This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
tan - _ + tan-I + tan- _ + tan |
| Answer» tan - _ + tan-I + tan- _ + tan | |
| 2. |
a cos A+b cos B+c cos C=2b sin A sin C=2 c sin A sin B |
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Answer» a cos A+b cos B+c cos C=2b sin A sin C=2 c sin A sin B |
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| 3. |
Prove that the determinant is independent of θ . |
| Answer» Prove that the determinant is independent of θ . | |
| 4. |
A = {1, 2, 3, 5} and B = {4, 6, 9}. Define a relation R from A to B by R = {( x , y ): the difference between x and y is odd; x ∈ A, y ∈ B}. Write R in roster form. |
| Answer» A = {1, 2, 3, 5} and B = {4, 6, 9}. Define a relation R from A to B by R = {( x , y ): the difference between x and y is odd; x ∈ A, y ∈ B}. Write R in roster form. | |
| 5. |
The most general value of θ satisfying 2sin2θ – 1 = 0 is ______________. |
| Answer» The most general value of θ satisfying 2sin2θ – 1 = 0 is ______________. | |
| 6. |
If A=[1 2−1 3]B=[4 01 5]C=[2 01 −2] a = 4, and b = - 2, then show that (vi) (bA)T = b AT |
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Answer» If A=[1 2−1 3]B=[4 01 5]C=[2 01 −2] a = 4, and b = - 2, then show that (vi) (bA)T = b AT |
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| 7. |
If the lines given by ax2 +2hxy + by2 =0from an equilateral triangle with the lines Lx+my =1then show that (3a+b)(a+3b)-4h2=0 |
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Answer» If the lines given by ax2 +2hxy + by2 =0from an equilateral triangle with the lines Lx+my =1then show that (3a+b)(a+3b)-4h2=0 |
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| 8. |
Which of the following unit vector is coplanar with vectors→A=2ˆi−3ˆj+ˆk and →B=3ˆi−ˆj−3ˆk and orthogonal to the vector →C=8ˆi−5ˆj+2ˆk |
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Answer» Which of the following unit vector is coplanar with vectors |
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| 9. |
If cosec θ + cot θ = 3, then cos θ = _________. |
| Answer» If cosec θ + cot θ = 3, then cos θ = _________. | |
| 10. |
Let f(x)=⎧⎪⎪⎨⎪⎪⎩(72)x−9x−8x+1√2−√1+cosx:x≠0klog2log3;x=0.If f(x) is continuous function at x=0, then √2k= |
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Answer» Let f(x)=⎧⎪ ⎪⎨⎪ ⎪⎩(72)x−9x−8x+1√2−√1+cosx:x≠0klog2log3;x=0. If f(x) is continuous function at x=0, then √2k= |
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| 11. |
If ∞∫0ln(1+x2)1+x2dx=πln√k, then the value of k= |
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Answer» If ∞∫0ln(1+x2)1+x2dx=πln√k, then the value of k= |
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| 12. |
The probability distribution of random variable X is given by:X12345P(X)K2K2K3KKLet p=P(1<X<4|X<3). If 5p=λK, then λ is equal to |
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Answer» The probability distribution of random variable X is given by: X12345P(X)K2K2K3KK Let p=P(1<X<4|X<3). If 5p=λK, then λ is equal to |
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| 13. |
limx→0+{1+tan2√x}12x |
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Answer» limx→0+{1+tan2√x}12x |
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| 14. |
Check the validity of the following statements : (i) p : 100 is a multiple of 4 and 5. (ii) q : 125 is a multiple of 5 and 7. (iii) r : 60 is a multiple of 3 or 5. |
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Answer» Check the validity of the following statements : (i) p : 100 is a multiple of 4 and 5. (ii) q : 125 is a multiple of 5 and 7. (iii) r : 60 is a multiple of 3 or 5. |
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| 15. |
Let the equation of the pair of lines, y=px and y=qx, can be written as (y−px)(y−qx)=0. Then the equation of the pair of the angle bisectors of the lines x2−4xy−5y2=0 is |
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Answer» Let the equation of the pair of lines, y=px and y=qx, can be written as (y−px)(y−qx)=0. Then the equation of the pair of the angle bisectors of the lines x2−4xy−5y2=0 is |
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| 16. |
If [X−Y2−24X6]+[3−2210−1]=[60052X+Y5],then |
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Answer» If [X−Y2−24X6]+[3−2210−1]=[60052X+Y5], |
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| 17. |
If (1+x)n=C0+C1x+C2x2+.......+Cnxnforn∈N and ∑nr=0(r+1)2.Cr=2n−2f(n) If the roots of the equation f(x) = 0 are α and β then (α)4 + (β)4 = |
