Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

If for any given reaction if E_(cell)^(@) value is negative, then choose correct option for DeltaG^(@) and K.

Answer»

`DELTAG^(@) lt 0, K_(eq)gt1`
`DeltaG^(@) lt 0, K_(eq)lt1`
`DeltaG^(@) GT 0,K_(eq)lt1`
`DeltaG^(@) gt0,K_(eq)gt1`

Solution :`E_(cell)^(@)=-ve`
`DeltaG^(@)=-nF" "E_(cell)^(@)`
`DeltaG^(@)=+ve impliesDeltaG gt0`
`DeltaG^(@)=-2.303" RT "log" "K_(eq)`
`THEREFORE K_(eq) lt 1`
2.

If for H_2 gas,C_p -C_v=a and for O_2 gas,C_p-C_v=b,where C_p and C_v is heat capacity in cal/g-k,then select the correct relation

Answer»

b=8a
a=b
a=16b
a=4b

Answer :C
3.

If for Ag|Ag_((0.01M))^(+)||Ag_((0.1M)^(+)|Ag, cell E_(Ag^(+)|Ag)^(@)=0.80V, then . . .

Answer»

`E_(CELL)^(@)=0.80V`
`E_(cell)=0.0296V`
Cell will not WORK as both electrodes are same
`E_(cell)=0.059V`

Solution :`E_(cell)=E_(cell)^(@)-(0.059)/(n)"LOG"(0.01)/(0.1)`
`=-0.059xx(-1.0)`
`=0.059V`
4.

If for a thermodynamic expansion, dq=0, the increase in volume is associated with ___________ .

Answer»

DECREASE in PRESSURE and INCREASE in temperature
decrease in pressure and decrease in temperature
increase in pressure and decrease in temperature
increase in pressure and increase in temperature

Answer :B
5.

If for a reaction Delta H is negative and Delta S is positive then the reaction is

Answer»

SPONTANEOUS at all temperatures
non-spontaneous at alltemperatures
spontaneous only at HIGH temperatures
spontaneous only at LOW temperature

Answer :A::B::C::D
6.

If for a sucrose solution elevation in boiling point is 0.1^(@)C then what will be the boiling point of NaCl solution for same molal concentration

Answer»

`0.1^(@)C`
`0.2^(@)C`
`0.08^(@)C`
`0.01^(@)C`

Solution :Elevation in a BOILING point is a colligative property as it depends upon the number of PARTICLES.
`Delta T_(B) ptop n`
For SUCROSE, `n = 1, Delta T_(b) = 0.1^(@)C`
For NACL, n = 2, `Delta T_(b)=0.2^(@)C`
7.

What will be half life period of a nucleus if at the end of 4.2 days, N =0.798 N_(0) ?

Answer»

10 days
12.83 days
15 days
20 days

ANSWER :B
8.

If for a given substance melting point is T_(B) and freezing point is T_(A), then correct variation shown by graph between entropy change and temperature is

Answer»




Solution :For a pure substance `T_(A)` and `T_(B)` represent the same TEMPERATURE. HENCE A is a correct choice.
9.

if for a given substance , melting point is T_(B) and freezing point is T_(A)then correct variation of entropy by graph between entropy change and temperature is

Answer»




Solution :for a PURE substance, `T_(A) and T_(B)` REPRESENT the same temperature. Hence , A is correct CHOICE.
10.

If for a first order reaction, the values of A and E_a are 4 x 10^(13) sec^(-1) and 98.6 kJ/mol respectively, then at what temperature will its half-life period be 10 minutes?

Answer»

330 K
`33^(@)C`
`57^(@)`
311.15 K

Solution : ACCORDING to Arrhenius equation,`k=Ae^(-Ea//RT)`
log k =log A `-(E_a)/(2.303RT)`….(1)
For a FIRST order reaction,`t_(1//2)=(0.693)/(k)`
`t_(1//2)`=10min=600 s
`therefore k = (0.693)/(600)=1.1xx10^(-3)s^(-1)`…(2)
Putting value of k from eq. (2) in eq.(1) we get,
`log(1.1xx10^(-3))" "=" "log (4XX10^(13))-(98.6xx10^(3))/(2.303xx8.314xxT)
`therefore` T=311.15K
11.

