Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Write IUPAC name of [Cu(NH3)4]Cl2

Answer»

Tetra ammino copper (II) chloride

2.

Define osmotic pressure. Why does osmotic pressure become abnormal?

Answer»

Osmotic Pressure:-

The extra pressure that must be applied to the soln component to prevent the flow of solvent into the solution when the two are separated by SPM. It is devoted by II.

Osmotic pressure be come abnormal due to-

(i) Association or dissociation of solute molecule in the soln.

(ii) Solutue is volatile

(iii) Solute become electolyte

3.

You have to first go through the paragraph carefully and then select the answer of the related questions from the option given:Transition elements show varibale oxidation state. This is because their valence electrons are found in two different orbitals i.e. ns and (n-1)d. Up to +2 oxidation state ns electrons are involved but in higher oxidation states electrons of (n-1)d subshell are involved.The cause of variable valency among transition elements is(A) They all exist in more than one oxidation states(B) They all form complex compounds(C) The valence electrons of them are found in two different subshells(D) They all have paired electrons

Answer»

Answer (C) The valence electrons of them are found in two different subshells

4.

Species having Bond order 2(1/2) is/are(a) N2+(b) O2+(c) O2-2(d) N2-2

Answer»

Answer (a,b) N2+ & O2+

5.

Read carefully the passage and select the correct answer out of given four options:Transition elements show variable oxidation states. This is due to their valence electrons which are found in two different orbitals i.e., ns and (n-1)d. Up to (+II) oxidation state ns electrons are involved, but in higher oxidation states, electrons of (n-1)d sun-shells are involved.The cause of variable oxidation state among transition elements is(a)  they all exist in more than one oxidation state(b) they all form complex compounds(c) the valence electrons of them are found in two different sub-shells(d) they all have paired sub-shells

Answer»

Answer (c)  the valence electrons of them are found in two different sub-shells

6.

There are two columns, Column-I contains 4 questions. You have to match the correct options of these questions as (a),(b),(c) and (d) from Column-II:Column-IColumn-II1. Lewis base(a) CaO2. Blue vitriol(b) C2H5HC3. Quicklime(c) NH34. Carbylamine(d) CuSO4.5H2O

Answer»

1. (c) 2. (d) 3. (a) 4. (b)

7.

Read carefully the passage and select the correct answer out of given four options:Transition elements show variable oxidation states. This is due to their valence electrons which are found in two different orbitals i.e., ns and (n-1)d. Up to (+II) oxidation state ns electrons are involved, but in higher oxidation states, electrons of (n-1)d sun-shells are involved.The transition metal which shows the highest oxidation state is(a) Mn(b) Pt(c) Fe(d) Ni

Answer»

Answer (a) Mn

8.

Read carefully the passage and select the correct answer out of given four options:Transition elements show variable oxidation states. This is due to their valence electrons which are found in two different orbitals i.e., ns and (n-1)d. Up to (+II) oxidation state ns electrons are involved, but in higher oxidation states, electrons of (n-1)d sun-shells are involved.The most common oxidation state shown by 1st row of transition elements is(a) (+II)(b) (+III)(c) (+IV)(d) All of these

Answer»

Answer (a) (+II)

9.

You have to first go through the paragraph carefully and then select the answer of the related questions from the option given:Transition elements show varibale oxidation state. This is because their valence electrons are found in two different orbitals i.e. ns and (n-1)d. Up to +2 oxidation state ns electrons are involved but in higher oxidation states electrons of (n-1)d subshell are involved.The most common oxidation state shown by first row transition elements is(A) +2(B) +3(C) +4(D) all of these

Answer»

Answer (B) +3

10.

Chlorobenzene gives DDT when it reacts with(A) Charcoal(B) Chloral(C) Naphthaiene(D) Benzenoid

Answer»

Answer (B) Chloral

11.