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Answer» If (1+x)n=C0+C1x+C2x2+.......+Cnxnforn∈N and ∑nr=0(r+1)2.Cr=2n−2f(n) If the roots of the equation f(x) = 0 are α and β then (α)4 + (β)4 = |
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| 18. |
The length of the Subnormal at point P(t) on the parabola y2=8x is equal to |
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Answer» The length of the Subnormal at point P(t) on the parabola y2=8x is equal to |
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| 19. |
Examine the continuity of f , where f is defined by |
| Answer» Examine the continuity of f , where f is defined by | |
| 20. |
The value of the integral ∫sinθ.sin2θ(sin6θ+sin4θ+sin2θ)√2sin4θ+3sin2θ+61−cos2θdθ is(where c is a constant of integration) |
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Answer» The value of the integral ∫sinθ.sin2θ(sin6θ+sin4θ+sin2θ)√2sin4θ+3sin2θ+61−cos2θdθ is |
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| 21. |
A function f:R→R is defined by f(x)=x2. Determine. i) Range of f ii) {x:f(x)=4} iii) {y:f(y)=−1} |
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Answer» A function f:R→R is defined by f(x)=x2. Determine. |
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| 22. |
144.if p is a prime number then prove that p to the power 1/n is irrational where n is greater than 1 |
| Answer» 144.if p is a prime number then prove that p to the power 1/n is irrational where n is greater than 1 | |
| 23. |
let y is equal to sin theta if percentage error in measuring angle at theta is equal to pi by 4 is 2% then the percentage error in bi at that anagallis |
| Answer» let y is equal to sin theta if percentage error in measuring angle at theta is equal to pi by 4 is 2% then the percentage error in bi at that anagallis | |
| 24. |
|3x+2|<1 then x belong to |
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Answer» |3x+2|<1 then x belong to |
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| 25. |
Find the integral: ∫(2x−3cosx+ex)dx |
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Answer» Find the integral: ∫(2x−3cosx+ex)dx |
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| 26. |
If 3∫0sgn(sinx−cosx)dx=a+b⋅π2, then which of the following statement(s) is/are true ? |
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Answer» If 3∫0sgn(sinx−cosx)dx=a+b⋅π2, then which of the following statement(s) is/are true ? |
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| 27. |
Solution of logx2+6x+8log2x2+2x+3(x2−2x)=0 is |
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Answer» Solution of logx2+6x+8log2x2+2x+3(x2−2x)=0 is |
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| 28. |
The radius of a circle with centre O is 25 cm. Find the distance of a chord from the centre if the length of the chord is 48 cm |
Answer» The radius of a circle with centre O is 25 cm. Find the distance of a chord from the centre if the length of the chord is 48 cm![]() |
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| 29. |
Solvethe equation for x,y, zand t if |
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Answer» Solve
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| 30. |
Prove the following.(1) secθ (1 – sinθ) (secθ + tanθ) = 1(2) (secθ + tanθ) (1 – sinθ) = cosθ(3) sec2θ + cosec2θ = sec2θ × cosec2θ(4) cot2θ – tan2θ = cosec2θ – sec2θ(5) tan4θ + tan2θ = sec4θ – sec2θ(6) 11-sinθ+11+sinθ=2 sec2θ(7) sec6x – tan6x = 1 + 3sec2x × tan2x(8) tanθsecθ+1=secθ-1tanθ(9) tan3θ-1tanθ-1=sec2θ+tanθ(10) sinθ-cosθ+1sinθ+cosθ-1=1sinθ-tanθ |
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Answer» Prove the following. (1) secθ (1 – sinθ) (secθ + tanθ) = 1 (2) (secθ + tanθ) (1 – sinθ) = cosθ (3) sec2θ + cosec2θ = sec2θ × cosec2θ (4) cot2θ – tan2θ = cosec2θ – sec2θ (5) tan4θ + tan2θ = sec4θ – sec2θ (6) (7) sec6x – tan6x = 1 + 3sec2x × tan2x (8) (9) (10) |
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| 31. |
In Figure, identify the following vectors. (i) Coinitial (ii) Equal (iii) Collinear but not equal |
| Answer» In Figure, identify the following vectors. (i) Coinitial (ii) Equal (iii) Collinear but not equal | |
| 32. |
The arbitrary constant on which the value of the determinant |
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Answer» The arbitrary constant on which the value of the determinant |
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| 33. |
Determine the continuity of f(x)=x3+2x2−x+4. |
| Answer» Determine the continuity of f(x)=x3+2x2−x+4. | |
| 34. |
33. VERIFY THAT f(x)= x pow(3)/3 - 5x pow(2)/3 +2x, x belongs to [0,3] |
| Answer» 33. VERIFY THAT f(x)= x pow(3)/3 - 5x pow(2)/3 +2x, x belongs to [0,3] | |
