Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Oxidation number of xenon in all the compounds XeO_(2)F_(2).XeF_(6).XeO_(3)andXeOF_(4) is :

Answer»

`+6`
0
`+2`
not the same in all .

ANSWER :D
Discussion
2.

Oxidation number ofnitrogen in (NH_4)_2SO_4 is

Answer»

-1/3
-1
+l
-3

Solution :(d) `(NH_4)_2,SO_4`, is SPLIT into IONS. `NH_(4)^(+)`. Let O.N. of N be x then, `1 XX (x) + 4 xx (+1)=1, therefore = -3`
Discussion
3.

Oxidation number ofsulphur in SO,SO_(2)SOCl_(2)andNa_(2)S_(4)O_(6) is respectively.

Answer»

`+2,+4,+6,+5`
`+2` in all compounds
`+2,+4,+4,+3`
`+2,+4,+4,+2.5`

ANSWER :D
Discussion
4.

Oxidation number of the central iron atom in the complex Fe_(4)[Fe(CN)_(6)]_(3) is.

Answer»


Solution :`OVERSET(+3)(Fe_(4))[overset(+2)(FE)(CN)_(6)]_(3)`
Discussion
5.

Oxidation number of sulphur in Na_2SO_4 is:

Answer»

`+2`
`+4`
`+6`
`-2`

ANSWER :C
Discussion
6.

Oxidation number of sulphur in sulphuryl chloride is

Answer»

`+4`
`+6`
`+2`
`+3`

Solution :Sulphuryl chloride is `SO_(2)Cl_(2)`
`S + 2O + 2Cl=` zero
`therefore x + 2(-2) + 2(-1)=0`
`therefore x-4 -2=0`
`therefore x-6=0, therefore x=+6`
Discussion
7.

Oxidation number of S in SO_(4)^(2-)

Answer»

`+6`
`+3`
`+2`
`-2`

SOLUTION :`x=8-2=+6`
Discussion
8.

Oxidation number of solution in sodium amalgam (Na/Hg) is

Answer»

0
`+1`
`-1`
`+2`

SOLUTION :Sodium EXISTS in ELEMENTAL form
Discussion
9.

Oxidation number of sodium is sodium amalgam is :

Answer»

`+2`
`+1`
`-3`
Zero

Answer :D
Discussion
10.

Oxidation number of S S_2CI_2 is:

Answer»

`+1`
`+6`
ZERO
`-1`

ANSWER :A
Discussion
11.

Oxidation number of S in S_2O_3^(2-) :

Answer»

`+2`
`-2`
4
Zero

Answer :A
Discussion
12.

Oxidation number of S in H_2SO_5 is:

Answer»

`+8`
`+2`
`+6`
`+4`

Answer :C
Discussion
13.

Oxidation number of P in PO_(4)^(3-),S" in "SO_(4)^(2-)and that of Cr in Cr_(2)O_(7)^(2-)are respectively

Answer»

`+3,+6and+5`
`-3,+6and+6`
`+5,+3and+6`
`+5,+6and+6`

ANSWER :D
Discussion
14.

Oxidation number of P in P_2O_7^(4-) :

Answer»

`+3`
`+4`
`+5`
`+6`

Answer :C
Discussion
15.

Oxidation number of P in PO_(4)^(3-) ion is :

Answer»

`-3`
`+7`
`+5`
`+3`.

SOLUTION :`x-2xx4=-3`
`thereforex=+5`
Discussion
16.

Oxidation number of oxygen in ozone (Q_(3)) is

Answer»

`+3`
`-3`
`-2`
0

Solution :MOLECULE and free atoms show zero oxidation STATE `O_(3)` is a molecule shows zero oxidation state.
Discussion
17.

Oxidation number of oxygen in F_(2)OandH_(2)O_(2) is respectively.

Answer»

`-2 and +2`
`+2AND -1`
`-2` in both
`+2 and -2`

ANSWER :B
Discussion
18.

Oxidation number of nitrogen in AgNO_3 is :

Answer»

`+5`
`-3`
`+3`
`-2`

ANSWER :A
Discussion
19.

Oxidation number of N in NOCl is

Answer»

`+2`
`+4`
`+3`
`+1`

Answer :C
Discussion
20.

Oxidation number of Mn in K_2MnO_4 and MnSO_4 are respectively :

Answer»

`+7` and `+2`
`+6` and `+2`
`+5` and`+2`
`+2`and`+6`

ANSWER :B
Discussion
21.

Oxidation number of iodine varies from

Answer»

`-1` to `+1`
`-1` to `+7`
`+3` to `+5`
`-1` to `+5`

Solution :IODINE SHOWS -1 to +7 oxidation STATE.
Discussion
22.

Oxidation number of iron in K_(4)[Fe(CN)_(6)] is :

Answer»

`+3`
`+2`
0
`+1`.

ANSWER :B
Discussion
23.

Oxidation number of iodine in IO_(3),IO_(4),KI andI_(2)respectively are

Answer»

`-1,-1,0,+1`
`=3,+5,+7,0`
`+5,+7,-1,0`
`-1,-5,-1,0`

ANSWER :C
Discussion
24.

