Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The most suitable reagent for the conversion of Benzyl alcohol → benzoic acid isA. PCCB. Acidified`KMnO_4`C. both of theseD. none of these |
|
Answer» Correct Answer - B |
|
| 2. |
The reaction between phenol and chloroform in the presence of aqueous NaOH isA. ReimerTeimann reactionB. Kolbe reactionC. williomson synthesisD. none of these |
|
Answer» Correct Answer - A |
|
| 3. |
If a person is suffering from the deficiency of nor-adrenaline, what kind of drug can be suggested ? (1) Anti-inflammatory (2) Analgesic (3) Antihistamine(4) Antidepressant |
|
Answer» (4) Antidepressant Anti depressant ® drug which enhance the mood. Non adrenaline is neurotransmitter and its level is low in body due to some reason then person suffers from depression and in that situation anti depressant drug is required. |
|
| 4. |
Which of the following structures are aromatic in nature?(A) A,B,C and D (B) Only A and B (C) Only A and C (D) Only B, C and D |
|
Answer» (B) Only A and B A, B aromatic C,D is nonaromatic |
|
| 5. |
Which of the following is aromatic |
|
Answer» Correct option is (2) Only A and C |
|
| 6. |
How many are aromatic compounds? |
|
Answer» Correct option is 2 Both 1 & 2 are cyclic, planar and follows Huckel' s rule |
|
| 7. |
Which of the following compounds is not aromatic? |
|
Answer» Correct option is (C) [10] Annulene, although follow (4n + 2)π electron rule, but it is non-aromatic due to its non planar nature. It is nonplanar due to repulsion of C – H bonds present inside the ring. |
|
| 8. |
0Karan bought I kg Puckic foor Rs 10cand bald I kg Cuctie for Rs 12 How muMoney does be caen on selling IkePlastic |
|
Answer» Multiply By Zero `0` |
|
| 9. |
Which of the following rection given secondary alcohol?A. `CH_(3)-MgBr+HCHOoverset(Aq.NH_(4)Cl)to`B. `CH_(3)-MgBr+CH_(3)-CHOoverset(Aq. NH_(4)Cl)to`C. `Ph-MgBr+Ph-CHOoverset(Aq. NH_(4)Cl)to`D. `Ph-MgBr+CH_(3)-CO-CH_(3)overset(Aq. NH_(4)Cl)to` |
|
Answer» Correct Answer - B::C (B). `CH_(3)-MgBr+CH_(3)-CHOoverset(aq. NH_(4)Cl)toCH_(3)-CH(OH)CH_(3)` (C). `Ph-MgBr+Ph-CHOoverset(aq. NH_(4)Cl)toPh-CH(OH)-Ph` |
|
| 10. |
An optically active compound `A` with molecular formula `C_(6)H_(14)` undergoes catalytic hydrogenation to give an optically inactive product. Which of the following structures for A is/are consistent with all the data?A. B. C. D. |
|
Answer» Correct Answer - B::C (A). This compound is not consistent with the data because it is mso and cannot be optically active. (B). This compound is consistent with the data because it is chiral but would hydrogenate to give trans-1,4- dimethyl chlohexane, an achiral product. (C). this compound is consistent with the data because it is chiral and would hydrogenate to give a mixture of cis and trans-1,4-dimethyl cyclohexane, which are both achiral product. (D). this compound is not consistent with the data, because although it is chiral and thus optically active, it would hydrogenate to give chiral and opticaly active product 1,3- dimethylcyclohexane. |
|
| 11. |
