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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

51.

K in K = Cα^2/1 – ɑ represents ___________(a) dissociation constant(b) molar concentration(c) degree of dissociation degree of ionization(d) degree of ionizationThe question was posed to me in an online interview.My query is from Ionic Equilibrium in Solution topic in section Equilibrium of Chemistry – Class 11

Answer» RIGHT choice is (a) DISSOCIATION constant

For explanation: The above equation represents OSTWALD’s dilution law, where K is the dissociation constant, C is the molar concentration of the solution and ɑ is a degree of dissociation or degree of ionization of the solution.
52.

Which of the following is in Ionic Equilibrium?(a) 2AgI + Na2S \(\rightleftharpoons\)Ag2S + 2NaI(b) 4 NH3 + 5 O2 \(\rightleftharpoons\)4 NO + 6 H2O(c) TiCl4 + 2 H2O \(\rightleftharpoons\)TiO2 + 4 HCl(d) H2O + H2O \(\rightleftharpoons\)H3O^+ + OH^–The question was posed to me in an online quiz.My doubt stems from Ionic Equilibrium in Solution in division Equilibrium of Chemistry – Class 11

Answer»

Right answer is (d) H2O + H2O \(\rightleftharpoons\)H3O^+ + OH^–

For EXPLANATION I would say: Only H2O + H2O \(\rightleftharpoons\)H3O^+ + OH^– is in ionic EQUILIBRIUM. As the equilibrium established between the UNIONIZED molecules and the IONS in the solution of WEAK electrolytes is known as Ionic Equilibrium.

53.

Degree of dissociation does not depend on which of the following factors?(a) nature of the solute(b) nature of the solvent(c) sound(d) concentrationThe question was asked in semester exam.This question is from Ionic Equilibrium in Solution topic in portion Equilibrium of Chemistry – Class 11

Answer»

The correct answer is (c) sound

Explanation: Values of the degree of dissociation or degree of ionization DEPENDS upon the following factors: 1) the nature of the solute, 2) the nature of the solvent 3) CONCENTRATION and 4) temperature of the solution.

54.

What is the degree of dissociation for strong electrolytes?(a) 1(b) 0(c) less than 1(d) greater than 1This question was addressed to me in an interview for job.This interesting question is from Ionic Equilibrium in Solution topic in portion Equilibrium of Chemistry – Class 11

Answer»

Right CHOICE is (a) 1

To explain: Degree of dissociation is the FRACTION of the TOTAL number of molecules which dissociate into constituent ions, it is represented by the symbol ɑ. As a strong electrolyte dissociate completely, it VALUES is 1.

55.

Sugar solution __________ electricity.(a) do not conduct(b) conducts(c) depends on the type of sugar(d) cannot sayI have been asked this question by my school teacher while I was bunking the class.The question is from Ionic Equilibrium in Solution topic in chapter Equilibrium of Chemistry – Class 11

Answer»

The correct choice is (a) do not conduct

Best EXPLANATION: Aqueous solution of SUGAR does not conduct electricity, but Aqueous solution of sugar CONDUCTS electricity. This is because the aqueous solution of sugar is a NONELECTROLYTE, whereas the salt solution is an electrolyte.

56.

All organic acids except sulfonic acid are _____________ electrolytes.(a) weak(b) strong(c) not(d) neither strong nor weakThis question was addressed to me during an internship interview.I want to ask this question from Ionic Equilibrium in Solution in chapter Equilibrium of Chemistry – Class 11

Answer»

Right option is (a) weak

The best I can explain: Electrolytes which dissociate into a lesser extent in aqua SOLUTION are called weak electrolytes. All organic acids except sulfonic acids and BASES like Ammonia, Ammonium hydroxide, AMINES,etc are weak electrolytes.

57.

Which of the following may not be a strong electrolyte?(a) hydrochloric acid(b) sulfuric acid(c) nitric acid(d) ammoniaThis question was addressed to me by my college director while I was bunking the class.I'd like to ask this question from Ionic Equilibrium in Solution in chapter Equilibrium of Chemistry – Class 11

Answer»

Right answer is (d) ammonia

The EXPLANATION: Electrolytes which dissociate ALMOST COMPLETELY into constituent ions in aqueous SOLUTIONS are known as strong electrolytes. THEREFORE ammonia is not a strong electrolyte because it can’t dissociate completely.

