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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
How to break a root? |
| Answer» The x coefficient must be the sum whereas the number must be the products of the two | |
| 2. |
term 2nd sample paper |
| Answer» Check Sample Papers here :\xa0https://mycbseguide.com/cbse-sample-papers.html | |
| 3. |
Abrhjfyj |
| Answer» ?? | |
| 4. |
If sin theta +cos theta =root3 than prove that tan theta +cot theta =1Plz answer |
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Answer» No prblm... but agar Brainly hota yoh phito bhej deta iski?? Where sin2 + cos2 is 0 so... 1/sincos .. put value of sincos ur answer is this Then solve tan + cot = ie sin/cos +cos/sin... Tke LCM then it will come like this ( sin2 + cos2)/sincos Meine whole square nhi liya tha... Thx so much Ok mil gaya Then took the value of sincos by trnasfering.. Where sin2 + fos2 is 1 .. so 1 + 2sincos =3 So u will get sin2 + cos2 + 2sincos Ha plz yar keh do... Take ur time par plz Then apply (a+b)2 identity on lhs 1st whole sq both the sides Yaar yeh ek priof hai.. yha pr kese.. chlo theek hai i will try Brainly uninstall kar liya kab ka.... Yaha keh do na plzzzzzzzz Kya aap kr rhi ho Hasti plzz add this question to ur Brainly id.. i will send u a picture of this questions answer Plz tell me yar Its very easy hasti ji |
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| 5. |
Hey guys, I feel lonely. Please answer me too |
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Answer» Hi ? hi Hlo |
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| 6. |
What is c&d rule? |
| Answer» It is component and divident rule. Basic rule is that a/b=c/d then a+b/a-b=c+d/c-d | |
| 7. |
J 2X +b 2 +2ab |
| Answer» Is it a2 instead of j2x?? | |
| 8. |
S+t=3;S/4+t/3=6;Solve the following pair of equation |
| Answer» s - t = 3;\xa0{tex}\\frac { s } { 3 } + \\frac { t } { 2 } = 6{/tex}The given pair of linear equations is :s - t = 3...............(1){tex}\\frac { s } { 3 } + \\frac { t } { 2 } = 6{/tex}..........(2)From equation(1),s = t + 3..............(3)Substitute this value of s in equation(2), we get{tex}\\frac { t + 3 } { 3 } + \\frac { t } { 2 } = 6{/tex}{tex}\\Rightarrow \\quad \\frac { 2 ( t + 3 ) + 3 t } { 6 } = 6{/tex}{tex}\\Rightarrow {/tex}2(t + 3) + 3t = 36{tex}\\Rightarrow {/tex}\xa02t + 6 + 3t = 36{tex}\\Rightarrow {/tex}\xa05t + 6 = 36{tex}\\Rightarrow {/tex}\xa05t = 30{tex}\\Rightarrow \\quad t = \\frac { 30 } { 5 } = 6{/tex}Substituting this value of t in equation (3), we gets = 6 + 3= 9therefore the solution is\xa0s = 9, t = 6Verification : Substituting s = 9 and t = 6, we find that both equation (1) and (2) are satisfied as shown below:s - t = 9 - 6 = 3{tex}\\frac { s } { 3 } + \\frac { t } { 2 } = \\frac { 9 } { 3 } + \\frac { 6 } { 2 } = 3 + 3 = 6{/tex}This verifies the solution. | |
| 9. |
Hasti, don\'t you have any questions? You only comment |
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Answer» I asked many questions but no one answered Tere paas nahi hai kya ? |
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| 10. |
Name the point where a tengent of a circle is perpendicular to its radius |
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Answer» Point of contact ☺☺☺☺☺ Point of contact Point of contact Point of contact |
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| 11. |
CosA /1-sinA + 1-sinA/cosA =2sec A |
| Answer» In NCERT | |
| 12. |
Since (1,p/3) is the mid point of the line segment joining the points(2,0) and (0,2/9) |
| Answer» (1,p/3)=(2+0/2 , 0+2/9/2) =1,1/9 P/3=1/9 P=1/3 | |
| 13. |
Prove that Sec sq.A +Cot sq.(90-A)=2Cosec sq.(90-A)-1 |
| Answer» L.H.SSec sq.A+cot sq(90-A)Sec sq.A+tan sq.ASecsqA +(SecsqA -1)2sec sq.A-1R.H.S2cosec sq.A (90-A)-12sec sq.A-1 Therefore,L.H.S=R.H.S | |
| 14. |
Express3835asproduct of its prime factors |
| Answer» 3845 = 5\xa0{tex}\\times{/tex}13{tex}\\times{/tex}59 | |
| 15. |
After how many decimals places, the decimal expansion of 325/2raise to 4*5raise to 3 terminate?? |
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Answer» After 5 places ?? No prblm ji Ok thx Multiply both numerator and denominator by 5.. and then solve Simple division karna hai?? 0.1625 Ok Wait |
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| 16. |
Cos30+sin60/1+cos60+sin30. Find the value of the expression |
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Answer» √3/2 √3+1 Value of expression is 8root 3 /5 √3/2 |
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| 17. |
How many terms of AP 17,15,13,11 must be added to get sum 72 ?explain double answer |
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Answer» -108 28 |
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| 18. |
Hey!!!!! I\'m New here. Anyone will be my frnd here |
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Answer» Ya why not Yes I am Hii Yeah I will Study kaisi chal rahi hai tum sabki Yes Hlo Ye Would u be my frnd In which school do u study What yup Yup |
