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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Jis triangle ki 2 side equal ho |
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Answer» Isosceles triangle Isosceles triangle Isosceles triangle Isosceles Isosceles triangle |
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| 2. |
What\'s the angle elevation of shadow of a man equal to the length of the man |
| Answer» 45° | |
| 3. |
(N+1)(n+2) |
| Answer» Nn+2n+1n+2 | |
| 4. |
How 2and 2 makes 5 ? |
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Answer» By mistake. T W O + TO=No of digits=5 |
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| 5. |
What are irrational no. |
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| 6. |
Show that any positive odd integer is of the form 6q+1,or 6q+3,or 6q+5, where q is some integer |
| Answer» Let a be any positive integer and b = 6∴ by Euclid’s division lemmaa = bq + r, 0≤ r and q be any integer q ≥ 0∴ a = 6q + r,where, r = 0, 1, 2, 3, 4, 5If a is even then then remainder by division of 6 is 0,2 or 4Hence r=0,2,or 4or A is of form 6q,6q+2,6q+4As, a = 6q = 2(3q), ora = 6q + 2 = 2(3q + 1), ora = 6q + 4 = 2(3q + 2).If these 3 cases a is an even integer.but if the remainder is 1,3 or 5 then r=1,3 or 5or A is of form 6q+1,,6q+3 or,6q+5Case 1:a = 6q + 1 = 2(3q) + 1 = 2n + 1,\xa0Case 2: a = 6q + 3 = 6q + 2 + 1,= 2(3q + 1) + 1 = 2n + 1,\xa0Case 3: a = 6q + 5 = 6q + 4 + 1= 2(3q + 2) + 1 = 2n + 1This shows that odd integer is of the form 6q + 1, or 6q + 3, or 6q + 5, where q is some integer. | |
| 7. |
tan^2A-tan^2B |
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| 8. |
(tan +sec-1)÷(tan- sec +1) |
| Answer» L.H.S={tex}\\frac { \\tan \\theta + \\sec \\theta - 1 } { \\tan \\theta - \\sec \\theta + 1 }{/tex}{tex}= \\frac { ( \\tan \\theta + \\sec \\theta ) - \\left( \\sec ^ { 2 } \\theta - \\tan ^ { 2 } \\theta \\right) } { \\tan \\theta - \\sec \\theta + 1 }{/tex}\xa0{tex}[\\because sec^2\\theta-tan^2\\theta=1]{/tex}{tex}= \\frac { ( \\tan \\theta + \\sec \\theta ) - ( \\sec \\theta - \\tan \\theta ) ( \\sec \\theta + \\tan \\theta ) } { \\tan \\theta - \\sec \\theta + 1 }{/tex}{tex}= \\frac { ( \\tan \\theta + \\sec \\theta ) [ 1 - \\sec \\theta + \\tan \\theta ] } { \\tan \\theta - \\sec \\theta + 1 }{/tex}=\xa0{tex}tan\\theta+sec\\theta{/tex}= R.H.S.Hence Proved. | |
| 9. |
Sahil ab hum nhi milenge sorry |
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| 10. |
Sahil tum essa q Kar rahe ho |
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| 11. |
Byee |
| Answer» | |
| 12. |
Vikash tu h??? Yaha |
| Answer» | |
| 13. |
Using euclid division algorithm find whether the pairs of numbers 847,2160 are co prime or not? |
| Answer» 2160=847×2+466847=466×1+281466=281×1+185281=185×1+96185=96×1+8996=89×1+789=7×12+57=5×1+25=2×2+12=1×2+0Therefore..... HCF=1As 1is the factor then it is a co prime no. | |
| 14. |
If the roots of the equation a×a |
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| 15. |
Find k so that the point P(-4,6) lies on the line segment joining A(k,10) and B(3,-8). |
| Answer» If P (-4, 6) lies on the line segment joining A (k, 10) and B (3, -8), then P, A and B are collinear.{tex} \\therefore{/tex}(-4 {tex} \\times{/tex}\xa010 + k {tex} \\times{/tex}\xa0-8 + 3 {tex} \\times{/tex}\xa06) - (6k + 30 + -4 {tex} \\times{/tex}\xa0-8) = 0{tex} \\Rightarrow{/tex}(-40 - 8k + 18) - (6k + 30 + 32) = 0{tex} \\Rightarrow{/tex}(-22 - 8k) - (6k + 62) = 0{tex} \\Rightarrow{/tex}\xa0-14k - 84 = 0{tex} \\Rightarrow{/tex}\xa0k = - 6Suppose P divides AB in the ratio {tex} \\lambda{/tex}: 1. Then, the coordinates of Pare {tex} \\left( \\frac { 3 \\lambda - 6 } { \\lambda + 1 } , \\frac { - 8 \\lambda + 10 } { \\lambda + 1 } \\right){/tex}.But, the coordinates of P are (-4, 6).{tex} \\therefore \\quad \\frac { 3 \\lambda - 6 } { \\lambda + 1 } = - 4 \\text { and } \\frac { - 8 \\lambda + 10 } { \\lambda + 1 } = 6{/tex}{tex} \\Rightarrow \\quad \\lambda = \\frac { 2 } { 7 }{/tex}Hence, P divides AB in the ratio\xa0{tex} \\frac 27{/tex} : 1 or 2: 7. | |
| 16. |
11th term from the last term of AP 27, 23 , 19 ---- -65 |
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Answer» a= -65 , d = 4 ....find t11 = -65+4×10 = -25 a11 = -25 |
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| 17. |
Hii friends... |
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| 18. |
Probabilty |
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| 19. |
