This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 751. |
Read the following passage and answer the questions that follow :When the spring sunshine awakens a man once more to a fresh awareness of his surroundings, and takes his mind back to other springs which first suggested to his infant mind that the earth was a beautiful place, it is not invariably a shining river that he remembers, or solitary hills, or green fields and greening woods. It may be, if he was a town mouse and nurtured among bricks and mortar, nothing more than a public park.A town park is a poor thing to set beside the country, but for many a man, before his legs grew strong enough and his spirit independent enough to carry him to the moors or the mountains, a park was his English heaven, air, rivers, ‘suns of home’. It was here that he was pushed along in his perambulator, and here that he made his first close contacts with Mother Earth-though large areas of the Mother Earth in the place might have been carefully concealed by Father Macadam and his associates. The ratio of gravel and asphalt to grass and flowers and water was likely to be in the neighborhood of two to five. And yet enough of Nature remained, enough at least to mark the passage of the seasons.It is not necessarily the birds and the flowers that flash from time to time upon the inward eye of the man thus indebted to the park. The annual spring visits in a party from school, to draw the bursting birds in the botanical garden, is remembered less for its intrinsic excitement than for the relief it afforded from ordinary lessons. The annual furnishing of the boathouse and the tea chalet were much more satisfying signs of spring and of the return to a fuller life. The boathouse from which the Princess Ida would soon be setting sail round the little-more-than-aduck pond with cargoes of small children gazing down into 18 inch depths, the tea chalet that was the trusty stand-by of mothers in the long summer holidays when the children grew bored and tea in the park was a sure diversion. In school-time the park had other uses. It was the obvious place to play truant in and, though adults might wonder what a child could find to do there alone all day, truants were untroubled by such trifling problems.At weekends in the summer in these present days there are concert parties in the park, and ‘A Midsummer Night’s Dream’, and roller skating. The former patron will remember that in his young days it was always brass bands. Good brass bands, too, for the audience was expert. The best bands in the country were summoned to the park and the local paper sent its music critic. The children might be deaf to musical points, but they could not be blind to uniforms of scarlet. For the rest, it was their parents who enjoyed it most-the band and the sunshine and the gossip with friends; their parents, and those older brothers and sisters who had reached the mysterious stage of washing without being told, and going for walks without father and mother, and flirting with the opposite sex. Though the last phenomenon, to be sure, did not wait on summer bands. It all began, in the park, in spring.1. What do people, who spent their childhood in the town, remember in the spring time?2. What did children like to do during the holidays in the park which the writer remembers?3. What can be seen in the park at the weekend?4. What used to be heard in the parks when the writer was a boy?5. What did the children like the most about the bands? |
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Answer» 1. lt may be a shining river, solitary hills or green fields or greening woods that they re member. 2. The children like to play truant during the holidays in the park. 3. At the weekends in the summer in these present days, concert parties can be seen in the park. 4. It was always brass bands, even good brass bands used to be heard in the parks when the writer was a boy. 5. The thing that the children most liked about the bands was their musical excellence. |
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| 752. |
Animal husbandry is the scientific management of(i) animal breeding(ii) culture of animals(iii) animal livestock(iv) rearing of animals(a) (i), (ii) and (iii)(b) (ii), (iii) and (iv)(c) (i), (ii) and (iv)(d) (i), (iii) and (iv) |
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Answer» Correct Answer is (d) (i), (iii) and (iv) |
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| 753. |
