Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

On mixing a certain alkane with chlorine and irradiating it with ultraviolet light, it forms only one monochloroalkaane. This alkane could be

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pentane
isopentane
NEOPENTANE
propane

Solution :In neopentane all the H ATOMS are same `(1^(@))`.
`CH_(3)-underset(CH_(3))underset(|)OVERSET(CH_(3))overset(|)C-CH_(3)`
2.

On mixing 10 mL of carbon tetrachloride with 10 mL of benzene the total volume of the solution is:

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`gt20 ML`
`lt20 mL`
`=20 mL`
Cannot be predicted

Answer :C
3.

On mixing 1 mole of C_(6)H_(6)(P^(@)=42mm) and 2 mole of C_(7)H_(8)(P^(@)=36mm) one can conclude

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total VAPOUR PRESSURE of mixture =38mm
MOLE fraction of vapours of `C_(6)H_(6)` above liquid mixture `=(7)/(19)`
positive DEVIATION from Raoult's law
ideal solution of two

Answer :A::B::D
4.

On mixing 10 mL of acetone with 40 ml of chlorofrom, the total volume of the solution is:

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`LT 50 ML`
`GT 50 ml`
`=50 mL`
Cannot be predicted

Answer :A
5.

On mixing 1 mole of C_(6)H_(6) (P^(0) = 42 mm) and 2 mole of C_(7)H_(8) (P^(0) = 36 mm), one can conclude

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total VAPOUR pressure of MIXTURE = 38 mm
mole FRACTION of vapours of `C_(6)H_(6)` above liquid mixture `= (7)/(19)`
positive deviation from RAOULT's law
ideal solution of two

Answer :A::B::D
6.

On mixing 1 mole of C_(6)H_(6) (P^(@) = 42 mm) and 2 mole of C_(7)H^(6) (P^(@) = 36 mm). One can conclude

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total vapour pressure of MIXTURE = 38 mm
mole FRACTION of vapours of `C_(6)H_(6)` above liquid mixture `=7/19`
positive deviation from RAOULT's law
Ideal solution of TWO

Answer :A::B::D
7.

On litre of 0.15 M Na_(2)SO_(3) aqueons solution is mixed with 500 mL of 0.2 M K_(2)Cr_(2)O_(7) aqueous solution in acid medium. What is the number of moles of K_(2) Cr_(2)O_(7) remaining in the solution after the reaction ?

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0.1
0.0125
0.025
0.05

Solution :When `0.15 M Na_(2)CO_(3)` (1L) mixed with `0.2 M K_(2)Cr_(2)O_(7)(5L)` than TOTAL molarity (M)
`M=(M_(1)V_(1)+M_(2) V_(2))/(V_(3))`
`M=(0.15xx1+0.2xx0.5)/(1 cdot 5)`
M=0.15 mol/L
Remaining mole of `K_(2) Cr_(2)O_(7) =0.2-0.15`
`=0.05` mol/L
8.

On long standing bleaching powder undergoes auto oxidation and converts into

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CALCIUM CHLORIDE `+` Calcium perchlorate
Calcium chloride `+` Calcium chlorate
Calcium chloride `+` Chloride
Calcium chloride `+` Chloride CHLORITE

ANSWER :B
9.

On long exposure to air ethanol becomes sour in taste, because of -

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Bacteria
Formation of FORMIC acid
Formation of ACETIC acid due to oxidation
None of these

Solution :Formation of acetic acid due to oxidation
10.

On Kumbh Mela, Solar Eclipses, festivals and other religious/social events, fairs are held on the banks of holy ponds/rivers for some stipulated days. Lacs of people participate in these fairs to pay homage to their deities. For the convenience of the pilgrims, make-shift, toilets are made in the 'Fair Area' by the district administration. in and around these toilets, a white powder is often, sprinkled. Read the above passage and answer the following questions:

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SOLUTION :(i). The common NAME of the COMPOUND contained in the white powder is p,p'-dichlorodiphenyltrichloroethane abbreviiated as DDT. its CHEMICAL name is 2,2-bis (4-chlorophenyl)-1,1,1-trichloroethane. it is prepared by the action of conc. `H_(2)SO_(4)` on a mixture of chlorobenzene and chloral.
(ii) it is used to kill mosquitoes, LICE and other insects which spread diseases.
11.

