Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Jaundice is a disease of …………(a) Kidney(b) Liver (c) Pancreas (d) Duodenum

Answer»

Correct Answer is: (b) Liver

2.

How vitamin E helps in maintaining normal membrane structure, and thus keeping skin healthy ?

Answer»

Primary role of vitamin-E is to serve as an antioxidant as it prevents oxidation of certain materials (i.e., it inhibits peroxide formation and thereby prevents damage of membrane lipids and thus maintains normal membrane structure). Thus vitamin E keeps skin healthy.

3.

Marasmus is the deficiency disease.

Answer»

Marasmus is the deficiency disease Protein.

4.

What is stomatal periodicity? What are the categories of stomata?

Answer»

Stomatal periodicity is the rate of opening and closing of stomata during day and night. Stomata usually open during day and close during night. 

There are three categories of stomata : 

(i) Barley or cereal type : They are dumb-bell shaped. The stomata usually open during the day for a few hours. 

(ii) Leuceme or alfalfa type : They open during day and close during night under mesophytic conditions. In succulents, the stomata remain closed during the day. They open only during night. 

iii) Potato Type : Under mesophytic conditions, the stomata can remain open through day and night but close down for different periods and at various times under less water availability.

5.

Which tissues are together called as periderm?

Answer»

Phellogen, phellem and phelloderm constitute periderm.

6.

How are plants classified based on their life span? Give an example each?

Answer»

Based on the life-span, plants are classified into 

  • Annuals – plants which complete their life-cycle in one season eg: mustard, sunflower
  • Biennials- plants which complete their life-cycle in two seasons eg: radish, beetroot
  • Perennials – plants which live for a number of years and produce flowers and fruits at specific seasons every year eg: mango, termarind. 
7.

Explain how growth rings are formed in trees?

Answer»

1. Growth rings are formed due cambial activity during favourable and non-favourable climatic conditions. 

2. During favourable conditions, spring wood (early wood) is formed which has broader xylem bands, lighter colour, tracheids with thin wall and wide lumen, fibres are less in number, low density. Whereas, during unfavourable conditions, autumn wood (late wood) is formed which has narrow xylem band, darker in colour, lumen is narrow and walls are thick with abundant fibres, high density. 

3. Spring wood and autumn wood that appear as alternate light and dark concentric rings, constitute an annual ring or growth ring.

8.

Explain how formation of cambial ring occurs in dicot stem.

Answer»

1. The cambium present between the primary xylem and primary phloem of a vascular bundle is called intrafascicular cambium.

2. With the onset of favourable season, meristematic cells of intrafascicular cambium become active. 

3. Simultaneously, the ray parenchyma cells, both fusiform initials and ray initials become meristematic. This is known as dedifferentiation. 

4. These form patch of cambial cells (meristematic cells) in between the adjacent bundles and produce interfascicular cambium. 

5. Both intrafascicular and interfascicular cambium join and form a complete ring, known as the cambial ring. This is possible because they lie in one plane.

9.

Explain how angiosperms are classified into different types based on habitat.

Answer»

Angiosperms can be classified into following types based on habitat: 

1. Hydrophytes – Growing in aquatic habitat e.g. Hydrilla 

2. Xerophytes – Growing in regions with scanty or no rainfall like desert e.g. Opimtia 

3. Psammophytes – Growing in sandy soil e.g. Elymus 

4. Lithophytes – Growing on rock e.g. Couchidium, Cladopus, Dalzellia, Paphiopedilum orchids, rock felt fem. 

5. Halophytes – Growing in saline soil e.g. Mangrove plants like Rhizophora

10.

Grass leaves curl inwards during very dry weather. Select the most appropriate reason from the following: (A) Shrinkage of air spaces in spongy mesophyll (B) Tyloses in vessels (C) Closure of stomata (D) Flaccidity of bulliform cells

Answer»

(D) Flaccidity of bulliform cells

Grass leaves curl inwards to the minimize water loss.

11.

Which of the statements given below is NOT true about formation of ‘annual rings’ in trees? (A) Activity of cambium depends upon variation in climate. (B) Annual rings are not prominent in trees of temperate region. (C) Annual ring is a combination of spring wood and autumn wood produced in a year. (D) Differential activity of cambium causes light and dark bands of tissue – early and late wood respectively.

