Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Hydroxylation of propyne in the presence of HgSO_4//H_2SO_4 is initiated by the attack of :

Answer»

Carbene
Free radical
Electrophile
Nucleophile

Answer :C
2.

Hydroxylamine reacts with

Answer»

`CH_(3)COCl`
`CH_(3)COCH_(3)`
`CH_(3)COOC_(2)H_(5)`
`CH_(3)CONH_(2)`

SOLUTION :`CH_(3)CONH_(2)` does not react with `NH_(2)OH`.
3.

Hydroxylamine condenseswith benzaldehyde to give

Answer»

PHCH=NOH
`PhCONH_(2)`
Phc=NHOH
`PhCH_(2)CH=NOH`

ANSWER :A
4.

Hydroxy derivatives of aromatic compound are called _____.

Answer»


ANSWER :ACIDIC,PHENOLS.
5.

Hydroxyl ion concentartion of 1 M HCI is

Answer»

`1 xx 10^(1) mol` `dm^(-3)`
`1 xx 10^(-13) mol` `dm^(-3)`
`1 xx 10^(-1) mol` `dm^(-3)`
`1 xx 10^(-14) mol` `dm^(-3)`

Solution :1 M HCI, CONC. Of `H^(+) = 1 "mol"/dm^(3)`
Now `K_(w) = [H^(+)][OH^(-)]`
i.e `10^(-14) = 1 xx [OH^(-)]`
`THEREFORE [OH^(-)] = 1 xx 10^(-14)` mol/`dm^(3)`
6.

Hydroxyl amine (NH_(2)OH

Answer»

Solution :Action of HYDROXYL amine: Glucose reacts with hydroxyl amine in aqueous solution to form glucose OXIME. This indicates the PRESENCE of CHO group in glucose.
`underset("Glucose")underset(CH_(2)OH)underset(|)overset(CHO)overset(|)((CHOH)_(4)) underset("hydroxyl amine")overset(NH_(2)-OH)tounderset("Glucose oxime")underset(CH_(2)OH)underset(|)overset(CH=NOH)overset(|)((CHOH)_(4)) `
7.

Hydroxide soluble in ammonia is

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`Al(OH)_(3)`
`Fe(OH)_(3)`
`Cr(OH)_(3)`
`Cu(OH)_(2)`

Solution :Due to FORMATION of complex
`Cu(OH)_(2)+4NH_(3)rarr[Cu(NH_(3))_(4)](OH)_(2)`
8.

Hydroxide ion in the following reaction behaves as a/an

Answer»

Catalyst
Electrophile
Nucleophile
Reducing agent

Answer :C
9.

Hydrophobic sol is easily coagulated. Give reason.

Answer»

SOLUTION :HYDROPHOBIC sols are not stable because they do not undergo hydration. HENCE, they are easily COAGULATED by addition of a SMALL amount of electrolyte, heating or by shaking.
10.

Hydrometallurgy method is used for the extraction of which of the following metals?

Answer»

ZN and Ag
Ag and CU
Zn and Hg
Hg and Cu

Answer :B
11.

Hydrometallurgy is useful in the extraction of:

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Sn
Al
Hg
Ag

Answer :D
12.

Hydrometallurgy is useful in the extraction of

Answer»

Sn
Fe
Hg
Ag

Answer :D
13.

Hydrometallurgy is a technique used

Answer»

for extracting silver from AQUEOUS SOLUTIONS
for extracting SODIUM from aqueous solutions
for extracting silver from its FUSED SALT
for extracting sodium from its fused salt

Answer :A
14.

Hydrometallurgy.

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Solution :It is a process of extraction of metals by converting their ores into aqueous SOLUTIONS of METAL COMPOUNDS and REDUCING then by suitable reducing AGENTS.
15.

Hydrolytic reaction of fats with is an ester

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Esterification
Saponification
Acetylation
CARBOXYLATION

ANSWER :D
16.

Hydrolytic reaction of fats, with causticsoda, is known as

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Acetylation
Carboxylation
SAPONIFICATION
Esterification

Solution :Oil/fat + ALKALI `OVERSET("Saponification")to` Soap+glycerol.
17.

Hydrolytic reaction of fats with caustic soda is known as

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Esterification
Saponification
Acetylation
Carboxylation

Answer :B
18.

Hydrolytic reaction of fats with caustic soda is known as____.

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carboxylation
acetylation
saponification
esterification

Answer :C
19.

Hydrolysis products of maltose are :

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GLUCOSE and glucose
Glucose and SUCROSE
Glucose and GALACTOSE
NONE of these

Answer :A
20.

Hydrolysis products of lactose are

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GLUCOSE and glucose
glucose and fructose
glucose and GALACTOSE
NONE of these

ANSWER :C
21.

