Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the last decades, most serious nuclear reactor accident created MIC gas tragedy in

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Russia (1990) and Bhopal (1996)
Ucraine (1986) and Bhopal (1984)
Bhopal (1994) and Russia (1990)
Ucraine and USA (1984)

Solution :Bhopal gas tragedy occurred on 3rd Dec. 1984 DUE to leakage of methyl isocyanate creating air POLLUTION and causing death of about 2500 PERSONS. Chernobyl DISASTROUS tragedy occurred on April 26, 1986 due to explosion at chernobyl nuclear power station resulting huge amount of radioactive clouds in the Ukraine atmosphere.
Discussion
2.

In the Lassaigne's test the sulphur present in the organic compound first changes into?

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`Na_2SO_3`
`CS_2`
`Na_2SO_4`
`Na_2S`

ANSWER :D
Discussion
3.

In the Lassaigne's test, one of the organic compounds gave red colour with FeCl_(3). Compound can be:

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`Na_(2)S`
`NH_(2)C SNH_(2)`
`C_(6)H_(6)CL`
`NaCl`

Solution :In the Lassaigne's test `NH_(4)C SNH_(2)` GAVE red COLOUR with`FeCl_(3)`.
Discussion
4.

In the Lassaigne's test, one of the organic compound X gives blood red colour with FeCl_(3). Compound X, when fused with sodium metal forms compound Y. Molecular mass of compound Y is

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Solution :COMPOUND `Y` is `rArr NASCN`
Molecular MASS of `NaSCN = 23+32+12+14 = 81`
Discussion
5.

In the Lassaigne's test for the detection of nitrogen in an organic compound, the appearance of blue coloured compound is due to

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FERRIC FERRICYANIDE
FERROUS ferricyanide
ferric FERROCYANIDE
ferrous ferrocyanide.

Answer :C
Discussion
6.

In the laboratory, sodium chloride is made by burning sodium in the atmosphere of chlorine. The salt obtained is yellow is colour. The cause of yellow colour is

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presence of`NA^(+)` ions in the crystal lattice
presence of `Cl^(-)` ions in the crystal lattice
presence OFELECTRONS in the crystal lattice
presence of face CENTRED cubic crystal lattice.

Solution :Yellow COLOUR on heating NaCl in presence of Na is due to presence ofelectrons in anion vacancies (F-Centre).
Discussion
7.

In the following questions a statement of Assertin (A) followed by a statement of Reason (R) is give. Choose the correct answer out of the following choices. Assertion (A):

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(A) and (R) both are CORRECT statement and (R) is correct explanation for (A)
(A) and (R) both are correct statements but (R) is not correct explanation for (A)
(A) is correct statement but (R) is wrong statement.
(A) and (R) both are incorrect statements

Solution :Correct assertion: Glycine MAY or may not be taken through diet. Correct reason: Glycine is not an ESSENTIAL `ALPHA`-amino ACID
Discussion
8.

In the laboratory method of preparation of dioxygen by thermal decomposition of potassium chlorate the catalyst used is

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IRON fillings
Manganese dioxide
PLATINUM
Copper CHLORIDE

Solution :`2KClO_3 undersetDeltaoverset(MnO_2)to 2KCL + 3O_2`
Discussion
9.

In the laboratory, manganese (II) salt is oxidized to pemanganate ion in aqueous solution by

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Hydrogen peroxide
Conc. Nitric acid
Peroxy disulphate
Dichromate

Solution :In laboratory, POTASSIUM permanganate is prepared by oxidizing a MANGANESE (II) ion salt by peroxodisulphate.
`UNDERSET("peroxodisu lphate ion")(2Mn^(2)+S_(2)O_(8)^(2-)+8H_(2)O)rarr2MnO_(4)^(-)+10SO_(4)^(2-)+16H^(+)`
Discussion
10.

In the laboratory, manganese (II) salt is oxidised to permanganate ion in aqueous solution by

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HYDROGEN peroxide
cone. nitric acid
peroxodisulphate
dichromate

SOLUTION :In laboratory, manganese (II) ion SALT is oxidised to permagnate ion in aqueous solution by peroxodisulphate.
`UNDERSET("Peroxodisulphate ion")(2Mn^(2+)+S_(2)O_(8)^(2-)+8H_(2)O) to 2MnO_(4)^(-)+10SO_(4)^(2-)+16H^(+)`
Discussion
11.

