459 + Interview Questions in GENETICS-&-MOLECULAR-BASIS-OF-INHERITANCE-AND-MUTATION IN GENERAL AWARENESS Page 7 InterviewSolution

301.	Assertion :-The unmodified allele, which represents the orginal phenotype is the dominant allele and the modified allele is generally the recessive allele. Reason :- The modified allele could be responsible for production of a non functional enzyme or no enzyme at al.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are trur but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is Flase.D. If both Assertion & Reason are false.
Answer» Correct Answer - A

Discussion

302.	When two independentaly assorting dominant genes interact whth each other to produce perticular phenotype but when they present alone they did not produce phenotype they are called :-A. Complementry geneB. Supplementary geneC. Dumplecate geneD. inhibitory gene
Answer» Correct Answer - A

Discussion

303.	AB-Blood group shows :-A. CO-dominanceB. Complete dominanceC. Mixed inheritanceD. Composite inheritance
Answer» Correct Answer - A

Discussion

304.	In sea urchin DNA, which is double stranded, 17% of the bases were show to be cytosine. The percentages of the other three bases expected to be present in this DNA areA. ` G 17%, A 16.5%, T32.5%`B. `G 17%, A 33%, T 33%`C. `G 8.5%, A50%, T24.5%`D. `G 34%, A24.5%, T24.5%`
Answer» Correct Answer - B

Discussion

305.	Complete linkage is found inA. BirdsB. SnakesC. Female-DrosophilaD. Male - Drosophila
Answer» Correct Answer - D

Discussion

306.	A phenomenon which works opposite to the linkage isA. Independent assortmentB. Crossing-overC. SegregationD. Mutation
Answer» Correct Answer - B

Discussion

307.	The recessive genes located on X-chromosome in humans are always:A. Expressed in femalesB. LetalC. Sub-lethalD. Expressed in males
Answer» Correct Answer - D

Discussion

308.	Mendel obtained wrinkled seeds in pea due to deposition of sugars instead of starch. It was due to which enzyme :-A. AmylaseB. InvertaseC. DiastaseD. Absence of starch branching enzyme
Answer» Correct Answer - D

Discussion

309.	Assertion :- Packaging of chromatin at higher lever required additional set of proteins. Reason : Non histone chromsomal proteins provide scaffold for packaging of chromatin.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are trur but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is Flase.D. If both Assertion & Reason are false.
Answer» Correct Answer - A

Discussion

310.	In the base sequence of one strand of DNA is `GAT, TAG, CAT, GAC` what shall be the sequence of its complementary strand -A. `CAT, CTG, ATC, GTA`B. `GTA, ATC, CTG, GTA`C. `ATC, GTA, CTG, GTA`D. `CTA, ATC, GTA, CTG`
Answer» Correct Answer - D

Discussion

311.	Assertion :- The split-gene arrangement complicates the definition of a gene in terms of a DNA segment. In eukaryotes the monocistronic structural genes have interrupted coding sequence.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are trur but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is Flase.D. If both Assertion & Reason are false.
Answer» Correct Answer - B

Discussion

312.	Assertion :- RNA viruses having shorter life span and evolve faster. Reason : In RNA rate of mutations is slower than DNA.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are trur but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is Flase.D. If both Assertion & Reason are false.
Answer» Correct Answer - C

Discussion

313.	The most polpularly known blood grouping is the ABO grouping. It is named ABO and not ABC, because, because "O" in it refers to havingA. No antigens A and B on RBCsB. Other antigens besides A and B on RBCsC. Overdominance of this type on the genes for A and B typesD. One antibody only - either anti-A-or andti-B- on the RBCs
Answer» Correct Answer - A

Discussion

314.	Which is incorrect - ABO blood groups are controlled by the gene I Gene I has four alleles (iii) `A^(I)and I^(B)` produce same type of suger (iv) I or `I^(@)` produce different type of sugar (v) `I^(A) and I^(B)` are incomplete dominantA. I,iiB. iiC. ii, iii, ivD. ii, iii, iv, v
Answer» Correct Answer - D

Discussion

315.	Blood grouping in human beings is controlled byA. 4 alleles in which `I^(A)` is dominantB. 3 alleles in which `I^(A) and I^(B)` are dominantC. 2 alleles in which none is dominantD. 3 alleles in which `I^(A)` is recessive
Answer» Correct Answer - B