| 35. |
In right angled ∆ LMN, ∠LMN = 90° ∠L = 50° and ∠N = 40°, write the following ratios.(i) sin 50° (ii) cos 50° (iii) tan 40° (iv) cos 40° |
Answer» ![]() In right angled LMN, LMN = 90° L = 50° and N = 40°, write the following ratios. (i) sin 50° (ii) cos 50° (iii) tan 40° (iv) cos 40°
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| 36. |
If the greatest integer less than or equal to (√2+1)6 is λ, then the value of (λ−1)49 is |
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Answer» If the greatest integer less than or equal to (√2+1)6 is λ, then the value of (λ−1)49 is |
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| 37. |
If 2x+2f(x)=2 , then the domain of the function f(x) is |
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Answer» If 2x+2f(x)=2 , then the domain of the function f(x) is |
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| 38. |
Find the sum of all two digit numbers which when divided by 4, yields 1 as remainder. |
| Answer» Find the sum of all two digit numbers which when divided by 4, yields 1 as remainder. | |
| 39. |
A unit vector coplanar with →i+→j+3→k and →i+3→j+→k and perpendicular to →i+→j+→k is |
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Answer» A unit vector coplanar with →i+→j+3→k and →i+3→j+→k and perpendicular to →i+→j+→k is |
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| 40. |
1 bc a(b+c1 ab cla+b |
| Answer» 1 bc a(b+c1 ab cla+b | |
| 41. |
The solution of the differential equation (y−xdydx)=a(y2+dydx) is (where k is constant) |
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Answer» The solution of the differential equation (y−xdydx)=a(y2+dydx) is (where k is constant) |
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| 42. |
The area enclosed between the curves y=ax2 and x=ay2 (a > 0) is 1 sq. unit. Then the value of ‘a’ is |
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Answer» The area enclosed between the curves y=ax2 and x=ay2 (a > 0) is 1 sq. unit. Then the value of ‘a’ is |
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| 43. |
The area (in square units) of the quadrilateral formed by the two pairs of lines l2x2−m2y2−n(lx+my)=0 and l2x2−m2y2+n(lx−my)=0 is |
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Answer» The area (in square units) of the quadrilateral formed by the two pairs of lines l2x2−m2y2−n(lx+my)=0 and l2x2−m2y2+n(lx−my)=0 is |
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| 44. |
Differentiate thefollowing w.r.t. x: |
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Answer» Differentiate the
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| 45. |
1. Find all the zeroes of the polynomial x4 − 3x3 − 5x2 + 21x - 14 , if two of itszeroes are √3 and − √3 .2. Find the value of k for which the points ( 3k -1 , k - 2 ), ( k , k - 7 ) and( k - 1 , - k - 2 ). |
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Answer» 1. Find all the zeroes of the polynomial x4 − 3x3 − 5x2 + 21x - 14 , if two of its zeroes are √3 and − √3 . 2. Find the value of k for which the points ( 3k -1 , k - 2 ), ( k , k - 7 ) and ( k - 1 , - k - 2 ). |
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| 46. |
If the curve y=ax12+bx passes through the point (1,2) and y≥0 for 0≤x≤9 and the area enclosed by the curve, the x− axis and the line x=4 is 8 sq. units, then |
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Answer» If the curve y=ax12+bx passes through the point (1,2) and y≥0 for 0≤x≤9 and the area enclosed by the curve, the x− axis and the line x=4 is 8 sq. units, then |
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| 47. |
The fundamental period of the function f(x)=−2cos(3x+π2)= |
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Answer» The fundamental period of the function f(x)=−2cos(3x+π2)= |
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| 48. |
Find thederivative of the following functions from first principle.(i) x3– 27 (ii) (x – 1) (x – 2)(ii) (iv) |
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Answer» Find the (i) x3 (ii) |
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| 49. |
DIFFERENTIATE THE FOLLOWING (x^2+3x)^4 |
| Answer» DIFFERENTIATE THE FOLLOWING (x^2+3x)^4 | |
| 50. |
Let θ,ϕ∈[0,2π] be such that 2cosθ(1−sinϕ)=sin2θ(tanθ2+cotθ2)cosθ−1,tan(2π−θ)>0 and -1 < sinθ<−√32. Then ϕ cannot satisfy |
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Answer» Let θ,ϕ∈[0,2π] be such that 2cosθ(1−sinϕ)=sin2θ(tanθ2+cotθ2)cosθ−1,tan(2π−θ)>0 and -1 < sinθ<−√32. Then ϕ cannot satisfy |
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