A crystalline solid (A) reacts with hydrogen gas to form a monoatomic gas (B) and a highly associated liquid ( C).(A) is soluble in water and undergoes hydroloysis slowly to form (B),(C ) and a diatomic gas (D).When pure and dry (D) is subjected to a silent electric discharge an another pale blue gas (E) is produced which like (A) also acts a strong oxidising agent.(E) dissolves in potassium hydroxide forming an orange coloured solid which is paramagnetic in nature. (A) reacts with `IF_5, SbF_5, PF_5` etc to form the addition compounds. (C ) forms an addition compound (F) with KF with when electrolysed in molten state forms a most reactive gas (G).(B) and (G) (taken in 2:1) ratio when heated in nickel tube at `400^@ C` and 6 atm pressure forms (A).The first ionization energy `(IE_1)` of (B) is fairly close to (D). Which of the following statements is true ?A. Gas (G) reacts with conc NaOH to form `OF_2`B. Pale Blue gas (E) oxidises alkaline KI to `KIO_3`C. Pale blue gas (E) in acidic medium reacts with `K_2Cr_2O_7` to form a bright blue coloured compound `(CrO_5)`D. (B) and (C ) both |
|
Answer» Correct Answer - B (A)`F_2` gives `O_2` gas ( C) `H_2O_2` in acidic medium from `CrO_5. "not" O_5` (B)`KI+3O_3 to KIO_3 + 3O_2` `underset((A))(XeF_2)overset(H_2)tounderset((B))(Xe)+underset((C ))(2HF)` `XeF_2+H_2overset(H_2)to+underset((B))(Xe)+underset((C ))(HF)+underset((D))(O_2)` `underset(( D))(3O_2)hArrunderset((E))(2O_3),5O_3+2KOH to 2KO_3`(orange solid)+`5O_2+H_2O` `underset(( C))(HF)+KFtoKHF_2("molten")overset("Electrolysis")tounderset((G))(F_2)` |
|
| 12. |
`0.562g` of graphite kept in a bomb calorimeter in excess of oxygen at `298K` and 1 atmospheric pressure was burnt according to the equation, `C_(Graph ite)+O_(2(g))rarr CO_(2(g))` durgin the reaction, temperature rises from `298K` o `298.89K`. If the heat capacity of the calorimeter and its contents is `20.7 kJ//K`, what is the enthalpy change for the above reaction at `298K` and `1 atm`? |
|
Answer» Suppose `q` is the quantity of heat from the reaction mixture and `C_(V)` is the capacity of the calorimeter and the content, then the quantity of heat absorbed by the calorimeter`=C_(V)xxDeltaT` Quantity of heat from the reaction will have the same magnitude but opposite sign, i.e., `q=C_(V)xxDeltaT=-20.7 kJ K^(-1)xx(298.89-298)K=-18.4 kJ` (Here, negative sign indicates the exothermic nature of the reaction) Thus, `DeltaH` for the combustion of the `0.562 g` of carbon `=-18.4 kJ` For combustion of `1 mol` of carbon, heat released `=1 mol Cxx(12.0 g C)/(1 mol C)xx((-18.4 kJ))/(0.562 g C)` `=- 3.9xx10^(2) kJ` (result reported to two significant figures) Thus, enthalpy for combustion of graphite `=-3.9xx10^(2) kJ mol^(-1)` Enthalpy change, `DeltaH` of a reaction Reachants `rarr` Products is represneted by `Delta_(r)H=("sum of enthalpies of products")- ("sum of enthalpies of reactants")` `=SigmaH_("Products")-SigmaH_("reactants")` (Here symbol `Sigma("sigma")` is used for summation). |
|
| 13. |
Which of the following is a non-crystalline solid ?(A) P4O10 (B) P4 (C) Graphite (D) Plastic |
|
Answer» Correct answer is (D) Plastic |
|
| 14. |
Assertion:- Acrylic acid is unsaturated compound. Reason:- One double bond between the carbon atoms is presentA. If both Assertion `&` Reason are True `&` the Reason is a correct explanation of the Assertion.B. If both Assertion `&` Reason are True but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is False.D. If both Assertion `&` Reason are False. |