On increasing the temperature , the rate of the reaction increases because of

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Decrease in the NUMBER of collisions
Decrease in the energy of activation
Decrease in the number of ACTIVATED MOLECULES
Increase in the number of effective collisions

Solution :Increase in the RATE of reaction is DETERMINED by the increase in the number of effective collisions .
12.

On increasing the temperature ,the rate of the reaction increases because of …..

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DECREASE in the NUMBER of collisions
decrease in the ENERGY of activation
decrease in the number of ACTIVATED molecules
increase in the number of EFFECTIVE collisions.

Answer :D
13.

On increasing the temperature, the rate of reaction increases because

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the activation ENERGY of the REACTION increases
the activation energy of the reaction decreases
at HIGHER temperature, the fraction of molecules with energies greater than the activation energy increases.
CONCENTRATION of the REACTING molecules increases.

Solution :at higher temperature, the fraction of molecules with energies greater than the activation energy increases.
14.

On increasing the temperature, the pKw

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INCREASE
Decrease
Remains constant
May increase or decrease

Answer :B
15.

On increasing the temperature by 10 K in the case of slow reactions:

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No. of COLLISIONS get DOUBLED
Value of rate constant increase
Energy of activation INCREASES
None of the above

Answer :D
16.

On increasing temperature , surface tension of water

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Increases
Decreases
Remains constant
Show IRREGULAR behaviour

Answer :B
17.

On increasing temperature, activation energy for a reaction decrease. Why?

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SOLUTION :ACTIVATION ENERGY and temperature are inversely proportional to each other.
18.

On increasing temperature, the value of Henry's constant ………

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decreases
increases
Remains constant.
uncertain

Solution :With increase in TEMP (T), `K_(H)` will also increase and solubility of GASEOUS solute decreases.
19.

On increasing temparature of the reacting system by 10 degrees, the rate of reaction almost doubles. The most appropriate reason for this is :

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COLLISION frequencyincreases
actevating ENERGY decreases with increase in temparature
the fraction of molecules having energy EQUAL to threshould energy or more increases
the value of threshold energy decreases.

Answer :C
20.

On increasing pressure, ice melts at a tempreatue lower than its usual melting point because

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the BONDS break, under PRESSURE
pressure GENERATES heat
ICE is less DENSER than water
in the fixed ratio with that of lower layer.

Solution :On applying pressure, intermolecular hydrogen bonds in ice breadk.
21.

On increasin g the tempearture by 10K in the case of slow reactions

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number of collisions get doubled
value of rate CONSTANT increasex
energy of activation INCREASES
none

Solution :Rate of reaction `PROP` TEMPERATURE.
22.

On igniting Fe_(2)O_(3) at 1400^(@)C, the product obtained is

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`Fe_(2)O_(3)` melts
FeO
`Fe_(3)O_(4)`
metallic iron

ANSWER :D
23.

On hydrolysis with dil. H_2SO_4, starch and cellulose give 'X' and 'Y'. Then 'X' and 'Y' are a pair of

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ENANTIOMERS
Anomers
Functional isomers
Homologues

Answer :B
24.

On hydrolysis , which produces only glucose

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GALACTOSE
maltose
Sucrose
None

Solution :`UNDERSET("Maltose")(C_(12)H_(22)O_(11))+H_(2)O underset("Hydrolysis")tounderset("Glucose")(C_(6)H_(12)O_(6))+underset("Glucose")(C_(6)H_(12)O_(6))`
25.

On hydrolysis of starch, we finally get

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GLUCOSE
fructose
both
sucrose

Solution :Glucose only.
26.

On hydrolysis, PCl_(5) gives ………………. .