58.

The equilibrium position does not change when there is an addition of inert gas at constant volume.(a) true(b) falseI have been asked this question in quiz.This intriguing question originated from Factors Affecting Equilibria in portion Equilibrium of Chemistry – Class 11

Answer»

Correct OPTION is (a) true

The best explanation: If keeping the volume of the SYSTEM constant and INERT GASES ADDED the relative molar concentration of the substance will not change hence the equilibrium position of the reaction remains unaffected.

59.

Electrolytes conduct electricity.(a) True(b) FalseThe question was asked in an online interview.Question is taken from Ionic Equilibrium in Solution topic in portion Equilibrium of Chemistry – Class 11

Answer» CORRECT choice is (a) True

Explanation: Chemical substances which can conduct ELECTRICITY in their Aqua state or in the molten state are called electrolytes. The conduction of current through the electrolyte is DUE to the MOVEMENT of Ions, hence the above statement is true.
60.

CH3COOH \(\rightleftharpoons\) CH3COO^– + H^+ is in __________________(a) ionic equilibrium(b) chemical equilibrium(c) dynamic equilibrium(d) physical equilibriumThe question was posed to me in unit test.My question is based upon Ionic Equilibrium in Solution topic in chapter Equilibrium of Chemistry – Class 11

Answer»

The correct CHOICE is (a) IONIC EQUILIBRIUM

The best explanation: The equilibrium that is attained between the ionized molecules and the ions in the solution of weak electrolyte is called Ionic Equilibrium. CH3COOH \(\rightleftharpoons\) CH3COO^– + H^+ is an example; CH3COO^– and H^+ are ions.

61.

What will happen to the position of equilibrium if the concentration of one of the products is increased?(a) shifts left(b) shift right(c) does not change(d) main shift left or rightThis question was posed to me at a job interview.This intriguing question comes from Factors Affecting Equilibria in division Equilibrium of Chemistry – Class 11

Answer»

Correct CHOICE is (a) shifts left

Easiest explanation: According to Le chatelier’s PRINCIPLE if at EQUILIBRIUM the concentration of one of the products is INCREASED the equilibrium will shift in the backward direction that is towards the left side and vice versa.

62.

The formation of products is favoured by ____________ temperature in an endothermic reaction.(a) high(b) low(c) moderate(d) 0This question was posed to me in a national level competition.Enquiry is from Factors Affecting Equilibria topic in portion Equilibrium of Chemistry – Class 11

Answer»

Correct ANSWER is (a) HIGH

The EXPLANATION: When the process is exothermic, low temperature of FAVORS Forward reaction and when the process is ENDOTHERMIC high temperature favors the formation of the products. This is according to le chatelier’s principle.

63.

Which side does the catalyst shift the equilibrium position?(a) left side(b) right side(c) may be left or right side(d) does change the positionThe question was posed to me in an online interview.I need to ask this question from Factors Affecting Equilibria in division Equilibrium of Chemistry – Class 11

Answer»

The correct option is (d) does CHANGE the position

Explanation: As per Le chatelier’s principle on the EFFECT of catalyst states that the PRESENCE of the catalyst does not change the position of the EQUILIBRIUM it simply fast and the ATTAINMENT of the equilibrium.

64.

At constant pressure, if the inert gases added then the equilibrium will shift in the direction of ___________(a) decrease in the number of moles(b) increase in the number of moles(c) does not depend on the number of moles(d) does not changeI had been asked this question in an online quiz.My query is from Factors Affecting Equilibria topic in portion Equilibrium of Chemistry – Class 11

Answer»

The correct option is (b) increase in the number of moles

The BEST I can explain: At constant pressure, if INERT gas added, it will increase the volume of the system there for the equilibrium will shift in a direction, in which there is an increase in the number of moles of GASES as PER le chatelier’s principle.