If the 2nd term of an A.P is 8 and the 5th term is 17 find its 19th term? |
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Answer» 59. If 2nd term is 8 So..a,a+d,a+2d....a+d=8................ Equation no.1Then...The 5th term is 17...Again same ...But now it\'s 5th term so ....a+4d=a5 I.e. a+4d=17................... Equation no.2Therefore....From 1 and 2a+d=8a+4d=17Now by elimination method....And subtracting Equation.no.1 from 2 ....We get ......Now a will be cancelled out ....So ...Remaining is...-3d=-9Therefore... d=3....... Equation.no.3.Now putting the value of d in 1 equation ...We get...a+d=8,a+3=8a=8-3Therefore...a=5...Now at the last ....U got a and d so form the AP and get the answer....No no don\'t form AP ...Then we will ...Put all the values in the formula An=a+(n-1)dA19=5+(19-1)×3A19=5+18×3A19=5+54A19=59Therefore....19th term of an AP is 59..., 59 Sorry 59 is correct. Its 59 54. |
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| 20. |
To construct a triangle similar to a given triangle as per given scale factor |
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| 21. |
Which is the smallest 4 digit number |
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| 22. |
1×1×2÷3=4?? How |
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| 23. |
Hlo Sahil |
| Answer» | |
| 24. |
Padhai khatam.......... Is anybody there to chat ??? With me☺️☺️☺️ |
| Answer» | |
| 25. |
Hlo ❤️❤️❤️❤️❤️ |
| Answer» | |
| 26. |
What control and cooridation |
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Answer» It is - working of all organs of the body in sysmetic nd control way to give better response to sitmulus Hii |
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| 27. |
If x^2+(ax/a+x)^2=3a^2;x#-a,then one of the value of x is |
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Answer» 3 Ooo mar gaye |
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| 28. |
Cos 2/5 find the value of 4+4 tan square a |
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| 29. |
A2 |
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| 30. |
If triangles are similar tgen proof that they are congurent |
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| 31. |
RIMSHA.. .... |
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| 32. |
If -4 is a zero of polynomial x^2 - x - (2+2k),then value of k is |
| Answer» K=5 | |
| 33. |
Which chapter have more weitage in maths?????? |
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| 34. |
ABC is aright angled |
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| 35. |
How to solve √2 |
| Answer» Use long division method of sqare root | |
| 36. |
If x=3 is one of quadratic equation x_2kx_6=0, then find the value of k |
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Answer» Hi mate thanks for your help x-2kx-6=0 then x=3 given so putting value of x in equation 3-2k(3)-6=0 , 3-6k=6 , -6k=6-3. , -6k =3 , k=3÷-6 , k =1/2\xa0 K=1/2 |
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| 37. |
Exceeds four times |
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| 38. |
LCM of 12345 |
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| 39. |
Rational no. |
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Answer» 4/8 A no. Which can be written in form of p/q where q is not equal to zero |
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| 40. |
0.32bar in p\\q form |
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Answer» 29/90 32/99 |
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| 41. |
Kriti aap Patna mea kaha rahte ho I\'m too from patna |
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| 42. |
who is apeksha? |
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| 43. |
virat kohli is the best human being |
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| 44. |
akshita .?..... |
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| 45. |
akshita thakur, lets come here |
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| 46. |
Maijoli means |
| Answer» | |
| 47. |
Eva teri freind ka nam gauri sharma haibkya jo baroda mein rehti hai |
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| 48. |
Define relationship in your words |
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| 49. |
Eva u like Gujarati boy |
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| 50. |
Eva from where u r |
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