In the following question, a statement of assertion is followed by a statement of reason . Mark the correct choice.Assertion :[Cu(NH_(3))_(4)]^(2+)is coloured while[Cu(CN)_(4)]^(3-)is colourless . Reason :[Cu(NH_(3))_(4)]^(2+) hasdsp^(2)hydridisation

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Both ASSERTION and reason are true and reason is the CORRECT explanation of assertion .
Both assertion and reason are true but reason .Is not the correct explanation of assertion.
Assertion is true but reason is false.
Both assertion and reason are false.

ANSWER :B
Discussion
12.

In the laboratory, bromine can be obtained by heating a mixture of KBr and .......... with conc.........

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SOLUTION :`MnO_2,H_2SO_4`
Discussion
13.

In the following question, a statement of assertion is followed by a statement of reason. Mark the correct choice. Assertion : Square planar complexes do not show optical isomerism. Reason : Optional isomerismis due to the absenceof elements of symmetry .

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Both assertion and reason are true and REASONIS the CORRECTEXPLANATION of assertion.
Bothassertion and reason are true but reason is not the correct explanation of assertion .
Assertion is true but reason is false.
Both assertion and reason are false.

ANSWER :B
Discussion
14.

In the lab students were asked to carry out the reaction between phenol and cons. HNO_3. But one student,'A' carried out the reaction between phenol and dil. HNO_3. Do you think that the student 'A' got the same result as others. Substantiate with suitable explanations. [Also write the chemical equations wherever necessary].

Answer»

Solution :The student 'A' got a MIXTURE of o-nitrophenol and p-notrophenol, while OTHERS got 2,4-6-trinitrophenol (PICRIC ACID).
Discussion
15.

In the following question, a statement of assertion is followed by a statement of reason. Mark the correct choice. Assertion : In any ionic solid [MX]with schottkydefects, the number of positive and negative ions are same. Reason :Equal number of cation and aniojn vacancies are present.

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Both assertion and REASON are TRUE and reason is the CORRECT explanation of assertion .
Both assertion and reason are true but reason.
Assertion is true but reason is false.
Both assertion and reason are false.

ANSWER :A
Discussion
16.

In the known interhalogen compounds the maximum number of halogen atoms is:

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4
5
7
8

Answer :D
Discussion
17.

In the following process of disproportionation 2CIO_(3)^(-)hArrCiO_(2)^(-)+CIO_(4)^(-) E_(CIO_(4)^(-)//CIO_(3)^(-))^(@)=+0.36V,E_(CIO_(3)^(-)//CIO_(2)^(-))^(@)=+0.33V If initial concentration of chloride ion was 0.1M, calculate the equilibrium concentration of perchlorate ion.

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Solution :The two reactions of the given reaction will be
`CIO_(3)^(-)(aq)+H_(2)O(l)toCIO_(4)^(-)(aq)+2H^(+)(aq)+2e^(-)`
`underline(""CI_(3)^(-)(aq)+2H^(+)(aq)+2e^(-)toCIO_(2)^(-)(aq)+H_(2)O(l)" ")`
Adding `2CIO_(3)^(-)(aq)hArrCIO_(2)^(-)(aq)+CIO_(4)(aq)`
`E_(CELL)^(@)=0.33-0.36=-0.03V`
`E=E^(@)-(0.059)/(n)logQ`
At equilibrium, `E=0,Q=K_(eq)`. also n=2, hence
`0=-0.03-(0.059)/(2)logK_(eq)`
or `logK_(eq)=-(0.03xx2)/(0.059)=-1=overline(1)` or `K_(eq)=0.1`
`{:(,2CIO_(3)^(-)(aq),hArr,CIO_(3)^(-)(aq),+,CIO_(4)^(-)(aq)),("Initial conc.",0.1M,,0,,0),("At eqm.",0.1-2x,,x,,x):}`
`K=(x xx x)/((0.1-2x)^(2))=0.1` or `(x)/(0.1-2x)=sqrt(0.1)=0.316`
or `x=0.0316-0.632` or `1.632x=0.0316` or `x=0.0194M`
Discussion
18.

In the following pairs which is represented correctly towards SN^2 reaction

Answer»




ANSWER :A
Discussion
19.

In the following pairs, which undergoes S_(N^(2)) reaction more readily?

