Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The boiling and melting points of carboxylic acids depend on :

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HYDROGEN BONDING
Polarisation
Resonance
All

Answer :A
2.

The Bohr orbit radius for the H-atom (Z=1) is approximately 0.53Å. The radius for the first excited state orbit is:

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`0.13Å`
`1.06Å`
`4.77Å`
`2.12Å`

SOLUTION :`r PROP N^(2)z^(2)`
For H-atom Z=1
`r prop n^(2)`
`(r_(1))/(r_(2))=(n_(1))/(n_(2))`
`0.530/(r_(2))=(1^(2))/(2^(2))`
`:.r_(2)=0.530xx4=2.12Å`
3.

The blue print process involves the use of

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Indigo dyes
Vat dyes
Iron compounds
Zinc compounds

Solution :The BLUE print PROCESS involve the USE of iron compound.
4.

The blue coloured mineral 'Lapis Lazuli' which is used as a semi-precious stone is a mineral of the following class

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SODIUM aluminosilicates
Zinc cobaltate
Basic COPPER carbonate
prussian blue

Solution :LAPIS LAZULI is sodium ALUMINOSILICATE.
5.

The blue complex ion formad on addition of conc. NH_4OH solution to a Cu^(2+) salt solution is :

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`[CU(NH_4)_2]^(2+)`
`[Cu(NH_3)_2]^(2+)`
`[Cu(NH_3)_4]^(2+)`
`[Cu(NH_4)_3]^(2+)`

Answer :C
6.

The blue coloured mineral 'Lapis Lazuli' used as semi precious stone is :

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PRUSSIAN blue
Sodium aluminosilicate
Zinc cobaltate
Basic COPPER carbonate

Answer :B
7.

The blue colour produced on adding hydrogen peroxide to acidified K_2Cr_2O_7 is due to the formation of

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`CrO_5`
`Cr_2O_3`
`CrO_4^(2-)`
`CrO_3`

ANSWER :A
8.

The blue coloured gas is:

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`F_2`
`O_3`
NO
`Cl_2`

ANSWER :B
9.

The blue colour produced on adding H_2O_2 to acidified K_2Cr_2O_7 is due to the formation of :

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`CrO_5`
`Cr_2O_3`
`CrO_4^(2-)`
`CrO_3`

ANSWER :A
10.

The blue colour of the sky is due to .......

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COAGULATION
peptisation
TYNDALL EFFECT
Brownian movement

Solution :Tyndall effect
11.

The blue colour obtained by the addition of excess dil. NH_(4)OH to an aqueous solution of a salt containing copper is due to the presence of :

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`CuSO_(4)`
`CU(OH)_(2)`
`(NH_(4))_(2)SO_(4)`
`[Cu(NH_(3))_(4)]^(+2)`

ANSWER :D
12.

The blue colour of liquid ammonia solutions of alkali metals is mainly due to :

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COLOURED cations
ammoniated cations
ammoniated electrons
colour of LIQUID ammonia

Answer :C
13.

The blue colour is obtained when a copper wire is immersed in AgNO_(3) solution, it is due to formation of

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`Ag^(+) ` ions
`CU^(+)` ions
`Cu^(2+)` ions
a soluble complex

Solution :Cu can DISPLACE Ag from `AgNO_(3)` as REDUCTION POTENTIAL of Cu is LESS than Ag.
14.

The blood red colour obtained in the detection of nitrogen and sulphur together in an organic compound in Lassaigne's test is due to

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`[FE(CNS)]^(+)`
`[Fe(CNS)_(2)]^(+)`
`[Fe(CNS)_(3)]^(-)`
`[Fe(CNS)_(2)]^(2+)`

SOLUTION :N//A
15.

The blocks of Mg metal are often strapped to the steel hulls of ocean going ships in order to

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PROVIDE CATHODIC protection
Provent OXIDATION of steel
Both A and B are correct
None of these is correct

Answer :C
16.

The blood buffers are most often involed in stabilizing the pH in presence of metabolically produced:

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Acids
bases
salts
None of these

Answer :A
17.

The bleeding from a wound is stopped by the application of ferric chloride as

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Blood starts FLOWING in the opposite DIRECTION
Ferric CHLORIDE seals the blood vessels
Blood reacts and a solid is formed which seals the blood vessels
Blood is COAGULATED and the blood vessels are sealed

Answer :D
18.

The blistered appearance of Cu obtained from the reverberatory furnace is due to evolution of

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`CO_(2)` gas
`SO_(2)` gas
`NO_(2)`
DUE to evaporation of VOLATILE materials.

Answer :B
19.

The bleaching action of the Bleaching powder is due to liberation of

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NASCENT CHLORINE
nascent oxyge
nascent hydrogen
atomic hydrogen

Answer :B
20.

