This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Reduction of ketones cannot be carried out with which of the following reagents ? |
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Answer» Sodium borohydride or Lithium aluminium hydride |
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| 2. |
Reduction of hexose A (molecular formula C_(6)H_(12)O_(6)) with sodium borohydride gives compound B and C. Compound B is optically inactive, whereas compound C is optically active. Which of the following is compound A? |
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Answer» D - fructose |
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| 3. |
Reduction of ester with Na//C_(2)H_(5)OH is called as : |
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Answer» Birch reduction |
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| 4. |
Reduction of glucose by HI suggest that |
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Answer» presence of OH groups |
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| 5. |
Reduction of CH_(3)CH_(2)NO_(2) with LiAlH_(4) gives: |
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Answer» `CH_(3)CH_(2)NH_(2)` |
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| 6. |
Reduction of chlorobenzene by LiAlH_(4) gives |
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Answer» toluene |
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| 7. |
Reduction of glucose with NaBH_(4)gives |
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Answer» SORBITOL |
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| 8. |
Reduction of benzenediazonium chloride with SnCl_(2) + HCl |
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Answer» Aniline |
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| 9. |
Reduction of carbonyl compounds to alkanes with NH_2-NH_2 and NaOH is called: |
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Answer» CLEMMENSEN REDUCTION |
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| 10. |
Reduction of benzenediazonium chloride with Zn/HCl gives |
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Answer» aniline |
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| 11. |
Reduction of can be carried out with |
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Answer» CATALYTIC REDUCTION |
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| 12. |
Reduction of carbonyl compound to alkanes using ZN/Hg + HCI is called: |
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Answer» CLEMMENSEN REDUCTION |
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| 13. |
Reduction of benzene diazonium chloride with Zn/HCl gives |
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Answer» PHENYL hydrazine |
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| 14. |
Reduction of bensaldehyde with zinc and hydrochloric and gives |
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Answer»
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| 16. |
Reduction of aromatic nitro compounds using Fe and HCl gives: |
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Answer» AROMATIC oxime |
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| 17. |
Reduction of aromatic nitro compounds using Fe and HCl gives____ |
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Answer» AROMATIC oxime |
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| 18. |
Reduction of aromatic nitro compounds using Fe and HCI gives |
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Answer» AROMATIC oxime |
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| 19. |
Reduction of aromatic nitro compounds using Fe and HCl gives ______________ . |
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Answer» AROMATIC oxime |
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| 20. |
Reduction of an alkyne to the double bond stage can yield a cis alkene or trans alkene (except in cases where triple bond is at the end of the chain ) Reduction of alknes with sodium or lithium in liquid NH_(3) yields predominantly trans alkene. Hydrogenation of alkynes with Lindlar's catalyst or a nickel boride called P_(2) catalyst yeilds is alkene (as high as 98%) If Pd/C/H_(2) is used in the absence of a catalyst poison, two equivlanet of H_(2) are added forming alkanes. Select the correct statement(s) |
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Answer» Trans form of vinylic anion is more stable |
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| 21. |
Reduction of an oxide ore with carbon at high temparature is called |
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Answer» |
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| 22. |
Reduction of an alkyne to the double bond stage can yield a cis alkene or trans alkene (except in cases where triple bond is at the end of the chain ) Reduction of alknes with sodium or lithium in liquid NH_(3) yields predominantly trans alkene. Hydrogenation of alkynes with Lindlar's catalyst or a nickel boride called P_(2) catalyst yeilds is alkene (as high as 98%) If Pd/C/H_(2) is used in the absence of a catalyst poison, two equivlanet of H_(2) are added forming alkanes.Reduction of alkynes to trans alkene by Li//NH_(3) is carried out in the presence of dry ice. This is because of |
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Answer» radical anion is formed at the temperature of dry ice |
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| 23. |
Reduction of an alkyne to the double bond stage can yield a cis alkene or trans alkene (except in cases where triple bond is at the end of the chain ) Reduction of alknes with sodium or lithium in liquid NH_(3) yields predominantly trans alkene. Hydrogenation of alkynes with Lindlar's catalyst or a nickel boride called P_(2) catalyst yeilds is alkene (as high as 98%) If Pd/C/H_(2) is used in the absence of a catalyst poison, two equivlanet of H_(2) are added forming alkanes.Lindlar's catalyst can be prepared in precipitating palladium calcium carbonate and treating it with lead acetate or quinoline. This treatement is |
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Answer» partically deactivities the catalyst WHICHCAUSES REDUCTION of ALKYNE to alkene |
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| 24. |
Reduction of an ester with lithium aluminium hydride gives |
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Answer» TWO acids |
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| 25. |