65.

If a reaction produces heat during the process then it is ____________(a) exothermic(b) endothermic(c) both exothermic and endothermic(d) neither exothermic nor endothermicI got this question in class test.My question comes from Factors Affecting Equilibria topic in chapter Equilibrium of Chemistry – Class 11

Answer»

The correct option is (a) EXOTHERMIC

Easy explanation: If a reaction releases heat then it is exothermic in NATURE and if the reaction CONSUMES heat it is endothermic in nature. An example of the exothermic reaction is the mixing of WASHING SODA in water and mixing glucose in water is an example of an endothermic reaction.

66.

Consider the chemical equation TiCl4 + 2 H2O \(\rightleftharpoons\) TiO2 + 4 HCl if the pressure is increased what will happen to the equilibrium?(a) it moves backward direction(b) moves forward direction(c) remains constant(d) cannot sayThe question was posed to me during an online interview.Question is taken from Factors Affecting Equilibria topic in section Equilibrium of Chemistry – Class 11

Answer»

The correct CHOICE is (a) it moves backward direction

To explain I WOULD say: When there is a change in a number of moles, the equilibrium will shift in the direction having a SMALLER number of moles when the pressure is INCREASED and vice-versa. Here the equilibrium moves in the backward direction because the reactants have less number of moles than products.

67.

Is a relationship between reaction quotient and Gibbs free energy at a temperature T?(a) ΔG = ΔG0 + RT lnQ(b) ΔG = ΔG0 + RT lnk(c) ΔG = ΔG0 + R lnQ(d) ΔD = ΔG0 + RT lnQI got this question in a job interview.My question comes from Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G in division Equilibrium of Chemistry – Class 11

Answer» CORRECT choice is (a) ΔG = ΔG0 + RT lnQ

Explanation: The relationship between reaction quotient and Gibbs free energy at temperature t is given as as ΔG = ΔG0 + RT lnQ, where ΔG is the Gibbs free energy, R is the universal gas CONSTANT, T is the temperature and Q is the reaction quotient.
68.

In the reaction, H2(g) + Br2(g) \(\rightleftharpoons\) 2HBr(g), what will happen if there is a change in pressure?(a) equilibrium moves left(b) equilibrium moves right(c) there is no change in equilibrium(d) we cannot sayThe question was asked in an interview.The origin of the question is Factors Affecting Equilibria in division Equilibrium of Chemistry – Class 11

Answer»

Correct option is (c) there is no change in equilibrium

To explain I would SAY: According to LE chatelier’s principle, there will be no effect of PRESSURE on equilibrium if the chemical equation has the same number of moles of reactants and products hear the moles on the left side is equal to the moles on the right side that is 2.

69.

What will happen if at equilibrium the concentration of one of the reactants is increased?(a) equilibrium will shift in the forward direction(b) equilibrium population will not change(c) equilibrium will shift in the backward direction(d) equilibrium will move to and froI have been asked this question in an interview for internship.My doubt stems from Factors Affecting Equilibria topic in division Equilibrium of Chemistry – Class 11

Answer»

The correct ANSWER is (a) equilibrium will shift in the FORWARD direction

To explain: As per the Le chatelier’s principle, if the concentration of ONE of the reactants is increased at equilibrium the equilibrium will shift in the forward direction and vice versa is also possible. Therefore we can say that there is an EFFECT of change of concentration on equilibrium.

70.

Which of the following factors do you think will not affect the state of the equilibrium?(a) concentration(b) pressure(c) temperature(d) colorThis question was addressed to me in an online quiz.My doubt stems from Factors Affecting Equilibria topic in chapter Equilibrium of Chemistry – Class 11

Answer»

Right answer is (d) color

The explanation is: According to Le chatelier’s principle, if a SYSTEM at equilibrium is SUBJECTED to a change in CONCENTRATION, pressure or temperature the equilibrium SHIFTS in the direction that tends to NULLIFY the effect of the change.

71.