In Column I four questions are given. You have to match the correct answers from the options in Column II.Column IColumn II1. Aqua Fortis(A) CaOCl22. Chloral(B) K2SO4Cr2(SO4)3,24H2O3. Alum(C) HNO34. Bleaching powder(D) CCl3CHO

Answer»

1. (C) 2. (D) 3. (B) 4. (A)

12.

(ii) 11 th term of the AP: -3,-(1/2), 2 ;....., is 

Answer» using formula = a + (n-1)d

where a=first term

n=nth term

d=common difference

answer  : -3 + (11-1)5/2

                -3 + 10*2.5

                -3 + 25

                 22
13.

In a given process on an ideal gas, dw = 0 and dQ < 0. Then for the gas(A) the temperature will decrease(B) the volume will increase(C) the pressure will remain constant(D) the temperature will increase

Answer»

Answer (A) the temperature will decrease

14.

Let S = {1, 2,....., 20}. A subset B of S is said to be "nice", if the sum of the elements of B is 203. Then the probability that a randomly chosen subset of S is "nice" is :(1)  4/220(2)  7/220(3)   5/220(4)  6/220

Answer»

Correct option  (3)  5/220

Explanation:

Sum of all number of set S = 210.

We have to find numbers whose sum is 203.

So basically we have to remove 7.

7 can be obtained as 7

1, 6

2, 5

3, 4

1, 2, 4 

Total = 5

Samples space = 220 

So   5/220

15.

In the following question, two statements are numbered as A and B. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option.Quantity A: A car completes a journey in 6 hours with a speed of 50 km/hr. At what speed must it travel to complete the journey in 8 hours?Quantity B: 40 km/hr1. Quantity A ≥ Quantity B2. Quantity A ≤ Quantity B3. Quantity A < Quantity B4. Quantity A > Quantity B5. Quantity A = Quantity B or No relation

Answer» Correct Answer - Option 3 : Quantity A < Quantity B

Quantity A:

Speed = Distance/Time

50 = Distance / 6

Distance = 300 km

To complete the journey in 5 hours

Speed = 300/8 = 37.5 km/hr

Quantity B: 40 km/hr

Quantity A < Quantity B

16.

In the following question, two statements are numbered as A and B. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option.Quantity A: In a bag there are 10 slips. One English alphabet is written on each slip. Bag contain all the vowels slips. One slip is drawn randomly. Find the probability of drawn slip contains vowel.Quantity B: 1/31. Quantity A ≥ Quantity B2. Quantity A ≤ Quantity B3. Quantity A &lt; Quantity B4. Quantity A &gt; Quantity B5. Quantity A = Quantity B or No relation

Answer» Correct Answer - Option 4 : Quantity A > Quantity B

Quantity A:

P(E) = Number of favorable outcomes/ total number of outcomes

⇒ Let E is a probability of an event.

⇒ Total number of outcomes = 10

⇒ Number of favorable outcomes = 5

P (E) = 5/10 = 1/2

Quantity B: 1/3

∴ Quantity A > Quantity B

17.

In one mowing, how much portion of lawn grass should be cut A. 1/2 B. 2/3 C. 1/4 D. 1/3

Answer»

D. 1/3

In one mowing, 1/3 portion of lawn grass should be cut.

18.

If a man cuts the grass of a lawn in T minutes, what part of the lawn can he cut in 30 minutes?1. T/302. T-303. 30-T4. 30/T

Answer» Correct Answer - Option 4 : 30/T

Given:

the grass of a lawn is cut by a man = T minutes

Concept used:

If a person does work in n days,

then one day work by a person = 1/n part of the total work.

Calculation:

∴  Grassland will be cut by a man in 1 minute = 1/T part

⇒ In 30 minutes, Grassland will be cut by a man = (1/T) × 30 part

⇒ In 30 minutes, Grassland will be cut by a man = 30/T part

Hence, part of the lawn can be cut in 30 minutes is 30/T.

19.