Answer»

(B) Annual rings are not prominent in trees of temperate region.

Annual rings are formed due to activity of cambium. The activity of cambium is under the control of many physiological and environmental factors. In temperate regions, the climatic conditions are not uniform throughout the year due to this, annual rings are formed.

12.

Hypodermis is collenchymatous in (A) monocot stem (B) dicot stem(C) monocot root (D) both (A) and (B)

Answer»

The correct answer is (B) dicot stem

13.

Which of the following is made up of dead cell?(A) Xylem parenchyma (B) Collenchyma (C) Phellem (D) Phloem

Answer»

(C) Phellem

Cork cambium (phellogen) cuts off cells on both the sides. The outer cells differentiate into cork or phellem. The cork is impervious to water due to suberin deposition in the cell wall.

14.

Distinguish between the following: Ectotherms and Endotherms

Answer»
EctothermsEndotherms
1. Ectotherms do not have ability to generate heat in the body.1. Endotherms possess the ability to generate their own body heat.
2. Ectotherms depend on the environmental sources to heat their bodies. E.g sunlight.2. Endotherms do not depend upon outside sources to generate heat.
3. Most ectotherms are confined to warmer parts of the world.3. Endotherms inhabit coldest parts of the earth.
4. Body temperature of ectotherms fluctuate according to ambient temperature.4. Body temperatures of endotherms remain constant and do not show fluctuations as per ambient temperatures.
5. Metabolic rate of ectotherms is low.
E.g. Amphibians and reptiles.
5. Metabolic rate of endotherms is high.
E.g. Mammals and birds
15.

Name the type of association: a. Clown fish and sea anemone b. Crow feeding the hatchling of Koel c. Humming birds and host flowering plants

Answer»

a. Commensalism 

b. Brood parasitism 

c. Mutualism

16.

Regeneration of damaged growing grass following grazing is largely due to: (A) secondary meristem (B) lateral meristem (C) apical meristem (D) intercalary meristem

Answer»

(D) intercalary meristem

Intercalary meristems occur in grasses at the base of intemode, which regenerates the grass damaged due to grazing.

17.

Casparian strips occur in (A) Cortex (B) Pericycle (C) Epidermis (D) Endodermis

Answer»

The correct answer is (D) Endodermis

18.

Identify the wrong statement in context of heartwood. (A) Organic compounds are deposited in it (B) It is highly durable (C) It conducts water and minerals efficiently (D) It comprises dead elements with highly lignified walls

Answer»

(C) It conducts water and minerals efficiently

19.

What is the ecological process behind the biological control method of managing with pest insects?

Answer»

1. Pest insects act as prey to predator birds or frogs. 

2. The biological control method consists of releasing the predators in the farms so that they can control the pest population in the natural way. 

3. This also eliminates the use of chemical pesticides. 

4. Frogs are natural predators of locust, therefore the population of this hazardous insect is controlled by frogs and the produce from agricultural farm can be saved.

Protocooperation:

1. Protocooperation is a type of population interaction where two species interact with each other.

2. Both are benefited but they have no need to interact with each other. 

3. They can survive and grow even in the absence of other species. 

4. Therefore this interaction is purely for the gain that they receive in such type of interaction. 

5. The interaction that occurs can be between different kingdoms.

20.

In the dicot root, the vascular cambium originates from: (A) intrafascicular and interfascicular tissue in a ring (B) tissue located below the phloem bundles and a portion of pericycle tissue above protoxylem (C) cortical region (D) parenchyma between endodermis and pericycle

Answer»

(B) tissue located below the phloem bundles and a portion of pericycle tissue above protoxylem

21.

The vascular cambium normally gives rise to (A) Phelloderm(B) Primary phloem (C) Secondary xylem(D) Periderm

Answer»

(C) Secondary xylem

22.

How is the dormancy of seeds different from hibernation in animals?

Answer»

In dormancy seed is not showing any metabolic activities. It can come back to life if and only if it gets suitable moisture and sunlight. Hibernation is suspended state, in which metabolic reactions do take place but at a very reduced pace. Animal arouses on its own after the winter sleep is over. This arousal is spontaneous and depends upon the ambient temperature. Dormant seed does not show such change unless it is planted or thrown in to moist place.

