This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 751. |
Observe the circuit and state whether the cells are connected in series or parallel. If each cell is of e.m.f. `1.5 V`, then find the total e.m.f applied across the bulb connected. |
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Answer» The positive terminal of each cell is connected to the negative terminal of the other cell. This shows that the cells are connected in series. When cells are con-neted in series. total e.m.f `= E_(1) + E_(2) + E_(3)` `= 1.5+1.5+1.5=4.5 V`. |
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| 752. |
When a positively charged and another negtively charged bodies with equal magnitude of charge are brought simultaneously in contact with the cap of a positively charged electroscope, then the stripsA. move apart.B. come closer.C. remains uneffectedD. Cannot be determined |
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Answer» Correct Answer - B When prositively charged and netgatively charged bodies are brought in contact with the brass cap of the gold leaf electroscope-both the charge neutral-ize each other and the net charge will be zero on the cap of electroscope,and hence the charge on strips flows to the bodies brought in contact with the cap and due to this the grap between strips decreases. |
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| 753. |
Observe the circuit and state whether the cells are connected in series or parallel. If each cell is of e.m.f. `1.5 V`, then find the total e.m.f applied across the bulb connected. |
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Answer» The positive terminal of each cell is connected to the negative terminal of the other cell. This shows that the cells are connected in series. When cells are con-neted in series. total e.m.f `= E_(1) + E_(2) + E_(3)` `= 1.5+1.5+1.5=4.5 V`. |
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| 754. |
A wire is cut into three equal parts and then connected in parallel with the same source. How will its.(i) resistance and resistivity gets affected? (ii) How would the total current and the current through the parts change? |
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Answer» i. Here, the new resistance: R = \(\frac{R}{3}\) \(\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\) \(\frac{1}{R_{eq}}=\frac{1}{\frac{R}3}+\frac{1}{\frac{R}3}+\frac{1}{\frac{R}{3}}\) \(\frac{1}{R_{eq}}=\frac{3}{R}+\frac{3}{R}+\frac{3}{R}\) \(\frac{1}{R_{eq}}=\frac9R\) \(\frac{1}{R_{eq}}=\frac9RΩ\) The resistivity is dependent on the nature of the material. Hence, there will be no change in the reisitivity of the wire. ii. Now, by Ohm’s Law V = I x R I = \(\frac{V}R=\frac{V}{\frac{R}9}=\frac{9V}{R}\) ∴ I = 9 x I Thus, the current will increase 9 times than the previous current. |
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| 755. |
Find the current drawn from the battery by network of four resistors shown in the figure? |
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Answer» Given: V = 3V R1 = R2 = R3 = R4 = 10Ω Here, R1 and R2 are connected in series And, R3 and R4 are connected in series. ∴ \(\frac{1}{R_{eq}}=\frac{1}{R_1\,+\,R_2}+\frac{1}{R_3\,+\,R_4}\) \(\frac{1}{R_{eq}}=\frac{1}{R_1\,+\,R_2}+\frac{1}{R_3\,+\,R_4}=\frac{1}{20}+\frac{1}{20}=\frac{2}{20}\) Req = \(\frac{20}{2}\) Now, by Ohm’s Law V = I x R I = \(\frac{V}{R}\) = \(\frac{3}{10}\) ∴ I = 0.3A Thus, Current drawn by the resistor from the battery is 0.3 A |
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| 756. |
Which of the following statements about the current in given circuit is correct?(A) Current at Q is greater than the current at R. (B) Current at R is greater than the current at P. (C) P has maximum current. (D) R has maximum current. |
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Answer» Correct option (C) P has maximum current. Explanation: Current at P is maximum because it is connected in series with battery and hence shows total current drawn from battery. |
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| 757. |
Following graph was plotted between V and l values, across a wire. Which of the following statement(s) is/are correct regarding this?(A) Value of ratio V/l when the potential difference is 0.8 V is not equal to the value of ratio V/l when the potential difference is 1.2 V.(B) This graph illustrates the non-ohmic law. (C) While plotting this graph, the temperature remains constant. (D) All of these |
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Answer» Correct option (C) While plotting this graph, the temperature remains constant. Explanation: The ratio of potential difference applied to the wire and current passing through it is a constant. Ohm's law is illustrated by this graph. Hence, temperature must be constant while calculating values. |
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| 758. |
A wire `1.0` m long, `0.2` mm in diameter, has a resistance of `10 Omega`. Calculate the resistivity of its material. |