Which is the national leader who walked the marathon 'Padayatra' from Kanyakumari to Rajghat in Delhi in 1983? The purpose of this visit was to renew the relationship with the Indian people.1. Chandrashekhar2. LK Advani3. Ram Vilas Paswan4. VP Singh

Answer» Correct Answer - Option 1 : Chandrashekhar

The correct answer is Chandrashekhar.

  • Chandrashekhar is the national leader who walked the marathon 'Padayatra' from Kanyakumari to Rajghat in Delhi in 1983.
  • Covering a distance of nearly 4260kms from January 6, 1983, it was completed on June 25, 1983.
  • The Padayatra was undertaken to renew rapport with the masses and to understand their pressing problems.

  • Shri Chandra Sekhar was among the few individuals in the then ruling party who was imprisoned during the Emergency.
  • He has been a Member of Parliament since 1962 except for a brief period from 1984 to 1989.
20.

If α and β are the zeros of the quadratic polynomial f(x) = ax2 + bx + c, then evaluate-

Answer»

Given that \(\alpha\) and \(\beta\) are zeros of the quadratic polynomial f(x) = ax2 + bx + c.

\(\because\) sum of zeros is \(\alpha\) + \(\beta\) \(=\frac{-b}{a}\).

And product of the zeros is \(\alpha \beta\) \(=\frac{c}{a}\).

Now, \(\frac{(\alpha+\beta)^2}{\alpha\beta}\) \(=\frac{\alpha^2}{\alpha\beta}+\frac{\beta^2}{\alpha\beta}+\frac{2\alpha\beta}{\alpha\beta}\) 

\(=\frac{\alpha}{\beta}+\frac{\beta}{\alpha}+2\)

⇒ \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) \(=\frac{(\alpha+\beta)^2}{\alpha\beta}-2\) \(=\frac{\left(\frac{-b}{a}\right)^2}{\frac{c}{a}}-2\) 

\(=\frac{b^2}{ac}-2\) \(=\frac{b^2-2ac}{ac}\)

\(\Rightarrow \frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) \(=\frac{b^2-2ac}{ac}\) ...........(1)

And \(\frac{(\alpha+\beta)^3}{\alpha\beta}\) \(=\frac{\alpha^3+\beta^3+3\alpha^2\beta+3\alpha\beta^2}{\alpha\beta}\)  

\(\Big(\because (a+b)^3\) \(=a^3+b^3+3a^2b + 3ab^2\Big)\)

\(=\frac{\alpha^2}{\beta}+\frac{\beta^2}{\alpha}+3\alpha+3\beta\)

\(=\frac{\alpha^2}{\beta}+\frac{\beta^2}{\alpha}+3(\alpha+\beta)\)

\(\Rightarrow \frac{\alpha^2}{\beta}+\frac{\beta^2}{\alpha}\) \(=\frac{(\alpha+\beta)^3}{\alpha\beta}\) \(-3(\alpha+\beta)\)

\(=(\alpha+\beta)\left(\frac{(\alpha+\beta)^2}{\alpha\beta}-3\right)\)

\(\Rightarrow \frac{\alpha^2}{\beta}+\frac{\beta^2}{\alpha}\) \(=\frac{-b}{a}\left(\frac{\left(\frac{-b}{a}\right)^2}{\frac{c}{a}}-3\right)\)  

(By putting values of \(\alpha \) + \(\beta\) and \(\alpha \)\(\beta\))

\(=\frac{-b}{a}\left(\frac{b^2}{ac}-3\right)\) ..........(2)

Now, \(a\times \left(\frac{\alpha^2}{\beta}+\frac{\beta^2}{\alpha}\right)\) \(+b\times \left(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\right)\)  

\(=a\left(\frac{-b}{a}\times \frac{b^2-3ac}{ac}\right)\)\(+b\times \left(\frac{b^2-2ac}{ac}\right)\)  (From equation (1) and (2))

\(=\frac{-b^3+3abc}{ac}+\frac{b^3-2abc}{ac}\)

\(=\frac{-b^3+3abc+b^3-2abc}{ac}\)

\(=\frac{abc}{ac}\)

\(=b\).

