Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In gaseous state, nitric oxide is ............ While in the liquid or solid state it is ........... .

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SOLUTION :PARAMAGNETIC, DIAMAGNETIC
2.

In gaseous reactions important for the understanding of the upper atomoshphere H_2O and O react bimolecularly to form two OH radicals .DeltaH for this reaction is 72 kJ mol^(-1)at 500 K and E_a is 77 kJ mol^(-1) then E_a for the bimolecular recombination of two OH radicals to form H_2O to O is:

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`3 kJ mol^(-1)`
`4 kJ mol^(-1)`
`5 kJ mol^(-1)`
`7 kJ mol^(-1)`

Answer :C
3.

In gaseous reactions important for-the understanding of the upper atmosphere H_2O and O react bimolecularly to form two OH radicals. DeltaH for this reaction is 72 kJ at 500 K and E_a is 77 kJ mol^-1, then E_u for the bimolecular recombination of two OH radicals to form H_2O and O is::

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3kj`mol^-1`
4kj `moll^-1`
5kj `moll^-1`
7kj`mol^-1`

ANSWER :C
4.

In gas phase, the basicities of amines increase in the order NH_(3) lt CH_(3)NH_(2) lt (CH_(3))_(2)NH lt (CH_(3))_(3)N This is due to

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Increase in molar mass
Avahability of one pair of electrons of atom as a result of ELECTRON donating in DUE to effect of METHYL groups
increase in dispersion forces
increase in H-bonding.

Answer :B
5.

In gaseous reactions important for-the understanding of the upper atmosphere H_2O and O react bimolecularly to form two OH radicals. DeltaH for this reaction is 72 kJ at 500 K and E_a is 77 kJ mol^-1, then E_b for the bimolecular recombination of two OH radicals to form H_2O and O is::

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3kj`mol^-1`
4kj `moll^-1`
5kj `moll^-1`
7kj`mol^-1`

ANSWER :C
6.

In Galvanic cell, the Zinc metal strip placed gets ……………… .

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Oxidised
REDUCED
HYDROLYSED
CONDENSED

ANSWER :A
7.

In galvanic cell, the salt bridge is used to :

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COMPLETE the circuit
To REDUCE lizuid junction potential in the ccell
Separate cathode SOLUTION from anode solution
Carry salts for chemical reactions to occur in cell

Answer :B
8.

In gamma-form of SO_(3), the hybridisation of sulphur is

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SP
`sp^(3)d`
`sp^(2)`
`sp^(3)`

Solution :In `SO_(2) and SO_(3)` SULPHUR undergoes `sp^(2)` HYBRIDIZATION.
9.

In galvanisation, metal plating on iron to protect againstcorrosion is:

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NICKEL plating
Copper plating
Tin plating
Zinc plating

Answer :D
10.

In galvanic cell, the salt bridge is used to

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COMPLETE the CIRCUIT
Reduce the ELECTRIC resistance in the cell
Separate cathode from anode
Carry salts for the chemical reaction

Solution :In GALVANIC cell, the salt bridge used to complete the circuit.
11.

Ingaesousstatethebasicityof amineis

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`1^(@) GT 2^(@) gt 3^(@) gt NH_(2)`
`3^(@) gt 2^(@) gt 1^(@)`
`NH_(3) gt3^(@) gt 1^(@) gt 2^(@)`
`2^(@) gt 1^(@) gtNH_(3) gt 3^(@)`

ANSWER :B
12.

In galvanic cell

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Complete the circuit
To REDUCE lizuid JUNCTION potential in the ccell
Separate cathode solution from anode solution
Carry salts for chemical reactions to OCCUR in cell

Answer :B
13.

In future an element 'X' will be discovered, names as "Tict" which belong to carbon family and it form two compound Tictous shloride andTictic chloride, then select the correct statement regarding above compound :

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Tictic ion has more ionic radii as compare to Tictous ion
Tictic ion has more ELECTRONEGATIVITY as compare to Tictous ion
Tictous chloride has more ACIDIC nature as compare to Tictic chloride
Tictous ion has more oxidation state as compare toTictic ion.

