94420 + Interview Questions in Chemistry in Class 12

1.	Passage of threee faraday of charge through aqueous solution of AgNO_3,CuSO_4,Al(NO_3)_3 and NaCl will deposit metals at the cathode in the molar ratio of :
Answer» `1:2:3:1` `6:3:2:6` `6:3:0:0` `3:2:1:0` ANSWER :C

Discussion

2.	Passage of 96500 coulomb of electricity liberates. litre of O_(2) at NTP during electrolysis
Answer» 11.2 6.5 22.2 5.6 Answer :D

Discussion

3.	Passage of 96500 coulmb of electricity liberates…….. Litre of O_2 at NTP during electrolysis :
Answer» `5.6` `6.5` `22.2` `11.2` ANSWER :A

Discussion

4.	Passage-IV : Sulphur and rest of the elements of group 16 are less electronegative than oxygen. Therefore, theiratoms cannot take up electrons easily. They can acquire ns^(2)np^(6) configurationby sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds. In addition to this, their atoms have vacant d-orbitals in their valence shell to which electronscan be promoted from the p and s-orbitals of the shell. As a result, they can show +4 and +6 oxidation states shell. Like sulphur, oxygen does not show +4 and +6 oxidation states. The reason is :
Answer» that oxygen is a GAS while sulphur is a SOLID that oxygen has high ionization enthalpies in comparison to sulphur that oxygen has high electron AFFINITY in comparison to sulphur that oxygen has no d-orbitals in its VALENCE shell Solution :DUE to the absence of vacant d-orbitals oxygen forms only stable compounds in valency of 2.

Discussion

5.	Passage-IV : Sulphur and rest of the elements of group 16 are less electronegative than oxygen. Therefore, theiratoms cannot take up electrons easily. They can acquire ns^(2)np^(6) configurationby sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds. In addition to this, their atoms have vacant d-orbitals in their valence shell to which electronscan be promoted from the p and s-orbitals of the shell. As a result, they can show +4 and +6 oxidation states shell. The nature of the compounds of sulphur having +4 oxidation state is :
Answer» ACT as oxidizing AGENTS act as reducing agents act as oxidizing as well as reducing agents cannot be predicted SOLUTION :It is in intermediateoxidation STATE it may increase (or) decrease. Therefore it act as oxidizing agent and also reducing agent.

Discussion

6.	Passage-III : The binary compounds of oxygen with other elements are called oxides. They are classified either depending upon their acid - base characteristics or on the basis of oxygen content. a ) Normal oxides : These oxides which contain oxygen atoms as permitted by the normal oxidation number, i.e., -2. Normal oxide may be acidic, basic, amphotericor neutral.b) Polyoxides : The oxides which contain oxygen atoms different than those permitted by the normal oxidation number of -2. i) Peroxides : Two oxygen atoms are linked to each other and oxygenhas -I oxidation number. They contain (O-O)^(2) unit. ii) Superoxides : These oxides contain (O-O)^(-1) units, i.e., each O-atom has oxidation number -1//2. c ) Suboxides : These contain low content of oxygen than expected. d) Mixed oxides : These oxides are made of two simpler oxides.Which of the following pairs contains neutral oxides ?
Answer» `SO_(2), SO_(3)` `N_(2)O_(3), N_(2)O_(5)` `CO, NO` `Na_(2)O, CAO` ANSWER :C

Discussion

7.	Passage-III : The binary compounds of oxygen with other elements are called oxides. They are classified either depending upon their acid - base characteristics or on the basis of oxygen content. a ) Normal oxides : These oxides which contain oxygen atoms as permitted by the normal oxidation number, i.e., -2. Normal oxide may be acidic, basic, amphotericor neutral.b) Polyoxides : The oxides which contain oxygen atoms different than those permitted by the normal oxidation number of -2. i) Peroxides : Two oxygen atoms are linked to each other and oxygenhas -I oxidation number. They contain (O-O)^(2) unit. ii) Superoxides : These oxides contain (O-O)^(-1) units, i.e., each O-atom has oxidation number -1//2. c ) Suboxides : These contain low content of oxygen than expected. d) Mixed oxides : These oxides are made of two simpler oxides.Which of the following pairs contains mixed oxides?
Answer» `Pb_(3)O_(4), Fe_(3)O_(4)` `MnO_(2), BaO_(2)` `KO_(2)Na_(2)O_(2)` `Mn_(3)O_(4), N_(2)O_(5)` ANSWER :A