Rewrite each sentence in Past Continuous Tense :1. The girls did not pluck flowers.2. Did the peon not ring the bell?3. Did Ram break the windowpanes?4. My friends talked to me in English.5. The watchman did not open the gate.6. He spent all his money in good deeds. |
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Answer» 1. The girls were not plucking flowers. 2. Was the peon not ringing the bell? 3. Was Rain breaking the windowpanes? 4. My friends were talking to me in English. 5. The watchman was not opening the gate. 6. He was spending all his money in good deeds |
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| 754. |
Figure 12.4 shows simultaneous records of changes in right hand and left forearm volume when collecting pressures are applied intermittently by means of cuffs on the right wrist and left upper arm respectively. The volume of the hand in the plethysmograph was 300 ml and the volume of the forearm was 600 ml. These records (venous occlusion plethysmograms) show: a. A greater hand blood flow in the third than in the fourth plethysmogram. b. That the rate of blood flow per unit volume of tissue is similar in the hand and forearm. c. That hand blood flow is more variable than forearm blood flow. d. That forearm blood flow is nearer 20 than 50 ml/minute. e. That the collecting cuffs are not occluding the arteries. |
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Answer» a. False Flow is measured as increase in volume with time and hence is directly proportional to the slope of the volume record during collection. b. False The total blood flow rates are similar on the two sides; since hand volume is half that of the forearm, its rate of flow per unit volume of tissue is approximately double forearm flow. c. True The slopes are more variable; the more variable flow is due to greater variability in the level of sympathetic vasoconstrictor tone. d. False The rate of flow is quite close to 50 ml/minute. e. True If the arteries were occluded, flow would be zero. |
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| 755. |
Read the following passage and answer the questions that follow : In my life I hold a high value for my family. I wish to maintain a happy, healthy family life, and therefore try to act so as to best promote a good family life. However, I am human, and therefore I do sometimes fall short. While I try to act in the best interest of my family, sometimes my own selfishness causes me to act in a way that is not in the best interest of my family. I do have ethical guidelines that I try to follow.The first of these guidelines is the golden rule. “Do unto others as you would have others do unto you.” I do not like to be treated badly and therefore I try to treat others in the way I want to be treated. I also do not enjoy treating others badly because it does not make me feel good to hurt others. I am sensitive to the feelings of others. On occasions, I lose sight of this rule, and treat others in a way that I know I would not want to be treated. This causes conflict and unhappiness, and I then realize that it was not worth for me to act selfishly, because while it made me happy temporarily, it made me unhappy in the end to hurt another person or people. The consequences of violating the golden rule cause discord and unhappiness. I would rather act so as to maintain happiness and harmony in my family and with others.I also feel that it is important to learn from my own mistakes, although some mistakes I do repeat. When I make a mistake, I am unhappy with myself for doing so. Because my ultimate goal is to be happy, I prefer not to repeat my mistakes. I already know that the last time I made that mistake, I was displeased with myself and my family was also displeased with me. I want to be happy, and therefore try not to act in a way in which I already know the consequences have made me unhappy.Like Socrates, I also believe that we should seek truth in life. Socrates encouraged people to seek new ideas and truth by asking questions that inspired people to think deeply and more analytically. Truth is beneficial for people and societies. Without truth, we would lose touch with human dignity. “The unexamined life is not worth living”, said Socrates. If we do not examine ourselves and seek truth, while we lose our dignity, we also lose our happiness and therefore our purpose of living.1. What did Socrates encourage people to do?2. What is the first ethical guideline which the writer follows ?3.What happens when the writer loses sight of the golden rule ?4. What did the writer learn from his previous mistakes ?5. What is the ultimate goal of the author ? |
