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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Formula of mid point in coordinate geometry |
| Answer» Numerically, the midpoint of a segment can be considered to be the average of its endpoints. This concept helps in remembering a formula for finding the midpoint of a segment given the coordinates of its endpoints. Recall that the average of two numbers is found by dividing their sum by two.Theorem 102:\xa0If the coordinates of\xa0A\xa0and\xa0B\xa0are (\xa0x\xa01,\xa0y\xa01) and (\xa0x\xa02,\xa0y\xa02) respectively, then the midpoint,\xa0M, of\xa0AB\xa0is given by the following formula\xa0(Midpoint Formula).\xa0\xa0 | |
| 2. |
A square + b square barabar Kya Hota Hai |
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Answer» Kon dakh ka likh diya (a+b)²-2ab Dekh krke likh diye (a+b)whole square +2ab (a+b)ka whole square+2ab |
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| 3. |
2+2=? Tell me plz |
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Answer» By enstien is 5 and common is 4 5... |
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| 4. |
A mettalic sphere 1dm in diameter is beaten into a circular |
| Answer» Ur que.is incomplete | |
| 5. |
Prove that Rute five is irrational |
| Answer» Ncert book me h | |
| 6. |
Evaluate sin45+cos45 |
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Answer» Answer is root2 Soory 2/root2 |
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| 7. |
Solve it (CosecA-sinA)(secA-cosA)(tanA+cotA)=? |
| Answer» (cosecA - sinA) (secA - cosA) (tanA + cotA) =\xa0{tex}= (\\cos ecA - \\sin A)(\\sec A - \\cos A)(\\tan A + \\cot A){/tex}{tex} = \\left( {\\frac{1}{{\\sin A}} - \\sin A} \\right)\\left( {\\frac{1}{{\\cos A}} - \\cos A} \\right)\\left( {\\frac{{\\sin A}}{{\\cos A}} + \\frac{{\\cos A}}{{\\sin A}}} \\right){/tex}\xa0{tex}\\left[ \\begin{gathered} \\because \\cos ecA = \\frac{1}{{\\sin A}},\\sec A = \\frac{1}{{\\cos A}}, \\hfill \\\\ \\tan A = \\frac{{\\sin A}}{{\\cos A}},\\cot A = \\frac{{\\cos A}}{{\\sin A}} \\hfill \\\\ \\end{gathered} \\right]{/tex}{tex} = \\left( {\\frac{{1 - {{\\sin }^2}A}}{{\\sin A}}} \\right)\\left( {\\frac{{1 - {{\\cos }^2}A}}{{\\cos A}}} \\right)\\left( {\\frac{{{{\\sin }^2}A + {{\\cos }^2}A}}{{\\cos A\\sin A}}} \\right){/tex}{tex} = \\frac{{{{\\cos }^2}A}}{{\\sin A}} \\times \\frac{{{{\\sin }^2}A}}{{\\cos A}} \\times \\frac{1}{{\\cos A\\sin A}}{/tex}\xa0{tex}\\left[ \\begin{gathered} \\because 1 - {\\sin ^2}A = {\\cos ^2}A,1 - {\\cos ^2}A = {\\sin ^2}A, \\hfill \\\\ {\\sin ^2}A + {\\cos ^2}A = 1 \\hfill \\\\ \\end{gathered} \\right]{/tex}{tex} = \\frac{{\\cos A \\times \\cos A}}{{\\sin A}} \\times \\frac{{\\sin A \\times \\sin A}}{{\\cos A}} \\times \\frac{1}{{\\cos A\\sin A}}{/tex}= 1 | |
| 8. |
Find the area of sector of a circle with radius 6 cm if angle of sector is 60 |
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Answer» Radius =6cm thetha 60 22/7 *6*6 *60/360 18.85cm2 |
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| 9. |
A(-1,0) b(3,1)c(2,2)d(-2,1) |
| Answer» Find kya krna | |
| 10. |
How can we prove 100-100/100-100=2 |
| Answer» Sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry | |
| 11. |
Class 10 math sample paper 2018 |
| Answer» Is aap me milenge | |
| 12. |
2×4÷8 |
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Answer» Abe BODMAS nhi pata kya 1 4 1 |
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| 13. |
Explain about real no |
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Answer» Imaginary no = √-3 ...it is solved by iota concept ( in 12th ) Rational and irrational combinally called real no Firstly u tell me what is imaginary number Real no.. Are 1234567890 |
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| 14. |
What is identity |
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Answer» An eq which is always true . ex :- x = x From trigonometry It\'s math bro From math ?? Or english |
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| 15. |
Find the value of 1°cos 2°cos 3℃......cos180° |
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Answer» O 0 0 |