If following reaction is started with 6 gm of H_(2) and 14 gm of N_(2) then mass of NH_(3) formed will be : N_(2) (g) + 3H_(2) (g) overset(60%)rarr 2NH_(3) (g)

Answer»

`10.2 gm`
`51 gm`
`8.5 gm`
`0.6 gm`

Solution :`{:(,N_(2) (G),+,3H_(2) (g),OVERSET(60%)rarr,2NH_(3) (g),),(Moles,(1)/(2),,3,,,),(N_(2) "is LR",,,,,,):}`
Moles of `NH_(3)` PRODUCED `= (1)/(2) xx 2 xx 0.6 = 0.6` mole
Mass of `NH_(3) = 0.6 xx 17 = 10.2 gm`
12.

If first order reaction (A to P ) ,"calculate"(t)/(t_(1//2))"if" (15)/(16) fraction of reactant is decayed in 't' time where t_(1//2) is half life.

Answer»


ANSWER :4
13.

In the first order reaction, the concentration of the reactant is reduced to 12.5% in one hour. The half-life period of the reaction is:

Answer»

15 min
30 min
20 min
3 hr

Solution :For a first order reaction,
`K = 2.303/t LOG""([A]_0)/([A]) =2.303/60log"" (100)/12.5 = 0.0346 "min"^(-1)`
Now t `1//2 = 0.693/K = 0.639/0.0346 = 20 min`.
14.

If first orbit energy of He^(+) is -54.4 eV, then the second orbit energy will be

Answer»

`-54.4 eV`
`-13.6 eV`
`-27.2 eV`
`+27.2 eV`

SOLUTION :`E=(E_(0))/(n^(2))=(-54.4)/(4)=-13.6eV`
15.

If Fe|Fe^(2+)(xM)||Cu^(2+)(0.01M)|Cu has cell potential of 0.78V then x= . . . E_(Fe^(2+)//Fe)^(@)=-0.44V,E_(Cu^(2+)//Cu)^(@)=+0.34V).

Answer»

`xgt0.01M`
`X=0.01M`
`x lt 0.01M`
No prediction regarding x

Solution :(i) `E_(cell)^(@)=E_("reduction")^(@)("Cathode")-E_("reduction")^(@)("Anode)`
`=E_(Cu^(2+)//Cu)^(@)-E_(FE^(2+)/?Fe)^(@)`
`=+0.34-(-0.44)`
=0.78V
So `E_(cell)=E_(cell)^(@)` Hence x=0.01 M
(ii) Cell reaction :
`Fe_((S))+Cu^(2+)(0.01M) t Fe^(2+)(xM)+Cu_((S))`
So n=2
`E_(cell)=E_(cell)^(@)-(0.0592)/(n)"log"([Fe^(2+)])/([Cu^(2+)])`
`therefore 0.78=0.78-(0.0592)/(2)"log"(x)/(0.01)`
`therefore logx-log(0.01)=0`
`therefore logx+2=0`
`therefore logx=-2`
`therefore x=10^(-2)=0.01M`
16.

If [Fe(CO)_x]follows the Sidgwick rule of stability, what is the value of 'x'?

Answer»

Solution :The complex COMPOUND `[Fe(CO)_x]` following the Sidgwick rule of stability, EAN of IRON is to be equal to the atomic number of nearst inert gas 36 (Krypton).
`36 = 26 - 0 + 2 xxx rArrx= 5`
HENCE the value of x is 5.
17.

If f-block elements, the last electron enters the

Answer»

nf-sublevel
(n-1)f-sublevel
(n-2)f-sublevel
4f-sublevel.

