Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In coordination chemistry there are a variety of methods applied to find out the structure of complexes.One method involves treating the complex with known reagents and from the nature of reaction, the formula of the complex can be predicted.An isomer of the complex Co(en)_2(H_2O)Cl_2Br,on reaction with concentrated H_2SO_4 (dehydrating agent) it suffers loss in weight and on reaction with AgNO_3 solution it gives a white precipitate which is soluble in NH_3(aq). If all the ligands in the coordination sphere of the above complex be replaced by F^(bar), then the magnetic moment of the complex ion (due to spin only) will be :

Answer»

2.8 BM
5.9 BM
4.9 BM
1.73 BM

Solution :With `F^(-)` ligand, metal ION has ELECTRON CONFIGURATION , `t_(2G)^(2,1,1)e_(g)^(1.1)`
So, `mu=sqrt(4(4+2))~~4.9` B.M , where n=number of unpaired ELECTRONS
2.

In coordination chemistry there are a variety of methods applied to find out the structure of complexes.One method involves treating the complex with known reagents and from the nature of reaction, the formula of the complex can be predicted.An isomer of the complex Co(en)_2(H_2O)Cl_2Br,on reaction with concentrated H_2SO_4 (dehydrating agent) it suffers loss in weight and on reaction with AgNO_3 solution it gives a white precipitate which is soluble in NH_3(aq). The correct formula of the complex is :

Answer»

`[CoClBr(en)_2] H_2O`
`[CoCl(en)_2 (H_2O)]BrCl`
`[CO Br(en)_2 (H_2O)]Cl_2`
`[CoBrCl(en)_2]Cl. H_2O`

Solution :Water present in IONISATION sphere is absorbed by conc. `H_2SO_4`(dehydrating agent).If `Cl^(-)` present as counter ION then reacts with `AgNO_3` to GIVE WHITE precipitate of AgCl
3.

In coordination chemistry there are a variety of methods applied to find out the structure of complexes. One method involves treating the complex with known reagents and from the nature of raction, the formula of the complex can be predicted. An isomer of the complex Co(en)_(2)(H_(2)O)Cl_(2)Br, on reaction with concentrated H_(2)SO_(4) (dehydrating agent), suffers loss in weight and on reaction with AgNO_(3) solution it gives a white precipitate which is soluble in NH_(3)(aq). Similarly if all the ligands in the coordination sphere br replaced by NO_(2)^(-), then the magnetic moment of the complex ion (due to spin only) will be :

Answer»

1.73 BM
0.0 BM
4.9 BM
5.9 BM

Solution :`[Co(NO_(2))_(6)]^(3-) d^(6)` (SPIN PAIRED) DIAMAGNETIC.
4.

In coordination chemistry there are a variety of methods applied to find out the structure of complexes. One method involves treating the complex with known reagents and from the nature of raction, the formula of the complex can be predicted. An isomer of the complex Co(en)_(2)(H_(2)O)Cl_(2)Br, on reaction with concentrated H_(2)SO_(4) (dehydrating agent), suffers loss in weight and on reaction with AgNO_(3) solution it gives a white precipitate which is soluble in NH_(3)(aq). If all the ligands in the coordination sphere of the above complex be replaced by F^(-), then the magnetic moment of the complex ion (due to spin only) will be :

Answer»

2.8 BM
5.9 BM
4.9 BM
1.73 BM

Solution :`[CoF_(6)]^(3-) d^(6)` (spin free) 4 unpaired electron.
5.

In coordination chemistry there are a variety of methods applied to find out the structure of complexes. One method involves treating the complex with known reagents and from the nature of raction, the formula of the complex can be predicted. An isomer of the complex Co(en)_(2)(H_(2)O)Cl_(2)Br, on reaction with concentrated H_(2)SO_(4) (dehydrating agent), suffers loss in weight and on reaction with AgNO_(3) solution it gives a white precipitate which is soluble in NH_(3)(aq). The correct formula of the complex is :

Answer»

`[CoClBr(EN)_(2)]H_(2)O`
`[COCL(en)_(2)(H_(2)O)]BrCl`
`[CoBr(en)_(2)(H_(2)O)]Cl_(2)`
`[CoBrCl(en)_(2)]Cl.H_(2)O`

SOLUTION :`[CoBrCl(en)_(2)]Cl.H_(2)O` satisfies both conditions.
6.