| Answer» Correct Answer - A | |
| 15. |
Assertion:- All the hydrogen atoms in but -2-ene lie in one plan. Reason:- All C-atom in it are `sp^(2)`-hybridisedA. If both Assertion `&` Reason are True `&` the Reason is a correct explanation of the Assertion.B. If both Assertion `&` Reason are True but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is False.D. If both Assertion `&` Reason are False. |
| Answer» Correct Answer - D | |
| 16. |
Defects are basically irregularities in the arrangement of constituent particles. Broadly speaking the defects are of two types. Namely point defects and line defects. Point defects: The irregularities or deviations from ideal arrangement around a point or an atom in the crystalline substance. Line defects: The irregularities or deviations from ideal arrangement in entire row of lattice points. Answer the following question. When crystals of LiCI is heated in an atmosphere of Li (vap). it appears pink in colour because ofA. Metal excess defect due to anionic vaccaniesB. Metal excess defect due to presence of extra cation at interstial site.C. Metal deficiency defectD. Schottky defect |
| Answer» Correct Answer - A | |
| 17. |
Ortho effect is a special type of effect that is shown by d-substituents, but it is not necessarily just a steric effect.This ortho-effect opertes with the benzoic acid.Irrespective of the polar types nearly all o-substitued benzoic acid are stronger than unsubstituted beznoic acid.Benzoic acid is a resonance hybrid and so the carboxyl group is coplanar with the ring.An o-substituent tends to prevent this coplanarity . Ortho effect also opertes in substituted anilines where as ortho substituent has base weakening effect. What is the order of acidity of following compounds : A. IgtIVgtIIIgtIIB. IgtIIIgtIVgtIIC. IVgtIgtIIIgtIID. IIIgtIVgtIgtII |
|
Answer» Correct Answer - A (i)Is strongest due to intramolecular bond formation in conjugate base. (iv)Comes next due to intramolecular H bonding with OH group. (iii)Comes next due to ortho effect. |
|
| 18. |
Defects are basically irregularities in the arrangement of constituent particles. Broadly speaking the defects are of two types. Namely point defects and line defects. Point defects: The irregularities or deviations from ideal arrangement around a point or an atom in the crystalline substance. Line defects: The irregularities or deviations from ideal arrangement in entire row of lattice points. Answer the following question. Select the correct statements : Frenkel defect create a vacancy defect at its original site and an interstitial defect at its new position. Frenkel defect is also called dislocation defect Silver halide shows Frenkel defectA. `(ii),(iii),(iv)only`B. `(i),(ii),(iii)only`C. `(i),(ii),(iii),(iv)`D. `(i),(ii),(iv)only` |
| Answer» Correct Answer - C | |
| 19. |
Broadly speaking there are four types of stereisomers namely conformational isomers geometrical isomers, enantiomers and diastereomers.Although conformational isomers , have same configuration geometrical isomers have different atoms attached to each of the doubly bonded carbon atom, and enantiomers are due to chirality in the molecule Enantiomers are also known as optical isomers and diastereomers are those stereoisomers which are not enantiomers.In simple compound, number of stereoisomers.In chiral molecule is given by the reaction `2^n`, where n is the number of dissimilar chiral carbon. Observe the following structures and answer the questions given below : How many stereoisomers are possible in pent-3-en-2-ol, `CH_3CH=CHCHOHCH_3`A. 1B. 2C. 3D. 4 |