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| 16. |
Sin15°= |
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Answer» 1/4 1/2 U want formulation also ? ? It us 11th concept !! Ncert book ch-3 question !! So easy ? Or sin (45-30) Cos (90-15) = cos75 or 0.605 Sin15° is not correct Q. √3 - 1 / 2√2 .65 |
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| 17. |
Show that exactly one of the number n,n+2 or ,n+4 is divisible by 3 |
| Answer» Let n =3kthen n + 2 = 3k + 2and n + 4 = 3k + 4Case 1: When n=3k ,n is divisible by 3 ............(1)n + 2 = 3k + 2or, n + 2 is not divisible by 3n + 4 = 3k + 4= 3(k + 1) + 1or, n + 4 is not divisible by 3Case 2:When n=3k+1, n is not divisible by 3\xa0n + 2 = (3k + 1) + 2=3k + 3 = 3(k + 1){tex} \\Rightarrow{/tex}\xa0n+ 2 is clearly divisible by 3..........................(2)n + 4 = (3k + 1) + 4= 3k + 5= 3(k + 1) + 2{tex}\\Rightarrow{/tex}\xa0n + 4 is not divisible by 3Case 3:When n=3k+2,n is not divisible by 3\xa0n + 2 = (3k + 2) + 2= 3k + 4(n + 2) is not divisible by 3x + 4 = 3k + 6 = 3(k + 2){tex}\\Rightarrow{/tex}\xa0n + 4 is divisible by 3........................(3)Hence, from (1),(2) and (3) it is clear that\xa0exactly one of the numbers n, n + 2, n + 4, is divisible by 3. | |
| 18. |
Where can i get free sample papers online? |
| Answer» This app,google n many apps r there | |
| 19. |
Find a point on the y axis which is equidistant from the point A(6,5) and B(–4,3) |
| Answer» By distance formula (0,9) y = 9 is answer | |
| 20. |
Is there is step marking also |
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Answer» Step by step he marking hoti hai What |
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| 21. |
Do you have the marking scheme of pre board 2017-18 |
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Answer» Are bta do apke pass marking scheme h ya ni See in this aap |
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| 22. |
The diameter of a wheel is 1.26m what the distance covered in 500 revolution |
| Answer» Diameter of the wheel = 1.26 mradius = 1.26/2 =0.63mThe diatnce travelled in one revolution = perimeter of the wheel = 2π r= 2 x 3.14 x 0.63 = 3.95 mDiatnce travelled in 500 revolutions = 500 X 3.95 m = 1975 m | |
| 23. |
Find the value of k so that the zeros of quadratic polynomial 3xsquare-kx+14 are in the ratio 7:6 |
| Answer» -13 | |
| 24. |
Show the points (-2,3)(8,3)and(6,7) are the vertices of right angle triangle |
| Answer» Let A(-2,3) ,B(8,3) and C(6,7) be the vertices of a given triangle.Then,{tex}(AB)^2=(8+2)^2+(3-3)^2=(10)^2+0^2=100{/tex}{tex}{/tex}{tex}(BC)^2=(8-6)^2+(3-7)^2=2^2+4^2=4+16=20{/tex}{tex}(AC)^2=(-2-6)^2+(3-7)^2=8^2+4^2=64+16=80{/tex}Clearly,\xa0{tex}(AB)^2=(AC)^2+(BC)^2{/tex}Therefore, A(-2,3),B(8,3) and C(6,7) are the vertices of right-angled triangle. | |
| 25. |
Lorthigrams |
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Answer» Hii Hi Kya kare bro iska |
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| 26. |
Find the number of terms in each of the following AP\'s. 7,13,19,.........205 |
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Answer» a+(n-1)dFirst term ....7 nd differences....67+(n-1)6=2057+6n-6=205.......6n=204.....n = 34 34 36 34 An = a +(n-1)d wala formula laga do |
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| 27. |
9×99 |
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Answer» 891 Use calculater |
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| 28. |
Prove that(CosecA-3sinA)(secA-cosA)=1/tanA+cotA |
| Answer» We haveL.H.S. =\xa0(cosecA - sinA)(secA - cosA){tex}= \\left( \\frac { 1 } { \\sin A } - \\sin A \\right) \\left( \\frac { 1 } { \\cos A } - \\cos A \\right) = \\left( \\frac { 1 - \\sin ^ { 2 } A } { \\sin A } \\right) \\cdot \\left( \\frac { 1 - \\cos ^ { 2 } A } { \\cos A } \\right){/tex}{tex}= \\frac { \\cos ^ { 2 } A \\sin ^ { 2 } A } { \\cos A \\sin A }{/tex}\xa0= cosA.sinA.R.H.S. =\xa0{tex}\\frac { 1 } { ( \\tan A + \\cot A ) } = \\frac { 1 } { \\left( \\frac { \\sin A } { \\cos A } + \\frac { \\cos A } { \\sin A } \\right) }{/tex}{tex}= \\frac { \\cos A \\sin A } { \\left( \\sin ^ { 2 } A + \\cos ^ { 2 } A \\right) } = \\cos A \\sin A{/tex}\xa0[{tex}\\because{/tex} sin2A + cos2A = 1]Hence, L.H.S. = R.H.S. | |