In conversion of lime-stone to lime, CaCO_(3)(s)toCaO(s)+CO_(2)(g) the value of DeltaH^(@)andDeltaS^(@)" are "+179.1KJmol^(-1) and 160.2 J/K respectively at 298 K and 1 bar. Assuming that DeltaH^(@)andDeltaS^(@) do not change with temperature, temperature above which conversion of limestone to lime will be spontaneous is -

Answer»

1008 K
1200 K
845 K
1118 K

Answer :D
7.

In conversion of lime-stone to lime CaCO_(3)(s) rarrCaO(s)+CO_(2)(g)the values of DeltaH^(@) and DeltaS^(@) are +179.1 kJ mol^(-1) and 160.2 J/K respectively at 298 K and 1 bar. Assuming that DeltaH^(@) do not change with temperature, temperatureabove which conversion of limestone to lime will be spontaneous is

Answer»

1008 K
1200
845 K
1118 K

Solution :We know, `DeltaG=DeltaH-TDeltaS`
So, LETS find the equilibrium TEMPERATURE, i.e. at which
`DeltaG=0, DeltaH-TDeltaS`
`T=(179.1xx1000)/(160.2)=1118 K`
So, at temperature above this, the REACTION will BECOME SPONTANEOUS.
8.

In conversion of 2-butanone to propanoic acid which reagent is used

Answer»

`NAOH,NaI//H^(o+)`
Fehling SOLUTION
`NaOH,I_(2)//H^(o+)`
TOLLEN's reagent

ANSWER :C
9.

In countries nearer to polar region, the roads are sprinkled with CaCl_(2). This is

Answer»

to MINIMISE the snow fall
to minimise pollution
to minimise the accumulation of DUST on the road
to minimise the wear and tear of the roads.

Solution :`CaCl_(2)` acts as a non volatile solute and results in depression in freezing point. THUS, snow fall is reduced and prevents BLOCKING of roads in the POLAR region.
10.

In conversion of 2-butanone to propanoic acid when reagent is used.

Answer»

`NaOH, NaI//H^(o+)`
FEHLING solution
`NaOH, I_(2)//H^(o+)`
Tollen's reagent

Solution :`CH_(3)-UNDERSET(O)underset(||)(C )-CH_(2)-CH_(3)OVERSET(I_(2))rarrCl_(3)-underset(O)underset(||)(C )-CH_(2)-CH_(3)overset(OH^(Θ))rarr CHI_(3)+CH_(3)-CH_(2)-underset(O)underset(||)(C )-O^(-)` ,
11.

In contextof the lanthanoids , which of the followingstatements is not correct ?

Answer»

All the members exhibit `+3` oxidation state
Because similar properties, the separation of lanthanoids is not easy.
Availability of 4f ELECTRONS results in the formation of compounds in `+4` state forall the members of the series.
There is a GRADUAL decrease in the radii of the members with increasing atomic NUMBER in the series

Solution :Availabilityof 4f electrons does not result in the formation of compounds in `+4`oxidation statefor all the members of the langthanoid series.
12.

In continuous etherification process 1^(st)step is

Answer»

FORMATION of carbocation
protonation of alcohol
loss of PROTON from oxocation
cleavage of O-H BOND in alcohol

Answer :B
13.

In context with the transition elements, which of the followingstatements is incorrect ?

Answer»

In the highestoxidation states,the transiton metals show basiccharacter and FORM cationic complexes.
In the highestoxidation states of the first five transitionelements (Sc to MN), all the 4s and 3d electrons are used forbonding
Once the`d^(5)` configuration is exceeded,the tendency to INVOLVE all the 3d electrons in BONDING decrease.
In addition to the normal states, the zero oxidation state is also SHOWN by these elementsin complexes.

Solution :In the highest oxidation state, transition metals show acidiccharacter and form anionic complexes.
14.

In context with the transition element, which of the following statement is incorrect?