The bleaching action of SO_(2) is temporary but that of Cl_(2) is permanent-why?

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Solution :In the presence of water, `SO_(2)` bleaches by reduction.
`SO_(2)+2H_(2)OtoH_(2)SO_(4)+2[H]`(NASCENT)
Coloured ORGANIC matter `underset("Reduction")overset([H])to`Bleached organic matter
It is not permanent bleaching because the bleached matter regains its original colour if it is kept in air. On the other hand, in the presence of water, `Cl_(2)` bleaches by oxidation.
`Cl_(2)+H_(2)Oto2HCl+[O]`(nascent)
Coloured organic matter `underset("Oxidation")overset([O])to`Bleached organic matter
It is permanent bleaching because if the bleached substance is exposed to air, there is no possibility of its reduction. Thus, its original colour cannot be restored.
21.

Bleaching action of H_2O_2 is due to its ---- character .

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REDUCING properties
Oxidising properties
Unstable NATURE
Acidic nature

ANSWER :B
22.

The bleaching action of bleaching powder is due to the formation of

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`CaCl_(2)`
`CaSO_(4)`
HClO
`Ca(ClO_(3))_(2)`

Solution :Chlorine REACTS with WATER forming HCL and HClO (Hypochlorus ACID) is not stable and decomposes giving nascentoxygen which is responsible for oxidising and bleaching.
23.

The bleaching action ofbleaching powder is due to the formation of:

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`CaCl_2`
`CaSO_4`
HCLO
`CA(ClO_3)_2`

ANSWER :C
24.

The black oxide of copper (CuO) in attacked by moisture and carbon dioxide in air and forms a green film of :

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`Cu(OH)_(2) and C`
`Cu(OH)_(2) * CuCO_(3)`
`CuCO_(3) and CO_(2)`
`Cu(OH)_(2) * CuSO_(4)`

Answer :B
25.

The bivalent metal ion having maximum paramagnetic behaviour among the first transition series elements is

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`Mn^(2+)`
`CU^(2+)`
`Sc^(2+)`
`Cu^(2+)`

Solution :`Mn^(2+) (3d^5 4s^0) to 5 ` unpaired electrons.
`Cu^(2+) (3d^9 4s^0) to 1 ` unpaired electron
`Sc^(2+) (3d^1 4s^0) to 1 `unpaired electron
`Cu^+ (3d^(10) 4s^0 ) to 0 ` unpaired electron
HENCE , `Mn^(2+)` has MAXIMUM NUMBER of unpaired THUS, it shows maximum paramagnetic behaviour
26.

The biodegradable polymer is ………….

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Nylon-6,6
Nylon-2-Nylon-6
Nylon-6
Buna-S

Solution :Nylon-2-Nylon-6
27.

The bite of honey - bee inject into our body

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ACETIC ACID
formic acid
butyric acid
carbolic acid

ANSWER :B
28.

The bivalent metalion having maximum paramagnetic behavior among the first transition series element is

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`Mn^(2+)`
`Cu^(2+)`
`SC^(2+)`
`Cu^(+)`

Solution : `Mn^(2+)(3d^(5)4s^(0))rightarrow5` UNPAIRED electrons
`CU^(2+)(3d^(9)4s^(0))rightarrow1` unpaired electron
`Sc^(2)(3d^(9)4S^(0))rightarrow` unpaired electron
`Cu^(+)(3d^(10)4S^(0))rightarrow0`unpaired electron
Hence , `Mn^(2+)` has MAXIMUM number of unpaired electrons THUS , it shows maximum paramagnetic behaviour
29.

The biodegradable polymer among the following is

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nylon-6
nylon-6-nylon-6, 6
nylon-2-nylon-6
nylon-6-nylon-6, 10

Solution :Nylon-2-nylon-6
30.

The biochemical reaction by using urease enzyme is ..

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hydrolysis of urea.
DIGESTION of lipid. (C
digestion of starch.
hydrolysis of maltose. 

SOLUTION :hydrolysis of urea.
31.

The binding energy of an element is 64 MeV . If BE/nucleon is 6.4 the number of nucleons are :

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10
64
16
6

Solution :`ABE = (B.E)/(A) = (64)/(A) = 6.4` (where A = 10 )
32.

The binding energy of ._(8)O^(16) is 127 MeV. Its binding energy per nucleon is

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0.794 MeV
1.5875 MeV
7.94 MeV
15.875 MeV

Solution :BINDING energy PER NUCLEON `= (127)/(16) = 7.94` MeV
33.

The binaphthol (Bnp) is:

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an opticlly ACTIVE compound having chiral centre
an OPTICALLY inactive compound
an meso compound
an sotically active compound WITHOUT having chiral centre

SOLUTION :
Compound give Attopi isomerism and is optically active due to absence of plane and centre of symmetry.
34.