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`H_(3)PO_(3)` on heating undergoes SELF - OXIDATION reduction as :

`PH_(3)`
`H_(3)PO_(4)`
`POCl_(3)`

Solution :`H_(3)PO_(3)` on heating undergoes self - oxidation reduction as :
27.

On hydrolysis of starch by dilute acids we get finally

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GLUCOSE and fructose
glucose
fructose
sucrose

Answer :B
28.

On hydrolysis of salts of strong acid and strong base, the solution obtained is neutral.Justify your answer with a suitable example.

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Solution :Let us consider the REACTION between `NaOH` and NITRIC acid to give sodium nitrate and water.
`NaOH_((aq))+HNO_(3(aq)) to NaNO_(3(aq))+H_2O(I)`
The salt `NaNO_3` completely dissociation in water to produce `Na^+ and NO_3^-` ions.
`NaNO_(3(aq)) to NO_((aq))^(+)+NO_(3(aq))^-`
Water dissociation to a small extent as
`H_2O(I) hArr H_((aq))^(+)+OH_((aq))^-`
Since `[H^+]=[OH^-]`,water is neutral `NO_3^-` ion is the conjugate base of the strong acid `HNO_3` and hence it has no tendency to react with `H^+`
Similarity, `Na^+` is the conjugate acid of the strong base `NaOH` and it has no tendency to react with `OH^-`
it means that there is no hydrolysis. In such cases `[H^+]=[OH^-] PH` is maintained and, THEREFORE, the solution is neutral .
29.

On Hydrolysis of phosphorus oxychloride which acid is formed ?

Answer»

`H_(3)PO_(3)`
`H_(3)PO_(4)`
`H_(3)PO_(2)`
`HPO_(3)`

Solution :`underset("Phosphorus oxy-chloride")(H_(3)PO_(4) + 3H_(2)O (g)) to underset("MOISTURE")(3HCl)(aq) + underset("Phosphoric acid")(H_(3)PO_(4))(aq) + POCl_(3)(g)`
30.

On hydrolysis of a "compound", two compounds, are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollen's reagent and Fehling's solution The "Compound: is

Answer»

`CH_(3)CH_(2)CH_(2)NC`
`CH_(3)CH_(2)CH_(2)CN`
`CH_(3)CH_(2)CH_(2)ON=O`
`CH_(3)CH_(2)CH_(2)CON(CH_(3))_(2)`

Solution :HYDROLYSIS gives `CH_(3)CH_(2)CH_(2)NH_(2)+ HCOOH` and `HCOOH` gives Tollen's reagent TEST.
31.

On hydrolysis, NCl_(3) gives NH_3 and HOCl while PCl_3 gives H_3PO_3 and HCl - explain.

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Solution :The acidity of a MOLECULE DEPENDS on BOND polarity of central atom and hydrogen. GREATER the polarity, higher will be the acidity. The polarity of bond depends on the electronegativity of the central atom. Since, S is more ELECTRONEGATIVE then p, `H_2S` is more acidic than `PH_3`
32.

On hydrolysis nitro ethane gives

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METHYL AMINE and HYDROXYL amine
acetic ACID and methyl amine
acetic acid and hydroxyl amine
formic acid and hydroxyl amine

Answer :C
33.

On hybridisation of one s and one p orbital we get

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THREE orbitals in plane
FOUR orbitals in plane
Two MUTUALLY perpendicular orbitals
Two orbitals at 180 degree

Answer :D
34.

On hydrolusis, all lipids yield

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Monocarboxylic acids
Monohydric alcohols
Monohaloalkanes
Enzymes

Answer :A
35.

On heating a salt with NaOH, smell of NH_3 is obtained, The salt contains:

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`NH_4^+`
`NO_3^-`
`NO_2^-`
`CH_3COO^-`

ANSWER :A
36.

On heating ZnCl_2.2H_2O the compound obtained is:

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`ZnCl_2`
ZN(OH)CL
`Zn(OH)_2`
ZnO

Answer :B
37.

On heating ZnCl_(2).2H_(2)O, the compounds obtained is

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`ZnCl_(2)`
`Zn(OH)_(2)`
`ZNO`
`ZnH_(2)`

Answer :B::C
38.