What happens when reaction quotient is equal to the equilibrium constant?(a) the reaction proceeds in the forward direction(b) the reaction proceeds in the backward direction(c) the reaction reaches equilibrium(d) cannot predictI got this question in exam.This question is from Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G in division Equilibrium of Chemistry – Class 11

Answer»

Correct ANSWER is (c) the reaction REACHES EQUILIBRIUM

Explanation: When Gibbs free ENERGY is zero, the reaction reaches equilibrium and at equilibrium, the reaction quotient is replaced by the equilibrium constant, as both the values are equal. That is when reaction quotient is equal to the equilibrium constant reaction reaches equilibrium.

72.

For a reaction, Kc = 3.81 × 10^–3 and ΔG0 = 13.8 kJ/mol. Then what is the value of R?(a) -8.314J mol^–1K^–1(b) 8.314J mol^–1K^–1(c) cannot say as the temperature is not given(d) -8.314J mol^–1I had been asked this question in a national level competition.The question is from Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G topic in division Equilibrium of Chemistry – Class 11

Answer»

Correct choice is (b) 8.314J mol^–1K^–1

Easiest EXPLANATION: THOUGH the TEMPERATURE is not given, UNIVERSAL gas CONSTANT value always remains the same, whatever may be the other values. So the universal gas constant is given by a constant value that is -8.314J mol^–1K^–1.

73.

If the value of Gibbs free energy for a reaction is 20J/mol, the reaction is ___________(a) spontaneous(b) nonspontaneous(c) may be spontaneous(d) may not be spontaneousI had been asked this question in a job interview.My enquiry is from Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G topic in section Equilibrium of Chemistry – Class 11

Answer»

The correct CHOICE is (b) nonspontaneous

For explanation: Is the value of Gibbs free energy for a REACTION is 20 J/mol, that MEANS it is positive,-ΔG0/RT is NEGATIVE and that e^-ΔG0/RT is greater than 1, so the K is greater than 1 this means the reaction is nonspontaneous.

74.

In a reaction, if the value of Gibbs free energy is greater than zero what does it infer?(a) K is greater than 1(b) K is less than 1(c) K is equal to 1(d) Cannot deduce K from Gibbs free energyThe question was asked in a job interview.This key question is from Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G topic in division Equilibrium of Chemistry – Class 11

Answer»

The correct option is (B) K is less than 1

Easiest explanation: If the VALUE of Gibbs free ENERGY is GREATER than the zero that means, -ΔG0/RT is negative and that e^-ΔG0/RT is greater than 1, so the K is greater than 1 this means the reaction is nonspontaneous and proceeds in the forward direction.

75.

What did the Q depicted in the equation; ΔG = ΔG0 + RT lnQ?(a) reaction coefficient(b) reaction quotient(c) equilibrium constant(d) free energyI got this question by my school teacher while I was bunking the class.I would like to ask this question from Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G in chapter Equilibrium of Chemistry – Class 11

Answer»

Right CHOICE is (b) REACTION quotient

The BEST explanation: In the EQUATION ΔG = ΔG0 + RT lnQ, ΔG is the Gibbs free energy, R is the universal gas constant, T is the temperature and Q is the reaction quotient. When Gibbs free energy is zero, the reaction quotient becomes EQUILIBRIUM constant.

76.

When is a reaction nonspontaneous?(a) Gibbs free energy is positive(b) Gibbs free energy is negative(c) Gibbs free energy is zero(d) Does not depend on Gibbs free energyI got this question in a national level competition.Question is taken from Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G in chapter Equilibrium of Chemistry – Class 11

Answer»

The CORRECT answer is (a) Gibbs FREE energy is POSITIVE

Explanation: When Gibbs free energy is positive, the reaction that occurs is nonspontaneous and a reaction occurs BACKWARD that is the products are converted into reactants. SIMPLY the reverse reaction could occur.

77.