Answer»

In ADDITION to the normal oxidation states, the zero oxidation state is also shown by these elements in complexes.
In the HIGHEST oxidation states, the transition metal show basic character and form cationic complexes.
In the highest oxidation states of the first five transition elements (Sc to Mn), all the 4S and 3D electrons are used for bonding.
Once the `d^5` configuration is exceeded, the TENDENCY to involve all the 3d electrons in bonding decreases.

Answer :B
15.

In context with the transition elements, which of the following statements is incorrect ?

Answer»

In addition to the normal OXIDATION states, zero oxidation state is also SHOWN by elements in complexes.
In the highest oxidation states, transition elements show BASIC character and form cationic complexes
In the highest oxidation states of the first fivetransition elements (Sc to Mn). All the 4 s and 3delectrons are used for bonding
Once the `d^(5)` CONFIGURATION is exceeded. The tendency to involve all the 3d electrons in bonding decreases.

Solution :In the highest oxidation states, the transition METALS cannot form cationic complexes. Also, they show acidic character because in the highest oxidation state. They can only accept the electrons but cannot lose them.
16.

Incontext with the industrial preparation of hydrogen from water gas (CO+H_(2))which of the followingis the correctstatement

Answer»

co is oxidised to `CO_(2)` with steam in the presence of a FOLLOWEDBY absorpitoin of `CO_(2)` in alkali
COand `H_(2)` fractionally separated USING diffeences in their densites
CO is removeby absorptioninaqueous`Cu_(2)CI_(2)` SOLUTION
`H_(2)` is removed through OCCLUSION with pd

Answer :A
17.

In context of the lanthanoids, which of the following statement is not correct?

Answer»

Availability of 4f electrons RESULTS in the formation of compounds in +4 STATE of all the members of the series
There is a gradual DECREASE in the radii of the members with INCREASING atomic number in the series
All the members exhibit +3 oxidation state
Because of similar properties the separation of lanthanoids is not easy

Answer :A
18.

IN context of the lanthanoids, which of the following statements is not correct ?

Answer»

Because of similar PROPERTIES the seperation of lanthanoids is not easy.
Availability of 4f electrons RESULTS in the formation of compounds in +4 state for all the members of the series.
There is a gradual DECREASE in the radii of the members with increasing ATOMIC number in the series.
All the members exhibit +3 OXIDATION state.

Solution :The common oxidation state of lanthanoids is +3.
19.

In context of the lanthanoids, which of the following statements about cerium is incorrect?

Answer»

There is a gradual decrease in the radii of the members with INCREASING atomic number in the SERIES
All the member EXHIBIT +3 oxidation state
because of similar properties the separation of lanthanoids is not easy
Availability of 4f electrons results in the FORMATION of compounds in +4 state for all the members of the series.

Answer :D
20.

In context of the lanthanoids , which of the following statement is not correct?

Answer»

There is a GRADUAL decrease in the radii of the members with increasing ATOMIC number in the series
All the member exhibit `+3` oxidation state
Availability of `4f` electrons result in the formation of COMPOUNDS in `+4` state for all member of the series

Solution :Availability of `4f` electrons donot RESULTS in the formation of compounds in `+4` state for all the members of the series.
21.

In contact process the formation of SO_3 takes place according to the following reaction, 2SO_2+O_2hArr2SO_3,DeltaH=-45.2kcal The formation of SO_3 is fovoured by

Answer»

INCREASE of VOLUME
Increasing in TEMPERATURE
Removal of oxygen
Increasing of pressure

Answer :D
22.

In Contact process impurities of arsenic are removed by:

Answer»

`AL(OH)_(3)`
`Fe(OH)_(3)`
`CR(OH)_(3)`
`Fe_(2) O_(3)`

ANSWER :B
23.

In [Co(NH_3)_4C1_2]C1 the co-ordination number of cobalt is

Answer»

4
6
2
7

Answer :B
24.

In compound made up of A and B elements, element B form hcp lattice structure and element A occupy 2/3part of tetrahedral voids, then molecular formula of compound made up of A and B = .........

Answer»

`A_3 B_4`
`A_4 B_3`
`A_2 B_3`
`A_3 B_5`

ANSWER :B
25.