23.

Define intrafascicular cambium.

Answer»

The cambium present between the primary xylem and primary phloem of a vascular bundle is called intrafascicular cambium.

24.

Name the following :One example of each epistomatic, hypostomatic and amphistomatic leaf.

Answer»

1. Epistomatic leaf – Lotus

2. Hypostomatic – Nerium. 

3. Amphistomatic – Grass

25.

Name two curable sexually transmitted diseases.

Answer»

Gonorrhoea and syphilis.

26.

Which organ can trap the microbes in the body fluid?

Answer»

The microbes in the body fluid is Lymph.

27.

Expand LSD. Name its source organism. What category of drug is it?

Answer»

LSD—Lysergic acid diethyl amide obtained from Ergot fungus. It is a hallucinogen and causes temporary well being.

28.

Name two STDs which can be transmitted through contaminated blood.

Answer»

Hepatitis-B and AIDS are the two STDs which can be transmitted through contaminated blood.

29.

What is incubation period? How long it is for AIDS virus?

Answer»

The time period between infection and appearance of symptoms is called incubation period. Incubation period in AIDS may vary from a few months to many year

30.

Name the type of cells the AIDS virus enters into after getting in the human body.

Answer»

Monocytes and helper T-lymphocytes.

31.

Name and explain giving reasons, the type of immunity provided to the newborn by the colostrum and vaccinations.

Answer»

Colostrum provides passive immunity, because the infant gets antibodies from the mother’s body directly for protection. 

Vaccinations provide active immunity because in this case microbes are injected into the body do develop immunity slowly.

32.

Seema saw that her grandfather was preparing stem cutting of rose. Seema asked to her grandmother, about the reason of this laborious task while new rose plants could be easily procured from the nurseries.(a) In what way this technique is useful?(b) What is the reason of using stern cutting for propagation?(c) Name two other plants where stem cuttings are used to propagate.(d) what values are exhibited by seema.

Answer»

(a) The plants with desired characteristics can be vegetatively propagated by this technique.

(b) Some plant can be vegetatively propagated by using stem cuttings. Stem cuttings when sown in the soii gives rise to roots and shoots and soon grow into a new plants which are exactly identical to the parent Plants.

(c) Sugarcane and banana are the other plants which are propagated by stem cutting.

(d) Seema exhibits the value of awareness and keen observations.

33.

Geeta's mother was preparing idli. She was watching her curiously. She found that her mother mixed a little amount of Yeast to the batter and kept it as such for some time. When they saw the batter again they found that it had risen in the bowl. Ceeta got mother surprised to see it and asked her mother about it.(a) Why only a little amount of yeast was added into the batter?(b) How yeast multiplies?(c) What is the process taking place in batter calledas.(d) What values are exhibited by Geeta and her mother?

Answer»

(a) Yeast multiplied very fast. Therefore,only a small amount was added for getting the desired effect in the batter.

(b)  Yeast multiplies asexually by the process called 'Budding'.

(c) The process that take place on in the batter is called fermentation.

(d) Geeta and her mother exhibit scientific aptitude and temperament,awareness and the power of keen observation.

34.

Complete the illustration given below. Vacuole, Mitochondrion, Endoplasmic Reticulum, Golgi complex

Answer»

Vacuole – Stores water, salts, and waste materials.

Mitochondrion – Power house of the cell, helps in the production and storage of energy.

Endoplasmic Reticulum – Pathway inside the cell. Provide rigidity and shape to cells.

Golgi Complex – Encloses enzymes, hormones & mucus in small vesicles.

35.

Give the binomials of two types of yeast and the commercial bioactive products they help to produce.

Answer»
YeastTheir bioactive products
Saccharomyces cerevisiaeEthanol/alcohol
Monascus purpureusStatin
36.

The primary treatment of waste water involves the removal of:a. dissolved impuritiesb. stable particlesc. toxic substancesd. harmful bacteria.

Answer» b. stable particles
37.