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SOLUTION :(a). I
(B). I
(C). I
(d). I
Discussion
20.

In the following pairs of halogen compounds which would undergo S_(N^(2)) reaction faster?

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Solution :
It is a primary HALIDE and HENCE it is more REACTIVE in `S_(N^(2))`
(II) As `I^(-)` is GOOD leaving group than is more reactive in `S_(N^(2)) and S_(N^(1))` reactions
Discussion
21.

In the following pairs of halogen compounds, which would undergo S_N2 reaction faster?

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Solution :(i) . It is primary halide and therefore undergoes `S_N2` REACTION faster.
(ii)
As iodine is a better leaving GROUP because of its large size, it will be released at a faster RATE in the presence of INCOMING nucleophile.
Discussion
22.

In the following pairs of halogen compounds, which compound undergoes S_(N^(1)) reaction faster?

Answer»

Solution :The reactivity of a particular halogen compound towards `S_N^(1)` reaction depends upont he stability of the CARBOCATION formed as a result of ionisation. This is a slow step and is called rate determining step. The order of relative stabilities of different CARBOCATIONS is in the order: tertiarygtsecondarygtprimaryk. in the LIGHT of this, the order of reactivity in the two cases is explain.
(i). The isomer (a) is a TERTIARY alkyl chloride while the other (b) is a secondary alkyl chloride. the isomer (a) is more reactive towards `S_(N^(1))` reaction since the tertiary carbocation formed carbocation formed in this case is more stable than the secondary carbocation which is likely to be formed in the other case.
(ii). The isomer (a) is a secondary alkyl chloride while the other isomer (b) is primary in NATURE. the secondary alkyl chloride (a) is expected to react faster since the secondary carboaction formed is more stable than the primary carbocation which is likely to be formed in the other case.
Discussion
23.

In the following pairs of halogen compounds, which compound undergoes faster S_N1 reaction?

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SOLUTION :(i) A and (II) C UNDERGO FASTER `S_N1`
Discussion
24.

In the following pairs of halogen compounds, which compound undergoes faster S_(N)1 reaction?

Answer»

Solution :The `S_(N)1` reaction procceeds through Stable Carbocation intermediate. GREATER is the Stability of Carbocation, greater is the reactivity. Thus order of reactivity of alkyl HALIDE is :
`3^(@)R-X gt 2^(@)R-X gt 1^(@)R-X`
(i) will REACT faster because is more stable.
(ii) REACTS faster due to the greater stability of `2^(@)` - carbocation as compared to `1^(@)` - carbocation.
Discussion
25.

In the following pair find the pair in which first compound do not form complex with NH_(3) and second give coloured complex with NH_(3)

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`CoCl_(2),ZnSO_(4)`
`Agl,CuSO_(4)`
`NiCl_(2),CuSO_(4)`
`Cd(NO_(3))_(2),ZnSO_(4)`

SOLUTION :`Agl+NH_(3)to` No reaction `:.Ag` I is covalent.
`CuSO_(4)+4NH_(4)to[Cu(NH_(3))_(4)]SO_(4)` Blue colour.
Discussion
26.

In the following oxyacid of sulphur the two sulphur atoms exhibit the oxidation numbers of + IV and - II

Answer»

`H_(2)S_(2)O_(2)`
`H_(2)S_(2)O_(7)`
`H_(2)S_(2)O_(3)`
`H_(2)S_(2)O_(6)`

ANSWER :A
Discussion
27.

In the Kipp's apparatus, the reaction gets stopped on closing the outlet because

Answer»

Gas STARTS COMING out from top
The CONTACT between sulphide and the acid is broken by the presenceof gas collected in the free SURFACE of the middle chamber
The acid becomes weak
A protective film is formed on iron sulphide

Solution :The contact between sulphide and the acid is brokenby the presence of gas collected in the free surface of the middle chamber.
Discussion
28.

In the following ofpi bond the atomic orbitals overlap in such a way that

Answer»

their axes remain parallel to each other and PERPENDICULAR to the internuclear axis
their axes remain parallel to each other and parallel to the internuclear axis
their axes remain perpendicular to each othr and parallel to the internuclear axis
their axis remain perpendicular to each other and PERPENDICULARTO the internuclear axis.

Solution :During `pi` - bond formation, the orbitals FORMED due to sidewise overlapoing consists of two SAUCER type charged CLOUDS above and below the plane of the participating atoms.
Discussion
29.