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Answer» 1. Socrates encouraged people to seek truth and new ideas by asking deep and searching questions. 2. The first ethical guideline for the author is “Do unto others as you would have others do unto you”. 3. Oversight of the golden rule causes conflict and unhappiness to the writer. 4. He learnt from his mistakes that he was displeased with himself and his family too was displeased with him. 5. The ultimate goal of the author is to keep himself and his family happy. |
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| 756. |
The boy did nothing but _____ throughout the lesson. A) yawning B) yawn C) to yawn D) yawns |
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Answer» Correct option is B) yawn |
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| 757. |
She can do everything except _____. A) is cooking B) cooks C) cook D) to cook |
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Answer» Correct option is C) cook |
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| 758. |
Read the following passage and answer the questions that follow : When boiling milk scalded Radha’s forearm, her mother-in-law lavishly applied ghee to the wound and wrapped a tight bandage around it. By the next day, the forearm was swollen and she was in severe pain. She then developed high fever, and four days later, was admitted to the Fortis Hospital in Noida, near Delhi, in a feverish state. She was in hospital for a month and had to undergo plastic surgery.Her mother-in-law had made a common mistake-she relied on an old prescription. First aid treatment has come down from generation to generation, and many of our mothers’ remedies are no longer recommended. Take a look at your first-aid kit; bandages, some gauze, painkillers, a tube of anti-bacterial cream, may be iodine or hydrogen peroxide. We are all familiar with these supposedly tried-and-true remedies.They may be tried, but they are not all true. “So many of us still follow traditional remedies like applying hydrogen peroxide on an open wound,” says Dr Asif Ali, head of Fortis Hospital’s emergency medicine department. “But this and other common remedies do more harm than good.” After years of research, experts are finding that your standard first-aid response sometimes may be the worst thing you can do to update your first-aid kit.When the skin is not broken, it’s hard to bear iodine for killing bacteria. That’s why doctors use it to clean an area before surgery. But if there’s a cut, says Dr Mahesh Joshi, Head of the department of emergency medicine, Apollo Hospitals, Hyderabad, full-strength iodine, hydrogen peroxide and rubbing alcohol can prove toxic to the exposed tissue, impending healing. The chemical reaction that occurs when hydrogen peroxide hits the skin isn’t only cleaning the wound- it’s killing healthy cells. This stuff hurts because it’s wiping out healthy tissue.Applying iodine on cuts and wounds kills bacteria, says Dr Mahesh Joshi, but it won’t clean the wound. “Iodine doesn’t protect good skin tissue, it harms it.” Instead of cleansing a wound: “The best way to rid of dirt and germs is to wash the wound out with water,” says Dr Asif Ali. Put the wound under a tap, or a hand shower. Flush it with water to clear it of all waste. If you are worried about the bandage sticking to the wound, consider using an antibacterial ointment like Soframycin to keep the area lubricated. In this way we should be very cautious in using traditional way of first aid.1. How according to Dr Asif should a wound be cleaned as a first-aid ?2. Which ointment for lubrication has been mentioned in the passage ?3. Which mistake caused Radha’s hospitalization and plastic surgery?4. How does hydrogen peroxide hurt the wound in the cleaning process ?5. What can prove toxic to exposed tissue ? |
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Answer» 1. According to Dr Asif, a wound should be cleaned by putting it under a tap shower or hand shower as a first aid. 2. The passage mentions soframycin as an antibacterial ointment used for lubrication. 3. Wrong first aid to Radha by her mother-in-law to her scalded arm caused her hospitalization and plastic surgery. 4. Cleaning a wound with hydrogen peroxide hurts the wound because it wipes away the healthy tissues. 5. Iodine, hydrogen peroxide and rubbing alcohol can hurt exposed tissue. |