Discussion

316.	There are two alleles `(A_(1)&A_(2))` out of which one `(A_(1))` has nil abundance in a population then the abundance of second allele `(A_(2))` is :-A. `0.25`B. `1.00`C. `0.40`D. `0.50`
Answer» Correct Answer - B

Discussion

317.	Mendel formulated the law of purity of gametes on the basis of:A. Dihybrid crossB. monohybrid crossC. Back crossD. Test cross
Answer» Correct Answer - B

Discussion

318.	Assertion :- The segregation of alleles in a random process and so there is a `50%` chance of a gamete containing either allele. Reason :- By the process of mitosis, the alleles of the parental pair separtes from each other & only one allele in transmitted to a gamete.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are trur but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is Flase.D. If both Assertion & Reason are false.
Answer» Correct Answer - C

Discussion

319.	Two crosses between the same pair of genotypes or phenotypes in which the sources of the gametes are reversed in one cross, is known as:A. Test crossB. Reciprocal crossC. Dihybrid crossD. Reverse cross
Answer» Correct Answer - B

Discussion

320.	A self-fertilizing trihybrid plant formsA. 8 different gametes and 32 different zygotesB. 8 different gametes and 64 different zygotesC. 4 different gametes and 16 different zygotesD. 8 different gametes and 16 different zygotes
Answer» Correct Answer - B

Discussion

321.	Which statement is incorrect about linkage-A. It helps in maintaining the value traits of new varietiesB. It helps in forming new recombinantsC. Knowledge of linkage helps to breeder to combine all desirable traits in a single variety.D. It helps in locating genes on chromosome
Answer» Correct Answer - B

Discussion

322.	A woman with normal vision,but whose father was colour blind,marries a colour blind man.Suppose that the fourth child of this couple was a boy .This boy:A. Must have normal colour visionB. May be colour blind or may be normal visionC. Will be partially colour blind since he is heterozygous for the colour blind mutant alleleD. Must be colour blind
Answer» Correct Answer - B

Discussion

323.	cDNA probes are copies from the messenger RNA molecules with the help of :A. Restrication enzymesB. Reverse transcriptaseC. DNA polymeraseD. Adensosine deaminase
Answer» Correct Answer - B

Discussion

324.	What is the first step in the Southern Blot techniqueA. Denaturation of DNA on the gel for hybridization with specific probeB. Production of a group of genetically identical cellsC. Digestion of DNA by restrication enzymeD. Isolation of DNA from a nucleated cell such as the one from the scane of crime
Answer» Correct Answer - A

Discussion

325.	Assertion :- The development & differentiation of embryo into adult organism are the result of coordinated regulation of expression of several sets or genes. Reason : The expression of all genes are not required simultaneously during development of organism.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are trur but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is Flase.D. If both Assertion & Reason are false.
Answer» Correct Answer - A

Discussion

326.	R and y genes of Maize lie very close to each other . When RRYY and rryy gneotypes are hybridised , `F_(2)` genertion will showA. Higher number of the recombination types. B. Segregation in the expected `9:3:3:1` ratio.C. Segregation in `3:1` ratio.D. Higher number of the parental types
Answer» Correct Answer - D

Discussion

327.	Differentiation of organs and tissues in a develping organism, is assoiated withA. Developmental mutationsB. Differetial expression of genesC. Lethal mutationsD. Deletion of genes
Answer» Correct Answer - B

Discussion

328.	R and y genes of Maize lie very close to each other . When RRYY and rryy gneotypes are hybridised , `F_(2)` genertion will showA. Higher number of the recombination types.B. Segregation in the expected `9:3:3:1` ratio.C. Segregation in `3:1` ratio.D. Higher number of the parental types
Answer» Correct Answer - D

Discussion

329.	Inheritance of skin colour in humans in an example of :-A. chromosomal aberrationB. point mutationC. Polygenic inheritanceD. codominance
Answer» Correct Answer - C

Discussion

330.	In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeds plant is crossed wit a green seeded plant, what ratio of yellow and green seeded plants would you expect in `F_(1)` generation :-A. `50:50`B. `9:1`C. `1:3`D. `3:1`
Answer» Correct Answer - A

Discussion

331.	How many different types of gametes can be formed by `F_(1)` progent, resulting from the following cross : AA BB CC x aa bb ccA. 3B. 8C. 27D. 64
Answer» Correct Answer - B