Match the following list of bioactive substances and their roles:Bioactive SubstanceRole(i) Statin(a) Removal of oil stains(ii) Cyclosporin A(b) Removal of clots from blood vessels(iii) Streptokinase(c) Lowering of blood cholesterol(iv) Lipase(d) Immuno-suppressive agentChoose the correct match:a. i b, ii c, iii a, iv db. i d, ii b, iii a, iv cc. i d, ii a, iii d, iv cd. i c, ii d, iii b, iv a

Answer» The correct answer is d. i c, ii d, iii b, iv a
38.

Bacteria cannot be seen with the naked eyes, but these can be seen with the help of a microscope. If you have to carry a sample from your home to your biology laboratory to demonstrate the presence of microbes under a microscope, which sample would you carry and why?

Answer»

Curd – Contains Lactic Acid Bacteria Lactobacillus acidophilus.

39.

In the case of the ‘Swiss cheese’ with large hole is due to the production of(a) CO(b) CO2(c) CH4(d) C2H5OH

Answer»

Answer is (b) CO2

40.

Bacteria cannot be seen with the naked eyes but can be seen with the help of a microscope. If you have to carry a sample from your home to your biology laboratory to demonstrate the presence of microbes under a microscope, which sample would you carry and why?

Answer»

Bacteria can be grown and multiplied on nutritive culture media in aseptic conditions to form colonies which can be transported from the home to biology laboratory where these can be demonstrated under a microscope. In homes easily available source of microbial culture is curd. It is with Lactic acid bacteria.

41.

Microbes are widely applied as bio control agents in biological farming approach.1. What is Bio control?2. What is the advantage of this over conventional chemical methods?3. Give two examples for bio control.

Answer»

1. Bio control refers to the use of biological methods for controlling plant diseases and pests.

2. Chemicals like insecticides and pesticides are toxic and extremely harmful to human beings and animals. They also pollute the environment. Use of bio control measures reduce the dependence on toxic chemicals.

3.

  • Bacillus thuringiensis (Bt)
  • Trichoderma
42.

If you went to silk showroom to know the quality of silk, what type of exact question do you ask? A) How do you decide the cost? B) Do they have good durability? C) How silk is prepared with? D) How many types of silks are there?

Answer»

The correct answer is B) Do they have good durability?

43.

The lactic acid bacteria is involved in(a) conversion of milk into curd(b) conversion of curd into ghee(c) lactic acid fermentation(d) both a and c

Answer»

(d) both a and c

44.

Patients who have undergone myocardial infarction are given clot buster. Mention the clot buster administered and its microbial source.

Answer»

Streptokinase is the clot buster and its microbial source is Streptococcus.

45.

Which bacterium has been used as a clot buster? What is its mode of action?

Answer»

Streptokinase produced by the bacterium Streptococcus and modified by genetic engineering is used as a ‘clot buster’ for removing clots from the blood vessels of patients who have undergone myocardial infarction leading to heart attack.

46.

Bio gas is pathogen free because(a) anaerobic digestion removes pathogens and bacteria(b) it is toxic to pathogens(c) during decomposition, it produces antibiotics(d) cattle dung is pathogen-free

Answer»

(c) during decomposition, it produces antibiotics

47.

During an aerobic digestion of organic waste, such as in producing bio gas, which one of the following is left undegraded?(a) Hemicellulose (b) Cellulose (c) Lipids (d) Lignin

Answer»

Answer is (d) Lignin

48.

In which food would you find lactic acid bacteria? Mention some of their useful applications.

Answer»

In curd Other Applications are,

1. Increases nutritional quality

2. Checking disease causing microbes

49.

A person has suffered a heart attack due to a floating clot in his coronary artery.1. Name the bacterium that can save him.2. Mention its product and its action.

Answer»

1. Strep to cocus

2. Strep to kinase. It is a clot-buster

50.

Match the following.MicrobeUsea. Penicillium notatumBio gasb. Methano bacteriumPenicillinc. Monascus purpureusBiofertilizerd. NostocCholesterol loweringe. Bacillus thuringiensisImmune suppressive agentf. Trichoderma polysporumBiological control

Answer»
MicrobeUse
a. Penicillium notatumPenicillin
b. Methano bacteriumBio gas
c. Monascus purpureusCholesterol lowering
d. NostocBio fertilizer
e. Bacillus thuringiensisBiological control
f. Trichoderma polysporumImmune suppressive agent