Solution :The ELECTRONIC configuration of elementof atomic NUMBER 24 is [AR] `4s^(1)3d^(5)`. Since the last electron enters d-subshell , it belongs to d-block.
18.

If excess of Zn is added to 1.0M solution of CuSO_4, find the concentration of Cu^(2+) ions at equilibrium. The standard reduction potentials of Zn and Cu at 25^@C are 0.76 V and +0.34V.

Answer»


ANSWER :`1.7xx10^(-28)`
19.

If extent of dissociation of both KCl and BaCl_2 of some concentrations with identical value of alpha as 0.9, what is the ratio of their van't Hoff factors?

Answer»

Solution :van.t Hoff FACTOR is given as , `i=(1+(n-1))/1 ALPHA`
n=2 for KCL , i=1+(2-1) `alpha` = 1+ `alpha`
=1+0.95 = 1.95
n=3 for `BaCl_2` , i=1+(3-1) `alpha` = 1+2 `alpha`
=1+1.9=2.9
The ratio of van.t Hoff factor for KCl and `BaCl_2`
=1.95 : 2.9 =1:1.51
20.

If excess of halogen reacts with benzene then second halogen atom isintroduced in the ring at meta positions. Is it true or false?

Answer»

SOLUTION :Second halogen atom is introuced in the RING at ortho and para POSITION
21.

If excess of AgNO_(3) solution is added to 100mL of a 0.024 M solution of dichlorobis (ethylene diamine) cobalt (III) chloride, how many mol of AgCl be precipitated?

Answer»

0.0012
0.0016
0.0024
0.0048

Solution :`[CoCl_(2)(en)_(2)]CL + UNDERSET(100 xx 0.024 = 2.4)(AgNO_(3)) to underset(=2/4"mole")(AgCldarr)`
22.

If excess F_(2)(g) reacts at 0^(@)C and 1.0 atm pressure with Br_(2)(g) to give a compound BrF_(n), if 224ml of Br_(2)(g) at the same temperature and pressure produced 3.5g of BrF_(n), what is n?

Answer»

SOLUTION :`Br_(2)+nF_(2)rarr2BrF_(n)`
`224 ML Br_(2)` at 273 K and 1 ATM
`n_(Br_(2))=((1)(224)xx10^(-3))/(0.0821xx273)=0.01` mol
`n_(Br)F_(n)=2n_(Br_(2))=0.02` mol
`(3.5)/((80+19n))=0.2`
3.5=1.6+0.38n
1.9=0.38n
`n=(1.9)/(0.38)=5`
23.

IF excess metallic iron is added to an N-CuSO_4 solution, calculate the approximate concentration of Cu^(2+) when equilibrium is established.

Answer»

SOLUTION :`3 TIMES 10^-27 M`
24.

If every quantity is expressed in SI units, then molar conductivity (wedge_(m)), conducitivy (kappa) and molarity (M) are related as____.

Answer»

SOLUTION :`wedge_(m)=(KAPPA)/(M)`
25.

If ethylene, carbon monoxide and water is heated at high temperature , which of the following is formed

Answer»

`C_4H_8O_2`
`C_2H_5COOH`
`CH_3COOH`
`CH_2=CH-COOH`

Solution :`underset"ETHYLENE"(C_2H_4)+CO+H_2O OVERSET"HIGH temp"to underset"Propionic ACID"(C_2H_5-COOH)`
26.

If ethanol dissolves in water, then which of the following would be done

Answer»

Absorption of HEAT and CONTRACTION in volume
Emission of heat and contraction in volume
Absorption and heat and INCREASE in volume
Emission of heat and increase in volume

Solution :When ethanol DISSOLVES in WATER then emissiion of heat and contraction in volume.
27.

If ethene molecule is present on YZ plane then nodal plane of its pi bond will lie on :

Answer»

XY plane
YZ plane
MOLECULAR plane
(B) and (c) are correct

Solution :NODAL plane is the molecular plane.
28.