21.

An engine has an efficiency of `1/6`. When the temperature of sink is reduced by `62^(@)C`, its efficiency is doubled. Temperature of the source isA. 470 KB. 372KC. 542KD. 1042K

Answer» Correct Answer - C
22.

The graph below shows how the force on a mass depends on the position of the mass. What is the change in the kinetic energy of the mass as it moves from x=0.0m to x=3.0 m ? A. 0.0JB. 20 JC. 50 JD. 60 J

Answer» Correct Answer - C
Change in KE-Workdone
-Area of graph
`=1//2(1)(20)+(2)(20)=50J
23.

A metal coin at the bottom of a beaker filled with a liquid of refractive index `4//3` to height of `6 cm`. To an observer looking from above the surface of the liquid, coin will appear at a depth of (consider paraxial rays).A. `7.5 cm`B. `6.75 cm`C. `4.5 cm`D. `1.5 cm`

Answer» Correct Answer - C
Here : Actual depth of liquid `h =6 cm`,
Refractive, index of the liquid `= (4)/(3)`
Using the relation
`mu=("actual depth(h)")/("apparent depth(x)")`
or `x=h xx (3)/() =6 xx (3)/(4) =4.5 cm`.
24.

In which of the following districts Fair of Jogeshwari organised?1. Ashok Nagar2. Alirajpur3. Shahdol4. Morena

Answer» Correct Answer - Option 1 : Ashok Nagar

The correct answer is Ashok Nagar.

  • The fair of Jogeshwari is organized at Chanderi (Famous for silk) in the Ashoka Nagar district. This fair is organized every year during the month of Chaitra (March-April).
  • In this fair Clothes, Utensils, and Cattle are sold and purchased. 
  • In this district, the state's only open jail (Mungawali) is situated.

StateMadhya Pradesh
DivisionAshok Nagar
TypeMayor-council
HeadquartersAshok Nagar
Area (Total)4673.94km(km) 
Population (2011) total8,45,071
Density147/km
Literacy rate66.4%
Sex Ratio902
Lok Sabha Constituencies1
Vidhan Sabha Constituencies7
25.

Ravish Kumar a journalist, is associated with which of the following news channels?1. NDTV2. Rajya Sabha TV3. Republic TV4. Times Now

Answer» Correct Answer - Option 1 : NDTV

The correct answer is NDTV.

  • Ravish Kumar is New Delhi Television Network (NDTV) India's senior executive editor and one of India's most influential TV journalists.
  • He has been reporting real-life and under-reported problems of ordinary common people.
  • He hosts many programs include Prime Time, Hum Log, Ravish Ki Report, and Des Ki Baat.
  • Television journalist Ravish Kumar was honored with the prestigious Ramon Magsaysay Award 2019 for giving "voice to the voiceless".
  • He was awarded Red Ink Award for Journalist of the Year in 2016.
26.

In which of the following states of India is the ‘Ambubachi Mela’ held every year ?1. Kerala2. Gujarat3. Sikkim4. Assam

Answer» Correct Answer - Option 4 : Assam

The correct answer is Assam.

  • Ambubachi Mela is one of the biggest congregations in eastern India. It is the most important festival of the Kamakhya temple and is celebrated in the month of June every year.
  • It is more of a ritual of austerities, a festival celebrated with Shakti rites. The belief is that Kamakhya embodies the mother cult, the Shakti.

