This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Hydroxylation of propyne in the presence of HgSO_4//H_2SO_4 is initiated by the attack of : |
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Answer» Carbene |
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| 2. |
Hydroxylamine reacts with |
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Answer» `CH_(3)COCl` |
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| 3. |
Hydroxylamine condenseswith benzaldehyde to give |
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Answer» PHCH=NOH |
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| 5. |
Hydroxyl ion concentartion of 1 M HCI is |
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Answer» `1 xx 10^(1) mol` `dm^(-3)` Now `K_(w) = [H^(+)][OH^(-)]` i.e `10^(-14) = 1 xx [OH^(-)]` `THEREFORE [OH^(-)] = 1 xx 10^(-14)` mol/`dm^(3)` |
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| 6. |
Hydroxyl amine (NH_(2)OH |
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Answer» Solution :Action of HYDROXYL amine: Glucose reacts with hydroxyl amine in aqueous solution to form glucose OXIME. This indicates the PRESENCE of CHO group in glucose. `underset("Glucose")underset(CH_(2)OH)underset(|)overset(CHO)overset(|)((CHOH)_(4)) underset("hydroxyl amine")overset(NH_(2)-OH)tounderset("Glucose oxime")underset(CH_(2)OH)underset(|)overset(CH=NOH)overset(|)((CHOH)_(4)) ` |
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| 7. |
Hydroxide soluble in ammonia is |
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Answer» `Al(OH)_(3)` `Cu(OH)_(2)+4NH_(3)rarr[Cu(NH_(3))_(4)](OH)_(2)` |
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| 8. |
Hydroxide ion in the following reaction behaves as a/an |
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Answer» Catalyst |
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| 9. |
Hydrophobic sol is easily coagulated. Give reason. |
| Answer» SOLUTION :HYDROPHOBIC sols are not stable because they do not undergo hydration. HENCE, they are easily COAGULATED by addition of a SMALL amount of electrolyte, heating or by shaking. | |
| 10. |
Hydrometallurgy method is used for the extraction of which of the following metals? |
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Answer» ZN and Ag |
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| 11. |
Hydrometallurgy is useful in the extraction of: |
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Answer» Sn |
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| 12. |
Hydrometallurgy is useful in the extraction of |
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Answer» Sn |
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| 13. |
Hydrometallurgy is a technique used |
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Answer» for extracting silver from AQUEOUS SOLUTIONS |
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| 14. |
Hydrometallurgy. |
| Answer» Solution :It is a process of extraction of metals by converting their ores into aqueous SOLUTIONS of METAL COMPOUNDS and REDUCING then by suitable reducing AGENTS. | |
| 15. |
Hydrolytic reaction of fats with is an ester |
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Answer» Esterification |
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| 16. |
Hydrolytic reaction of fats, with causticsoda, is known as |
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Answer» Acetylation |
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| 17. |
Hydrolytic reaction of fats with caustic soda is known as |
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Answer» Esterification |
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| 18. |
Hydrolytic reaction of fats with caustic soda is known as____. |
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Answer» carboxylation |
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| 19. |
Hydrolysis products of maltose are : |
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Answer» GLUCOSE and glucose |
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| 20. |
Hydrolysis products of lactose are |
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Answer» GLUCOSE and glucose |
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| 21. |
Hydrolysis of which saccharide does not give aldose or ketose ? |
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Answer» Disaccharide |
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| 22. |
Hydrolysis of ______yields acids. |
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Answer» cyanides |
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| 23. |
Hydrolysis of XeF_2 gives |
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Answer» XE and `O_2` only |
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| 24. |
Hydrolysis of which of the following compound liberates acidic gas? |
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Answer» `Li_(2)NH` |
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| 25. |
Hydrolysis of urea is an examples of |
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Answer» HOMOGENOUS catalyst Since it involves BIOLOGICAL catalyst (ENZYME) so it is an example of biochemical catalysis. |
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| 26. |
Hydrolysis of urea is an example of |