Solution :(1) `"Tict"^(+2) gt "Tict"^(+4)` (Ionic radii)
(2) `"Tict"^(+2) LT "Tict"^(+4)` (Electronegativity)
(3) Acidic nature `prop` Oxidation state
(4) OUS means lower oxidation state
14.

In fuel cell H_2 and O_2 react to produce electricity . In the process, H_2 gas is oxidised at the anode and O_2 at cathode. If 44.8 litre of H_2 at 25^@C and also pressure reacts in 10 minutes, what is average current produced ? If the entire current is used for electro deposition of Cu from Cu^(2+) , how many grams of Cu deposited ?

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Solution :Oxidation at anode : `2H_2(g) + 4OH^(-)(aq) to 4H_2O(l) + 4e^(-)`
1 mole of hydrogen gas produces 2 moles of electrons at `25^@C` and 1 atm pressure, 1 mole of hydrogen gas occupies = 22.4 litres.
`:.` no. of moles of hydrogen gas produced = `(1"mole")/(22.4 "litres") xx 44.8` litres = 2 moles of hydrogen
`:.` 2 of moles of hydrogen produces 4 moles of ELECTRO i.e., 4F CHARGE.
We know that `Q = It`
`I = Q/t = (4F)/(10 "mins") = (4 xx 96500 C)/(10 xx 60S)`
`I = 643.33 A`
Electro deposition of COPPER
`Cu_((aq))^(2+) + 2e^(-) to Cu(s)`
2F charge is REQUIRED to deposit
1 mole of copper i.e., 63.5 g
If the entire current produced in the fuel cell i.e., 4F is utilised for electrolysis, then `2 xx 63.5` i.e, 127.0 g copper will be deposited at cathode.
15.

In fuel cell H_(2) and O_(2) react to produce electricity. In the process, H_(2) gas is oxidised at the anode and O_(2) at cathode. If 44.8 litre of H_(2) at 25^(@)C and also pressure reacts in 10 minutes, what is average current produced? If the entire current is used for electro deposition of Cu from Cu^(2+), how many grams of Cu deposited?

Answer»

SOLUTION :Oxidation at ANODE :
`2H_(2(g))+4OH_((AQ))^(-) rarr 4H_(2)O(l)+4E^(-)`
1 mole of hydrogen gas produces 2 moles of electrons at `25^(@)C` and 1 atm pressure, 1 mole of hydrogen gas OCCUPIES = 22.4 litres
`therefore` no. of moles of hydrogen gas produced
`=(1" mole")/(22.4" litres") times 44.8" litres"`
= 2 moles of hydrogen
`therefore` 2 of moles of hydrogen produces 4 moles of electro i.e., 4F charge.
We know that Q = It
`I=Q/t`
`""=(4F)/(10" mins")`
`""=(4 times 96500C)/(10 times 60s)`
I = 643.33 A
Electro deposition of copper
`Cu^(2+)""_((aq))+2e^(-) rarr Cu_((s))`
2F charge is required to deposit
1 mole of copper i.e., 63.5 g
if the entire current produced in the fuel cell i.e., 4 F is utilised for electrolysis, then
`2 times 63.5` i.e., 127.0 g copper will be deposited at cathode.
16.

In Fruendlich adsorption isotherm, graph (x)/(m)rarrP does not increases suddenly on increase with value of P, because....

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VALUE of `(x)/(m)` is very less.
It POSSESS only uni-MOLECULAR adsorption.
It has MULTI molecular adsorption.
Value of k do not express. 

SOLUTION :It has multi molecular adsorption.
17.

In fructose ,the possibleoptical isomers are ……….. .

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12
16
8
4

Answer :C
18.

In froth flotation process whichof the following is used as froth stabiliser

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PINE OIL
XANTHATES
Fatty acids
ANILINE (or) Cresol

Answer :D
19.

In fructose, the possible optical isomers are ………………..

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12
16
8
4

Solution :8
20.