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Answer» Here , `l = 1.0 m, r = (0.2 mm)/(2) = 0.2 mm = 10^-4 m R = 10 Omega` As `R = (rho l)/(A), rho = (RA)/(l) = ((10 Omega) [3.14 xx 10^-8 m^2])/(1.0 m) = 3.14 xx 10^-7 Omega m` `[as A = pi r^2 = 3.14 xx (10^-4 m)^2 = 3.14 xx 10^-8 m^2]`. |
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| 759. |
Resistance of a metal wire of length 1 m is `26 Omega` at `20^@ C`. If the diameter of the wire is `0.3 mm`, what will be the resistivity of the metal at that temperature ? Using Table `1.1`, predict the material of the wire. |
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Answer» We are given resistance R of the wire `=26 Omega`, the diameter `d=0.3 mm =3xx10^(-4)m`, and the length I of the wire= 1 m. Therefore. From Eq. (12.10), the resistivity of the given metallic wire is `rho=(RA//I0=(RpiD^(2)//4I)` Substitution of values in this gives `rho=1.84xx10^(-6)Omega`m The resistivity of the metal at `20^(@)C "is " 1.84xx10^(-6) Omega`m. From Table 12.2, we see that this is the resistivity of manganese. |
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| 760. |
A wire of given metarial having length l and ares of cross-section A has a resistance of `4 Omega`. What would be the resistance of another wire of the same meterial having length l/2 and area of cross-section 2A ? |
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Answer» For first wire `R_(1)=rhol/A=4Omega` Now for second wire `R_(2)= rho(l//2)/(2A)=1/4rhol/A` `R_(2)=1/4R_(1)` `R_(2)=1Omega` The resistance of the new wire is `1Omega`. |
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| 761. |
Match the column I with column II and select the correct option from the codes given.Column IColumn II(a) Electric current(i) volt(b) E.m.f(ii) ohm(c) Resistance(iii) ohm-metre(d) Resistivity(iv) ampere(A) (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii) (B) (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii) (C) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii) (D) (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv) |
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Answer» (C) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii) |
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| 762. |
Give reason for the following :Why is lead-tin alloy used for fuse wires ? |
| Answer» Low melting point. | |
| 763. |
Fuse wire is an alloy of1. tin-lead2. copper-lead3. tin-copper4. lead-silver |
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Answer» Fuse wire is an alloy of tin-lead. |
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| 764. |
Observe the following circuit diagrams and answer the question.What difference do you find between diagrams A and B? |
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Answer» We observe that the bulb in circuit A is not glowing and in circuit B it is glowing. We can also see the switch is in OFF mode in circuit diagram A and it is in ON mode in circuit diagram B. Circuit diagram A represents open circuit, where as circuit diagram B represents closed circuit. in circuit A it was open and where as in B the circuit is closed |
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| 765. |
Coil of wire is rotated between electromagnets is created (a) Heat (b) Electromagnetic induction (c) Kinetic energy (d) None |
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Answer» (b) Electromagnetic induction |
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| 766. |
On what principle do electric cranes work? |
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Answer» Electric cranes are worked on the principle of magnetic effects of electricity. |
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| 767. |
What are electromagnets? |
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Answer» The devices which act as magnets when electricity passes through them are called electromagnets. |
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| 768. |
What is magnetic effect of electricity? |
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Answer» The production of magnetic force due to the flow of electricity thrombi a wire is called Magnetic effect of electricity. |
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| 769. |
What happen if all cells are connected in series ? |
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Answer» If a number of cells are connected in series the brightness of the bulb is enhanced. |
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| 770. |
Name the metal used as a filament in the iron box and buld? |
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Answer» 1. Generally, the filament in an iron box is made up of Niehrome. 2. The filament in a bulb is made of Tungsten. |
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| 771. |
What happen if all cells are connected in parallel ? |
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Answer» If a number of cells are connected in parallel the brightness of the bulb remains same. |