In the known interhalogen compound the maximum number of halogen atoms is

Answer»


Solution :Interhalogen COMPOUND with maximum number of halogen atoms = IF7.
O.N. of `I = + 7`
O.N. of F = -1
`:. ` Sum of O.N.s `= + 7 -1 = + 6`
Discussion
30.

In the following nuclear reactions ._(7)N^(14) + ._(2)He^(4) rarr ._(8)O^(17) + X_(1) and ._(13)Al^(27) + ._(1)D^(2) rarr ._(14)Si^(28) + X_(2) X_(1) and X_(2) are respectively

Answer»

`._(1)H^(1) and ._(0)n^(1)`
`._(0)n^(1) and ._(1)H^(1)`
`._(2)He^(4) and ._(0)n^(1)`
`._(0)n^(1) and ._(2)he^(4)`

SOLUTION :Equate atomic number and mass no.
Discussion
31.

In the following molecules which one is having strongest C–H bond :-

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`H-C-=C-H`
same in all

Answer :C
Discussion
32.

In the Kjeldahl's method, the nitrogen in the organic compound in Kjeldhal's flask is converted to

Answer»

AMMONIUM sulphate
Ammonia
Nitric acid
Nitrogen

Answer :A
Discussion
33.

In the following Me_(2)C=CH-CH_(2)-CH=CH_(2)+C_(6)H_(5)CO_(3)H(1"equiv".) to X , X is

Answer»




ANSWER :C
Discussion
34.

In the IUPAC version, the ligand OH^(-) is named as

Answer»

hydroxide
hydroxyl
hydroxo
ol

Answer :C
Discussion
35.

In the following isotherm (Fig)

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`x/m ALPHA P^@` When point B is reached 
Desorption MAY start along AB 
`x/m alpha p^(1//n)` along OA 
`x/m alphaP` when point B is reached 

Solution :At low `P x/m=K.P`: medium `p x/m = K.P^(1/n)`, HIGH `P x/m = K.P^@`
Discussion
36.

In the IUPAC system. PhCH_(2)CH_(2)CO_(2)H is named as:

Answer»

benzyl acetic ACID
carboxy ETHYLBENZENE
3-phenylpropanoic acid
2-phenylpropanoic acid

ANSWER :C
Discussion
37.

In the following ions : Mn^(3+),V^(3+),Cr^(3+),Ti^(4+) (Atomic no. : Mn = 25, V = 23, Cr = 24, Ti = 22) (a) Which ion is most stable in an aqueous solution ? (b) Which ion is the strongest oxidising agent ? (c) Which ion is colourless ? (d) Which ion has the highest number of unpaired electrons ?

Answer»

Solution :`Mn^(3+),V^(3+),Cr^(3+),Ti^(4+)`
(a) `Cr^(3+)` has the highest negative electrode potential, THEREFORE, it is most stable.
(b) `Mn^(3+)` has `d^(4)` configuration, it has the maximum TENDENCY to gain one electron to change into stable HALF filled configuration, `d.^(5)`. Therefore it is the strongest oxidising AGENT.
(c) `Ti^(4+)` has no electrons in the d-orbital, therefore no absorption of light and hence colourless.
(d) `Mn^(3+)` has `d^(4)` configuration. The electrons occupy different orbitals. It has the highest number of unpaired electrons among the four.
Discussion
38.

In the IUPAC name of product .Y. is

Answer»

N - Methylpropan -2- AMINE
BUTAN -2 - amine
N -Isopropylmethanamine
N-Methylpropanamine

SOLUTION :
Discussion
39.

In the following hypothetical reaction A+3B hArr 2C+D initial moles of A are twice that of B. If at equilibrium moles of B and C are equal. Percentage of B reacted is

Answer»

0.6
0.4
0.1
0.2

Solution :`{:(A,+,3B,hArr,2C,+,D),(2A,,a,,0,,0),(2a-X,,a-3x,,2X,,x):}`
a-3x=2x(condition given)
`therefore x=(a)/(5)`
The % of b reacted is
`(3x)/(a)xx100=(3)/(a).(a)/(5)xx100=60%`
Discussion
40.

In the following how many cations are forms hydroxide as precipitates in qualitative analysis Cr^(+3), Ni^(+2), Ba^(+2), Pb^(+2), Ag^(+), Hg_(2)^(+2)

Answer»


SOLUTION :`CR^(+3)`
Discussion
41.