If (eta^(5)-C_(5)H_(5))" "M(C_(2)H_(4))_(2) follows EAN rule, the central metal atom/ion would be :

Answer»

`Co(Z=27)`
`Fe(Z=26)`
`Ni(Z=28)`
`Rh(Z=45)`

SOLUTION :`[(eta^(5)-C_(5)H_(5))overset(+1)M(C_(2)H_(4))_(2)]`
`impliesZ-1+6+2xx2=36 or 54`
`implies ""Z=27or 45`
29.

If equlibrium constnats of reaction, N_(2)+O_(2)hArr 2NO is K_(1) and 1/2N_(2)+1/2O_(2)hArrNO is K_(2), then

Answer»

`K_(1)=K_(2)`
`K_(2)=sqrtK_(1)`
`K_(1)=2K_(2)`
`K_(1)=1/2K_(2)`

SOLUTION :`N_(2)+O_(2)hArr2NO""...(i)`
`1/2N_(2)+1/2O_(2)hArrNO""...(ii)`
From equation NUMBER (i)
`K_(1)=([NO]^(2))/([N_(2)][O_(2)])""...(iii)`
For equation number (ii)
`K_(2)=([NO])/([N_(2)]^(1//2)[O_(2)]^(1//2))""...(IV)`
From equation (iii) & (iv) it is clear that
`K_(2)=(K_(1))^(1//2)=sqrt(K_(1)),"""Hence",K_(2)sqrt(K_(1))`
30.

If equlibrium constant for reaction 2ABhArrA_(2)+B_(2).is 49 then the equlibrium constant for reacton ABhArr1/2A_(2)+1/2B_(2). wll be

Answer»

7
20
49
21

Answer :A
31.

If equivalent conductance of 1M benzoic aid is 12.8ohm^(-1)cm^(2) and 288.42 ohm^(-1)cm^(2) respectively. Its egree of dissociation is

Answer»

0.39
`3.9%`
0.0035
`0.039%`

SOLUTION :`wedge_(m_(C_(6)H_(5)COOH))^(@)=wedge_((C_(6)H_(5)COO^(-)))^(@)+wedge_((H^(+)))^(@)`
`=42+288.42=330.42`
`ALPHA=(wedge_(m)^(@))/(wedge_(m)^(@))=(12.8)/(330.42)=3.9%`
32.

If equivalent conductance of 1 M benzoic acid is 12.8 ohm^(-1) cm^(2) and if the conductance of benzoic ion and H^(+) ion are 42 and 288.42 ohm^(-1) respectively, its degree of dissociation is

Answer»

0.39
0.039
0.0035
0.00039

Solution :`(^^_(C_(6)H_(5)COOH)^(@))=lambda_(C_(6)H_(5)COO^(-))^(@)+lambda_(H^(+))^(@)`
`=42+288.42=330.42`
`alpha=(^^_( m)^(@))/(^^_( m)^(@))=(12.8)/(330.42)= 0.03 9=3.0%`
33.

If equilibrium constant of reaction, N_(2)+3H_(2)iff2NH_(3) is K, then K' for reaction, 2N_(2)+6H_(2)iff4NH_(3) is

Answer»

`K^(2)`
`SQRT(K)`
`1//sqrt(K)`
`1//K^(2)`

SOLUTION :`K^(2)`
34.

If equilibrium constant K is 10^(3), the Delta G^(theta) for the reaction at 300 K is (assume R = 8.314 JK^(-1) mol^(-1)) :

Answer»

`- 16.582 KJ`
16.582 kJ
165.82 kJ
1658.2 kJ

Solution :`Delta G^(@) = -2.303 RT log K`
`= -2.303 x 8 XX 300 xx log 10^(3)`
`= -2.303 xx 8 xx 300 xx 3 = -16.582 kJ`
35.

if equal volumes of 0.1 M H_2SO_4 and 0.1 M HCl are mixed then the pH of resulting solution will be (log 15 = 1.176)

Answer»

0.82
1.64
2.82
1.82

Answer :4
36.

if equal volume of O.1 M NH_4OH and 0.1 M HCl are mixed, then the pH of resulting mixture will be [Given pK_b (NH_4 OH)= 4.75, log 5=0.7)]

Answer»

8.72
6.28
7.28
5.28

Answer :1
37.