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| 759. |
Are they going to stay ______ a tent? A) in B) over C) on D) of |
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Answer» Correct option is A) in |
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| 760. |
He has a pain ______ his leg. A) on B) over C) in D) at |
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Answer» Correct option is C) in |
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| 761. |
the cell organelle which is rich in manganese |
| Answer» golgi apparatus | |
| 762. |
During the operation, doctors were wearing ______ which were covering all face except eyes. A) casts B) masks C) bandage D) sling |
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Answer» Correct option is B) masks |
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| 763. |
A: Who cooks dinner at your house? B: It _____ by my elder sister. A) is cooked B) is cooking C) has cooked D) can cook |
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Answer» Correct option is A) is cooked |
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| 764. |
When I came in my mother ___ dinner. A) cooked B) were cooking C) will cook D) have cooked E) was cooking |
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Answer» Correct option is E) was cooking |
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| 765. |
She put a bandage ______ the boy’s cut finger. A) at B) to C) on D) in |
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Answer» Correct option is C) on |
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| 766. |
The wound has healed now. You _____ that bandage any longer. A) needn’t have worn B) didn’t need to wear C) don’t have to wear D) didn’t have to wear |
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Answer» Correct option is C) don’t have to wear |
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| 767. |
I like _____ . A) cooks B) cooking C) cook D) cooked |
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Answer» Correct option is B) cooking |
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| 768. |
When I _____ at the party, everyone _____ a good time. A) was arriving / had B) arrived / was having C) arrived / had D) arrived / were having |
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Answer» Correct option is B) arrived / was having |
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| 769. |
I _____ and I _____ the knife. A) cooked / was dropping B) cook / drop C) was cooking / dropped D) cooked / dropped |
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Answer» Correct option is C) was cooking / dropped |
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| 770. |
She put a bandage _____ the boy’s cut finger. A) at B) to C) on D) in |
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Answer» Correct option is C) on |
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| 771. |
While the waiter _____ up the broken plates, he _____ his finger. A) picked / was cutting B) was picking / cut C) pick / cut D) picks / cut |
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Answer» Correct option is B) was picking / cut |
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| 772. |
Did you see the size of the diamond on her finger? A) rig B) rock C) roast |
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Answer» Correct option is B) rock |
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| 773. |
How _____ your finger? A) are you cutting B) were you cutting C) did you cut D) you cut |
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Answer» Correct option is C) did you cut |
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| 774. |
What do we mean by cutting the surface with finger? (See below) |
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Answer» The explanation of whole activity is given below The meaning of cutting the surface with a finger is :
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| 775. |
You have chosen a plasmid as vector for cloning your gene. However this vector plasmid lacks a selectable marker. How would it affect your experiment? |
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Answer» In a gene cloning experiment, first a recombinant DNA molecule is constructed, where the gene of interest is ligated to the vector, [The step would not be affected] and introduced inside the host cell (transformation). Since, not all the cells get transformed with the recombinant/plasmid DNA, in the absence of selectable marker, it will be difficult to distinguish between transformants and non-transformant, because role of selectable marker is in the selection of transformants. |