 

  • Kumbh Mela is a very big fair and the largest gathering of Hindu pilgrims, celebrated every twelve years at four holy places Prayag (Allahabad), Haridwar, Ujjain, and Nashik.
  • The Sonepur Cattle Fair held (November) on full moon day in Bihar, on the confluence of river Ganges and Gandak. Sonepur Fair is also known as the Harihar Chhetra Mela.
  • Pushkar Fair is one of the world’s largest camel fairs, held (October-November) in the oldest city of Rajasthan “Pushkar”. The Pushkar camel fair attracts a large number of visitors from all around the world, especially from Israel.
  • Hemis Gompa festival is a religious fair and one of the most auspicious Occasions for the Buddhist community in India.
27.

The currency of European Union is?(a) Dollar(b) Rupees(c) Euro(d) None of These 

Answer»

The currency of European Union is Euro

28.

In 2020, India's purchasing power parity was 22 national currency units (rupees) per US dollar. Source: OECD What does this mean? A. Goods that can be bought for 1 dollar in the US would require 22 rupees in India. B. Goods in India that can be bought for 1 dollar would require 22 dollars in the US. C. Goods that can be bought for 1 dollar in the US would require 22 dollars in India.D. Goods in India that can be bought for 1 rupee would require 22 dollars in the US.

Answer»

A. Goods that can be bought for 1 dollar in the US would require 22 rupees in India

29.

Higgs Boson are also known as1. Proton2. Neutrons3. God Particles4. Electron

Answer» Correct Answer - Option 3 : God Particles

The correct answer is God Particles.

  • Higgs Boson is also known as  God Particles.
  • It is a subatomic particle whose existence is predicted by the theory which unified the weak and electromagnetic interactions.
  • It is the fundamental particle associated with the Higgs field, a field that gives mass to other fundamental particles
  • Nobel Prize-winning physicist Leon Lederman referred to the Higgs as the "Goddamn Particle" as it was difficult to detect it.
  • The Higgs boson was proposed in 1964 by Peter Higgs, François Englert, and four other theorists to explain why certain particles have mass.
  • Scientists confirmed its existence in 2012 through the ATLAS and CMS experiments at the Large Hadron Collider (LHC) at CERN in Switzerland.
  • This discovery led to the 2013 Nobel Prize in Physics being awarded to Higgs and Englert.
30.

A wire carrying a current `i` is placed in a uniform magnetic field in the form of the curve `y=asin((pix)/L)0 lexle2L`. The force acting on the wire is A. `(iBL)/(pi)`B. iBL`pi`C. `2iBL`D. zero

Answer» Correct Answer - C
Shortest distance between end points of wire is
2L so force
` F = I ( 2L) b sin 90 ^(@)`
31.

The number of significant figures in 0.06900 isA. 5B. 4C. 3D. 2

Answer» Correct Answer - B
If the number is less than 1, the zero (s) on the right of decimal point and before the first non-zero digit are not significant. In 0.06900, the underlined zeroes are not significant. Hence, number of significant figures are four (6900).
32.

Which of the following statements is correct regarding adsorption.A. Graph between `log x//m` and log P is linear with slope n.B. Physisorption is specific while chemisorption is not specific in nature.C. Order of extent of physisorption on 1 gm of activated charcoal of `SO_(2).CH_(4)` and `H_(2)` gas is `SO_(2) gtCH_(4) gtH_(2)`.D. On increasing pressure physical adsorption decreases.

Answer» Correct Answer - C
33.

A small ball of mass m and charge q is attached to the bottom end of a piece of negligible mass thread of length l, whose top end is fixed. The system formed by the thread and ball is in vertical plane and is in uniform horizontal magnetic field B, which is perpendicular to the plane of figure and points into the paper The ball is started with a velocity `v_(0)` from lower most point of circle in a direction perpendicular both to the magnetic induction and to direction of thread. The ball moves along a circular path such that thread remains tight during the whole motion. Neglect any loss of enery. Choose CORRECT statementA. If direction of magnetic field is reversed then value of B will be same as calculated in above question of this paragraphB. If B is reversed, then conservation of energy will still be applicableC. If magnetic field were not present then particle will complete vertical circle for any value of `v_(0)`D. All of above are correct

Answer» Correct Answer - B
34.