On heating with P_(2)O_(5) , acetic acid gives :

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ACETONE
ACETIC anhydride
Acetaldehyde
Ethyl acetate.

Answer :B
39.

On heating with soda-lime, salicylic acid gives

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Phenol
Benzoic acid
Sodium salicylate
Benzene

Answer :A
40.

On heating with conc.H_2SO_4 sucrose gives:

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CO and `CO_2`
CO and `SO_2`
`CO,CO_2`and`SO_2`
NONE of the above

Answer :D
41.

On heating with concentrated NaOH solution in an inert atmosphere of CO_(2) , white phosphorus gives a gas. Which of the following statement is incorrect about the gas ?

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It is highly poisonous and has smell like ROTTEN fish.
It's SOLUTION in water decomposes in the PRESENCE of light.
It is more basic than `NH_3`.
It is less basic than `NH_3`.

Solution :`PH_(3)` is less basic than `NH_(3)`
`P_(4)+ 3NaOH + 3H_(2)O to PH_(3) + 3NaH_(2)PO_(2)`
42.

On heating with concentrated NaOH solution in an inert atmosphere of CO_2, white phosphorus gives a gas. Which of the following statements is incorrect about the gas ?

Answer»

It is highly poisonous and has SMELL like rotten fish.
It's solution in WATER DECOMPOSES in the PRESENCE of light.
It is more basic than `NH_3`.
It is less basic THATN `NH_3`

Solution :White phosphorus on heating with NaOH gives `PH_3` which is less basic than ammonia.
43.

On heatingwith concentratedNaOH solution in an inert atmosphere of CO_(2) white phorusgivesa gas . Which of the following statementsis incorrect about the gas ?

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It ismore basicthan `NH_(3)`
Its solution in water decomposes in the presence of light
It is LESS basic than `NH_(3)`
It is highly poisonnous and has smell like rotten fish .

Solution :`P_(4) +3NOH+3H_(2)O overset (Delta) underset (CO_(2)) to 3NaH_(2)PO_(2)underset ("Phosphine")( +PH_(3) uarr)`
`PH_(3)`is less basic than `NH_(3)` as the electron DENSITY is diffused over the LARGER phosphorus atom .
44.

On heating with concentrated NaOH solution in an inert atmosphere of CO_(2), white phosphorus gives a gas. Which of the following statement is incorrect about the gas ?

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It is highly poisonous and has smell like rotten fish
It's solution in WATER decomposes in the PRESENCE of light
It is more BASIC than `NH_(3)`
It is less basic than `NH_(3)`

Solution :`PH_(3)` is produced which is less basic than `NH_(3)`, i.e., OPTION (d) is incorrect.
45.

On heating with concentration NaOH solution in an inert atmosphere of CO_2, white phosphorous gives a gas. Which of the following statement is incorrect about the gas ?

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It is highly poisonous and has SMELL like rotten fish.
It is less basic than `NH_(3)`.
Its solution in WATER decomposes in the PRESENCE of light.
It is more basic than `NH_(3)`.

Answer :D
46.

on heating with CHCl_(3) and alcoholic KOH gives foul smell of

Answer»




ANSWER :C
47.

On heating with conc. HNO_3 proteins give yellow colour. This test is called

Answer»

OXIDISING test
Xanthoproteic test
Hoppe.s test
Acid BASE test

Answer :B
48.

On heating with aqueous alkali,chloroform yields:

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HCHO
HCOOH
`CH_3OH`
`CO_2` and `H_2O`

ANSWER :B
49.

On heating vapours of S_(8)(g) decomposes to S_(2)(g). Due to this, the van-der Waal's constant 'b' for the resulting gas

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INCREASES
DECREASES
REMAINS same
change UNPREDICTABLY

SOLUTION :N//A
50.

On heating two molecules of urea, a gas evolves along with formation of biuret. Identity the gas :

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CO
`NH_3`
`CO_2`
`H_2`

ANSWER :B