|
Answer» Correct Answer - D `CH_3CH=CHCH(OH)CH_3` has two stereocentres. Hence 4 stereoisomers. |
|
| 20. |
Assertion:- All compounds having C=C bond exhibit geometrical isomerism Reason:- Rotation about C=C is restrictedA. If both Assertion `&` Reason are True `&` the Reason is a correct explanation of the Assertion.B. If both Assertion `&` Reason are True but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is False.D. If both Assertion `&` Reason are False. |
| Answer» Correct Answer - D | |
| 21. |
In which cases the octet rule is violated: `BeBr_(2),NH_(3),AlBr_(3),PBr_(5),CO_(3)^(2-),CO_(2),SO_(2),SF_(2),SF_(2),SF_(6)` |
| Answer» The octet rule is violated in `BeBr_(2),AlBr_(3),PBr_(5),SF_(4)` and `SF_(6)`. | |
| 22. |
Broadly speaking there are four types of stereisomers namely conformational isomers geometrical isomers, enantiomers and diastereomers.Although conformational isomers , have same configuration geometrical isomers have different atoms attached to each of the doubly bonded carbon atom, and enantiomers are due to chirality in the molecule Enantiomers are also known as optical isomers and diastereomers are those stereoisomers which are not enantiomers.In simple compound, number of stereoisomers.In chiral molecule is given by the reaction `2^n`, where n is the number of dissimilar chiral carbon. Observe the following structures and answer the questions given below : The correct names for the above structure is :A. (2S, 3E)-3-penten-2-olB. (2R, 3E)-3-penten-2-olC. (2R, 3Z)-3-penten-2-olD. (2S, 3E)-3-penten-2-ol |
|
Answer» Correct Answer - B In naming of the above compound, follow the rules for priority order (E,Z) and (R,S) system. |
|
| 23. |
Assertion Geometrical isomers are non-inter- convertible by rotation. Reason Alkenes have restricted rotation about pi`(pi)` bond. |
| Answer» The overlapping vanishes and bond breaks. | |
| 24. |
In allene `(C_(3)H_(4))`, the type(s) of hybridisation of the carbon atoms, is (are)A. sp and `sp^(3)`B. sp and `sp^(3)`C. only `sp^(2)`D. `sp^(2)` and `sp^(3)` |
| Answer» Correct Answer - B | |
| 25. |
Stoichiometric air-fuel ratio by mass for combustion of petrol is (a) 5 (b) 10 (c) 12 (d) 15.05. |
|
Answer» Correct option is (d) 15.05. |
|
| 26. |
The lower heating value of propane at constant pressure and 25°C is 2044009 kJ per kg mole. Find the higher heating value at constant pressure and at constant volume. |
|
Answer» (i) Higher heating value at constant pressure, (HHV)P : The combustion reaction for propane is written as C3H8 + 5O2 = 3CO2 + 4H2O Now (HHV)p = (LHV)p + mhfg where, HHV = Higher heating value at constant pressure, LHV = Lower heating value, m = Mass of water formed by combustion = 4 × 18 = 72 kg per kg mole, and hfg = Latent heat of vaporisation at given temperature per unit mass of water = 2443 kJ/kg at 25°C. ∴ (HHV)p = 2044009 + 72(2442) = 2219833 kJ/kg. (ii) Higher heating value at constant volume, (HHV)v : Now (∆U) = ∆H – ∆nR0T or – (HHV)v = – (HHV)p – ∆nR0 T or (HHV)v = (HHV)p + ∆nR0 T where R0 = universal gas constant = 8.3143 kJ/kg mol K ∆n = nP – nR [np = number of moles of gaseous products] [nR = number of moles of gaseous reactants] Now, the reaction for higher heating value is C3H8 + 5O2 = 3CO2 + 4H2O (liquid) ∆n = 3 – (1 + 5) = – 3 (HHV)v = 2219905 – 3(8.3143)(25 + 273) = 2212472 kJ/kg. |