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| 776. |
The undefined nuclear region in a bacteria is (a) nucleoid (b) nucleus (c) chromosome (d) nucleolus |
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Answer» (a) In prokaryotes, the nucleoid is an irregularly shaped region within the cell where the genetic material is localised. |
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| 777. |
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.Quantity A: A mixture of spirit and water measure 90 liters. It contains 20% water. How much water should be added to it so that water may be 50%?Quantity B: 45 litres1. Quantity A > Quantity B2. Quantity A < Quantity B3. Quantity A ≥ Quantity B4. Quantity A ≤ Quantity B5. Quantity A = Quantity B or No relation. |
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Answer» Correct Answer - Option 1 : Quantity A > Quantity B Quantity A: Given that, mixture of 90 litres of the spirit and water contains 20% water. In the first mixture Water = (20/100) × 90 = 18 litres ∴ Spirit = 90 – 18 = 72 litres After adding some water to the mixture, water became 50% of the new mixture ∴ 72 litres of water in new mixture = 50% of new mixture ∴ Total litres of new mixture = (100/50 × 72) = 144litres So, water to be added = 144 – 90 = 54 litres Quantity B: 45 litres ∴ Quantity A > Quantity B |
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| 778. |
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.Quantity A: A boat goes 8 km upstream and comes back in 6 hours. Speed of the current is 1 km/hr then find the time taken by the boat to travel the same distance in still water. Quantity B: 2 hours1. Quantity A > Quantity B2. Quantity A < Quantity B3. Quantity A ≥ Quantity B4. Quantity A ≤ Quantity B5. Quantity A = Quantity B or No relation. |
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Answer» Correct Answer - Option 1 : Quantity A > Quantity B Quantity A: Let the speed of boat in still water be B km/hr According to the given statement, boat goes 8 km upstream and comes back in 6 hours and speed of the current is 1 km/hr ⇒ {8/(B + 1)} + {8/(B - 1)} = 6 ⇒ 16B = 6B2 - 6 ⇒ 6B2 - 18B + 2B - 6 = 0 ⇒ 6B(B - 3) + 2(B - 3) = 0 ⇒ (B - 3)(6B + 2) = 0 ⇒ B = 3 km/hr and -2/6 km/hr ⇒ Speed of boat in still water = 3 km/hr ⇒ Time taken to cover the distance in still water = 8/3 = 2 hours 40 minutes Quantity B: 2 hours ∴ Quantity A > Quantity B |
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| 779. |
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.Quantity A: A vessel of 100 liters is filled with milk and water. 80% of milk and 20% of water is taken out of the vessel. It is found that the vessel is vacated by 50%. Find the initial quantity of milkQuantity B: 60 litres1. Quantity A > Quantity B2. Quantity A < Quantity B3. Quantity A ≥ Quantity B4. Quantity A ≤ Quantity B5. Quantity A = Quantity B or No relation. |
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Answer» Correct Answer - Option 2 : Quantity A < Quantity B Quantity A: Let the initial quantity of milk be x litres ∴ Initial quantity of water = (100 – x) litres Given, 80% of x + 20% of (100 – x) = 50% of 100 ⇒ 80x + 2000 – 20x = 5000 ⇒ 60x = 3000 ⇒ x = 50 litres ∴ Initial quantity of milk = x = 50 litres Quantity B: 60 litres ∴ Quantity A < Quantity B |
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| 780. |
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.Quantity A: A man goes certain distance downstream in 2 hours and returns back upstream in 3 hours. If the stream flows at the rate of 4 km/hr, find the time taken by the man to cover the distance in still water.Quantity B: 3 hours 1. Quantity A > Quantity B2. Quantity A < Quantity B3. Quantity A ≥ Quantity B4. Quantity A ≤ Quantity B5. Quantity A = Quantity B or No relation. |
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Answer» Correct Answer - Option 2 : Quantity A < Quantity B Quantity A: Let the speed of boat in still water be B km/hr According to the given statement, distance travelled downstream and upstream is same ⇒ (B + 4) × 2 = (B - 4) × 3 ⇒ 2B + 8 = 3B - 12 ⇒ B = 20 ⇒ Speed of boat in still water = 20 km/hr ⇒ Distance covered by the man either way = (20 + 4) × 2 = 48 km ⇒ Time taken to cover the distance in still water = 48/20 = 2.4 hours = 2 hours 24 minutes Quantity B: 3 hours ∴ Quantity A < Quantity B |