Hydrolysis of which saccharide does not give aldose or ketose ?

Answer»

Disaccharide
MONOSACCHARIDE
Polysaccharide
OLIGOSACCHARIDE

SOLUTION :Monosaccharide
22.

Hydrolysis of ______yields acids.

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cyanides
amides
esters
All the above

ANSWER :D
23.

Hydrolysis of XeF_2 gives

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XE and `O_2` only
Xe, HF and `O_2`
`O_2` only
`XeF_6` and `O_2` only

Answer :B
24.

Hydrolysis of which of the following compound liberates acidic gas?

Answer»

`Li_(2)NH`
`Al_(2)S_(3)`
`CaC_(2)`
`CaNCN`

Solution :`Al_(2)S_(3)` on hydrolysis GIVES `H_(2)S` GAS which is acidic.
25.

Hydrolysis of urea is an examples of

Answer»

HOMOGENOUS catalyst
Heterogenous catalyst
biochemical catalyst
zeolite catalyst

Solution :Hydrolysis of urea can be REPRESENTED as FOLLOWS
Since it involves BIOLOGICAL catalyst (ENZYME) so it is an example of biochemical catalysis.
26.

Hydrolysis of urea is an example of

Answer»

HOMOGENOUS catalysis
heterogenous catalysis
biochemical catalysis
zeolite catalysis

Solution :Hydrolysis of urea can be represented as follows
`H_(2)N-underset(O)(C)-NH_(2)+H_(2)Ounderset(enzyme)overset(UREASE)to2NH_(3)+CO_(2)`
Since it involves BIO"log"ical catalyst (enzyme) so it is an example of biochemical catalysis.
27.

Hydrolysis of the salt of a strong acid and weak base will

Answer»

Increase with increase in temperature
Decrease with increase in temperature
REMAINS unaffected with CHANGE in temperature
Remains uneffected with change in concentration of the SALT

ANSWER :A
28.

Hydrolysis of the monomers of polyacrylonitrile gives

Answer»

Propanamine
ETHANOIC acid
BUTANAMINE
Propanoic acids

ANSWER :D
29.

Hydrolysis of sugar is called :

Answer»

MUTAROTATION
SAPONIFICATION
inversion
deesterification.

ANSWER :C
30.

Hydrolysis of sucrose with dilute aqueous sulphuric acid yields

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1:1 (D) (+)-GLUCOSE,D-(-)-fructose
1:2(D) (+)-Glucose,D-(-)-fructose
1:1(D) (-)-Glucose,D-(+)-fructose
1:2(D) (-)-Glucose,D-(+)-fructose

Answer :A
31.

Hydrolysis of sucrose is called

Answer»

hydration
saponification
esterification
INVERSION

Solution : Since sucrose is dextrorotatory while hydrolysis PRODUCT of sucrose, having equimolar MIXTURE of glucose and fructose, is laevorotatory. HENCE the hydrolysed product of sucrose is known as invert SUGAR and the hydrolysis of sucrose is known as inversion.
32.

Hydrolysis of sucrose gives glucose.TRUE/FALSE

Answer»


Answer :Hydrolysis of sucrose GIVES INVERT SUGAR (equal mixture) of GLUCOSE and FRUCTOSE
33.

Hydrolysis of sucrose gives ……………………..

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GLUCOSE and FRUCTOSE
GALACTOSE and maltose
Galactose and glucose
NONE of these

SOLUTION :Glucose and fructose
34.

Hydrolysis of sucrose (C_12H_22O_11) by invertase give :

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Gluose
Fructose
Both (a) and (B)
None

Answer :C
35.

Hydrolysis of proteins give

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`alpha`-amino ACID only
`beta`-amino acids only
`gamma`-amino acids only
mixture of all i.e. `alpha , beta` and `gamma`-amino acids

Solution :Only `alpha`-amino acid are obtained on HYDROLYSIS of PROTEIN.
36.

Hydrolysis of protein in the stomach and interstine takes place due to presence of the enzymes

Answer»

TRYPSIN and pepsin RESPECTIVELY
pepsin and trypsin respectively
trypsin in both cases
pepsin in both cases

SOLUTION :Pepsin in STOMACH and trypsin in intestine.
37.

Hydrolysis of prop-1- yne in the presence of HgSO_4and H_2SO_4gives .............

Answer»

`CH_3 - undersetoverset(||)(O)(C ) - CH_3`
`CH_3CHO`
`CH_3CH_2CHO`
`HCHO`

SOLUTION :`CH_3 - undersetoverset(||)(O)(C ) - CH_3`
38.

Hydrolysis of protein in stomach and in intestine takes place due to action of enzyme.