|
| 27. |
∆H0 (enthalpy of combustion at reference temperature T0) for benzene vapour (C6H6) at 25°C is – 3301000 kJ/mole with the H2O in the liquid phase. Calculate ∆H0 for the H2O in the vapour phase. |
|
Answer» If H2O remains as a vapour the heat transferred to the surroundings will be less than when the vapour condenses by the amount due to the change in enthalpy of the vapour during condensation at the reference temperature. ∆H0 (vapour) = ∆H0 (liquid) + ms hfgo where, ms = Mass of H2O formed, and hfgo = Change in enthalpy of steam between saturated liquid and saturated vapour at the reference temperature T0 = 2441.8 kJ at 25°C For the reaction : C6H6 + 7.5O2 → 6CO2 + 3H2O 3 moles of H2O are formed on combustion of 1 mole of C6H6 ; 3 moles of H2O = 3 × 18 = 54 kg H2O ∆H0 (vapour) = – 3301000 + 54 × 2441.8 = – 3169143 kJ/mole. |
|
| 28. |
Hydration energy of the given ions follows the order.A. `Li^(+) gt K^(+) gt Na^(+) gt Rb^(+) gt Cs^(+)`B. `Cs^(+) gt Rb^(+) gt K^(+) gt Rb^(+) gt Cs^(+)`C. `Na^(+) gt K^(+) gt Rb^(+) gt Cs^(+) gt Li^(+)`D. ` Li^(+) gt Na^(+) gt K^(+) gt Rb^(+) gt Cs^(+)` |
|
Answer» Correct Answer - 4 `Li^(+) gt Na^(+) gt K^(+) gt Rb^(+) gt Cs^(+)`=Hydration energy order `to` Size of cation increases `to ` hydration energy decreases |
|
| 29. |
When x gm carbon is burnt with y gm oxygen in a closed vessel, no residue is left behind. Which of the following statement is correct regarding the relative amounts of oxygen and carbon?A. y/x must be less than 1.33B. y/x must be equal to 1.33C. y/x must be greater than 2.67D. y/x must lie from 1.33 to 2.67 |
|
Answer» Correct Answer - 4 For maximum ratio `C_((s))+O_(2(g))to CO_(2(g))` `12 gm=x, 32 gm =y" " 32/12=8/3` For minimum ratio `C_((s))+1/2 O_(2(g)) to CO_((g))` `12 g m " " 16 gm " " 16/12 =4/3` `4/3 4/3 le y/x le 8/3` |
|
| 30. |
`2g` of a non-volatile hydrocarbon solute dissolved in `100g` of a hypothetical organic solvent (molar mass `=50`) was found to lower the vapour pressure from `75.00` to `74.50 mm` of `Hg` at `20^(@)C`. Given that the hydrocarbon contains `96%` of `C`, what is the molecular formula of the hydrocarbon ?A. `C_(6)H_(6)`B. `C_(12)H_(6)`C. `C_(7)H_(6)`D. `C_(14)H_(10)` |
|
Answer» Correct Answer - 4 According to Raoutls law `(Deltap)/(p^(0))=x_(2)` Where `-Delta p =(74.01-74.66)` torr and `p^(0)=74.66` torr ltbtgt If M is the molar mass of hydrocarbon, then `X_(2)=(n_(2))/(n_(1)+n_(2))=((8)/(M))/(((100)/(78))+((2)/(M)))` Hence `(74.66-74.01)/(74.66)=((2)/(M))/((100)/(78)+(2)/(M))` Solving for M, we get , `M =177.6 g mol^(-1)` . Given mass ratio is `m_(c):m_(H): :934.4:5.6` This atomic ratio is `N_(C): N_(H): :(84.4)/(12):(5.6)/(1)implies7.87:5.6" "implies1.4:1implies7:5` Hence, Empirical formula is `C_(7)H_(5)` Molar Emipirical mass `89g mol^(-1)` Number of `C_(7)H_(5)` unit in the given molecule `=("Molar mass")/("Molar empirical mass")=(177.6)/(89)-=2` Thus molecular formula is `C_(14)H_(10)` |