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| 19. |
What services will be u provide,if two trains r collide |
| Answer» | |
| 20. |
C.B.S.E |
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Answer» ICSE Central Board Of Secondary Education From where are you Central board of secondary education |
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| 21. |
Evaluate sinA+cosA=√3,then prove that tanA + cotA=1 |
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Answer» Now tan=sin /cos and cot =cos /sinTan+cot =sin2+cos2 /sin*cos=1/1=1 (Sin +cos) 2=3Sin2 +cos2+2sin*cos =32sin*cos=2Sin *cos =1 |
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| 22. |
Prove that 1+cos-sin/cos-1+sin. Equals to cosec+cot |
| Answer» Are bhag bae ????? | |
| 23. |
Is any on here |
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Answer» Yaaaa Yess..hii Yes |
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| 24. |
1×1=? |
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Answer» 1 aree bhai 57 hai answer mujh pe believe kar ?? Itna hard nhi aata.... ??? |
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| 25. |
Tan ka formula |
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Answer» Perpendicular /base P/b P/b |
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| 26. |
Rohit |
| Answer» What rohit? | |
| 27. |
In an arranged series of 4n terms which term is median |
| Answer» | |
| 28. |
Find three numbers in A.P. whose sum is 21 and their product is 231. |
| Answer» 3,7,11 | |
| 29. |
(a+b)^2 -2( a^2+b^2)x +a^2-b^2=0 |
| Answer» | |
| 30. |
Sin thita +cos thita =√2 find value of tan thita +cot thita |
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Answer» 2 2 |
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| 31. |
Sin theta+cos theta=√3, pt tan theta+cot theta=1 |
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Answer» Its OK, bye Y r u asking such type of easiest question ...............par type karne kaa Mann nhi h sorry bye |
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| 32. |
Root of 13.6250 |
| Answer» 3. Something ???? | |
| 33. |
Hi guys have u prepared your hindi exam |
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Answer» Hindi to liye he nhii Sanskrit h Bus itna ha app sure ho Samas ,alankar ,ras, vachya Yrr koi muja hindi grammar ma kya kya aha Ra ha batyga I am not sure ppz |
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| 34. |
How to study during exam time |
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Answer» ☺☺☺☺????????? From book ??? |
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| 35. |
5 is an irrational |
| Answer» No. Root5 is irrational Because 5 is terminating number | |
| 36. |
2x+jsjjsksskk |
| Answer» Yeh kaisha question h | |
| 37. |
How we prove identityes |
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Answer» ?? Yeah?? ?? Manasvi.... ????????.....awsm reply Just kidding... Dimag se?? |
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| 38. |
Explain why 13233343563715 is a composite number ? |
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Answer» Because it has three factors 3(1*1*3*1*1*1*4*1*5*6*1*7*1*5)Solve it and u will find the answer of your question |
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| 39. |
Explain why 7*11*13+13abd7*6*5*4*3*2*1+5 are composite |
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Answer» Both* more* Bcoz bith hve mire than 1 factor |
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| 40. |
Using Euclid division algorithm find HCF of 243 and 625 verify that LCM*Hcf =product of two numbers |
| Answer» | |
| 41. |
What\'s going in this app? |
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Answer» I am new here. It seems as if it\'s an app like what\'s app or facebook. No body is questioning everybody is chatting Oh really .. Chating n qn answering... Chatting |
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| 42. |
What must be added to 6x^5+5x ^4+11x^3-3x^2+x+5 so that it may be exactly divisible by 3x^2-2x+4 |
| Answer» Therefore, we must add -(-17x + 13) i.e. 17x - 13. | |
| 43. |
tan A - cot A=2sec*2A-1/sinAcosA |
| Answer» | |
| 44. |
8)Evaluate sin230cos245 + 4tan230 + ½ sin290-2cos290 + 1/24 |
| Answer» | |
| 45. |
Value of Sin210 |
| Answer» | |
| 46. |
What are acids |
| Answer» Which turn blue litmus to redWhich give H+. Ion on dissolving in water React with base to form salt and waterETC.... | |
| 47. |
Gys r u on brainy app |
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Answer» Me .. ranjandas1 Aru03 Famous , 560 FOLLOWER I\'d :- ranjandas1 Yes me Jo koi bhi h apni I\'d bata da Hn but aaj uninstall kar dungi |
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| 48. |
The perimeter of a triangle is 40 cm and its hypotenus measures 17 cm. Find the area of triangle |
| Answer» 60cmsq. | |
| 49. |
write 3.234 p/Q form |
| Answer» | |
| 50. |
question no.10 of sample question paper 2017 2018 |
| Answer» | |