In the isolation of metals, reaction proces susually results in

Answer»

METAL SULPHIDE
metal carbonate
metal HYDROXIDE
metal oxide

Solution :Reduction PROCESS resultsin metal oxides.
Discussion
42.

In the following how many cations are belongs to V group in qualitative salt analysis Ba^(+2), Mg^(+2), Pb^(+2), Cu^(+2), Sr^(+2), Sn^(+2) Ca^(+2)

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SOLUTION :`BA^(+2), SR^(+2), CA^(+2)`
Discussion
43.

In the IUPAC system , "PhCH"_(2) CH_(2) CO_(2 )H is narmed as

Answer»

3-phenylpropanoic ACID
benzylacetic acid
carboxyethyl BENZENE
2 - phenylpropanoic AICD.

SOLUTION :
Discussion
44.

In the following how many cations are forms carbonate as precipitates in qualitative analysis Sr^(+2),Ni^(+2),Cr^(+3), Zn^(+2), Mn^(+2).Co^(+2), Al^(+3)

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SOLUTION :`SR^(+2)`
Discussion
45.

In the isolation of metals, calcination process usually results in:

Answer»

metal hydroxide
metal sulphide
metal oxide
metal carbonate

Solution :Calcinationis the PROCESS of convertingan oreintoitsoxideby heatingitstronglybelowitsmeltingpointeitherbyheatingit stronglybelowitsmeltingpointeitherinabsenceor limitedsupplyof air. Itis usuallydoneto convertmetalcarbonatesand hydrogento their respecitiveoxides .
` underset( "Limestone") (CaCO_3)OVERSET(DELTA)tounderset( "calciumoxide") (CaO +CO_2 uarr )`
` underset( "malachite ") ( CuCO_3.Cu (OH)_2 overset(Delta)to2CuO+H_2Ouarr+CO_2 uarr `
Discussion
46.

In the following group : -OAc(I),-OMe(II),-OSO_(2)(III),-OSO_(2)CF_(3)(IV) The order of leaving group ability is :

Answer»

`I GT II gt III gt IV`
`IV gt III gt I gt II`
`III gt II gt I gt IV`
`II gt III gt IV gt I`

SOLUTION :`IV gt III gt I gt II`.
Discussion
47.

In the isolation of metals, calcination process usually results in .........

Answer»

METAL carbonate 
Metal hydroxide 
Metal sulphide 
Metal OXIDE 

Solution :`MCO_3 overset(Delta)(rarr)MO + CO_2`
Discussion
48.

In the following groups-Oac(I), - O Me(II) , -SO_2Me(III) OSO_2CF_3 (IV) , the order of leaving group ability is

Answer»

I gt II gt III gt IV
IV gt III gt I gt II
III gt II gt I gt IV
IV gt III gt II gt I

Solution : IV > III > I > II
Discussion
49.

In the isolation of fluorine , a number of difficulties were encountered. Which statement is correct :

Answer»

The potential requied for the discharge of the fluoride ions is the lowest
Fluroine reacts with most glass vessels
ELECTROLYSIS of aqueous HF gives ozonized oxygen
Electron affinity of F is highest

Solution :(a) The potential required for the discharge of the fluoride ions is the lowest
(B) FLUORINE reacts with most glass vessels.
(C ) Electrolysis of aqueous HF gives ozonized oxygen.
Discussion
50.

In the following groups: -OA c (I),-Ome (II)-OSO_(2)(Me(III),-OSO_(2)CF_(3)(IV) the order of leaving group ability is

Answer»

IgtIIgtIIIgtIV
IVgtIIIgtIgtII
IIIgtIIgtIgtIV
IIgtIIIgtIVgtI

Solution :Weaker the base better is the leaving group. Now acidity DECREASES in the order: `CF_(3)SO_(2)OH gt MeSO_(2)OH gt AcOH gt MeOH,` therefore, basicity of their conjugate BASES increases in the reverse direction, i.e., `CF_(3)SO_(2)O^(-)(IV) lt MeSO_(2)O^(-) (III) lt AcO^(-)(I) lt MeO^(-)(II)`. thus, the CORRECT order is: IVgtIIIgtIgtII, i.e., option (b) is correct.
Discussion