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| 781. |
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.Quantity A: A computer is marked at Rs. 10000. Find the cost price of the computer if the shopkeeper earns 20% profit even after giving two successive discounts of 10% and 20%.Quantity B: Rs. 50001. Quantity A > Quantity B2. Quantity A < Quantity B3. Quantity A ≥ Quantity B4. Quantity A ≤ Quantity B5. Quantity A = Quantity B or No relation. |
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Answer» Correct Answer - Option 1 : Quantity A > Quantity B Quantity A: Given the marked price of computer is Rs. 10000; Two successive discounts of 10% and 20% are given; ∴ Selling price of the computer = 10000 × 0.90 × 0.80 = Rs. 7200 ∵ The shopkeeper earns 20% profit; ∴ Cost price of the computer = 7200/1.2 = Rs. 6000 Quantity B: Rs. 5000 ∴ Quantity A > Quantity B |
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| 782. |
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.Quantity A: A discount of 20% is given on the marked price of a Television set. Find the marked price of the Television set if 20% profit is earned from it. (Cost price of Television set is Rs. 20000)Quantity B: Rs. 300001. Quantity A > Quantity B2. Quantity A < Quantity B3. Quantity A ≥ Quantity B4. Quantity A ≤ Quantity B5. Quantity A = Quantity B or No relation. |
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Answer» Correct Answer - Option 5 : Quantity A = Quantity B or No relation. Quantity A: Given the cost price of Television set is Rs. 20000; ∵ 20% profit is earned in it; ∴ Selling price of Television set = 20000 × 1.2 = Rs. 24000 ∵ the discount of 20% is given on the marked price of a Television set; ∴ Marked price of Television set = 24000/0.8 = Rs. 30000 Quantity B: Rs. 30000 ∴ Quantity A = Quantity B |
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| 783. |
Pipe P can fill an empty tank in 15 h and pipe Q can fill the same tank in 45 h. Both pipes open alternatively for 1 h each without any time gap. In how many hours 90% of the tank will be filled?1. \(20\frac{1}{6}\;h\)2. \(24\frac{1}{7}\;h\)3. \(21\frac{1}{6}\;h\)4. \(20\frac{1}{4}\;h\)5. \(30\frac{1}{4}\;h\) |
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Answer» Correct Answer - Option 1 : \(20\frac{1}{6}\;h\) Given: Pipe P can fill the tank in 15 hours. Pipe Q can fill the tank in 45 hours. Concept: Time and efficiency concepts will be used. Calculation: Let the total quantity of tank be LCM of (15, 45) = 45 units ⇒ Efficiency of P = 45/15 = 3 units ⇒ Efficiency of Q = 45/45 = 1 unit Now, 90% of 45 units = 40.5 units If they are open alternatively then they will fill the 4 units of tank in 2 hours ⇒ In 20 hours they will 40 unit of tank Remaining quantity = 40.5 – 40 = 0.5 units ⇒ 0.5 unit work left is filled by Pipe P ⇒ Total time = 20 hrs. + 0.5/3 ⇒ Total time = 20 hrs. + 1/6 ⇒ Total time ∴ In the given condition total tank will be filled in \(20\frac{1}{6}\;\)hours |
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| 784. |
Two pipes A and B can fill a tank in 8 h and 12 h respectively. A waste pipe C can empty the tank in 4 h. A and B are kept open for 2 h, then C is also opened. Then the tank will empty in1. 5 h2. 6 h3. 7 h4. 10 h |
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Answer» Correct Answer - Option 4 : 10 h Given: Time taken by A to fill the tank = 8 h Time taken by B to fill the same tank = 12 h Time taken by C to empty the tank = 4 h Concept used: If a tap can fill a tank in X h, part of the tank filled in 1 h = 1 / X For outlet pipe, efficiency should be taken with negative sign Part filled by A in 1 h = 1 / 8 Part filled by B in 1 h = 1 / 12 Part empty by C in 1 h = 1 / 4 Part filled by (A + B) in 2 h = (1 / 8 + 1 / 12) × 2 = 5 / 24 × 2 = 5 / 12 Now, C is also opened ∴ Part fill / empty in 1 h = 1 / 8 + 1 / 12 + (-1 / 4) = -1 / 24 Here, negative sign shows the tank get empty when (A + B + C) opened together ∵ 1 / 24 part empty in 1 h ∴ 5 / 12 part will get empty in = 24 × 5 / 12 = 10 h Therefore, tank will get empty in 10 h |
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| 785. |
In a city, 80% of the population are literate and ratio of literate male to literate female is 5 ∶ 2 and illiterate male are equal to illiterate female. If number of literate female is 2,000. Find difference of literate male and illiterate male.1. 42752. 41253. 42504. 1750 |