Discussion

332.	I the cell of n organism heterozygous for two pairs of genes represented by Aa, Bb, undergoes meiosis, then the possible genotypic combination of gametes will be :-A. AB, Ab, aB, abB. AB, abC. Aa, BbD. A, a, B, b
Answer» Correct Answer - A

Discussion

333.	Hybrid of pure red flowered and white flowered Pea is crossed to pure red flowered plant. The progeny shall beA. All red flowered plantsB. White flowered plantsC. `50%` red and `50%` white flowered plantsD. 3 Red : 1 white flowered plants
Answer» Correct Answer - A

Discussion

334.	A cross between AaBB X aa BB yields a genotypic ratio of :-A. 1 AaBB: 1 aaBBB. 1 AaBB : 3 aaBBC. 3AaBB: 1 aa BBD. All AaBB
Answer» Correct Answer - A

Discussion

335.	Cross between recessive parent and `F_(1)` hybrid is called :A. Back crossB. Teat crossC. Monohybrid crossD. Dihybrid cross
Answer» Correct Answer - B

Discussion

336.	A pure tall and a pure dwarf plant were crossed to produce offsprings. Offsprings were self crossed, then find out the ratio between true breeding tall to true breeding dwarf?A. `1:1`B. `3:1`C. `2:1`D. `1:2:1`
Answer» Correct Answer - A

Discussion

337.	What shall be the ratio of hetorozygous, homozygous and colourblind hemizygous in offsprings of a colour blind husbnad & a carrier wife :-A. `1:1:2`B. `1:1:1`C. `2:1:1`D. `1:2:1`
Answer» Correct Answer - B

Discussion

338.	When `F_(1)` generation hybrid tall Tt is crossed with dwarf tt parent, it is a case of :-A. Dihybrid crossB. test crossC. Crossing overD. Reciprocal cross
Answer» Correct Answer - B

Discussion

339.	When a tall plant with rounded seeds (TTRR) is crossed with a dwarf plant with wrinkled seeds (ttrr), the `F_(1)` generation consists of tall plants with rounded seeds. How many types of gamets an `F_(1)` plant would produceA. OneB. ThreeC. FourD. Eight
Answer» Correct Answer - C

Discussion

340.	In monohybrid cross what is the ratio of homozygous dominant and homozygous recessive individuals in `F_(2)` generation :-A. `1:2:1`B. `2:1//1:2`C. `3:1//1:3`D. `1:1`
Answer» Correct Answer - D

Discussion

341.	A diseased man marries a normal woman.They get three daughters and five sons were normal . The gene of this disease is :A. Sex linked dominantB. Sex linked recessiveC. Sex limited characterD. Autosomal dominant
Answer» Correct Answer - A

Discussion

342.	If a homozygous tall plant is crossed with a dwarf plant, what shall be the ratio of plants in offsprings :-A. All heterozygous tallB. Two tall & Two dwarfC. `1:2:1`D. All homozygous dwarf
Answer» Correct Answer - A

Discussion

343.	Heterozygous tall plant (Tt) is crossed with homozygous dwarf (tt) plant. Then what will be the percentage of dwarf plants in the next generation?A. `25%`B. `100%`C. `75%`D. `50%`
Answer» Correct Answer - D

Discussion

344.	In a Random mating population of `28,800` individuals percentage of dominant homozygous individuals is `49%` find out the precentage of heterozygous individual -A. `21%`B. `42%`C. `32%`D. `9%`
Answer» Correct Answer - B

Discussion

345.	A cross used to ascertian whether a dominant is homozygous or heterozygous is termed :A. ReciprocalB. Back crossC. Test crossD. Monohybrid
Answer» Correct Answer - C

Discussion

346.	Haemolytic jaundice is due to dominant gene but only `20%` of the people develop this disease. A heterozygous man marries a homozygous normal wiman. What proportion of the children in population would be expected th have this disorder :-A. `1/5`B. `1/20`C. `1/10`D. `1/2`
Answer» Correct Answer - C

Discussion

347.	From a single ear of corn, a farmer planted 200 kernals which produced 140 tall and 40 dwarf plants. The genotype of these offsprings are most likelyA. TT, Tt & ttB. TT & ttC. TT & TtD. Tt & tt
Answer» Correct Answer - A

Discussion

348.	A useful process for determining whether an individual is homozygous or heterozygous is :-A. Cross-breedingB. Self fertilizationC. Back-crossingD. Test cross
Answer» Correct Answer - D

Discussion

349.	Assertion :- Most of the X-linked disorders can not be eliminated easily formanature and our gene pool. Reason : X-linked dosorders are due to recessive genes.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are trur but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is Flase.D. If both Assertion & Reason are false.
Answer» Correct Answer - A

Discussion

350.	Short legged variety of sheep is an example of :-A. Recessive germinal mutationB. Dominant germinal mutationC. Recessive somatic mutationD. Dominant somatic mutation
Answer» Correct Answer - B

Discussion

Explore topic-wise InterviewSolutions in .