Discussion

8.	Passage-III : The binary compounds of oxygen with other elements are called oxides. They are classified either depending upon their acid - base characteristics or on the basis of oxygen content. a ) Normal oxides : These oxides which contain oxygen atoms as permitted by the normal oxidation number, i.e., -2. Normal oxide may be acidic, basic, amphotericor neutral.b) Polyoxides : The oxides which contain oxygen atoms different than those permitted by the normal oxidation number of -2. i) Peroxides : Two oxygen atoms are linked to each other and oxygenhas -I oxidation number. They contain (O-O)^(2) unit. ii) Superoxides : These oxides contain (O-O)^(-1) units, i.e., each O-atom has oxidation number -1//2. c ) Suboxides : These contain low content of oxygen than expected. d) Mixed oxides : These oxides are made of two simpler oxides. Which of the following oxides is paramagnetic in nature?
Answer» `KO_(2)` `BaO_(2)` `H_(2)O` `CO_(2)` ANSWER :A

Discussion

9.	Passage-III : The binary compounds of oxygen with other elements are called oxides. They are classified either depending upon their acid - base characteristics or on the basis of oxygen content. a ) Normal oxides : These oxides which contain oxygen atoms as permitted by the normal oxidation number, i.e., -2. Normal oxide may be acidic, basic, amphotericor neutral.b) Polyoxides : The oxides which contain oxygen atoms different than those permitted by the normal oxidation number of -2. i) Peroxides : Two oxygen atoms are linked to each other and oxygenhas -I oxidation number. They contain (O-O)^(2) unit. ii) Superoxides : These oxides contain (O-O)^(-1) units, i.e., each O-atom has oxidation number -1//2. c ) Suboxides : These contain low content of oxygen than expected. d) Mixed oxides : These oxides are made of two simpler oxides.Which pair of species is referred to as suboxides?
Answer» CO, NO `SO_(2), CAO` `N_(2)O, CO` `S_(2)O, C_(3)O_(2)`. ANSWER :D

Discussion

10.	Passage - II : The solid(A) is a laboratory reagent. Give the following reactions.i) On strongly heating it gives two oxides of sulphur ii) On adding aqueous NaOH solution to its aqueous solution a dirty green precipitate is obtained, which starts turning brown on exposure to air. The two oxides of sulphur are
Answer» `SO_(2), SO_(3)` `SO, SO_(2)` `SO, SO_(3)` `S_(2)O, S_(2)O_(3)` Solution :`FeSO_(4).7H_(2)Ounderset(-7H_(2)O) overset(300^(@)C)to 2FeSO_(4) overset("high T")to Fe_(2)O_(3)+SO_(2)+SO_(3)`. `Fe_(2)(SO_(4))_(3)3NaOH to underset("Dirty GREEN ppt") (2Fe(OH)_(3)+Na_(2)SO_(4))` Oxides are `SO_(2),SO_(3)`.

Discussion

11.	Passage - II : The solid(A) is a laboratory reagent. Give the following reactions.i) On strongly heating it gives two oxides of sulphur ii) On adding aqueous NaOH solution to its aqueous solution a dirty green precipitate is obtained, which starts turning brown on exposure to air. What is compound in dirty green ppt.
Answer» `Ca(OH)_(2)` `Fe(OH)_(2)` `Fe(OH)_(3)` None of these Solution :`FeSO_(4).7H_(2)Ounderset(-7H_(2)O) OVERSET(300^(@)C)to 2FeSO_(4) overset("high T")to Fe_(2)O_(3)+SO_(2)+SO_(3)`. `Fe_(2)(SO_(4))_(3)3NaOH to underset("Dirty green ppt") (2FE(OH)_(3)+Na_(2)SO_(4))` Oxides are `SO_(2),SO_(3)`.

Discussion

12.	Passage - II : The solid(A) is a laboratory reagent. Give the following reactions.i) On strongly heating it gives two oxides of sulphur ii) On adding aqueous NaOH solution to its aqueous solution a dirty green precipitate is obtained, which starts turning brown on exposure to air. The solid A is
Answer» `BaCl_(2)` `FeSO_(4)` `CaSO_(4)` None of these Solution :`FeSO_(4).7H_(2)OUNDERSET(-7H_(2)O) overset(300^(@)C)to 2FeSO_(4) overset("high T")to Fe_(2)O_(3)+SO_(2)+SO_(3)`. `Fe_(2)(SO_(4))_(3)3NaOH to underset("DIRTY green ppt") (2Fe(OH)_(3)+Na_(2)SO_(4))` Oxides are `SO_(2),SO_(3)`.