If the value of ΔG0 is -2502 J/mol and K is 2, what is the temperature of the reaction that is occurring?(a) 200 k(b) 101 k(c) 100 k(d) 300 kThe question was posed to me in class test.The origin of the question is Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G in portion Equilibrium of Chemistry – Class 11

Answer»

The correct option is (c) 100 k

The BEST I can EXPLAIN: We know that ΔG0 = – RT LNKC, where ΔG0 is the standard Gibbs free energy, R is universal GAS constant, T is the temperature and KC is equilibrium constant; substituting ΔG0 as -2502 J/mol, we get -2502 J/mol = -8.314J mol^–1K^–1 × T ln2 = 2502 J/mol = T = 2502/2.502 = 100 k.

78.

For a chemical reaction, the value of ΔG0 is -831.4 J/mol. Then what is the value of KC at 100 k?(a) 1.0077(b) 1.077(c) 1.007(d) 2.7I have been asked this question in unit test.I would like to ask this question from Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G topic in section Equilibrium of Chemistry – Class 11

Answer»

Right answer is (d) 2.7

The explanation is: We know that ΔG0 = – RT lnKc, where ΔG0 is the STANDARD Gibbs free energy, R is UNIVERSAL gas constant, T is the temperature and KC is EQUILIBRIUM constant; substituting ΔG0 as-831.4 J/mol, we get LNK = -831.4J/mol divided by -8.314J mol^–1K^–1 × 100K = 1; lnk = 1; K = e^1 = 2.7

79.

In a reaction, at 300k, KC is given as 2 x 10^13, then what is the value of ΔG?(a) – 7.64 × 10^4 J(b) – 7.64 × 10^4 J mol^–1(c) – 7.64 × 10 J mol^–1(d) – 7.64 × 10^4 mol^–1This question was addressed to me in semester exam.I'm obligated to ask this question of Relationship between Equilibrium Constant K, Reaction Quotient Q and Gibbs Energy G in portion Equilibrium of Chemistry – Class 11

Answer»

The correct choice is (b) – 7.64 × 10^4 J mol^–1

For explanation I WOULD say: We know that ΔG0 = – RT lnKc, where ΔG0 is the standard Gibbs free energy, R is universal gas CONSTANT, T is the temperature and KC is equilibrium constant; substituting KC as 2 x 10^13, ΔG0 = (– 8.314J mol^–1K^–1 × 300K) × ln(2×10^13); ΔG0 = – 7.64 × 10^4 J mol^–1.

80.

Equilibrium constant depends on the temperature.(a) true(b) falseThis question was addressed to me in an interview for job.This question is from Applications of Equilibrium Constants topic in chapter Equilibrium of Chemistry – Class 11

Answer» CORRECT CHOICE is (a) true

Explanation: Yes, the equilibrium constant depends on the temperature and its unique for a chemical REACTION at a GIVEN temperature. So the above-given statement about the equilibrium constant is considered to be true.
81.

What do you understand from the reaction if reaction quotient is 2 and the equilibrium constant is 3?(a) the equilibrium constant increases(b) the equilibrium constant decreases(c) the equilibrium constant remains the same(d) reaction quotient increasesI have been asked this question in an interview for internship.I need to ask this question from Applications of Equilibrium Constants topic in section Equilibrium of Chemistry – Class 11

Answer»

The correct choice is (d) reaction quotient increases

To explain I would say: In a reaction, if reaction quotient is less than the equilibrium CONSTANT, the reaction quotient will tend to increase and the reaction will proceed in the FORWARD direction TILL it reaches equilibrium.

82.

If [H2]t=0.10 M, [I2]t = 0.20 M and [HI]t = 0.40 M, in the reaction H2(g) + I2(g) \(\rightleftharpoons\) 2HI(g), what is the value of QC?(a) 8(b) 4(c) 2(d) 1The question was posed to me in my homework.This intriguing question originated from Applications of Equilibrium Constants topic in division Equilibrium of Chemistry – Class 11

Answer» CORRECT ANSWER is (a) 8

The best explanation: We know that reaction quotient Qc = [HI]t^2 / [H2]t[I2]t and given that [H2]t=0.10 M, [I2]t = 0.20 M and [HI]t = 0.40 M, So by substituting, we GET Qc = (0.40 M x 0.40 M)/(0.20 M x 0.10 M) = 8.0, 8 is the answer.
83.