In concentration process of minerals by froth foloatation method , the ore particles float because :

Answer»

They are light
They are insoluble
Their SURFACE is hydrophobic
None

Answer :C
26.

In compound A,1,.0g nitrogen combines with 0.57g oxygen. In compound B,2.0g nitrogen unite with 2.24 g oxygen and in compound Cdd, 3.0g nitrogen combine with 5.11g oxygen. These results obey the law of:

Answer»

MULTIPLE PROPORTIONS
CONSTANT proportions.
reciprocal proportions
NONE of these.

Answer :A
27.

In compound A(C_(30)H_(60)O) following tests are observed negatively. A can be

Answer»

an unsaturated ether
an epoxide
a cyclic ketone
a cycloalanol

Solution :The compound `C_(30)H_(60)O` has ONE degree of UNSATURATION since it gives negative test with `Br_(2)//H_(2)O,2,4DNP` and `Na` METAL it MUST be an epoxide.
28.

In compound A (C_(30)H_(60)O) following tests are observed negatively, A can be

Answer»

an UNSATURATED ether
an epoxide
a CYCLIC ketone
a cycloalkanol

Solution :N//A
29.

In compound A (C_30H_60O)following tests are observed negatively, A can be :

Answer»

An unsaturated ether
an epoxide
A cyclic ketone
A cycloalkanol

Solution :The compound `C_30H_60O` has ONE degree of UNSATURATION since it gives negative TEST with `Br_2//H_2O, 2,4` DNP and NA metal it must be an epoxide.
30.

In complexes off wea field ligands, Delta_(o) lt P (pairing energy), the energy difference between t_(2g) and e_(g) sets is relatively less. Under the unfluence of strong field ligands, Delta_(O) gt p (Pairing energy), the energy difference between t_(2g) and e_(g) sets is relatively high. Q. Select the correct statement regarding [Cr(en)_(2)Cl_(2)]^(+) and [Co(C_(2)O_(4))_(2)(NH_(3))_(2)]^(-) complex ions:

Answer»

Both are EQUALLY STABLE complexes
Both have equal number of stereoisomers
Both are diamagnetic complexes
a and C both

Answer :B
31.

In complexes off wea field ligands, Delta_(o) lt P (pairing energy), the energy difference between t_(2g) and e_(g) sets is relatively less. Under the unfluence of strong field ligands, Delta_(O) gt p (Pairing energy), the energy difference between t_(2g) and e_(g) sets is relatively high. Q. Which of the following is correct statement?

Answer»

Complex `[Co(H_(2)O)_(6)]^(2+)` is more STABLE than `[Co(H_(2)O)_(6)]^(3+)`
All compounds of `Ni(II)` are bound to be outer-d-orbital complexes
Stability constant for `[Ni(en)_(3)]^(2+)` is greater than stability constant for `[Ni(NH_(3))_(6)]^(2+)`
`Delta_(OCT)` for `[Cr(H_(2)O)_(6)]^(3+)` is greater than `Delta_(oct)` for `[Cr(NH_(3))_(6)]^(3+)`

Answer :C
32.

In complexes off wea field ligands, Delta_(o) lt P (pairing energy), the energy difference between t_(2g) and e_(g) sets is relatively less. Under the unfluence of strong field ligands, Delta_(O) gt p (Pairing energy), the energy difference between t_(2g) and e_(g) sets is relatively high. Q. Select the correct increasing order of 10 Dq. value of chromium complexes: (1) [Cr(en)_(3)]^(3+) (2) [Cr(o x)_(3)]^(3-) (3) [CrF_(6)]^(3-) (4) [Cr(H_(2)O)_(6)]^(3+)

Answer»

`4 LT 3 lt 1 lt 2`
`3 lt 4 lt 2 lt 1`
`4 lt 3 lt 2 lt 1`
`3 lt 4 lt 1 lt 2`

Answer :B
33.

In complexes of gold, the coordination number of gold may be

Answer»

6
4
5
2

Solution :CN of AG and AU MAY be 2 or 4
34.

In complexes more stability is shown by:-

Answer»

`[Fe(H_(2)O)_(6)]^(3+)`
`[Fe(CN)_(6)]^(3-)`
`[Fe(C_(2)O_(4))_(3)]^(3-)`
`[FeCl_(6)]^(3-)`

ANSWER :B
35.