Discussion

13.	Passage-II : Sulphuric acid is considered as the king of chemicals. The prosperity of any country is measured by the amount of sulphuric acid it consumes. Sulphuric acid is, thus a substance of very great commercial importance as it is used practically in every important industry. This is due to the following properties of sulphuric acid Only carbon is obtained when concentratedH_(2)SO_(4) is added to :
Answer» formic acid cane SUGAR oxalic acid ethyl ALCOHOL Solution :`C_(12)H_(22)O_(11)+H_(2)SO_(4) to 12C+11H_(2)O` cane sugar

Discussion

14.	Passage-II : Sulphuric acid is considered as the king of chemicals. The prosperity of any country is measured by the amount of sulphuric acid it consumes. Sulphuric acid is, thus a substance of very great commercial importance as it is used practically in every important industry. This is due to the following properties of sulphuric acidConcentrated H_(2)SO_(4) cannot be used to prepare HBr or HI from KBr or KI because it :
Answer» reacts too SLOWLY with KBr or KI reduces HBr or HI OxidizesHBr or HI Oxidizes KBr to `KBrO_(3)` or KI to `KIO_(3)`. SOLUTION :Oxidizes HBr (or) HI to `Br_(2) and I_(2)` `2HBr+H_(2)SO_(4) to SO_(2)+2H_(2)O+Br_(2)` `2HI+H_(2)SO_(4) to SO_(2)+H_(2)O+I_(2)`

Discussion

15.	Passage-II : Sulphuric acid is considered as the king of chemicals. The prosperity of any country is measured by the amount of sulphuric acid it consumes. Sulphuric acid is, thus a substance of very great commercial importance as it is used practically in every important industry. This is due to the following properties of sulphuric acidThe formationof nitroglycerine is done by the use of concentrated nitricand concentratedsulphuric acid. The process of conversionof glycerine into nitroglycerine is termed as:
Answer» sulphonation oxidation nitration DEHYDRATION Solution :The MIXTURE of `HNO_(3)` and `H_(2)SO_(4)` is known as nitration mixture. So the PROCESS is known as nitration.

Discussion

16.	Passage-II : Sulphuric acid is considered as the king of chemicals. The prosperity of any country is measured by the amount of sulphuric acid it consumes. Sulphuric acid is, thus a substance of very great commercial importance as it is used practically in every important industry. This is due to the following properties of sulphuric acid Sulphuric acid has very corrosive action on skin because:
Answer» it reacts with proteins it ACTS as an OXIDIZING agent it acts as a dehydrating agent it acts as a dehydrating agent and absorption of WATER is highly exothermic Solution :It acts as dehydrating AGENTAND absorption of water is highly exothermic.

Discussion

17.	Passage-II : Sulphuric acid is considered as the king of chemicals. The prosperity of any country is measured by the amount of sulphuric acid it consumes. Sulphuric acid is, thus a substance of very great commercial importance as it is used practically in every important industry. This is due to the following properties of sulphuric acid Which of the following reactions predict the oxidizing behavior of H_(2)SO_(4)?
Answer» `2HI+H_(2)SO_(4) to I_(2)+SO_(2)+2H_(2)O` `NaCl+H_(2)SO_(4) to NaHSO_(4)+NaHSO_(4)+HCl` `2NaOH+H_(2)SO_(4) to Na_(2)SO_(4)+2H_(2)O` `2PCl_(5)+H_(2)SO_(4) to 2POCl_(3)+2HCl+SO_(2)Cl_(2)` Solution :`2HI+H_(2)SO_(4) to I_(2)+SO_(2)+2H_(2)O`

Discussion

18.	Passage - II : Sulphuric acid is a substance of very great commercial importance as it is used practically in every important industry. This due to the chemical properties of sulphuric acid. This very reaction with metals & non-metals. It has properties of dehydration, oxidation, reduction and sulphonation etc. for example: H_(2)SO_(4)+PCl_(5) to A overset(H_(2)O) to B+C. Where B & C are two strong acids. The compound A is
Answer» <P>`SO_(2)Cl_(2)` `SO_(2)Cl` `ClSO_(3)H` `POCl_(3)` Solution :`H_(2)SO_(4)+PCl_(5)to underset((A))(SO_(2)Cl_(2))+P,SO_(2)Cl_(2)+2H_(2)O to underset((B))(2HCl)+underset((C )) (H_(2)SO_(4))`