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Answer» HOMOGENOUS catalysis `H_(2)N-underset(O)(C)-NH_(2)+H_(2)Ounderset(enzyme)overset(UREASE)to2NH_(3)+CO_(2)` Since it involves BIO"log"ical catalyst (enzyme) so it is an example of biochemical catalysis. |
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| 27. |
Hydrolysis of the salt of a strong acid and weak base will |
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Answer» Increase with increase in temperature |
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| 28. |
Hydrolysis of the monomers of polyacrylonitrile gives |
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Answer» Propanamine |
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| 29. |
Hydrolysis of sugar is called : |
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Answer» MUTAROTATION |
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| 30. |
Hydrolysis of sucrose with dilute aqueous sulphuric acid yields |
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Answer» 1:1 (D) (+)-GLUCOSE,D-(-)-fructose |
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| 31. |
Hydrolysis of sucrose is called |
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Answer» hydration |
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| 32. |
Hydrolysis of sucrose gives glucose.TRUE/FALSE |
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Answer» |
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| 33. |
Hydrolysis of sucrose gives …………………….. |
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Answer» GLUCOSE and FRUCTOSE |
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| 34. |
Hydrolysis of sucrose (C_12H_22O_11) by invertase give : |
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Answer» Gluose |
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| 35. |
Hydrolysis of proteins give |
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Answer» `alpha`-amino ACID only |
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| 36. |
Hydrolysis of protein in the stomach and interstine takes place due to presence of the enzymes |
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Answer» TRYPSIN and pepsin RESPECTIVELY |
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| 37. |
Hydrolysis of prop-1- yne in the presence of HgSO_4and H_2SO_4gives ............. |
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Answer» `CH_3 - undersetoverset(||)(O)(C ) - CH_3` |
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| 38. |
Hydrolysis of protein in stomach and in intestine takes place due to action of enzyme. |
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Answer» PEPSIN in STOMACH, TRYPSIN in intestine |
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| 39. |
Hydrolysis of phenyl isocyanide forms |
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Answer» BENZOIC acid |
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| 40. |
Hydrolysis of phenyl isocyanide forms : |
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Answer» BENZOIC ACID |
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| 43. |
Hydrolysis of one mole of peroxidisulphuric acid produces |
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Answer» TWO moles of sulphuric ACID |
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| 44. |
Hydrolysis of one mole of peroxodisulphuric acid produces : |
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Answer» two MOLES of SULPHURIC ACID |
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| 45. |
Hydrolysis of oils and fats gives glycerol and long chain fatty acids containing: |
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Answer» Even NUMBER of carbon ATOMS |
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| 46. |
Hydrolysis of NCl_(3) indicates |
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Answer» `N^(-)-CI^(+)` POLARITY |
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| 47. |
Hydrolysis of nitriles with alkaline solution gives |
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Answer» SLAT of ACID |
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| 48. |
Hydrolysis of NCl_(3) gives NH_(3) and X. Which of the following is X. |
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Answer» `HClO_(4)` |
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| 49. |
Hydrolysis of methyl acetate in aqueous solution has been studied by titrating the liberated acetic acid against sodium hydroxide. The concentration of an ester at different temperatures is given below. {:("t (min)",0,20,40,60,prop),("v (mL)",20.2,25.6,29.5,32.8,50.4):} Show that the reaction is the first order reactions. |
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Answer» Solution :`k=(2.303)/(t)"log"((V_(OO)-V_(0)))/((V_(oo)-V_(0)))` `V_(oo)-V_(0)=50.4-20.2=30.2` When t = 20 MTS. `k=(2.303)/(20)"log"(50.4-20.2)/(50.4-25.6)` `=0.1151"log"^(30.2)/(24.8)` `= 0.1151 log 1.2479` `= 0.1151xx0.0959` ` = 11.03xx10^(-3)"MIN"^(-1)` When t = 40 mts `k=(2.303)/(40)"log"(50.4-20.2)/(50.4-29.5)` `=0.0576xx "log"(30.2)/(20.9)` `= 0.0576xx0.1596` `= 9.19xx10^(-3)"min"^(-1)` When t = 60 mts `k=(2.303)/(60)"log"(50.4-20.2)/(50.4-32.8)` `= 0.03838xx "log"(30.2)/(17.6)` `=0.03838xx0.2343` `= 8.99xx10^(-3)"min"^(-1)` The constant values of k show that the REACTION is of first order. |
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