When two independentaly assorting dominant genes interact whth each other to produce perticular phenotype but when they present alone they did not produce phenotype they are called :-A. Complementry geneB. Supplementary geneC. Dumplecate geneD. inhibitory gene

AB-Blood group shows :-A. CO-dominanceB. Complete dominanceC. Mixed inheritanceD. Composite inheritance

In sea urchin DNA, which is double stranded, 17% of the bases were show to be cytosine. The percentages of the other three bases expected to be present in this DNA areA. ` G 17%, A 16.5%, T32.5%`B. `G 17%, A 33%, T 33%`C. `G 8.5%, A50%, T24.5%`D. `G 34%, A24.5%, T24.5%`

Complete linkage is found inA. BirdsB. SnakesC. Female-DrosophilaD. Male - Drosophila

A phenomenon which works opposite to the linkage isA. Independent assortmentB. Crossing-overC. SegregationD. Mutation

The recessive genes located on X-chromosome in humans are always:A. Expressed in femalesB. LetalC. Sub-lethalD. Expressed in males

Mendel obtained wrinkled seeds in pea due to deposition of sugars instead of starch. It was due to which enzyme :-A. AmylaseB. InvertaseC. DiastaseD. Absence of starch branching enzyme

In the base sequence of one strand of DNA is `GAT, TAG, CAT, GAC` what shall be the sequence of its complementary strand -A. `CAT, CTG, ATC, GTA`B. `GTA, ATC, CTG, GTA`C. `ATC, GTA, CTG, GTA`D. `CTA, ATC, GTA, CTG`

Which is incorrect - ABO blood groups are controlled by the gene I Gene I has four alleles (iii) `A^(I)and I^(B)` produce same type of suger (iv) I or `I^(@)` produce different type of sugar (v) `I^(A) and I^(B)` are incomplete dominantA. I,iiB. iiC. ii, iii, ivD. ii, iii, iv, v

Blood grouping in human beings is controlled byA. 4 alleles in which `I^(A)` is dominantB. 3 alleles in which `I^(A) and I^(B)` are dominantC. 2 alleles in which none is dominantD. 3 alleles in which `I^(A)` is recessive

There are two alleles `(A_(1)&A_(2))` out of which one `(A_(1))` has nil abundance in a population then the abundance of second allele `(A_(2))` is :-A. `0.25`B. `1.00`C. `0.40`D. `0.50`

Mendel formulated the law of purity of gametes on the basis of:A. Dihybrid crossB. monohybrid crossC. Back crossD. Test cross

Two crosses between the same pair of genotypes or phenotypes in which the sources of the gametes are reversed in one cross, is known as:A. Test crossB. Reciprocal crossC. Dihybrid crossD. Reverse cross

A self-fertilizing trihybrid plant formsA. 8 different gametes and 32 different zygotesB. 8 different gametes and 64 different zygotesC. 4 different gametes and 16 different zygotesD. 8 different gametes and 16 different zygotes

Which statement is incorrect about linkage-A. It helps in maintaining the value traits of new varietiesB. It helps in forming new recombinantsC. Knowledge of linkage helps to breeder to combine all desirable traits in a single variety.D. It helps in locating genes on chromosome

cDNA probes are copies from the messenger RNA molecules with the help of :A. Restrication enzymesB. Reverse transcriptaseC. DNA polymeraseD. Adensosine deaminase

R and y genes of Maize lie very close to each other . When RRYY and rryy gneotypes are hybridised , `F_(2)` genertion will showA. Higher number of the recombination types. B. Segregation in the expected `9:3:3:1` ratio.C. Segregation in `3:1` ratio.D. Higher number of the parental types

Differentiation of organs and tissues in a develping organism, is assoiated withA. Developmental mutationsB. Differetial expression of genesC. Lethal mutationsD. Deletion of genes