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Answer» Correct Answer - Option 2 : 4125 Given: Literate population = 80% and illiterate population = 20% Ratio of literate male to female = 5 ∶ 2 Illiterate male = illiterate female Literate female = 2000 Concept used: If X is distributed between A and B in the ratio of a ∶ b, then A = a / (a + b) × X and B = b / (a + b) × X To convert any ratio to exact value, we should have to multiply any constant value Calculation: Ratio of literate male to female = 5 ∶ 2 Let, literate male = 5X and female = 2X ∵ 2X = 2000 ∴ X = 1000 ∴ 5X = 5000 ∴ Total literate population = 7X = 7 × 1000 = 7000 Now, Let total population of city = Y ∴ 80% of Y = 7000 ∴ Y = (7000 × 100) × 1 / 80 = 8750 Total population of city = 8750 Total illiterate population = 20% of 8750 = 1750 ∵ Illiterate male = illiterate female ∴ Illiterate female = 1750 / 2 = 875 Therefore, difference = 5000 – 875 = 4125 |
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| 786. |
How is the refractive index of a medium related to the speed of light? Obtain an expression for refractive index of a medium with respect to another in terms of speed of light in these two media? |
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Answer» The refractive index of the medium nm is given by |
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| 787. |
A convex lens of focal length 20 cm can produce a magnified virtual as well as real image. Is this a correct statement? If yes, where shall the object be placed in each case for obtaining these images? |
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Answer» Statement is correct if the object is placed within 20cm from the lens in the first case and between 20 cm and 40cm in the second case. |
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| 788. |
A light ray enters from medium A to medium B as shown in Figure 10.2. The refractive index of medium B relative to A will be(a) greater than unity(b) less than unity(c) equal to unity(d) zero |
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Answer» (a) greater than unity Since light rays in medium B goes towards normal. So it has greater restrictive index and lesser velocity of light with respect to medium A. So refractive index of medium B with respect to medium A is greater than unity. |
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| 789. |
The energy of an electron in hydrogen atom is determined solely by its :A. (n + l) valueB. Subsidiary quantum numberC. Principal quantum numberD. None of these |
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Answer» Correct Answer - C `Eprop(z^(2))/(n^(2))` |
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| 790. |
Today is Alka's birthday. 3 years from today she will be twice as old as she was 12 years ago. How old is Alka today ?1. 23 years2. 24 years3. 26 years4. 27 years |
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Answer» Correct Answer - Option 4 : 27 years Given: 3 years from Alka's birthday, she will be twice as old as she was 12 years ago Calculation: Let Alka’s age today be x years. Then, Alka’ age after 3 year = (x + 3) years. 12 years ago, Alka's age = (x - 12) years According to question: ⇒ x + 3 = 2 × (x - 12) ⇒ x + 3 = 2x – 24 ⇒ x = 27 |
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| 791. |
Give reasons ---1. lungs always contain residual volume of air.2. nostrils are lined with mucus. |
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Answer» 1. Residual volume is the amount of gas remaining in the lungs of the and of a maximal exhalation.The lungs always contain a residual volume of air so that during breathing cycle there is sufficient time for oxygen to be absorbed and for the carbon dioxide to be released. Residual volume is important because it prevents the lungs from collapsing. 2. Harmful substances and germs present in the inhaled air get trapped in the hairs and mucus present in nostrils. In this way, they help in the filtration of inhaled air. After that, if some germs get escaped from filtration, their movement in the respiratory system is stopped by mucus and cilia present in the air passages. Mucus is secreted by the cells of the trachea and bronchial tubes which keep the air passages moist, clean and stop the entry of germs in lungs. |
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| 792. |
Let S = {1, 2, 3, 4}. Then the number of elements in the set {f : S x S → S : f is onto and f(a,b) = f(b,a) ≥ a ∀ (a,b) ∈ S x S} is |