Discussion

19.	Passage - II : Sulphuric acid is a substance of very great commercial importance as it is used practically in every important industry. This due to the chemical properties of sulphuric acid. This very reaction with metals & non-metals. It has properties of dehydration, oxidation, reduction and sulphonation etc. for example: H_(2)SO_(4)+PCl_(5) to A overset(H_(2)O) to B+C. Where B & C are two strong acids. The compound C is
Answer» `H_(2)SO_(4)` `HCl` `HOCl_(4)` `H_(2)S_(2)O_(7)` Solution :`H_(2)SO_(4)+PCl_(5)to UNDERSET((A))(SO_(2)Cl_(2))+P,SO_(2)Cl_(2)+2H_(2)O to underset((B))(2HCl)+underset((C )) (H_(2)SO_(4))`

Discussion

20.	Passage - II : Sulphuric acid is a substance of very great commercial importance as it is used practically in every important industry. This due to the chemical properties of sulphuric acid. This very reaction with metals & non-metals. It has properties of dehydration, oxidation, reduction and sulphonation etc. for example: H_(2)SO_(4)+PCl_(5) to A overset(H_(2)O) to B+C. Where B & C are two strong acids. The compound B is
Answer» <P>`POCl_(5)` `HOCl_(4)` `POCl_(3)` `H_(2)SO_(4)` Solution :`H_(2)SO_(4)+PCl_(5)to underset((A))(SO_(2)Cl_(2))+P,SO_(2)Cl_(2)+2H_(2)O to underset((B))(2HCL)+underset((C )) (H_(2)SO_(4))`

Discussion

21.	Passage - II : Sulphur forms hexahalides, tetrahalides, dihalides and monohalides, sulphur forms only hexa fluorides but not hexachlorides, hexa bromides and hexaiodides. Sulphur halides tend to hydrolyse easily. Sulphur hexa fluorides is an exception. Of the oxohalides, the most important are those of sulphur especially sulphur dichloride oxide (Thionyl chloride) SOCl_(2) and sulphurdichloride dioxide (Sulphuryl chloride) SO_(2)Cl_(2) these are also hydrolyse in water SO_(2)Cl_(2) is dissolved in H_(2)O which of the following statement is wrong about the solution
Answer» GIVES WHITE ppt with `BaCl_(2)` in soluble in any acid The solution contain two differenttype of acids a monobasic and dibasic acid The solution can decolourizecan decolourizethe PERMANGANATE The oxidaction states of the elements in `SO_(2)Cl_(2)` do not CHANGE when dissolve in WATER Solution :`SOCl_(2)+H_(2)O to 2HCl +H_(2)SO_(4)`. It does not decolorize `KMnO_(4)`.

Discussion

22.	Passage - II : Sulphur forms hexahalides, tetrahalides, dihalides and monohalides, sulphur forms only hexa fluorides but not hexachlorides, hexa bromides and hexaiodides. Sulphur halides tend to hydrolyse easily. Sulphur hexa fluorides is an exception. Of the oxohalides, the most important are those of sulphur especially sulphur dichloride oxide (Thionyl chloride) SOCl_(2) and sulphurdichloride dioxide (Sulphuryl chloride) SO_(2)Cl_(2) these are also hydrolyse in water SOCl_(2) is dissolved in water which of the following statement is wrong about the solution
Answer» The SOLUTION will give WHITE ppt with baryta WATER soluble in dil.HCl The solution turns the lead acetetepaper to black The solution turns orange dichromate to GREEN The solution is acidic in nature Solution :`SOCl_(2)+H_(2)O to SO_(2)+2HCl`

Discussion

23.	Passage - II : Sulphur forms hexahalides, tetrahalides, dihalides and monohalides, sulphur forms only hexa fluorides but not hexachlorides, hexa bromides and hexaiodides. Sulphur halides tend to hydrolyse easily. Sulphur hexa fluorides is an exception. Of the oxohalides, the most important are those of sulphur especially sulphur dichloride oxide (Thionyl chloride) SOCl_(2) and sulphurdichloride dioxide (Sulphuryl chloride) SO_(2)Cl_(2) these are also hydrolyse in water SF_(6) do not hydrolyse water because
Answer» Due to STRONG S-F bonds which cannot be broken EASILY Because of STERIC hinderance of six fluorine atoms surrounding sulphur `H_(2)O` molecules can not approach sulphur Due to double BOND CHARACTER of 'S-F' bonds because of back bonding All the above Solution :Because of steric hinderance of six fluorine atoms surrounding sulphur `H_(2)O` molecules can not approach sulphur.