R and y genes of Maize lie very close to each other . When RRYY and rryy gneotypes are hybridised , `F_(2)` genertion will showA. Higher number of the recombination types.B. Segregation in the expected `9:3:3:1` ratio.C. Segregation in `3:1` ratio.D. Higher number of the parental types

Inheritance of skin colour in humans in an example of :-A. chromosomal aberrationB. point mutationC. Polygenic inheritanceD. codominance

In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeds plant is crossed wit a green seeded plant, what ratio of yellow and green seeded plants would you expect in `F_(1)` generation :-A. `50:50`B. `9:1`C. `1:3`D. `3:1`

How many different types of gametes can be formed by `F_(1)` progent, resulting from the following cross : AA BB CC x aa bb ccA. 3B. 8C. 27D. 64

I the cell of n organism heterozygous for two pairs of genes represented by Aa, Bb, undergoes meiosis, then the possible genotypic combination of gametes will be :-A. AB, Ab, aB, abB. AB, abC. Aa, BbD. A, a, B, b

Hybrid of pure red flowered and white flowered Pea is crossed to pure red flowered plant. The progeny shall beA. All red flowered plantsB. White flowered plantsC. `50%` red and `50%` white flowered plantsD. 3 Red : 1 white flowered plants

A cross between AaBB X aa BB yields a genotypic ratio of :-A. 1 AaBB: 1 aaBBB. 1 AaBB : 3 aaBBC. 3AaBB: 1 aa BBD. All AaBB

Cross between recessive parent and `F_(1)` hybrid is called :A. Back crossB. Teat crossC. Monohybrid crossD. Dihybrid cross

A pure tall and a pure dwarf plant were crossed to produce offsprings. Offsprings were self crossed, then find out the ratio between true breeding tall to true breeding dwarf?A. `1:1`B. `3:1`C. `2:1`D. `1:2:1`

What shall be the ratio of hetorozygous, homozygous and colourblind hemizygous in offsprings of a colour blind husbnad & a carrier wife :-A. `1:1:2`B. `1:1:1`C. `2:1:1`D. `1:2:1`

When `F_(1)` generation hybrid tall Tt is crossed with dwarf tt parent, it is a case of :-A. Dihybrid crossB. test crossC. Crossing overD. Reciprocal cross

When a tall plant with rounded seeds (TTRR) is crossed with a dwarf plant with wrinkled seeds (ttrr), the `F_(1)` generation consists of tall plants with rounded seeds. How many types of gamets an `F_(1)` plant would produceA. OneB. ThreeC. FourD. Eight

In monohybrid cross what is the ratio of homozygous dominant and homozygous recessive individuals in `F_(2)` generation :-A. `1:2:1`B. `2:1//1:2`C. `3:1//1:3`D. `1:1`

A diseased man marries a normal woman.They get three daughters and five sons were normal . The gene of this disease is :A. Sex linked dominantB. Sex linked recessiveC. Sex limited characterD. Autosomal dominant

If a homozygous tall plant is crossed with a dwarf plant, what shall be the ratio of plants in offsprings :-A. All heterozygous tallB. Two tall & Two dwarfC. `1:2:1`D. All homozygous dwarf

Heterozygous tall plant (Tt) is crossed with homozygous dwarf (tt) plant. Then what will be the percentage of dwarf plants in the next generation?A. `25%`B. `100%`C. `75%`D. `50%`

In a Random mating population of `28,800` individuals percentage of dominant homozygous individuals is `49%` find out the precentage of heterozygous individual -A. `21%`B. `42%`C. `32%`D. `9%`

A cross used to ascertian whether a dominant is homozygous or heterozygous is termed :A. ReciprocalB. Back crossC. Test crossD. Monohybrid

Haemolytic jaundice is due to dominant gene but only `20%` of the people develop this disease. A heterozygous man marries a homozygous normal wiman. What proportion of the children in population would be expected th have this disorder :-A. `1/5`B. `1/20`C. `1/10`D. `1/2`

From a single ear of corn, a farmer planted 200 kernals which produced 140 tall and 40 dwarf plants. The genotype of these offsprings are most likelyA. TT, Tt & ttB. TT & ttC. TT & TtD. Tt & tt

A useful process for determining whether an individual is homozygous or heterozygous is :-A. Cross-breedingB. Self fertilizationC. Back-crossingD. Test cross

Short legged variety of sheep is an example of :-A. Recessive germinal mutationB. Dominant germinal mutationC. Recessive somatic mutationD. Dominant somatic mutation