A small ball of mass m and charge q is attached to the bottom end of a piece of negligible mass thread of length l, whose top end is fixed. The system formed by the thread and ball is in vertical plane and is in uniform horizontal magnetic field B, which is perpendicular to the plane of figure and points into the paper The ball is started with a velocity `v_(0)` from lower most point of circle in a direction perpendicular both to the magnetic induction and to direction of thread. The ball moves along a circular path such that thread remains tight during the whole motion. Neglect any loss of enery. By what factor is the force acting on the thread (tension in thread) at point A is greater than at point C, when speed of the ball is the above stated one?A. `(21+sqrt(17))/(18)`B. `(21+2sqrt(17))/(18)`C. `(21+3sqrt(17))/(18)`D.

Answer» Correct Answer - C
35.

The arms of a `U` shaped tube are vertical. The arm on right side is closed and other arm is closed by light movable piston. There is mercury in the tube and initially the level of the mercury in the arms is the same. Above the mercury, there is an air column of height h in each arm, and initial pressure is the same as atmospheric pressure in both arms. Now pistion is slowly pushed down by a distance of `h//2` (see figure) Let x is the displacement of mercury level in one of the stem and `P_(1)` is pressure in left column of air after compression, `P_(2)` is pressure in right column of air after compression and `P_(0)` is atmospheric pressure thenA. `h P_(0)=((h)/(2)+x)P_(1)`B. `hP_(0)=(h-x)P_(2)`C. `P_(1)=P_(2)`D. `P_(1)-P_(2)=2xpg` where p is density of mercury

Answer» Correct Answer - A::B::D
`p_(1)=(P_(0)h)/((h)/(2) + x )`
`P_(2)= (P_(0)h)/(h-x)`
` P_(1)-P_(2)=2x pg`
`(P_(0)h)/((h)/(2)+2)-(P_(0)h)/(h-x)=2xpg`
`P_(0)h[h-x-(h)/(2)-x]=((h)/(2)+x)(h-x)2xpg`
36.

A cup contains some mercury in it. Now a narrow glass tube is lowered in the mercury. After some time the mercury level in the tube becomes lower than the mercury level outside the tube as shown in diagram. During this process (Choose correct statements) A. Work done by atmospheric air on mercury is positveB. Gravitational potential energy of mercury is decreasedC. Work done by atmospheric air on mercury is zeroD. Gravitational potential energy of mercury increases

Answer» Correct Answer - C::D
Interaction energy loss is conveted in G.P.E and heat losses
37.

From a water tap, liquid comes out in from of cylinder. As water moves down, radius of that cylinder decreases. Consider, a very small element of height h and and radius R (due to smell height radius is assumed to be constant) This element is given in the diagram. An imaginary cross-section ABCD divides this element in two equal semi cylinder. S is surface tensionof liquid. Now choose correct statement(s) A. Surface energy of this elementary cylinder is `S[2piRh+2piR^(2)]`B. Pressure inside the cylinder is more than atmospheric pressure by` (2S)/(R )`C. Force exerted by one half cylinder on another half cylinder due to surface tension is 2Sh.D. Surface energy of this elementary cylinder is `Sxx2piRh`

Answer» Correct Answer - C::D
`"Surface energy" = "free surface area" xx "surface tension"`
for a cylindrical surface excess pressure is `(S)/(R )`
38.

“The cause for the Crusades was religious.” Do you agree with this. statement? Give details.

Answer»

The main goaf of the Crusades was recapturing Jerusalem which is the holy land of the Christians. Christians believe that the crucixion and resurrection of Jesus took place here. Thus Jerusalem is their most holy land. Jerusalem was once part of the Byzantine Empire. In 638, the Arabs captured it. But the Christians were given full protection by them.