What do you think will happen if reaction quotient is smaller than the equilibrium constant?(a) equilibrium constant will change(b) reaction quotient remains constant(c) reaction quotient increases continuously(d) reaction quotient increases till KCI have been asked this question in a national level competition.I would like to ask this question from Applications of Equilibrium Constants topic in portion Equilibrium of Chemistry – Class 11

Answer» RIGHT option is (d) reaction quotient increases till KC

For explanation: If the reaction quotient is less than the equilibrium constant KC, the reaction quotient will tend to INCREASE and the reaction will proceed in the forward direction, till it REACHES the value of the equilibrium constant.
84.

At equilibrium, KC is _______________(a) greater than reaction quotient(b) equal to the reaction quotient(c) less than the reaction question(d) independent of reaction questionI got this question during a job interview.I'm obligated to ask this question of Applications of Equilibrium Constants in portion Equilibrium of Chemistry – Class 11

Answer» RIGHT answer is (b) equal to the reaction QUOTIENT

Explanation: At EQUILIBRIUM, the equilibrium constant and the reaction quotient is equal. The equilibrium constant is depicted by the SYMBOL KC and the reaction quotient is represented by the symbol QC.
85.

What will happen If QC > KC?(a) QC decreases till equilibrium(b) QC increases till equilibrium(c) QC remains constant(d) cannot sayI got this question during an online exam.Question is from Applications of Equilibrium Constants in chapter Equilibrium of Chemistry – Class 11

Answer»

The correct answer is (a) QC DECREASES till equilibrium

The explanation is: If QC > KC, the value of QC will tend to decrease to REACH the value of equilibrium constant (that is towards equilibrium) and the REACTION will continue in the opposite DIRECTION, where QC is reaction quotient and KC is the equilibrium constant.

86.

For a reaction aA + bB → cC + dD, which is not in equilibrium the QC is given as __________(a) [A]^a[B]^b/[C]^c[D]^d(b) [C]^c[D]^d/[A]^a[B]^b(c) [A][B]/[C][D](d) [C][D]/[A][B]The question was asked in unit test.My doubt is from Applications of Equilibrium Constants topic in division Equilibrium of Chemistry – Class 11

Answer» RIGHT choice is (b) [C]^c[D]^d/[A]^a[B]^b

To EXPLAIN I WOULD say: A very basic reaction like AA + bB → cC + dD, where the capital letters represent the compounds or molecules and the small letters are the coefficients of them the reaction QUOTIENT QC, is given by [C]^c[D]^d/[A]^a[B]^b.
87.

Reaction quotient is depicted by this symbol __________(a) K(b) QC(c) R(d) qI had been asked this question in an interview for job.I want to ask this question from Applications of Equilibrium Constants topic in chapter Equilibrium of Chemistry – Class 11

Answer»

Right ANSWER is (b) QC

Easy EXPLANATION: For any reversible REACTION at any stage other than EQUILIBRIUM, the ratio of the molar concentrations of the products to that of the reactants, where is concentration TERM is raised to the power equal to the stoichiometric efficient to the substance concerned is called the reaction quotient, QC.

88.

What will happen if KC > 10^-3 in a chemical reaction?(a) products are predominant(b) reactants are predominant(c) equilibrium(d) dynamic equilibriumI got this question during an interview for a job.I'm obligated to ask this question of Applications of Equilibrium Constants topic in portion Equilibrium of Chemistry – Class 11

Answer»

Correct OPTION is (d) dynamic equilibrium

For explanation I would say: If KC > 10^-3, the reactants are predominant over the PRODUCTS in a CHEMICAL reaction and the products are predominant, over the reactants in a chemical reaction, ifKC > 10^3, where KC is the equilibrium constant.

89.