In complexes more stability is shown by :

Answer»

`[FE(H_(2)O)_(6)]^(3+)`
`[Fe(CN)_(6)]^(3-)`
`[Fe(C_(2)O_(4))_(3)]^(3-)`
`[Fe(CL)_(6)]^(3-)`

Solution :`[Fe(C_(2)O_(4))_(3)]^(3-)` is more stable due to chelation.
36.

In complete combustion of petrol or diesel oil in automobile engines from can be best detected by testing the fuel gas for the presence of :

Answer»

`CO +H_2O`
`CO`
`NO_2`
`SO_2`

ANSWER :B
37.

In complexes, metal atom acts as:

Answer»


ANSWER :D
38.

In complex compounds the metal atom or ion acts as a

Answer»

LEWIS ACID
Lewis BASE
BRONSTED acid
Bronsted base

Answer :A
39.

In comparison to the zeolite process for the removal of permanent hardness, the synthetic resins method is

Answer»

more EFFICIENT as it can EXCHANGE only CATIONS
less efficient as it can exchange only anions
less efficient as it can exchange only cations
more efficient as it can exchange both cations as WELL as anions

Answer :C
40.

In comparison to ferrous salts , ferric salts are :

Answer»

More STABLE
Less stable
Equally stable
NONE of the above

Answer :A
41.

In comparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M MgCl_(2) solution is …….

Answer»

the same
about twice
about three TIMES
about six times

SOLUTION :Explanation : Depression in freezing point is a colligative property. In case of `MgCl_(2)` value of van.t. HOFF factor will be more.
No. of ions yielded when a molecule of `MgCl_(2)` gets DISSOCIATED in its aqueous solution is = 3. THUS one molecule of 0.01 M `MgCl_(2)` given out three particles / ions in solution, thereby increasing the number of particles present in its solution to three times.
It is because of this that depression in freezing point of 0.01 M `MgCl_(2)` will be three times as compared to that of 0.01 M - glucose solution, where no dissociation of the molecule takes place.
42.

In comparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M MgCl_(2) solution is ………….. .

Answer»

the same
about twice
about three times
about SIX times

Solution :`"0.01 M MgCl"_(2)=0.03 M` PARTICLE concentration which is three times in comparison to 0.01 M GLUCOSE. HENCE, depression will be about three times.
43.

In comparison of ferrous salts, ferric salts are:

Answer»

more stable
less stable
equally stable
None of these

Answer :A
44.

In coparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M MgCl_(2) solution is……

Answer»

the same
about twice
about three times
about SIX times

Solution :is the correct answer. Glucose is a molecular solid while `MgCI_(2)` being lonic, provides (0.03 M) MOLES of inos per LITRE. It is thrice the number os inos procided by glucose (0.01 M).
45.

In coming years, skin related disorders will be more common due to

Answer»

Pollutants in air
Use of detergents
Water pollution
Depletion of ozone layer

Solution :In coming years, when the ozone layer BECOMES THINNER or has HOLE, ultraviolet radiations come directly that causes CANCER especially related to SKIN like melanoma
46.

In the coming years, skin related disorders will be more common due to :

Answer»

pollutants in AIR
use of detergents
water pollution
depletion of ozone LAYER

Solution :In coming years, when the ozone layer will become thinner or has hole, ultraviolet radiations will come directly to the earth that will cause cancer ESPECIALLY related to SKIN like melanoma.
47.

In column chromatography , the mixture whose different components are to be seperated is dissolved in __________.

Answer»

STATIONARY phase
mobile phase
eluents
alumina

Answer :B
48.

In colloidal state, particle size ranges from :

Answer»

1 to `10A^@`
20 to `50A^@`
10 to `1000A^@`
1 to `280A^@`

ANSWER :C
49.

In colour discharge tubes, which is used:

Answer»

Ne
Argon
Kr
He

Answer :B
50.

In colloidal state particle size ranges from

Answer»

`1 - 10 Å`
`20 - 50 Å`
`10 - 1000 Å`
`1 – 280 Å`

ANSWER :C