Discussion

24.	Passage - I : X+H_(2)SO_(4) to Y, a colourless gas with irritating smell. y+K_(2)Cr_(2)O_(7)+H_(2)SO_(4) to green solution. The compound present in green solution
Answer» `H_(2)SO_(4)` `MnSO_(4)` `Cr_(2)(SO_(4))_(3)` None of these SOLUTION :`underset((x))(Na_(2)SO_(3))+2HCl to 2NaCl +H_(2)O +underset((y))(SO_(2)), K_(2)Cr_(2)O_(7)+3SO_(2)+H_(2)SO_(4) to K_(2)SO_(4)+underset("GREEN")(Cr_(2)(SO_(4))_(3))+H_(2)O`

Discussion

25.	Passage - I : X+H_(2)SO_(4) to Y, a colourless gas with irritating smell. y+K_(2)Cr_(2)O_(7)+H_(2)SO_(4) to green solution. What is Y?
Answer» `SO_(2)` `SO_(3)` `O_(3)` `O_(2)` Solution :`underset((X))(Na_(2)SO_(3))+2HCl to 2NaCl +H_(2)O +underset((y))(SO_(2)), K_(2)Cr_(2)O_(7)+3SO_(2)+H_(2)SO_(4) to K_(2)SO_(4)+underset("Green")(Cr_(2)(SO_(4))_(3))+H_(2)O`

Discussion

26.	Passage - I : X+H_(2)SO_(4) to Y, a colourless gas with irritating smell. y+K_(2)Cr_(2)O_(7)+H_(2)SO_(4) to green solution. What is X?
Answer» `SO_(3)` `SO_(3)^(2-)` `SO_(2)` `OF_(2)` Solution :`underset((X))(Na_(2)SO_(3))+2HCl to 2NaCl +H_(2)O +underset((y))(SO_(2)), K_(2)Cr_(2)O_(7)+3SO_(2)+H_(2)SO_(4) to K_(2)SO_(4)+underset("Green")(Cr_(2)(SO_(4))_(3))+H_(2)O`

Discussion

27.	Passage-I : Whena gas 'A' is passed through dry KOH at low temperature a deep red coloured compound, B and a gas 'C' are obtained. The gas A, on reaction with but -2-ene, followed by treatment with Zn//H_(2)O yields acetaldehyde. Identify A, B & C. What is deep red coloured compound
Answer» `KO_(3)` `O_(3)` `CH_(3)CHO` NONE of these SOLUTION :`2KOH+UNDERSET((A))underset(uarr)(5O_(3))to underset((B))undersetuarr(2KO_(3))+underset((C ))underset(uarr)(5O_(2))+H_(2)O` `A=O_(3), B=KO_(3), C=O_(2)`

Discussion

28.	Passage-I : Metallic sulphates can be obtained by reacting the metals (above hydrogen in ECS), or its oxide, hydroxide or carbonate with dil. H_(2)SO_(4). Group IA metals also form hydrogen sulphates which can be isolated in solid. In general metal sulphates are soluble in water and crystallize with water of crystallization. Sulphates are thermally more stable than nitrates.When BaCl_(2) solution is added in aq. Solution of NaHSO_(4) a white ppt. is obtained which is of:
Answer» `Ba(HSO_(4))_(2)` `BaSO_(4)` `Ba. NaSO_(4)` NONE of these Solution :`BaCl_(2)+2NaHSO_(4) to BaSO_(4)darr`

Discussion

29.	Passage-I : Whena gas 'A' is passed through dry KOH at low temperature a deep red coloured compound, B and a gas 'C' are obtained. The gas A, on reaction with but -2-ene, followed by treatment with Zn//H_(2)O yields acetaldehyde. Identify A, B & C. What is A
Answer» `O_(2)` `O_(3)` `SO_(2)` `CO_(2)` SOLUTION :`2KOH+underset((A))underset(UARR)(5O_(3))to underset((B))undersetuarr(2KO_(3))+underset((C ))underset(uarr)(5O_(2))+H_(2)O` `A=O_(3), B=KO_(3), C=O_(2)`

