find 15 term |
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| 39. |
Hey BAJRANGI abe kahan hai tu saale kya comment kiya h tune |
| Answer» Gaali bhi de raha hai aur keh raha hai ki mei gaali nahi de raha abb. Samj me ayaa tuuu topa hai | |
| 40. |
Prove 5 is irrational |
| Answer» Let 5 is rational than... | |
| 41. |
Hey SHIVIKA where\'s your question |
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| 42. |
Where is your question SHIVIKA |
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| 43. |
If p-1,p+3,3p-1 are in AP , then p is equal to what? |
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Answer» 2 shayad P=4 |
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| 44. |
Find the coordinates of points sown in the diagram |
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| 45. |
??????????Santa is coming!??????????Santa is coming!?????Santa is coming!??????????Santa is coming! |
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| 46. |
Sim 45 |
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| 47. |
If the sum of an AP is 2n×2n+5n, then find its nth term |
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| 48. |
Blue print of the 12th class |
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| 49. |
The sum of first nth term of AP is 3n2+6n.Find nth term of AP |
| Answer» Here it is given that sum of first n terms\xa0is equal to Sn\xa0= 3n2\xa0+ 6n\xa0Now,\xa0Sn-1\xa0= 3(n - 1)2\xa0+ 6(n - 1)= 3(n2\xa0- 2n + 1) + 6n - 6= 3n2\xa0- 6n + 3 + 6n - 6= 3n2\xa0- 3Therefore nth term, Tn\xa0= Sn\xa0- Sn-1\xa0= 3n2\xa0+ 6n - 3n2\xa0+ 3 | |
| 50. |
Badshaaoo |
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