Reduction of an alkyne to the double bond stage can yield a cis alkene or trans alkene (except in cases where triple bond is at the end of the chain ) Reduction of alknes with sodium or lithium in liquid NH_(3) yields predominantly trans alkene. Hydrogenation of alkynes with Lindlar's catalyst or a nickel boride called P_(2) catalyst yeilds is alkene (as high as 98%) If Pd/C/H_(2) is used in the absence of a catalyst poison, two equivlanet of H_(2) are added forming alkanes.Shown below is the first step in hte synthesis of hte important perfume constituent, cis-Jasmone which reagents you choose to carry out this last step? |
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Answer» `Li//NH_(3)` |
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| 26. |
Reduction of an aldehyde produces |
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Answer» PRIMARY ALCOHOL |
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| 27. |
Reductionof alkyl nitrilewith sodiumand ethanalis called |
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Answer» CARBYLAMINE |
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| 29. |
Reduction of aldehydes with Lia1H_4 or NaBH_4 GIVES 1^@ alcohol |
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Answer» |
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| 30. |
Reduction of aldehydes and ketones into hydrocarbons using zinc amalgam and conc. HCl is called : |
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Answer» Wolff-Kishner Reduction Clemmensen Reduction. |
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| 31. |
Reduction of an aldehyde with H_2 /Pd gives a 1^@ alcohol. |
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Answer» |
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| 32. |
Reduction of Aldehydes and Ketones to hydrocarbon take place in the presence of |
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Answer» ZN AMALGAM and HCl acid |
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| 33. |
Reduction of Al_(2)O_(3) is occurred at low potential and high current through electrolysis. If 4.0xx10^(4) ampere current is pass through molten Al_(2)O_(3) solution for 6 hours then how much aluminium is obtained ? (atomic mass of aluminium is 27 gm/mol at 100% efficiency) |
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Answer» `8.1xx10^(4)GM` `Q=4.0xx10^(4)xx6xx60xx60C` `=8.64xx10^(8)C` Now, 96500 C liberate 9 gm AL, So, `8.64xx10^(8)C` So, `(9)/(96500)xx8.64xx10^(8)` gram Al is liberated `=8.05xx10^(4)` gram Al. |
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| 34. |
Reduction of aldehydes and ketones produces |
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Answer» `1^@` ALCOHOLS |
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| 35. |
Reduction of aldehyde with HCl gives: |
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Answer» PRIMARY alcohol |
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| 36. |
Reduction of acetone in the presence of sodium borohydride gives |
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Answer» 1-propanol |
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| 37. |
Reduction of acetyl chloride with H_(2) in presence of Pd gives |
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Answer» `CH_(3)COCH_(3)` |
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| 38. |
Reduction of Ag^+ ions, provided by Tollen's reagent to silver metal is known as _____. |
| Answer» SOLUTION :SILVER MIRROR | |
| 40. |
Reductionof a ketogroup to a methylene group is converted by using |
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Answer» `ZnHg + CONC. HCL` |
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| 41. |
Reduction in presence of amalgamated zinc and conc. HCl is known as |
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Answer» Mendius REDUCTION |
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| 42. |
Reduction of 2-Butyne with Na in liquidNH_3 givespredominantly: |
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Answer» n-butane |
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| 43. |
Reduction half reaction for the reaction :Fe^(2+)+MnO_(4)^(-)toFe^(3+)+Mn^(2+)is |
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Answer» 1. `MnO_(4)^(-)+8H^(+)+5e^(-)toMn^(2+)+4H_(2)O` |
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| 44. |
Reducing sugar can reduce : |
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Answer» ALDEHYDES to alcohols |
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| 45. |
Reducing property of monosaccharide is due to the presence of |
| Answer» Answer :D | |
| 46. |
Reducing power of A,B,C and D are w,x,y and z respectively such that z gt y gt x gt z. The one which will displace all others is |
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Answer» A |
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| 47. |
Reducing property of SO_(2) is represented by the following reaction |
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Answer» `2H_(2)S+SO_(2) rarr 3S+2H_(2)O` |
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| 48. |
Reducing property of SO_(2) is shown in A) 2H_(2)S+SO_(2)rarr 3S+2H_(2)O B) I_(2)+SO_(2)+2H_(2)Orarr SO_(4)^(-2)+2I^(-)+4H^(+) C) 3Fe+SO_(2)rarr 2Fe+FeS |
| Answer» ANSWER :B | |
| 49. |
Reducing agent used to convert benzene diazonium salt to benzene is |
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Answer» `Zn+NH_(4)Cl` |
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| 50. |
Redox reactions play a pivotyal role in chemistry and biology. The values of standard redox potential (E^(@)) of two half-cell reactions decidewhich way the reaciton is expected to proced. A simple exampler is a Daniel cell in which zinc goes into solution and copper gerts deposited. Given below are a set of half-cell reactions (acidic medium) along with theirE^(@) (V with respect to normal hydrofgen electrode) values. Using this data : I_(2) + 2e^(-) rarr 2I^(-)"" E^(@) = 0.54, CI_(2) + 2e^(-) rarr 2CI^(-) ""E^(@) = 1.36, .Mn^(3+) + e^(-) rarr Mn^(2+) ""E^(@) = 1.50, Fe^(3+) + e^(-) rarr Fe^(2+)"" E^(@) = 0.77, O_(2) + 4H^(+) + 4e^(-) rarr 2H_(2)O ""E^(@) = 1.23, Soldium fusion extract, obtained from aniline, on treatment with iron (II) sulphatge and H_(2)SO_(4) in presence of airgives a Prussion buleprecipitate. The blue colour is due to the formation of : |
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Answer» `Fe_(4)[Fe(CN)_(6)]_(3)` `Fe^(2+) + 6CN^(-) rarr [Fe(CN)_(6)]^(4-)` `4Fe^(3+) + 3[Fe(CN)_(6)]^(4-) rarr underset("Prussion blue")(Fe_(4)[Fe(CN)_(6)]_(3darr)` |
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