Discussion

30.	Passage-I : Metallic sulphates can be obtained by reacting the metals (above hydrogen in ECS), or its oxide, hydroxide or carbonate with dil. H_(2)SO_(4). Group IA metals also form hydrogen sulphates which can be isolated in solid. In general metal sulphates are soluble in water and crystallize with water of crystallization. Sulphates are thermally more stable than nitrates.Select the stable hydrogen sulphate which can be obtained in solid state:
Answer» `KHSO_(4)` `CaHSO_(4)` `FeHSO_(4)` All of these SOLUTION :Only `KHSO_(4)` is EXIST in SOLID STATE.

Discussion

31.	Passage-I : Metallic sulphates can be obtained by reacting the metals (above hydrogen in ECS), or its oxide, hydroxide or carbonate with dil. H_(2)SO_(4). Group IA metals also form hydrogen sulphates which can be isolated in solid. In general metal sulphates are soluble in water and crystallize with water of crystallization. Sulphates are thermally more stable than nitrates.Which metal sulphate will decompose into SO_(3) and metal oxide when heated:
Answer» `K_(2)SO_(4)` `Li_(2)SO_(4)` `FeSO_(4)` `BaSO_(4)` Solution :`FeSO_(4). 7II_(2)O UNDERSET(-7H_(2)O)overset(300^(@)C)to 2FeSO_(4) overset("HIGH T")to Fe_(2)O_(3)+SO_(2)+SO_(3)`

Discussion

32.	Passage-I : Metallic sulphates can be obtained by reacting the metals (above hydrogen in ECS), or its oxide, hydroxide or carbonate with dil. H_(2)SO_(4). Group IA metals also form hydrogen sulphates which can be isolated in solid. In general metal sulphates are soluble in water and crystallize with water of crystallization. Sulphates are thermally more stable than nitrates.Select the thermally more stable salt from given pairs: A) Al_(2)(SO_(4))_(3)""B)Al(NO_(3))_(3)""C) Ca(NO_(3))_(2)""D) CaSO_(4)""E )FeSO_(4)""F) Fe(NO_(3))_(2)
Answer» A,C,E A,D,E B,C,F B,D,E Solution :`Al_(2)(SO_(4))_(3), CaSO_(4), FeSO_(4)`

Discussion

33.	Passage-I : Metallic sulphates can be obtained by reacting the metals (above hydrogen in ECS), or its oxide, hydroxide or carbonate with dil. H_(2)SO_(4). Group IA metals also form hydrogen sulphates which can be isolated in solid. In general metal sulphates are soluble in water and crystallize with water of crystallization. Sulphates are thermally more stable than nitrates.Select the sulphate which is water soluble:
Answer» `Hg_(2)SO_(4)` `SrSO_(4)` `Ag_(2)SO_(4)` `Rb_(2)SO_(4)` Solution :Alkali metal SULPHATE are soluble in `H_(2)O`.

Discussion

34.	Passage-I : Metallic sulphates can be obtained by reacting the metals (above hydrogen in ECS), or its oxide, hydroxide or carbonate with dil. H_(2)SO_(4). Group IA metals also form hydrogen sulphates which can be isolated in solid. In general metal sulphates are soluble in water and crystallize with water of crystallization. Sulphates are thermally more stable than nitrates. Among the metals given below, which metal will not give its sulphate on treatment with dil. H_(2)SO_(4).
Answer» Ni Cr Co Cu SOLUTION :Copper dissolved in HOT dilute ACIDS HCl (or) `H_(2)SO_(4)` only in presence of air (or) `O_(2)`. `Cu+underset("(dil.)")(H_(2)SO_(4))+(1)/(2)O_(2) to CuSO_(4)+H_(2)O`

Discussion

35.	Passage - I : A yellow powder 'x' is burnt in a steam of Fluorine to obtain a colourlessgas 'y' which is thermally stable and chemically inert its molecule has octahedral geometry another colourless gas 'z' with same constituent atoms as that of 'y' is obtained when sulphur dichloride is heated with sodium fluoride. It's molecule has trigonal bi-pyramidal geometry The colourless gas 'z' is
Answer» `SF_(4)` `SF_(6)` `S_(4)F_(4)` NAF SOLUTION :`Z=SF_(4), 4SCl_(2)+4NaF to 2SF_(4)+4NaCl`