If equal masses of oxygen and nitrogen are placed in separate containers of equal volume at the same temperature, which one of the following statements is true ?(Mol wt. N_2=28, O_2=32)

Answer»

<P>Both flasks contain the same number of molecules
The pressure in the nitrogen FLASK is greater than in the oxygen flask.
More molecules are present in the oxygen flask
Molecules in the oxygen flask are moving FASTER on the average than the ones in the nitrogen flask

Solution :`PV=nRT implies P=(nRT)/V implies n_(N_2)gtn_(O_2)implies P_(N_2)gtP_(O_2)`
38.

If E^(o)""_(Fe^(+2)//Fe) is x_(1),E^(o)""_(Fe ^(+3)//Fe)is x_(2), then E^(o) ""_(Fe^(+3)//Fe^(2+)) will be :

Answer»

`3x_(2) - 2x_(1)`
`x_(2) - x_(1)`
`x_(2) + x_(1)`
`2x_(1) + 3x_(2)`

ANSWER :A
39.

If enthalpies of methane and ethane are respectively 320 and 360 calories then the bond energy of C - C bond is

Answer»

80 CALORIES
40 calories
60 calories
120 calories

Solution :`CH_(4)` has 4C-H bond
`E_(C-H)=(320)/(4)=80`
In `C_(2)H_(6)` there is
6 implies C-H bond and 1 implies C-C bond
`360=E_(C-C)+6E_(C-H)`
`360=E_(C-C)+6xx80`
`E_(C-C)=120 cal`.
40.

If enthalpy of hydrogenation of cyclohexene is [-x kJ mol^-1] and resonance energy of benzene is [-y kJ mol^-1] then the enthalpy of hydrogenation of benzene will be

Answer»

`[(y - 3X) KJ mol^-1]`
`[-(X + y) kJ mol^-1]`
`[(y + 3x) kJ mol^-1]`
`[(x + y) kJ mol^-1]`

ANSWER :4
41.

If enthalpy of hydrogenation of C_(6)H_(6)(l) into C_(6)H_(12)(l) is -205 kJ & resonance energy of C_(6)H_(6)(l) -152 kJ/mol then enthalpy of hydrogenation of 1, 4-cyclohexadiene (l) is Assume DeltaH_("vap") of C_(6)H_(6)(l), C_(6)H_(8)(l), C_(6)H_(12) (l) all are equal

Answer»

`-535.5` kJ/mol
`-238` kJ/mol
`-357` kJ/mol
None

Solution :
42.

If enthalpy of neutralisation of dil HCl and NaOH(aq) is x then enthalpy of neutralisation of dil. HI and Ba(OH)_2 (aq) is

Answer»

`x//2`
2x
x
slightly LESS than x in magnitude

Solution :Enthalpy of NEUTRALISATION of strong ACID and strong base is always constant. HI is a stronger acid than HCl while `Ba(OH)_(2)` is a strong base.
43.

if enthalpies of formatuon of C_(2)H_(4)(g),CO_(2)(g) and H_(2)O(l)at 250^(@)and 1 atm pressure be 52 ,-394 and -286 kJ mol ^(-1) respectively,the enthalpy of combustion of C_(2) H_(4)(g)will be

Answer»

`1412 kJ MOL ^(-1)`
`-1412 kJ mol ^(-1)`
`+ 141 .2 kJ mol ^(-1)`
` -141 .2 kJ mol ^(-1)`

SOLUTION :`C_(2)H_(4)+3O_(2)to 2CO_(2)+2H_(2)O`
`DeltaH("REACTION")=[2xxDeltaH_(F)^(@)(CO_(2))+2xxDeltaH_(f)^(@)(H_(2)O)]`
`[DeltaH_(f)^(@)(C_(2)H_(4))+3xxDeltaH_(f)^(@)(O_(2))]`
`[2(-394)+2(286)]-[52+0]= 1412kJ mol^(-1)`
44.