|
| 31. |
4g of copper chloride on analysis was founded to contain 1.890 g of copper (Cu) and 2.110 g of chlorine (Cl). What is the empirical formula of copper chloride? [At. mass of Cu = 63.5 u, Cl = 35.5 u]. |
||||||||||||||||||
Answer»
Empirical formula = CuCl2. |
|||||||||||||||||||
| 32. |
pH value of 0.001 M NaOH solution is______. |
|
Answer» 0.001 M NaOH [OH– ] = 10–3 pOH = 3 pH = 11 |
|
| 33. |
Why is red phosphorus denser and less chemically reactive than white phosphorus ? |
|
Answer» [Hint : Because it have polymeric structure consisting chains of P4 tetrahedra, hence denser than white P while red P is not having angular strain as in white P, hence less reactive than white P.] |
|
| 34. |
Cement is a complex mixture of silicates and aluminates. 1. What is the function of gypsum in cement? 2. Explain setting of cement. |
|
Answer» 1. The purpose of adding gypsum is only to slow down the process of setting of the cement so that it gets sufficiently hardened. 2. When the cement is mixed with water, it forms a gelatinous mass which sets slowly to a hard mass having 3 dimensional network structure with -Si- O-Si and -Si-OAI- chains. This is an exothermic process and is called setting of cement. |
|
| 35. |
Give the names of the followingi) An aldehyde derived from ethane.ii) Ketone derived from butaneiii) Compound obtained by the oxidation of ethanol by chromic anhydride. |
|
Answer» i) Ethanal (CH3CHO) ii) Butanone (CH3CO CH2CH3) iii) Ethanol (CH3CHO). |
|
| 36. |
Charles was not sure which profession to enter, but finally ________ for the Law. A) chose B) opted C) selected D) accepted E) preferred |
|
Answer» Correct option is B) opted |
|
| 37. |
How is ethyne prepared from calcium carbide? |
|
Answer» When calcium carbide react with water to form ethyne. CaC2 + 2H2O → CH ≡ CH + Ca(OH)2 |
|
| 38. |
Name the oxidizing agent used in the ostwald process |
| Answer» Oxygen is used as oxidising agent in Ostwald Process. | |
| 39. |
State the pH of a mixture of a polyprotic weak acid and a strong acid. |
|
Answer» pH of a mixture of a polyprotic weak acid and a strong acid :
|
|
| 40. |
Statement I: KHSO4 dehydrates Glycerol to form acroleinStatement II: Acrolein has fruity smell and reaction is used for test of GlycerolChoose the most appropriate option:(1) Both Statement I and Statement II are correct.(2) Both Statement I and Statement II are incorrect.(3) Statement I is correct but Statement II is incorrect.(4) Statement I is incorrect but Statement II is correct. |
|
Answer» Correct option is (2) Both Statement I and Statement II are incorrect. |
|
| 41. |
Consider the following metal complexes : [Co(NH3)]3+[CoCl(NH3)5]2+[Co(CN)6]3–[Co(NH3)5(H2O)]3+ The spin-only magnetic moment value of the complex that absorbs light with shortest wavelength is B.M. (Nearest integer) |
|
Answer» \(\Delta_0 \propto \frac1\lambda\) Here, CN– being SFL will have maximum CFSE So, [Co(CN)6]3– will be d2 sp3, µ = 0 |
|
| 42. |
Statement-1: Pig iron is formed by cast iron and iron scrap.Statement - II: Pig iron contain less carbon, than cast iron.(1) Both statement - I & II are true(2) Statement - I is true while statement - II is false(3) Statement - I is false while statement - II is true(4) Both statement - I & Statement - II are false. |