Discussion

36.	Passage - I : A yellow powder 'x' is burnt in a steam of Fluorine to obtain a colourlessgas 'y' which is thermally stable and chemically inert its molecule has octahedral geometry another colourless gas 'z' with same constituent atoms as that of 'y' is obtained when sulphur dichloride is heated with sodium fluoride. It's molecule has trigonal bi-pyramidal geometry The colourless gas 'y' is
Answer» `SF_(4)` `SF_(6)` NAF `S_(2)F_(2)` Solution :`y=SF_(4)+F_(2)to SF_(6)`

Discussion

37.	Passage - I : A yellow powder 'x' is burnt in a steam of Fluorine to obtain a colourlessgas 'y' which is thermally stable and chemically inert its molecule has octahedral geometry another colourless gas 'z' with same constituent atoms as that of 'y' is obtained when sulphur dichloride is heated with sodium fluoride. It's molecule has trigonal bi-pyramidal geometry The yellow powder 'x' is
Answer» `Fe_(2)Cr_(2)O_(7)` `FeCl_(3)` `K_(2)CrO_(4)` S Solution :`S+3F_(2) overset(Delta)to SF_(6)(x)` (Octahedral, CHEMICALLY INSERT)

Discussion

38.	Partition coefficient of an organic compound (A) in 50 mL. 20 betweenn ether and water. 5 g of (A) is 50 mL. water is shaken with 50 mL ether. (A) extracted into ether is
Answer» 4.0g 4.2g 4.6g 4.8g Answer :D

Discussion

39.	Partin of gold may be done with:
Answer» SULPHURIC acid SODIUM hydroxide borax Chlorine`(CL)_(2)` ANSWER :A,D

Discussion

40.	Particulates (< 10^(-6) m size )remaining suspended in air indefinitely and transported by wind currents are called :
Answer» Fumes Mist Aerosols Soot ANSWER :C

Discussion

41.	Particulate air pollutants are finely divided solids and liquids. Which of the given is not a 'particulate' ?
Answer» DUST and mists Smoke and fumes Photochemical SMOG and soot None of the above Answer :A

Discussion

42.	Particles which are present at every corners as well as present on centers of every faces of unit cells are known as……….
Answer» Body CENTER End center FACE center Primitives Answer :C

Discussion

43.	Partial reduction of fructose with sodium amalgam and water produces ………..and ………….which are …………..atsecondcarbon.
Answer» SOLUTION :SORBITOL,MANNITOL, EPIMERS

Discussion

44.	Particles of which of the following donot pass through ultra filter paper
Answer» COLLOIDS only True solutions SUSPENSIONS only Colloids and SUSPENSION ANSWER :D

Discussion

45.	Partial pressures of A, B, C and D on the basis of gaseous system A+2B hArr C+3D are =0.20,B=0.10, C=0.30 and D=0.50 atm. The numerical value of equilibrium constant is
Answer» `11.25` `18.75` 5 `3.75` Solution :`A+2BhArrC+3D` `K=([pC][PD]^(3))/([PA][pB]^(2))=(0.30xx0.50xx0.50xx0.50)/(0.20xx0.10xx0.10)=18.75`

Discussion

46.	Practical pressure utilised in contact tower
Answer» 2 BAR `0.2` bar 20 bar 200 bar ANSWER :A

Discussion

47.	Partial pressure of solvent in solution of nonvolatile solute isgiven by equation,
Answer» `P=x_(2)P^(@)` `P^(@)=xP` `P=x_(1)P^(@)` `P^(@)=x_(1)P` ANSWER :A::C

Discussion

48.	Partial reduction of acetic acid in the presence of LiAlH_(4) results in the formation of _______.
Answer» ethane ethanol ethene ethyne Answer :B

Discussion

49.	Partial pressue of O_(2) in the reaction 2Ag(2)O((s))hArr4A_((s))+O_(2(g)) s
Answer» <P>`K_(p)` `sqrt(K_(p))` `3sqrt(K_(p))` `2K_(p)` Solution :`2Ag_(2)O_((s))hArr2Ag_((s))+O_(2(g))` For this REACTION, `K_(p)=P_(O2)(Ag_(2)O and AG "are in solid state")`

Discussion

50.	Partial oxidation of methane gives:
Answer» HCHO HCOOH `H_2O`and`CO_2` CO and `H_2O` ANSWER :D

Discussion

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