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| 772. |
What is the tearing effect of electricity? |
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Answer» The production of heat due to the flow of electricity through a wire is called heating effect of electricity. |
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| 773. |
What is a simple electric circuit? |
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Answer» A simple electric circuit consisting of a battery, a bulb, a switch, and connecting wires. |
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| 774. |
Write the common sequence of components in electric circuit diagram. |
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Answer» Positive terminal of the cell → wire → bulb → wire → switch → wire → negative terminal of the cell. |
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| 775. |
What are circuit diagrams? |
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Answer» The diagrams which show the arrangement of electric components in a circuit are called circuit diagrams. |
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| 776. |
What is the use of MCB ? |
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Answer» Miniature Circuit Breaker (MCB) is being used in place of electric fuses. |
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| 777. |
Explain the common sequence of components in electric circuit diagram . |
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Answer» The common sequence of components in electric circuit diagram is as follows : Positive terminal of the cell → wire bulb wire → switch → wire → negative terminal of the cell. |
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| 778. |
What is simple electric circuit consist of ? |
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Answer» A simple electric circuit consisting of a battery, a bulb, a switch and connecting wires. |
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| 779. |
What is circuit diagrams ? |
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Answer» The diagrams which show the arrangement of electric component’s in a circuit are called circuit diagrams. |
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| 780. |
In a parallel-plate capacitor, the plates are kept vertical. The upper half of the space between the plates is filled with a dielectric with dielectric constant K and the lower half with a dielectric with dielectric constant 2 K. The ratio of the charge density on the upper half of the plates to the charge density on the lower half of the plates will be equal to (a) 1 (b) 2 (c) 1/2 (d) 3/2 |
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Answer» Correct Answer is: (c) 1/2 The p.d. between the plates is the same at all the points. As p.d. = intensity x distance, the intensity E is the same in both dielectrics. Let σ1 and σ2 be the charge densities in the upper and lower halves. ∴ E = σ1/ε0K = σ2/ε0 x 2K ∴ σ1/σ2 = 1/2. |
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| 781. |
A parallel-plate capacitor, whose plates are kept horizontal, is charged from a cell and then isolated from it. A dielectric slab which can just fit in the gap between the plates is now inserted to fill exactly half of the gap and then left alone. Neglect gravity and friction. The slab will (a) remain stationary (b) move further into the gap (c) move out of the gap (d) either (b) or (c) depending on whether its dielectric constant is greater or less than 2 |
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Answer» Correct Answer is: (b) move further into the gap Energy = Q2/2C .Here, Q is constant. As the slab moves into the gap, C increases and hence energy decreases. A system tends to move towards lower energy. |
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| 782. |
1000 identical drops of mercury are charged to a potential of 1 V each. They join to form a single drop. The potential of this drop will be (a) 0.01 V (b) 0.1 V (c) 10 V (d) 100 V |
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Answer» Correct Answer is: (d) 100 V Volume = 4/3 πR3 = 1000 x 4/3 πr3 or r = R/10 Q = CV = (4πε0R) x V = 1000(4πε0r) 1 or V = 103 τ/R = 103/10 = 100 V |
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| 783. |
A simple pendulum has time period T. Charges are now fixed at the point of suspension of the pendulum and on the bob. If the pendulum continues to oscillate, its time period will now be(a) greater than T(b) equal to T(c) less than T(d) either (a) or (c) depending on whether the charges attract or repel each other |
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Answer» Correct Answer is: (b) equal to T The additional electrostatic force acts along the string. this dose not have a component in the direction of motion of the bob. |
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| 784. |
Define the SI unit of potential difference. |
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Answer» If the amount of work done in bringing a one-coulomb charge from one point to the other is 1 joule then potential difference between two points is said to be 1volt. |