|
Answer» Correct option is (4) Both statement - I & Statement - II are false. Cast iron are formed by pig iron & scarp iron Pig iron ⇒ Carbon 4% Cast iron ⇒ Carbon 3% |
|
| 43. |
In the following complexes(a) : [Co(NH3)6]3+, (b) : [Co(en)3]3+, (c) : [Co(H2O)6]3+Identify the correct order of absorption of energy.(1) c < a < b(2) a < b < c(3) c < b < a(4) a < c < b |
|
Answer» Correct option is (1) c < a < b All are Co3+ complex so stronger the ligand, greater is splitting of d orbital and greater is amount of energy absorbed. Order of strength of ligands: en > NH3 > H2O \(E = \frac{hc}\lambda\) |
|
| 44. |
For an acid base titration, methyl orange is used as indicator, then which form of the methyl orange is exist at end point(1) Quinonoid(2) Heterocyclic (3) Phenolic(4) Benzonoid |
|
Answer» Correct option is (1) Quinonoid |
|
| 45. |
1. प्यूपा 2. अंडा 3. तितली 4. डिंभकA. 1, 3, 2, 4B. 3, 1, 4, 2C. 2, 4, 1, 3D. 4, 3, 2, 1 |
|
Answer» Correct Answer - C शब्दों का सार्थक क्रम: `{:("2. अंडा "),(" "darr),("4. डिंभक"),(" "darr),("1. प्यूपा "),(" "darr),("3. तितली"):}` |
|
| 46. |
निम्नलिखित विकल्पों में से कौन-सा विकल्प नीचे दिये हुए शब्दों का सार्थक क्रम दर्शाता है? (A) पदार्थ (B) परमाणु (C ) अणु (D) प्रोटोनA. (D), (B), (C ), (A)B. (A), (B), (C ), (D)C. (B), ( C ), (D), (A)D. (D), ( C), (B), (A) |
|
Answer» Correct Answer - A छोट से बड़े बढ़ते आकारों में शब्दों का सार्थक क्रम : `{:("D.प्रोटोन "),(" "darr),("B. परमाणु "),(" "darr),("C. अणु "),(" "darr),("A. पदार्थ "):}` |
|
| 47. |
निम्नलिखित विकल्पों में से कौन-सा विकल्प नीचे दिए हुए शब्दों का सार्थक आरोही क्रम दर्शाता है ? (A) ब्रह्मपुत्र (B) अटलांटिक (C) चिलका (D) बंगाल की खाड़ीA. (A), (D), (C ), (B)B. (B), (D), (C ), (A)C. (C ), (A), (D), (B)D. (C ), (D), (B) (A) |
|
Answer» Correct Answer - C शब्दों का सार्थक क्रम : `{:("C. चिलका "),(" "darr),("D. ब्रहापुत्र "),(" "darr),("B. बंगाल की खड़ी"),(" "darr),("B. अटलांटिक "):}` चिलका एक झील है, ब्रह्मपुत्र एक नदी है | बंगाल की खाड़ी एक समुंद्र है | जबकि अटलांटिक एक महासागर है | |
|
| 48. |
इस प्रश्न में दिया गया कौन सा विकल्प निम्नलिखित शब्दों का सार्थक क्रम होगा ? 1. बालक 2. व्यवसाय 3. विवाह 4. शिशु 5.शिक्षाA. 1, 3, 5, 2, 4B. 5, 4, 1, 3, 2C. 2, 1, 4, 3, 5D. 4, 1, 5, 2, 3 |
|
Answer» Correct Answer - D शब्दों का सार्थक क्रम : `{:("4.शिशु "),(" "darr),(" 1.बालक "),(" "darr),(" 5.शिक्षा "),(" "darr),(" 2.व्यवसाय "),(" "darr),(" 3.विवाह "):} |
|
| 49. |
परमाणु युग, धात्विक युग, प्रस्तर (पाषाण ) युग और मिश्रधातु युग को (सबसे प्रारंभ से शुरू करते हुए ) यदि सार्थक क्रम में रखा जाए, तो तीसरे स्थान पर कौन-सा युग होगा ?A. मिश्रधातु युगB. प्रस्तर युगC. धात्विक युगD. परमाणु युग |
|
Answer» Correct Answer - A `{:("प्रस्तुरत योग "),(" "darr),("घटविक योग "),(" "darr),("मिश्रधातु योग "),(" "darr),(" परमाणु योग ):}` |
|
| 50. |
हार्डवेयर में अनुक्रम वार आर्डर देने का सर्वोत्तम तरीका क्या है ? 1. सिलिकॉन चिप्स 2. ट्रांसिस्टर 3. निर्वात नली 4. एकीकृत परिपथA. 4, 2, 3, 1B. 3, 4, 1, 2C. 3, 2, 4, 1D. 4, 1, 3, 2 |
|
Answer» Correct Answer - C `{:("3.निर्वात नाली ( पहली पीढ़ी : 1940 - 55 )"),(" "darr),("2. ट्रांसिस्टर ( दूसरी पीढ़ी : 1956 - 63 )"),(" "darr),("4. एकीकृत परिपथ ( तीसरी पीढ़ी : 1964 - 71 ) "),(" "darr),(" 1.सिलिकॉन चिप्स ):}` |
|