If energies of the two photons are in the ratio 3:2, their wave lengths will be in the ratio of:

Answer»

`9:4`
`2:3`
`1:2`
`3:2`

Solution :`E prop 1/(LAMDA)` or `(E_(1))/(E_(2))=(lamda_(2))/(lamda_(1))=3/2`
or `lamda_(1):lamda_(2)=2:3`
45.

If energy of activation of a reaction is 2303 joule,then whatIs the value of slope of graph log kto(1)/(T)?

Answer»

`-12195.12` JOULE
`-503.27` Joule
`-120.28` joule
`-239.0` joule

Answer :C
46.

If emf of standard cell during cell reaction is 0.295 V at 298 K and n=2, then what is the equilibrium constant of such reaction ? [F=96500," "R=8.314KJ^(-1)mol^(-1)]

Answer»

`4.0xx10^(12)`
`1.0xx10^(2)`
`1.0xx10^(10)`
`2.0xx10^(11)`

Solution :`LOGK=(NF)/(0.059)`
`THEREFORE logK=(2xx0.295)/(0.059)=10`
`therefore K=1xx10^(10)`.
47.

If enthalpies of formation of C_(2)H_(4)(g), CO_(2)(g) and H_(2)O(l) at 25^(@)C and 1 atm pressure be 52, - 394 and - 286 kJ mol^(-1) respectively, the enthalpy of combustion of C_(2)H_(4)(g) will be

Answer»

`+1412 kJ mol^(-1)`
`-1412 kJ mol^(-1)`
`+141.2 kJ mol^(-1)`
`141.2 kJ mol^(-1)`

Solution :`C_(2)H_(4)+3O_(2)rarr2CO_(2)+2H_(2)O`
`DeltaH_("reaction")=[2xxDeltaH_(f)^(@)(CO_(2))+2xxDeltaH_(f)^(@)(H_(2)O)]-DeltaH_(f)^(@)(C_(2)H_(4))+3xxDeltaH_(f)^(@)(O_(2))]`
`=[2(-394)+2(-286)]-[52+0]=-1412 kJ`.
48.

If elevation in boiling point when AB is dissolved in water to make saturated solution at 25^(@)C is 2xx10^(-4) .^(@)C and K_(sp) of AB is 4xx10^(-x) then determine the value of x. (Assume alpha=1 molality = molarity) (given K_(b)=0.5K//m).

Answer»


ANSWER :8
49.

if the elevation in boiling point of a solution of non-volatile, non-electrolytic and non-associanting solute in solvent (K_(b) =xK.kg."mol"^(-1))is y K,then the depression in freezing point of solution of same concentration would be (K_(f) )of the sovent= zk.kg"mol"^(-1))

Answer»

`(Zxz)/Y`
`(YZ)/x`
`(XZ)/Y`
`(YZ)/(ZX)`

SOLUTION :`Y=xxxm,m=y//x`
`DeltaT_(f)=Zxxm=(Zn)/x`
50.

If electron, hydrogen, helium and neon nuclei are all moving with the velocity of light, then the wavelengths associated with these particles are in the order

Answer»

electron GT hydrogen gt HELIUM gt neon
electron gt helium gt hydrogen gt neon
electron lt hydrogen lt helium lt neon
neon lt hydrogen lt helium lt electron.

Solution :`lamdaprop1/m,m_(E)ltm_(H)ltm_(He)ltm_(NE^(-)).`