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PEPSIN in STOMACH, TRYPSIN in intestine
Trypsin in stomach, pepsin in intestine
Both (a) and (B)
None

Answer :A
39.

Hydrolysis of phenyl isocyanide forms

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BENZOIC acid
FORMIC acid
Acetic acid
None of these

Solution :HYDROLYSIS of phenyl ISOCYANIDE forms formic acid.
40.

Hydrolysis of phenyl isocyanide forms :

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BENZOIC ACID
FORMIC acid
acetanilide
acetic acid

ANSWER :B
41.

Hydrolysis of PCI_5 gives

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`H_(3)PO_(3)`
`H_(3)PO_(4)`
`HPO_(3)`
`PH_(3)`

ANSWER :B
42.

Hydrolysis of oxide ion in water produces

Answer»

`H^+`
`OH^-`
`O_2`
`H_2O`

ANSWER :B
43.

Hydrolysis of one mole of peroxidisulphuric acid produces

Answer»

TWO moles of sulphuric ACID
Two moles of peroxomonosulphuric acid
One mole of sulphuric acid and one mole of peroxomonosulphuric acid
One mole of sulphuric acid, one mole of hydrogen PEROXIDE.

Solution :`underset("Peroxidisulphuric acid")(HO-overset(O)overset(||)underset(O)underset(||)(S)-O-O-overset(O)overset(||)underset(O)underset(||)(S)-OH) +H_(2)O to underset("Peroxomonosulphuric acid")(HO -overset(O)overset(||)underset(O)underset(||)(S)-O-OH)+ underset("Sulphuric acid")(HO-overset(O)overset(||)underset(O)underset(||)(S)-OH)`
44.

Hydrolysis of one mole of peroxodisulphuric acid produces :

Answer»

two MOLES of SULPHURIC ACID
two moles of peroxomonosulphuric aicd
one mole of sulphuric acid and one mole of peroxomonosulphuric acid
one mole of sulphuric acid, one mole of peroxomono sulphuric acid and one mole of hydrogen peroxide.

Solution :`H_(2)S_(2)O_(8)+H_(2)Orarr H_(2)SO_(4)+H_(2)SO_(5)`
45.

Hydrolysis of oils and fats gives glycerol and long chain fatty acids containing:

Answer»

Even NUMBER of carbon ATOMS
Odd number of carbon atoms
Both (a) and (B)
None

Answer :C
46.

Hydrolysis of NCl_(3) indicates

Answer»

`N^(-)-CI^(+)` POLARITY
`N^(+) -CI^(-)` polarity
`N^(-)-CI^(-)`polarity
`N^(+)-CI^(+)`polarity

Answer :A
47.

Hydrolysis of nitriles with alkaline solution gives

Answer»

SLAT of ACID
AMIDES
acid
ESTERS

ANSWER :A
48.

Hydrolysis of NCl_(3) gives NH_(3) and X. Which of the following is X.

Answer»

`HClO_(4)`
`HClO_(3)`
`HOCL`
`HClO_(2)`

ANSWER :C
49.

Hydrolysis of methyl acetate in aqueous solution has been studied by titrating the liberated acetic acid against sodium hydroxide. The concentration of an ester at different temperatures is given below. {:("t (min)",0,20,40,60,prop),("v (mL)",20.2,25.6,29.5,32.8,50.4):} Show that the reaction is the first order reactions.

Answer»

Solution :`k=(2.303)/(t)"log"((V_(OO)-V_(0)))/((V_(oo)-V_(0)))`
`V_(oo)-V_(0)=50.4-20.2=30.2`
When t = 20 MTS.
`k=(2.303)/(20)"log"(50.4-20.2)/(50.4-25.6)`
`=0.1151"log"^(30.2)/(24.8)`
`= 0.1151 log 1.2479`
`= 0.1151xx0.0959`
` = 11.03xx10^(-3)"MIN"^(-1)`
When t = 40 mts
`k=(2.303)/(40)"log"(50.4-20.2)/(50.4-29.5)`
`=0.0576xx "log"(30.2)/(20.9)`
`= 0.0576xx0.1596`
`= 9.19xx10^(-3)"min"^(-1)`
When t = 60 mts
`k=(2.303)/(60)"log"(50.4-20.2)/(50.4-32.8)`
`= 0.03838xx "log"(30.2)/(17.6)`
`=0.03838xx0.2343`
`= 8.99xx10^(-3)"min"^(-1)`
The constant values of k show that the REACTION is of first order.
50.

Hydrolysis of methyl cyanide gives :

Answer»

FORMIC acid
Acetic acid
Acetaldehyde
Formaldehyde.

Solution :`CH_(3)CNoverset(H_(2)O)tounderset("Acetic acid")(CH_(3)COOH)`