There was no ban on visiting places including Jerusalem by Christian merchants, pilgrims, diplomats, and travellers. But in 1076, Seljuk Turks captured Jerusalem and from then they started persecuting the Christians there. This increased the enmity of Christians towards Muslims Many Normans, Hungarian, and Slavs became Christians around this time. Muslims Were the only rivals of Christians, The Peace of God movement in Europe also made the circumstances rife for the Crusades This Movement recognized and encouraged the fight against the enemies of the Christian God and nonbelievers in Christianity.

39.

Gradually the Crusaders lost their zeal. Based on this statement; analyse the results of the Crusades.

Answer»

The Crusaders gradually lost their zeal. They gave themselves to a life of luxury. Moreover, Christian rulers began to fight among themselves to get more territory. In the meantime, Salah ad-din (Saladin) built an Egyptian-Syrian Empire and gave a call for Jihad (holy war) against Christians. In 1187 he defeated the Crusaders and recaptured Jerusalem. Thus one century after the First Crusade, Jerusalem again came under the Turks. 

Saladin treated the Christiansguite humanely. They allowed them to keep the area of the sepulcher of Jesus. But, at the same time, he converted many Christian Churches into mosques. Once again Jerusalem became a Muslim city The 3 Crusade took place in 1189. It was the loss of the city of Jerusalem that prompted the Pope to give a call for another battle. 

In this war, the Crusaders did not get much benefit. They were able to capture some cities along the shores of Palestine. Christian pilgrims were given the right to visit Jerusalem at will. But in 1291 the Mamluks of Egypt, the rulers there, drove away all the Crusaders from Palestine. Europe slowly lost its interest in the Crusades. European nations began to give emphasis to their internal political and cultural development.

40.

During the Islamic rule, urbanization developed fast Explain.

Answer»

During the Islamic rule, many cities grew and many new cities were founded. The new cities were built to give residences to the Arab soldiers who were the backbone of the Provincial administration. These military cities were known as Misr. Kufa and Basra in Iraq and Fustar and Cairo in Egypt were the most famous of them. During the Abbasid Khalifas, the population of Baghdad reached 1 million and it became an important city. Old cities like Damascus, Isfahan, and Samarkhand also developed. The cities were interconnected.

Main military cities: 

Kufa, Basra, Fustar, Cairo.

Baghdad (capital city) 

Damascus, Isfahan, Samarkhand (old cities) 

In the heart of the city, there used to be two blocks of buildings. They were the centers for cultural and economic activities. One of them would be a mosque. It was big enough to be noticed from far. Another was a central market. In one row there would be shops, the residences of the merchants and a place, for changing money.

41.

Between 950 arid 1200, the Islamic society of the Middle Ages stood united because of certain common economic and cultural factors. Evaluate this statement.

Answer»

Between 950 and 1200, the Islamic society of the Middle Ages stood united not because of any political order or because of the one-language (Arabic) culture, but because of certain common economic and cultural factors. Even in the midst of political differences what maintained the unity was the separation between nation and society. The growth of Persian language and the intelligent discussions between different traditions nurtured this unity. 

Scholars, artists, and merchants travelled freely in the various Islamic countries and propagated their ideas, Through the converts, some of these ideas reached even remote villages. There was a big growth in the Muslim population. As a religion and as cultural system, the identity of Islam attracted members of other religion, making conversions meaningful.

42.

A bartender has three kinds of drinks of quantities of 204, 238 and 306 litres. The tender wants to pour them into minimum number of containers of equal capacity without mixing. Find the capacity of each container.1. 55 litres2. 64 litres3. 34 litres4. 44 litres

Answer» Correct Answer - Option 3 : 34 litres

Given:

The quantities of 3 kinds of drinks = 204 litres, 238 litres, and 306 litres.

Concept:

H.C.F. of two or more factors is the greatest factor that divides each of them exactly.

Calculation:

Factors of 204 = 2² × 3 × 17

Factors of 238 = 2 × 7 × 17

Factors of 306 = 3² × 2 × 17

H.C.F. of 204, 238 and 306 = 17 × 2 = 34

The capacity of each container = 34 litres

The capacity of each container is 34 litres.