Oxidation number of iodine in IF_3 is:

Answer»

-5
+3
-1
+1

Answer :B
Discussion
25.

Oxidation number of Fe in the compound Na_4[Fe(CN)_5NO](SO_4).2H_2O is:

Answer»

0
`+1`
`+2`
`+3`

Answer :C
Discussion
26.

Oxidation number of Fe in Na_2[fe(CN)_5NO] is

Answer»

2
1
3
-2

Answer :A
Discussion
27.

Oxidation number of Fe in K_3[Fe(CN)_6] is:

Answer»

`+3`
`+2`
`+10`
1

Answer :A
Discussion
28.

Oxidation number of F in Mg_(2)P_(2)O_(7) is

Answer»

`+3`
`+2`
`+5`
`-3`

SOLUTION :`Mg_(2) overset(**)(P_(2))O_(7)`
`4+2x-2xx7=0, 2x=14-4=10`
`2x=10, x=10/2=+5`.
Discussion
29.

Oxidation number of Fe inFe_(0.94)O is:

Answer»

200
`200//94`
94//200
None

Answer :B
Discussion
30.

Oxidation number of Cl in Cl_(2) O_(6)compound.

Answer»


Solution : `2X + ( -2)6 = 0, 2x = 12, x = 6` o.n OF CL in `Cl_(2) O_(6) ` is ` = + 6`
Discussion
31.

Oxidation number of Ca in CaOCI_2 is:

Answer»

- 1 and + 1
2
-2
None

Answer :A
Discussion
32.

Oxidation number of Cr in CrO_5 is:

Answer»

6
10
4
8

Answer :A
Discussion
33.

Oxidation number of Cl in CaOCl_(2) is

Answer»

`-2`
`-1 and +1`
`+2`
NONE of these

Answer :B
Discussion
34.

Oxidation number of Cl in NOClO_(4) is

Answer»

-5
-7
`+5`
`+7`

ANSWER :D
Discussion
35.

Oxidation number of chlorine in perchloric acid is :-

Answer»

`+1`
`+3`
`+5`
`+7`

ANSWER :D
Discussion
36.

Oxidation number of chromium in K_(2)Cr_(2)O_(7) is

Answer»

-4
`+3`
`+6`
`+2`

Answer :C
Discussion
37.

Oxidation number of chromium in chromyl chloride is

Answer»

`+2`
`+3`
`+4`
`+6`

ANSWER :D
Discussion
38.

Oxidation number of chlorine in Cl_(2)O,Cl_(2)andClO_(3)^(-) is respectively.

Answer»

`+1,-1,+5`
`+1,0,-1`
`-1,0,-1`
`+1,0+5`.

ANSWER :D
Discussion
39.

Oxidation number of chlorine in HOCl is

Answer»

`+2`
`+6`
`+1`
`+5`

Answer :C
Discussion
40.

Oxidation number of chlorine in chlorine heptaoxide is :

Answer»

`+1`
`+4`
`+6`
`+7`

ANSWER :D
Discussion
41.

Oxidation number of central metal atom in the complex formed during the exraction of Ag in the Mac,Arthur forrest process.

Answer»


ANSWER :1
Discussion
42.

Oxidation number of central atom in the stable volatile complex formed in the Mons's Method

Answer»


ANSWER :0
Discussion
43.

Oxidation number of carbon is HCHO is ,

Answer»

0
2
3
4

Answer :A
Discussion
44.

Oxidation number of carbon of carbon in carbon suboxide is :

Answer»

`+2//3`
`+4//3`
`+4`
`-4//3`

ANSWER :B
Discussion
45.

Oxidation number of carbon in KCN is :

Answer»

`+2`
`-2`
`+1`
`+3`

ANSWER :A
Discussion
46.

Oxidation number of carbon is correctly given for

Answer»

`{:("Compound","O.No."),(HN-= C , +2):}`
`{:("Compound","O.No."),(H-C-=N , +4):}`
`{:("Compound","O.No."),(C C I_4, +4):}`
`{:("Compound","O.No."),(C_6H_(12) O_6, 0):}`

Solution :InJ+HNCit is+2, in `C C I_4`it is+4and in`C_6H_(12)O_6` it ISZERO
Discussion
47.

Oxidation number of C in CH_(3)OH,CH_(2)O,COOH and C_(2)H_(2) is respectively :

Answer»

`-2, 0, +2, -1`
`+2,0,+2,-2`
`-2,0,+2,0`
`-2,-4,+2,-2`

ANSWER :A
Discussion
48.

Oxidation number and coordination number of silver in Tollen's reagent respectively are

Answer»

1, 1
2, 1
2, 2
1, 2

Solution :Tollen's reagent contains silver-ammonia COMPLEX ION, `[AG(NH_(3))_(2)]^(+)`. Thus, oxidation number is + 1 and coordination number is 2.
Discussion
49.

Oxidation means,

Answer»

ADDITION of oxygen
increase in OXIDATION state
loss of electron
all of these

Answer :D
Discussion
50.

Oxidation method is used for refining of:

Answer»

Pb
Cu
Hg
All

Answer :D
Discussion