In froth floatation process…….acts as a collector

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SOLUTION :SODIUM ETHYL XANTHATE
21.

In froth floatation process, the lighter ore particles are wetted by ..........

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OLIVE OIL
PINE oil
Soap oil
Neem oil

Solution :Pine oil
22.

In froth floatation process many chemicals (frother, collector, activator and depressent) are use . Which is called a frother ?

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`CuSO_4`
NACN + alkali
Pine oil
Potassium xanthate

Answer :C
23.

In froth floatation method , the role of collectors is

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to enhance non-WETTABILITY of the MINERAL particles
to enhance wettability of the mineral particles
Both (a) and (b)
None of the above

SOLUTION :In FROTH floatation method , the role of collectors is to enhance the non-wettability of the minerals particles .
24.

In froth floatation process for the purification of ores, the particles of ore float because

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their surface is not easily wetted by WATER
 they are light
 they are insoluble
they hear electrostatic CHARGE.

Solution :Froth FLOATATION PROCESS is based on the PREFERENTIAL wetting properties with the frothing agent and water.
25.

In Friedel Crafts synthesis of toluene, reactants in addition to anhydrous AlCl_(3) are :

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`C_(6)H_(6) + CH_(4)`
`C_(6)H_(6) + CH_(3)CL`
`C_(6)H_(5)Cl + CH_(3)Cl`
`C_(6)H_(5)Cl + CH_(4)`

ANSWER :B
26.

In Friedel Crafts reaction, anhydrous AlCl_(3) is used. Its function is to :

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ABSORB HCl
absorb `H_(2)O`
produce ELECTROPHILE
produce NUCLEOPHILE

Answer :C
27.

In Friedel Craft reaction the electrophilie is

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`CL^(-) or X^(-)`
`OVERSET(+)(C)H_(3) or CH_(3)overset(+)(C)O`
`CH_(3)Cl`
`CH_(3)COCL`

ANSWER :B
28.

In Friedel-Crafts acylation , besidesAlCl_3 , the other reactantsare ________.

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ANSWER :B
29.

In Friedel-Craft , acylation , besides AlCl_(3) , the other reactants are

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Solution :In Friedal Craft's acylation aromatic compounds such as BENZENE, phenol etc. undergo acylation with `CH_(3)COCl` in the presence of anhydrous `AlCl_(3)` and gives ORTHO and PARA DERIVATIVES. INTERMEDIATE is `CH_(3)C^(+)=O`(acylium ion) of this reaction
30.

In Freundlich adsorption isotherm, the value of 1/n is:

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between 0 and 1 in all cases
between 2 and 4 in all cases
1 in CASE of PHYSICAL adsorption
1 in case of chemisorption

Answer :A
31.

In freundlich adsorption isotherm, the value of 1/n is

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any value from 0 to 1 
Less than 1 
Greater than 1 
a positive or negative FRACTIONAL NUMBER 

SOLUTION :`1/n = 0.1 - 0.5 i.e., n > 1 `
32.

In Freundlich adsorption isoteerm, in the plot of log (x)/(n) versus log P, if 'a' is the slope of the line and 'b' is th intercfept on the log (x/m) axis, then constant k=……… and n= ……….

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SOLUTION :ANTILOG B, 1/a
33.

In free radical bromination reaction, 3^@ alkyl bromide form as major product in :-

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Solution :Reactivity of C–H BOND = `3^@ gt 2^@ gt 1^@`
34.

In free radical mechanism of polymerization of addition polymer the chain propagation step is

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`I^*+MtoIM^*`
`"INITIATOR"toI^*`
`IM^*+MtoIM" "M^*`
`I(M)NM^*+I(M)nM^*toI(M)_nM-M(M)_n`

Answer :C
35.

In fourth group, Mn(OH)_2 on heating with PbO_2 and conc. HNO_3 gives purple colour due to the formation of

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`HMnO_4`
`K_2 MnO_4`
`PbO_2`
`PbMnO_3`

SOLUTION :`MN(OH)_(2) +2 HNO_(3) to Mn(NO_(3))_(2) + 2 H_(2)O 2 Mn (NO_(3))_(2) + 5 PbO_(2) + 6 H NO_(3) to underset("Purple colour")(2 HMnO_(4)) + 5 Pb (NO_(3))_(2) + 2H_(2)O`
36.