43.

The HCF of two numbers is 23 and their LCM is 1035. If one of them is 207 and the other is X, find X/23.A. 15B. 7C. 5D. 91. C2. D3. B4. A

Answer» Correct Answer - Option 1 : C

Given:

HCF of two numbers is 23.

Their LCM is 1035.

One of them is 207.

Formula used:

HCF × LCM = Product of two numbers

Calculation:

HCF × LCM = Product of two numbers

⇒ 23 × 1035 = 207 × X

⇒ X = (23 × 1035)/207

⇒ X = 115

So, X/23 = 115/23 = 5

∴ The value of X/23 is 5.

44.

Bacteria differ from other filamentous fungal groups in one of the following feature?A. Cell wall of bacteria is celluloseB. Heterotrophic nutrition in fungiC. Binary fission in bacteriaD. presence of chlorophyll

Answer» Correct Answer - C
45.

When does cyclic photophosphorylation take place?

Answer» When noncyclic photophosphorylation is stopped, cyclic photophosphorylation takes place.
46.

How many `NADPH_(2)` and ATP are required for the synthesis of one molecule of glucose?

Answer» Twelve molecules of `NADPH_(2)` and eighteen molecules of ATP are required for the synthesis of one molecule of glucose.
47.

What will be the molar conductivity of Al 3+ ions at infinite dilution if molar conductivity of `Al^(2) (SO_(4))_(3)`is 858 S `cm^(2)` `"mol" ^(-1)` and ionic conductance of `SO_(4)^(2-)` is 160 S `cm^(2) "mol" ^(-1)` at infinite dilution ?A. `189 S cm^(2) "mol"^(-1)`B. `698 S cm^(2) "mol"^(-1)`C. `1018 S cm^(2) "mol"^(-1)`D. `429 S cm^(2) "mol"^(-1)`

Answer» Correct Answer - A
`overset(oo)Lambda_(m)[Al_(2)(SO_(4))_(3)]=Aoverset(oo)Lambda_(m)(Al^(+3))+3overset(oo)Lambda_(m)(SO_(4)^(-2))`
48.

Fill in the blanks with suitable modal auxiliary verbs:We ........... respect our elders

Answer»

We ouuhgt to respect our elders.

49.

Make a precis of the following passage and suggest a suitable title:Science has made the world a better place to live in. There is almost no end to the benefits that science has conferred on us. All the same, the work of science is no unmixed blessing. It has created new problems that threaten man. Science has to attend to the problems threatening man. It has to take up the problems of social life too. It has to work for freedom from war and various social and economic evils.Science can deal with these human affairs.There would be happiness and good feeling all round if we applied the scientific attitude to all our affairs.Properly using science and cultivating the scientific spirit man can control his destiny.

Answer»

Precis Title -Science: Blessing or Curse

Science has posed a great threat or problems but it has proved a boon for man.Really science is neither good not bad in itself.It totally depends on its use.It is used only for the welfare for humanity. It is a boon and good servant. But it is used for destruction it is a curse and a bad master.

50.

Make a precis of the following passage and suggest a suitable title:I do not, I repeat, enjoy seeing animals, forced to perform unnatural movements which they cannot possibly enjoy. I am prepared to believe that animals are treated by their trainers with real bindness and affection. But that is not the point. The Nazis enjoyed forcing their human victims to crawl about naked and on all fours. Ought we really to enjoy seeing animals dressed in crinolines and staraining with trembling limbs to maintain an erect position ? The taughtless laughter, even of adults, which greets and encourages these performances fill one with sadness.

Answer»

Importance of Animals

In this passage man enjoy to seeing animals. Animals also behaves man as for good behaves. Animals also follow guide of man. Some animals as dog, monkey and some other animals helped man to search some one. Hence animal has very good importance for human being.