If KC > 10x, the products predominate over reactants. Then what is the value of x?(a) 2(b) 3(c) 4(d) 1I have been asked this question in an online interview.This interesting question is from Applications of Equilibrium Constants topic in division Equilibrium of Chemistry – Class 11

Answer»

Right choice is (b) 3

To EXPLAIN I would say: If KC > 10x, the products are PREDOMINANT, over the reactants in a chemical reaction because if KC is very large the reaction proceeds nearly to completion an example for this is at 300K,H2(g) + Cl2(g) \(\rightleftharpoons\) 2HCL(g), KC = 4 X 10^31.

90.

WHat is the expression of KC of the chemical equation Ag2O(s) + 2HNO3(aq) \(\rightleftharpoons\) 2AgNO3(aq) +H2O(l)?(a) [AgNO3(aq)]^2/[HNO3(aq)]^2(b) [AgNO3(aq)]/[HNO3(aq)]^2(c) [AgNO3(aq)]^2/[HNO3(aq)](d) [AgNO(aq)]^2/[HNO3(aq)]^2The question was posed to me in semester exam.The question is from Homogeneous Equilibria in section Equilibrium of Chemistry – Class 11

Answer»

Right choice is (a) [AgNO3(aq)]^2/[HNO3(aq)]^2

To explain: It is important that for the EXISTENCE of HETEROGENEOUS equilibrium pure solid or liquid must also be at equilibrium, but their concentrations do not APPEAR in the expression of the equilibrium CONSTANT. So here KC = [AgNO3(aq)]^2/[HNO3(aq)]^2.

91.

CO2(g) + C(s) \(\rightleftharpoons\) 2CO(g) is an example of _____________(a) homogeneous equilibrium(b) heterogeneous equilibrium(c) neither homogeneous nor heterogeneous(d) both homogeneous and heterogeneousI had been asked this question in an international level competition.Query is from Homogeneous Equilibria topic in division Equilibrium of Chemistry – Class 11

Answer»

Right choice is (b) heterogeneous EQUILIBRIUM

Easy explanation: In heterogeneous equilibrium, the reactants and PRODUCTS are present in two or more physical States or phases. Here carbon DIOXIDE is present in the GASEOUS state while carbon is present in the solid state, so it is an example of heterogeneous equilibrium.

92.

For the following equation, 2HBr(g) \(\rightleftharpoons\) H2(g) + Br2(g); are both KP and KC are equal?(a) yes(b) cannot say(c) no(d) depends on the temperatureThe question was asked by my school teacher while I was bunking the class.I would like to ask this question from Homogeneous Equilibria topic in division Equilibrium of Chemistry – Class 11

Answer» CORRECT option is (a) yes

For explanation: We have here KC = [H2][BR2]/[HBR]^2; KP = [pH2][pBr2]/[PHBR]^2, where pH2 = [H2]RT, pBr2 = [Br2]RT and [pHBr] = [HBr]RT. So in this case as Δng = 0, where Δng = moles of products – moles of reactants which are in gaseous state only, both KP and KC are equal.
93.

If KC of a reaction N2(g) + O2(g) \(\rightleftharpoons\) 2NO(g) is 2 x 10^-3, then what is the KP?(a) 4 x 10^-3(b) 1 x 10^-3(c) 3 x 10^-3(d) 2 x 10^-3I had been asked this question by my school principal while I was bunking the class.This interesting question is from Homogeneous Equilibria in section Equilibrium of Chemistry – Class 11

Answer»

The CORRECT choice is (d) 2 x 10^-3

For EXPLANATION: As we know that KC = KP(RT)^Δng, here Δng = moles of PRODUCTS – moles of reactants which are in gaseous state only = 2 – (1+1) = 0. So KC = KP(RT)^0, KC = KP(1) = KP; KC = KP, therefore KP is same as KC and KP is 2 x 10^-3.

94.

What is the relation between KP and KC?(a) KC = KP(b) KC = KP(RT)(c) KC = KP(RT)^Δng(d) KP = KC(RT)^ΔngThis question was posed to me in quiz.I need to ask this question from Homogeneous Equilibria topic in chapter Equilibrium of Chemistry – Class 11

Answer»

Correct answer is (c) KC = KP(RT)^Δng

The explanation is: For example, take the reaction 2HBr(g) \(\leftrightarrow\) H2(g) + Br2(g), KC = [H2][Br2]/[HBr]^2; KP = [pH2][pBr2]/[pHBr]^2, where pH2 = [H2]RT, pBr2 = [Br2]RT and [pHBr] = [HBr]RT. So we can SAY that KC = KP(RT)^Δng, where Δng = moles of products – moles of reactants which are in GASEOUS state only.