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Answer» Correct answer is 37 (1, 1), (1, 4), (4, 1), (2, 4), (4, 2), (3, 4), (4, 3), (4, 4) – all have one choice for image. (2, 1), (1, 2), (2, 2) – all have three choices for image (3, 2), (2, 3), (3, 1), (1, 3), (3, 3) – all have two choices for image. So the total functions = 3 x 3 x 2 x 2 x 2 = 72 Case 1 : None of the pre-images have 3 as image Total functions = 2 x 2 x 1 x 1 x 1 = 4 Case 2 : None of the pre-images have 2 as image Total functions = 2 x 2 x 2 x 2 x 2 = 32 Case 3 : None of the pre-images have either 3 or 2 as image Total functions = 1 x 1 x 1 x 1 x 1 = 1 ∴ Total onto functions = 72 – 4 – 32 + 1 = 37 |
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| 793. |
Three photodiodes D1, D2 and D3 are made of semiconductors having band gaps of 2.5 eV, 2eV and 3eV respectively. Which of them will not be able to detect light of wavelength 600 nm? |
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Answer» Here, E1 = 2.5eV, E2 = 2eV, E3 = 3eV E = \(\frac{hc}{\lambda}\) = \(\frac{6.6\times10^{-34}\times 3\times 3 \times 10^8}{600\times 10^{-9}\times 1.6\times 10^{-19}}\) eV = 2.06 eV Here, 2.06 eV< E1 and E3 So, D1 and D3 cannot detect the radiation of wavelength 600 nm. But, Since, 2.06 eV> E2 Therefore, D2 can detect the wavelength of 600 nm. |
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| 794. |
State Snell’s law of refraction. |
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Answer» SNELL’S LAW: The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given colour and for the given pair of media. We have: \(\frac{sin} {sin}\) = constant = µ µ is called the refractive index of the second medium with respect to the first. According to Snell's Law : The sine of angle of incidence to the sine of angle of refraction is always constant for same given medium . Sin i / Sin r = constant = µ And that constant is the refractive index (µ) of the second medium with respect to first medium . |
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| 795. |
What is the unit of admittance?(a) ohm(b) henry(c) farad(d) ohm^-1 |
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Answer» The correct choice is (d) ohm^-1 For explanation: The unit for admittance is ohm^-1 because the unit of impedance is ohm and admittance is the reciprocal of impedance. |
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| 796. |
In a parallel circuit, we consider admittance instead of _________(a) Resistance(b) Capacitance(c) Inductance(d) Impedance |
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Answer» The correct answer is (d) Impedance The explanation: In a parallel circuit, we consider admittance instead of impedance, where admittance is the reciprocal of impedance. |
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| 797. |
Which, among the following is the correct expression for admittance?(a) Y=Z(b) Y=1/Z(c) Y=Z^2(d) Y=1/Z^2 |
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Answer» Correct choice is (b) Y=1/Z Explanation: We know that admittance is the reciprocal of impedance, hence the correct expression for admittance is: Y=1/Z. |
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| 798. |
In an AC circuit, resistance 50 Ω, inductance 0.3 H and capacitance 15 μF is connected to an AC voltage source 25 V, 50 Hz. Determine the phase difference between current and voltage.(a) 670(b) 540(c) 470(d) 770 |
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Answer» Right choice is (a) 670 To explain: XL=2πfL, XC=1/(2πfC) f=50Hz and L=0.3H and C=15 μF XL=2π(50)(0.3) = 94.25 ohm. XC=1/(2π*50*15*10^-6) = 212.21 ohm. tanϕ = |(XL-XC)|/R = (212.21-94.25)/50 = 2.3592 ϕ=67^0. |
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| 799. |
The admittance of a system is 10 ohm^-1, calculate its impedance.(a) 10 ohm(b) 0.1 ohm(c) 1 ohm(d) 1.1 ohm |
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Answer» The correct choice is (b) 0.1 ohm To explain: We know that: Z=1/Y. Z = 1/10 = 0.1 => Z = 0.1 ohm. |
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| 800. |
if the impedance of a system is 4 ohm, calculate its admittance.(a) 0.25 ohm^-1(b) 4 ohm^-1(c) 25 ohm^-1(d) 0.4 ohm^-1 |
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Answer» Correct choice is (a) 0.25 ohm^-1 For explanation: We know that: Y=1/Z. Substituting the value of Z from the question, we get Y = 1/4 = 0.25 => Y= 0.25 ohm^-1. |
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