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| 785. |
Write true or false for the following statements: Insulator like wood and rubber has a very low electrical resistance. |
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Answer» False Insulator like wood and rubber has a very high electrical resistance. |
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| 786. |
Write true or false for the following statements: Resistance of a conductor increases with the increase in temperature. |
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Answer» True With increase in temperature the random motion of the atoms and electrons in a conductor increases and so the resistance decreases. |
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| 787. |
Why does resistance of a metallic conductor increase with increase in temperature? |
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Answer» When a metallic conductor is heated, the atoms in the metal vibrate with greater amplitude and frequency. Due to increase in temperature, the thermal velocities of free electrons also increases. Therefore, the number of collisions between free electrons and atoms increases. This increases the opposition to the movement of electrons and hence the resistance of the conductor. |
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| 788. |
Why is it not advisable to handle high voltage electrical circuit with wet hands? |
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Answer» The resistance of dry-skin human body is about 50,000Ω. When the skin is wet, the resistance gets lowered to about 10,000Ω. If a person with wet hands touches the electrical circuit, high current will flow through the body causing risk to life. |
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| 789. |
What is the general name of the substances having infinitely high electrical resistance ? |
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Answer» Solution : The general name of the substances having infinitely high electrical resistance Insulators. |
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| 790. |
The substance having infinitely high electrical resistance is called:A. conductorB. resistorC. superconductorD. insulator |
| Answer» Correct Answer - D | |
| 791. |
Keeping the potential difference constant, the resistance of a circuit is doubled. The current will becomes:A. doubleB. halfC. one-fourthD. four times |
| Answer» Correct Answer - B | |
| 792. |
When the diameter of a wire is doubled, its resistance becomes:A. doubleB. four timesC. one-halfD. one-fourth |
| Answer» Correct Answer - D | |
| 793. |
An electric lamp is marked 26 W, 220V. It is used for 10 hours daily. Calculate its resistance while glowing. |
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Answer» Given Power (P) = 26W Voltage (V) = 220V We know that P = \(\frac{V^2}{R}\) ⇒ R = \(\frac{V^2}{P}\) ⇒ R = \(\frac{220\,\times\,220}{26}\) ⇒ R = \(\frac{48400}{26}\) = 1861.53 Hence the resistance is 1861.53 Ω |
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| 794. |
An electric lamp is labelled 12 V, 36 W. This indicates that it should be used with a 12 V supply. What other information does the label provide ? |
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Answer» Other information is that it will consume energy at the rate of 36 J/s. |
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| 795. |
If the potential difference between the end of a wire of fixed resistance is doubled, by how much does the electric power increase ? |
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Answer» P=V2/R R is fixed. V becomes double. Now, P = (2V)2/R = 4 V2/R So, the electric power becomes four times its previous value. |
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| 796. |
What is the meaning of the symbol kWh ? Which quantity does it represent ? |
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Answer» kWh is the short form of kilowatt-hour, which is the commercial unit of electrical energy. |
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| 797. |
Which quantity has the unit of watt ? |
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Answer» Electric power has the unit of watt. |
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| 798. |
Which quantity has the unit of watt ? |
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Answer» Electric power has the unit of watt. |
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| 799. |
Name the quantity whose unit is (i) kilowatt, and (ii) kilowatt-hour. |
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Answer» (i) Electric power (ii) Electric energy |
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| 800. |
Name the quantity whose unit is (i) kilowatt, and (ii) kilowatt-hour. |
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Answer» (i) Electric power (ii) Electric energy |
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