In forth floation process, the sulphide are particles are wetted by ............

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SOLUTION :PINE OIL
37.

In following reaction yMnO_(4)^(-)+xH^(+)+C_(2)O_(4)^(2-)rarryMn^(++)+2CO_(2)+(x)/(2)H_(2)O, x and y are

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2 and 16
16 and 2
8 and 16
5 and 2

Solution :`2MnO_(4)^(-)+16H^(+)+C_(2)O_(4)^(--)rarr 2Mn^(+2)+2CO_(2)+8H_(2)O`
38.

In following structure: If Y element belongs to group number 15 in periodic table and X,Z and P elements belongs to group number 16 then calculate the addition of formal charge of each element. [Order rule is followed]

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0
`+1`
`-1`
`-2`

SOLUTION :
39.

In following reaction what are P, Q, R and S.C_(6)H_(5)N_(2)^(+)Cl^(-)overset(H_(2)O)underset(Delta)rarr P overset((CH_(3)CO)_(2)O)underset(NaOH)rarr P overset(An.AlCl_(3))rarr R overset(" Zn Powder ")underset(Delta)rarr S

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P - Aniline, Q - Acetanilide, R - P - AMINO ACETOPHENONE, S - Benzene
P - Phenol, Q - PHENYL ACETATE, R - 2-Hydroxy acetophenone,S - Acetophenone
P - Phenol, Q - Acetophenone, R - 2-Hydroxy acetophenone, S - Benzene
P - Phenol, Q - P-methyl acetophenone, R - 2-Hydroxy acetophenone, S - Acetophenone

Answer :B
40.

In following reactionThe major product of reaction will be :-

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ANSWER :A
41.

In following how many structures show geometrical isomerism?

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Solution :[II,III,IV,VI,VIII,IX]
In case of II,III,IV,VI geometrical isomerism EXIST along `sp^(3)-sp^(3)` carbon. In these cases ring should have at least two `sp^(3)` hybridised carbon with two DIFFERENT group. In case of VIII & IX geometrical isomerism exist with `sp^(2)-sp^(2)` carbon. in cycloalkene geometrical isomerism along with C `=C` exist with EIGHT of more carbon atoms.
42.

In following how many molecules contain plane of symmetry. (9). PCl_(5)

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SOLUTION :2,3,4,6,7,8,9
43.

In following how many structures are chiral?

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Solution :[II,VI,VIII]
The dissymmetric molecules are ALWAYS chiral. Molecules in which PLANE of symmetry, centre of symmetry and ALTERNATING axis of symmetry are absent, CALLED dissymmetric molecules.
44.

In fcc , a tetrahedral void is formed by atoms at

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3 corners and 1 FACE centre
3 face CENTRES and 1 corner
2 face centres and 2 corners
2 face centres , 1 corner and 1 BODY centre

Answer :B
45.

In Fischer-Tropsch process for production of hydrocabons from CO and H_(2), the catalyst used is………..

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SOLUTION :IRON or COBALT
46.

In first transition series which of the following has lowest enthalpy of atomisation?

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Sc
Cu
Ti
Zn

Answer :d
47.

In Fitting reaction metal to used is

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NA
Cu
K
Mg

Answer :A
48.

In first order reaction concentration of reactant decrease from 0.80 mol L^(-1) to 0.06 mol L^(-1) in 45 min.Calculate half -life (t_(1)/(2))

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SOLUTION :108.4 MM
49.

In first inner-transition series, the highest oxidation state oxhibited by

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Pm
Eu
Sm
Nd

Answer :D
50.

In fire flies the flashes are produced due to the slow combustion of a protein luciferin in air and moisture . The phenomenon is known as

Answer»

Photochemical CHANGE
Photocombustion
CHEMILUMINESCENCE
None of the above

Answer :C