| 29. |
An acute angle |
| Answer» So what | |
| 30. |
Find the value of cos theta sin theta is equal to a over b |
| Answer» | |
| 31. |
Smallest 6 digit number exactly divisible by 15,24 and 36 |
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Answer» 99640???? But kya Ans shi koi batayga Thanku undisputed ji... 99280 Hmmm Maybe It\'s greatest May be. 999279 |
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| 32. |
Surface area volume |
| Answer» Check revision notes here :\xa0https://mycbseguide.com/cbse-revision-notes.html | |
| 33. |
Prove that : (1+cotA-cosecA)(1+tanA+secA)=2 |
| Answer» | |
| 34. |
If sin(2x +3y)=1 and cos (2x-3y)=√3\\2 find the value of x and y |
| Answer» Sin 2x+3y =1Sin 2x+3y =sin 902x+3y=90. eq 1Now Cos 2x-3y=√3/2Cos 2x-3y=cos302x-3y=30. Eq 2Adding 2x+3y+2x-3y=90+304x=120X=30. From eq12×30+3y=9060+3y=903y=90-60Y= 10 ie. X=30 ,y=10 answer | |
| 35. |
Which term of the AP 3,15,27,39,... will be 132 more than its 54th term? |
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Answer» Find the 54 term and then add 132 to the result Rs agrawal me hai |
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| 36. |
Some theorem |
| Answer» | |
| 37. |
draw a line segment AB of 7 cm. using ruler and compass find a point P on AB such that AP/AB=3/5 |
| Answer» Steps of construction:\tDraw a line segment AB = 7 cm}\tDraw a ray AX making an acute angle BAX with AB\tAlong AX mark (3 + 5) = 8 points.\tA1, A2, A3, A4, A5, A6, A7, A8\tsuch that AA1\xa0=\xa0A1A2\xa0= A2A3\xa0= A3A4\xa0= A4A5\xa0= A5A6\xa0= A6A7\xa0= A7A8\tJoin A8B.\tThrough the point A3, draw a line parallel to A8B by making an angle equal to\xa0{tex}\\angle{/tex}AA8B at A3.Suppose this line meets AB at a point P.Thus, P is the required point such that\xa0{tex}\\frac { A P } { P B } = \\frac { 3 } { 5 }{/tex}. | |
| 38. |
How to practice the chapter trigonometry?????? |
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Answer» Should be understand the concepts and doing the sums with intrest understanding simple cocepts By doing more and more practice , you understand trignomatry easily By applying partial knowledge By understanding the basic concepts of tigonometry and by learning the formula |
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| 39. |
Difference between linear and quadratic equation |
| Answer» Degree of linear equation is 1 and degree of quadratic equation is 2 | |
| 40. |
find the value of 3 tan²26°- 3 cosec²64° |
| Answer» | |
| 41. |
Important exam question |
| Answer» In this aap | |
| 42. |
NtanB = tanA and MsinB=sinA then p.t m2 -1 / n2+1 = 1 |
| Answer» So easy | |
| 43. |
What is sleep apnea??? |
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Answer» Sleep apnea means frequently stop breathin for 10or more second ? Bhai I am honest if I don\'t know if simply tell Nhi pta..? Donot know Know Don\'t bro.. |
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| 44. |
How to best score in math |
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Answer» Bakwass Hey don\'t practice it only solve Simple practice, practice, practice and practice Perfect practice makes men perfect You can best score in maths by practicing......?? By practicing |
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| 45. |
Will optional exercise come in board exam? |
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Answer» yes they may come ,because according to board in india any ques may come from book ie.ncert What? Yes.... U do....no one knows from where ques.come in board |
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| 46. |
(X+1)=2(x_3 |
| Answer» X equa l. To7 | |
| 47. |
If tana+ tan(2)a=1 then prove that cos(2)a+cos(4)a=1 |
| Answer» | |
| 48. |
Find one solution of the equation 4x-3y-5=0 |
| Answer» | |
| 49. |
Converse of Thales theorem |
| Answer» | |
| 50. |
Which of the following are quadratic equation in x?X2-x+3=0 |
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Answer» ????? Following Q likh raha jb 1 he h to 2nd wala |
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