The bimolecular reaction is represented by :

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<P>(I)(II)(R)
(IV)(i)(Q)
(III)(ii)(S)
(II)(iv)(P)

SOLUTION :
35.

The bicabonates of group 2 metals are

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EASILY oxidized by air
Stable only in SOLUTION
Unstable in solution
Stable to HEAT in solid state

Solution :The bicarbonates of GROUP 2 METALS are stable only in solution
36.

The biggest ion is:

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`Al^(3+)`
`Ba^(2+)`
`NA^+`
`MG^(2+)

Answer :B
37.

The beta- decay of a radioactive element results in formation of its :

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isotope
isobar
isodiapher
nuclear isomer.

Solution :When a `beta-`particle is emitted, the atomic mass remains same but nuclear charge is increased by 1 unit.
38.

The beta and alpha glucose have different specific rotations. When either is dissolved in water , their rotation changes until the same fixed value results. This is called

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epimerization
RACEMISATION
anomerisation
MUTAROTATION

ANSWER :D
39.

The beta and alpha glucose have different specific rotations. When either is dissolved in water, their rotation changes until the same fixed value results. This is called

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Epimerisation
Racemisation
Anomerisation
Mutarotation

Solution :The `beta` and `ALPHA`-glucose have DIFFERENT rotation. When either is dissolved in WATER, their rotation changes until the same fixed VALUES results. This CALLED mutarotation.
40.

The best yield of product 'X' can be obtained by using which one of the following sequence of reagents and reactants X=CH_3-C-=C-oversetoverset(OH)(|)CH-CH(CH_3)_2

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`CH_3-C=Choverset(NaNH_2)tooverset((CH_3)_2CHCHO)tooverset(H_3O^+)to`
`(CH_3)_2CH-oversetoverset(OH)(|)CH-C=C-Hoverset(NaNH_2)tooverset(CH_3I)to`
`CH_3-C=C-oversetoverset(OH)(|)CH-CH_2-OH_3overset(NaNH_2)tooverset(CH_3I)to`
`(CH_3)_2CH-oversetoverset(OH)(|)CH-C=C-Hoverset(CH_3MgI)tooverset(CH_3I)to`

SOLUTION :
41.

The beta-decay of""_(11)^(24)Na produces in isotope of

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Al
Na
Mg
Ne

Answer :C
42.

The best source of vitamin A is

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beans
pulses
orange
carrot

Answer :D
43.

The best source of vitamin C is

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COD LIVER oil
Egg yolk
Citrous fruits
Fish liver oil

Answer :C
44.

…...... is the precursor of vitamin-A.

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Beans
Wheat
Carrots
Oranges

Answer :C
45.

Vitamin C is a :

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Beans
Wheat
Carrots
Oranges

Answer :C
46.

The best source of vitamin A is :

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Wheat
Carrots
Beans
Oranges.

Answer :B
47.

The best reagent to convert pent-3-en-2-ol into pent-3-en-2-oneis

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ACIDIC permanganate
Acidic dichromate
CHROMIC ANHYDRIDE in glacial acid
Pyridinium chloro -chromate

Solution :Chromic anhydride in glacial acetic acid is the best reagent to CONVERT pent-3-en-2-ol into pent-3-en-2-one.
48.

The best reagent for the preparation of pure C_2H_5Cl from ethanol is

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LUCAS reagent
`PCl_5`
Thionyl chloride in PYRIDINE
Red PHOSPHOROUS + Chlorine

Answer :C
49.

The best reagent for converting 2-phenylpropanamide into 2-phenylpropanamine is _____________ .

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excess `H_2`
` Br_2`in aqueous NaOH
IODINE in the presence of RED phosphorus
`LiAlH_4` in ETHER.

Solution :`underset("2-Phenylpropanamide")(C_6 H_5 - overset(CH_3) overset(|)(CH) -CONH_2) overset(LiAIH_4 // " ether")to underset("2-Phenylpropanamine")(C_6 H_5 - overset(CH_3) overset(| ) (CH )-CH_2 NH_2)`
50.

The best reagent for converting 2-phenylpropanamide into 2-phenylpropanamine is

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excess `H_2`
` Br_2`in AQUEOUS NAOH
iodine in the presence of RED phosphorus
`LiAlH_4` in ether.

Solution :`underset("2-Phenylpropanamide")(C_6 H_5 - OVERSET(CH_3) overset(|)(CH) -CONH_2) overset(LiAIH_4 // " ether")to underset("2-Phenylpropanamine")(C_6 H_5 - overset(CH_3) overset(| ) (CH )-CH_2 NH_2)`