95.

At constant temperature, the pressure is directly proportional to the concentration of the gas.(a) true(b) falseThis question was addressed to me at a job interview.This key question is from Homogeneous Equilibria in section Equilibrium of Chemistry – Class 11

Answer»

The correct choice is (a) true

To EXPLAIN I would say: We have P = CRT e where p is PRESSURE, R is a universal CONSTANT and T is the temperature, we derive the equation from the ideal gas equation PV=nRT. So from P = CRT, we can say that at a constant temperature the pressure is directly proportional to the concentration of the gas.

96.

Write pressure in terms of concentration and temperature.(a) P = CRT(b) P = nrt(c) p = CT(d) C = PTI have been asked this question during an interview.This question is from Homogeneous Equilibria in division Equilibrium of Chemistry – Class 11

Answer» CORRECT choice is (a) P = CRT

To explain I would say: We all know that the ideal GAS equation is PV = nRT; P = nRT/V; P = CRT here N/v is CONCENTRATION, P is the pressure, V is the volume, n is the number of moles, C is the concentration, R is the UNIVERSAL gas CONSTANT and T is the temperature.
97.

The equilibrium N2(g) + O2(g) \(\rightleftharpoons\) 2NO(g), is an example of _____________(a) homogeneous chemical equilibrium(b) heterogeneous chemical equilibrium(c) neither homogeneous nor heterogeneous(d) both homogeneous and heterogeneousI had been asked this question during an online interview.The above asked question is from Homogeneous Equilibria topic in division Equilibrium of Chemistry – Class 11

Answer»

The correct answer is (a) homogeneous chemical equilibrium

The explanation: In homogeneous equilibrium, the REACTANTS and PRODUCTS are present in the same phase or physical state. Nitrogen, OXYGEN, and nitrogen monoxide are present in a gaseous state, so it is homogeneous chemical equilibrium.

98.

The units of KP and KC are equal.(a) true(b) falseThe question was asked in a national level competition.My doubt is from Homogeneous Equilibria topic in portion Equilibrium of Chemistry – Class 11

Answer»

The correct answer is (B) false

To elaborate: The units of KP are (atm)^Δng and the units of KC are (mol/L)^Δng. Where Δng = moles of products – moles of reactants which are in the gaseous STATE only. As the units of KP and KC are not equal the above STATEMENT is considered to be false.

99.

Br2(l) \(\rightleftharpoons\) Br2(g) is in ________(a) homogeneous equilibrium(b) not in both Homogeneous and heterogeneous equilibrium(c) cannot say(d) may or may not be in Homogeneous equilibriumThis question was posed to me in exam.The above asked question is from Homogeneous Equilibria topic in section Equilibrium of Chemistry – Class 11

Answer»

Right choice is (b) not in both Homogeneous and heterogeneous EQUILIBRIUM

For explanation: As we know that in Homogeneous equilibrium the REACTANTS and PRODUCTS are present in the same PHASE or physical state but here it is in a liquid state and gaseous state, so it is not in Homogeneous equilibrium.

100.

If the chemical reaction is: aA + bB → cC + dD and K is the equilibrium constant. Then what is the equilibrium constant of the reaction naA + nbB → ncC + ndD?(a) K(b) nK(c) K^n(d) K/nThe question was posed to me in semester exam.My question is taken from Law of Chemical Equilibrium and Equilibrium Constant in section Equilibrium of Chemistry – Class 11

Answer» CORRECT answer is (c) K^n

The explanation: If a chemical reaction is multiplied by a constant then the EQUILIBRIUM constant of the PARTICULAR chemical reaction is RAISED to the power of the constant by which the chemical reaction is multiplied, so here and is a constant and equilibrium constant of the reaction is k^n.